I am a new to Java and currently doing a study on applets.
I was looking for the demo folder in the jdk but I cannot find it. I was previously using jk7_51 and now using jdk8. and both of them do ot have the folder. I downgraded to jdk6 but i still could not find the foler. I need it since i need to try out the applets that come with the jdk. What I should do?
Whenever I try accessing the appdata folder from my applet it gives me the following error:
java.io.FileNotFoundException: C:users<user name>AppDataRoaming est est.class (Access is denied)
I need to copy a file from Windows folder to unix folder using Java
I need a FTP utility.
The file is processed by a Java program and the file has to be written to Unix folder
I have the unix server name and folder name.
how to do it?
Where can I learn or how can I, being the most efficient way known to do so, create a folder outside my JAR file with the java source code, this then will copy YAML documents from my JAR file to that folder, then I need to read the YAML documents some way. I'm making an addon for a game, I am using an API that allows you to make a config.yml easily, and add and read entries from it, but I've read that I need to make my own methods to be able to create additional YAML documents.
I don't exactly know what to type in google to perhaps find such a page, but I did try to find a tutorial page about this or something and couldn't.
I've partially figured out how to create a folder, but I have a problem, how can I RETURN one directory to make the folder, I don't want to make the folder in the JAR file I want to make it just outside the Jar file in the same folder that the Jar file is at.
Ok, here's what I got.
import java.util.Random;
import java.util.Scanner;
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
public class demoGuessGame {
public static void main(String[] args) {
Random any = new Random();
Scanner input = new Scanner (System.in);
try {
int maxNum, maxTries, guess;
boolean win = false;
[Code] .....
I want to make it loop again when asked, "Do you want to play again?"
Oracle's MouseEventDemo.java does not compile.
I get error message "Cannot find BlankArea class"
BlankArea class exists in same folder as MouseEventDemo.
Which application i need to download and set up ?
Means like in php we can install xampp and there for a new app we need to create a folder in htdocs folder...and after that , that folder works like a app.
I am creating a very simple webpage where I am using just a little bit of JSP to include partials (header, footer and asides) that are centrally located. One of the constraint that the site owner has put is that, for SEO reason, he wants to keep the url's the way they are. Most of the pages are located in the same folder, except for one which is in a subfolder.
Here is my problem, I have the partials in a folder and at the same level the images. Now, for that page located in the subfolder, when I include the partials, it is not able to locate the images because they are located in a folder one level up. What I could do is create a copy of the image folder in the subfolder or an adapted copy of the partials (referring to the images one level up), but either solution would make for a maintenance nightmare and repeat information on the server.
Here is a visual representation of my file system:
- Top level folder
- Partial_Folder
- header.html
- footer.html
- images
- picture_1.jpg
- Page_1.html
- Page_2.html
- Another_Folder
- Page_3.html
I am creating a bukkit plugin, but my question has nothing to do with bukkit, just Java. I am trying to load a file that is located in the same folder as the jar file that is being run and I am having no luck. I can't set a manual path because if I move this plugin to a remote server it won't work. So how to get a file from the same folder as the jar.
View Replies View RelatedI have developed small program which read file from particular folder, i used method "getfilename" to read file name but system raise an error.
how can we read file name instead of completion path of file.
What is wrong with my code? System.out.println prints the correct name, but it fails when i try to rename the files in a directory.
import java.io.BufferedReader;
import java.io.IOException;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.io.*;
import java.io.File;
[code]....
Within my program I allow users to write their own code to be executed. I then save that code in a .java file and then compile. This gives me a .java file and a .class file within the same package in the src folder. However, the compilation process also creates a .class file in the build folder. When the user edits their code and then re-runs it, the .class file in the build folder does not get updated with the new data, but the .class in the src folder does.
What I want to do is to execute the .class file in the src folder and not the build folder. So far I have the following method, but that somehow refers to the .class file in the build folder:
public void runMethod(String packageFilePath, String className){
try{
URI fileURI = new URI("file:/src/uk/learningAid/UserInputs/");
URL url = fileURI.toURL();
URL[] urls = new URL[]{url};
[code]....
i have some jsps under WEB-INF folder and as i know that they cant be access directly. so how can i access those jsps.
View Replies View RelatedI have observed a strange behavior in my system. whenever i installed jdk1.8.0_11, the issue is that, unknowingly the 'Bin' folder which is underneath 'C:Program FilesJavajdk1.8.0_11' is emptied. When and how it is emptied i wouldn't be knowing. I have to download the entire jdk every time in order to have Bin folder content every time.
I am using my office laptop, Is that the problem? I mean office IT department have any control on this? If so , what can i do to over come this problem?
I inherited a web application and am trying to build it. I recently installed JasperSoft Studio 5.5.0 final on my developer machine. I also have Eclipse Juno on my developer machine. I was advised by the previous developer to put some of his Jasper .jar files into my web app's lib folder. I did do this and now the localhost will not run, it is generating this error:
org.apache.jasper.JasperException: java.lang.NullPointerException
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:502)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:430)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:313)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:260)
javax.servlet.http.HttpServlet.service(HttpServlet.java:723)
I went out to the lib folder and saw these files:
jasperreports-5.1.2
jasperreports-applet-5.1.2
jasperreports-expressions-1.0.0
jasperreports-exprfunction-1.0.0
jasperreports-fonts-5.1.2
jasperreports-javaflow-5.1.2
The version on them would appear incorrect given my version of 5.5. I am new to Jasper Reports. