How To Exit A Java Program If User Input Nothing
Apr 17, 2014
How do i exit a java program is the user input is nothing "",This is my code
Java Code:
import java.util.Scanner;
public class MyQueue<T> implements Queue<T> {
private T[] ringbuffer;
static int capacity = 0;
int mysize = 0;
[code]....
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Aug 18, 2014
/* Jessie Garza
* 08 / 18 / 14
* ModCalculator
*/
import java.util.Scanner; // program uses Class Scanner
import javax.swing.JOptionPane;
public class ModCalculator
{
// main method begins execution of Java application
[code]....
I am having troubles with allowing the user to input operations/digits until they want to exit, I have tried looping, but I was unsuccessful, came here hoping to figure this out.Currently I have it ending with Break statements after each switch so that they don't coincide all together.. I can't figure out how to keep the Break statement AND loop to previous code of System.out.println( "Please enter an operand which you would like me to calculate with :");
String st = input.next();
c = st.charAt(0);
System.out.println( "I will need for you to input two integers and I will output the result.");
System.out.print( "Enter first integer to calculate: " ); // prompt
number1 = input.nextInt(); // read first number from user
System.out.print( "Enter second integer to calculate: " ); // prompt
number2 = input.nextInt(); // read second number from user
and allowing it to run through the rest of the program with the options still in tact, while having an if statement of an exit keyword.
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Apr 16, 2014
If a user inputs nothing the code should end ... How Should i do it?
import java.util.Scanner;
public class MyQueue<T> implements Queue<T> {
private T[] ringbuffer;
static int capacity = 0;
int mysize = 0;
[Code] ....
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Mar 12, 2014
I just want to know how I can get my program to end when the user inputs "0." By using: System.exit(0);
import java.util.Scanner;
public class TestCode
{
public static void main (String [ ]args ) {
Scanner console =new Scanner(System.in);
System.out.println("To exit program input 0");
for (int y = 1; y < 11; y++ ){ // Executes output 10 times
[code]....
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Feb 18, 2014
My question is how can I make the program repeat until the user enters the number 4 to exit?
/**
* Write an application for a furniture company; the program determines the price of a table. Ask the user to choose 1 for pine, 2 for oak, or 3 for mahogany. The output is the name of the wood chosen as well as the price of the table. Pine table cost $100, oak tables cost $225, and mahogany table cost $310. Also ask the user to specify a
(1) large table or a
(2) small table.
Add $35 to the price of any large table and add nothing to the price for a small table. Display the output. Your program must repeat until the user chooses to exit.
*/
import java.util.Scanner;
public class Wood {
public static void main(String[] args) {
Scanner input = new Scanner (System.in);
System.out.println ("Table Prices");
[Code] .....
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Apr 9, 2014
Write a java program that will ask a user to input grades until the user inputs the sentinel value -1. The program should test each input to determine whether 0<=grade<=100. If the grade entered is within this range, the program should print "Grade accepted;" if not, the program should print "Invalid input".
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Sep 25, 2014
Write a Java program that randomly generates a five-digit lottery number and prompts the user to enter a five-digit number. Each digit in the number is in the range between 0~9. The program should determine which prize the user wins according to the following rule:
• The user wins the first prize if the user input matches all five digits in the lottery number in exact order.
• The user wins the second prize if the user input matches any four digits in the lottery number in exact positions.
• The user wins the third prize if the user input matches any three digits in the lottery number in its exact position.
• The user wins the fourth prize if the user input matches any two digits in the lottery number in its exact position.
• The user wins the fifth prize if the user input matches any one digit in the lottery number in its exact position.
and here is my code. I cant get it to print the right statements.
import java.util.Scanner;
import java.util.Random;
class Hw5 {
static int getPrize(int g1, int g2, int g3, int g4, int g5,
int u1, int u2, int u3, int u4, int u5) {
//code for determining the prize comparing (g1, g2, g3, g4, g5) to (u1, u2, u3, u4, u5)
if (u1 == g1 && u2 == g2 && u3 == g3 && u4 == g4 && u5 == g5)
[code]....
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Nov 4, 2014
I have been struggling with this program for weeks. This program is supposed to take a user's inputted odd number and then print out all prime numbers lower than that number.
public class PrimeNumber
{
Scanner scan = new Scanner(System.in);
int userNum;
String neg;
public void getUserNum()
[code]...
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May 19, 2014
So i'm just toying around with making a simple inventory system, and when i'm trying to get the user's input (first the ID number, then the item name, then the item price) it will take the ID number, output asking for the name (but not take any input for it) and then ask for the item's price. I'm really not sure why it's never happened to me before when getting user input.
This is the input part of my code:
public void getInfoAdd() {
int id;
String name;
double price;
System.out.print("Enter ID: ");
id = sc.nextInt();
System.out.print("Enter item name:");
name = sc.nextLine();
System.out.print("Enter desired price: ");
price = sc.nextInt();
addItem(id, name, price);
}
And this is what it outputs:
Quote
Enter ID: 2
Enter item name:Enter desired price: 40
Successfully added: 2 $40.0
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Oct 23, 2014
Writing a program to take input from user. This input must be done with numbers only. If the input is a string I would like the program to loop and ask for input again.
double depositCheckingAmount;
do
{
System.out.println("Please insert amount to deposit into checking.");
[Code]....
As you can see my attempt is to use the ! expresssion incase the input does not equal a double. Is there another method I should be using?
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Aug 28, 2014
I have been going over my code line by line, over and over again for nearly and hour now...When I execute method `file.createNewFile()`, the method returns true and throws no exceptions. It even says that the file exists. However, the file is not created and cannot be accessed until the program has exited.
File portLib = new File("");
private class RememberPortAction extends AbstractMenuItemAction
{
methods...
protected void actionPerformed() {
LibraryCreator creator = new LibraryCreator(self, logger);
File newPortLib;
[code]....
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Oct 1, 2014
Description of the program: read a sequence of positive integers from terminal. When user types
-1, the program will print out the largest number and exit.
Program mid.java
import java.util.Scanner;
public class test
{
public static int num;
public static void main (String[] args)
{
Scanner in = new Scanner(System.in);
num = in.nextInt();
int large = num;
while(num > 0);
{
if(0 > num && num > large)
large = num;
}
System.out.println("The largest number is : " + large);
}
}
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Jan 24, 2015
This is my first java program,i am using eclipse IDE-----
package day1.example;
public class MyFirstJava {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("hi");
}
}
When i saved it,it shows no error.when i run it then a pop-up says "could not find the main class.the program will exit" and in the console it says---
java.lang.UnsupportedClassVersionError: day1/example/MyFirstJava : Unsupported major.minor version 51.0
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClass(Unknown Source)
at java.security.SecureClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.access$000(Unknown Source)
[Code] ......
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Sep 17, 2014
I am new to Java an have to Create a program that keeps track of the following information input by the user: First Name, Last Name, Phone Number, and Age. Now - let's store this in a multidimensional array that will hold 10 of these contacts. So our multidimensional array will need to be 10 rows and 4 columns.You should be able to add and remove contacts in the array.
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Oct 28, 2014
So the assignment is as follows. Develop a new class called BankAccount. A bank account has the owner's name and balance. Be sure to include a constructor that allows the client to supply the owner's name and initial balance. A bank account needs - accessors for the name and balance, mutators for making deposits and withdrawals. I have the following code :
import java.util.Scanner;
public class BankAccount{
public static void main(String [] args){
Scanner reader = new Scanner(System.in);
double name;
double balance;
double deposit;
double withdrawl;
[Code] ....
I am having trouble with my if statements. I don't know how to link the number 1 & 2 keys to deposit and withdrawal actions. Plus I am supposed to have a while loop yet don't know how to implement this so that the while loop will ask the user if they would like to make another transaction after either depositing or withdrawing.
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Mar 24, 2014
a. Assume that we have a list of employees' names of a company and their ages. Write a program that reads from the user several lines of input. Each line includes an employee's name and his/her age (as an integer). The program should calculate and print the following:
- The average age of all employees (rounded to 2 decimal places).
- The oldest employee and his/her age.
Hints:
You could assume that the user will insert valid data and at least one employee.
You could assume that the oldest employee is only one person.
User could stop the program via entering the word "end" as an employee's name.
Sample Input and Output: In each line, insert an employee's name and his/her age To halt the program, insert "end" as an employee's name
Adam 30
Tom 41
Ted 45
Karl 30
end
The average age of all employees is 36.50.The oldest employee is Hisham whose age is 45
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Feb 24, 2014
I had to write a program for class to request user input for base salary, number of years worked, and total sales. Then use the data to find out the employee's paycheck when including a bonus. I have a few issues with the code, as I have one bug, then it won't calculate anything. what I'm missing?
package chapterone;
import java.util.Scanner;
public class Examplelab {
static Scanner console = new Scanner(System.in);
public static void main(String[] args){
double baseSalary;
double noOfServiceYears;
double totalSales;
[Code]....
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Oct 1, 2014
I'm playing with vectors for the first time... What I'm trying to do is to allow a user to input one or more integers and store them in a vector for manipulation later on in the program... Here's the portion of the program I'm working with:
Java Code:
package com.itse2317;
import java.util.*;
public class VectorTest
{
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
[code]...
My question is this: Is there any way to move from inputting integers to printing them, without entering a non-integer (for example, hitting enter)? I looked at the API for the Vector class, and either I'm not thinking about the problem the right way to be able to find an answer, or it's just not there.
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Oct 20, 2014
I am writing a short quiz program, and when the user inputs their answer they hit the enter key (the are int). But the last question on my quiz is asking the user to they want to repeat the quiz, but when I run the program, it won't allow me to input any information. I can briefly remember my lecturer saying something about entering in a code after each int the user inputs but I can't remember what it was.
Here is a snippet of my code:
//Question 3
do{
System.out.println("Question 3- What Hollywood actor did Mila Kunis have a baby with recently?");
System.out.println( question3 + ".Ashton Kutcher 2.Bradly Cooper 3.Leonardo Dicaperio h.Get a hint");
answer3 = stdIn.nextInt();
if(answer3 != question3)
[Code] ....
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Feb 2, 2015
Ok so I have my program working for the most part. In this program I am supposed to take input from the user until they enter a negative number and that works, the problem is that it doesn't work if I enter a negative number on the first prompt. For example if I enter a 100 it would prompt me again and if I enter a negative number it would quit and give me the average, but if I enter a negative number the first time I am prompted the program just gives me an error. How do I fix that?
import java.util.List;
import java.util.ArrayList;
import java.util.Scanner;
public class Application {
public static void main(String [] args){
Scanner input = new Scanner(System.in);
List<Integer> grades;
[Code] ....
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Sep 23, 2014
I need to design, implement, and test a program to input and analyze a name. The program begins by retrieving a user input string from the keyboard. This string is intended to be the user's name. These are the errors we have to search analyze the user input for: No blanks between names firstName and lastName, Non-alphabetic characters in names, Less than two characters in first name, and Less than two characters in last name. Each of these errors must be thrown. All exceptions must be derived from a programmer-defined class called NameException. Each exception should use a detailed message to differentiate among the file types of errors.
This is the format of my NameException class, is the format itself correct? I will fill in the details of each exception I am just wondering if that is how I should set it up.
public class NameException extends Exception {
private String firstName, lastName;
public NoBlanksException(String firstName,String lastName) {
}
public NonAlphabeticalCharactersException(String firstName, String lastName) {
[Code] .....
I was told not to try and catch thrown errors in the main method, would I just create another method in the Driver class to take care of that then?
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Dec 17, 2014
My program is user input 20 char and the program will print the most common. So I use another int arr which count the number appears in the original array. i know its not so Effective but I don't know why it run but it stop in the middle. I got this code :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 20
at Ex2.common(Ex2.java:39)
at Ex2.main(Ex2.java:23)
import java.util.Scanner;
class Ex2 {
public static void main(String[] arg) {
Scanner reader = new Scanner (System.in);
char[] arr=new char[20];
System.out.println("Please enter 20 chars:");
for (int i=0;i<20;i++)
[Code] ....
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Apr 7, 2014
I have been assigned to write a program that has a user input random numbers then the program is to sort them in different ways. I have the coding for the different sorts but, I have an error saying that I am missing a return statement in the "Bubble" method. I am trying to return "arr[i]" in the "for loop" which gives me this error, and when I try to take the "return arr[i]" outside of the "for()" loop the error reads the it cannot locate variable "i".
import java.awt.* ;
import java.awt.event.*;
import javax.swing.*;
public class SwingSorts extends JFrame implements ActionListener
{
JRadioButton bubble;
JRadioButton selection;
[Code] .....
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Oct 26, 2014
My homework assignment is: Using a do-while statement, write a Java program that continuously requests a grade to be entered. If the grade is less than 0 or greater than 100, your program should display an appropriate message informing the user that an invalid grade has been entered; a valid grade should be added to a total. When a grade of 999 is entered, the program should exit the repetition loop and compute and display the average of the valid grades entered. Run the program on your computer and verify the program using appropriate test data.
When I run it, I don't get the correct average. I know that i'm supposed to enter 999 to exit the loop and to display the average, but 999 is being added with the loop. I'm not sure how to make it not do that.
//stephanie
import java.util.Scanner;
public class gradeAverage
{
public static void main(String[] args)
[code]....
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Apr 13, 2015
With my code the menu runs. But when the user has typed in the name of a fruit (to reserve it) I'd like it to say 'Reserved' when the user then presses 'V' (to go and view all fruit)I have read Oracle Java Collections Arraylist and from my understanding I either have to code using the get method or equals method but I'm not too sure how to (I did try though)
import java.util.ArrayList;
import java.util.Scanner;
public class FruitApril {
public static void main(String[] args) {
[code]...
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Jul 21, 2014
This is the java code that I wrote for a password:
// java application that asks the user to enter a password
import java.util.Scanner; //program uses class scanner
public class password{
//main method used to execute java application
public static void main(String args[]){
//create scanner to obtain input from command window
[Code] ....
here is the output of the code when I run it :
entered the passwordreason
Try againPress any key to continue . . .
The code compiles without errors. The problem is when , I entered the actually password that I declared in my code, it doesn't output "You entered the correct password" but it instead outputs "Try again", which is supposed to be the output if you've entered the incorrect password. What did I do wrong?
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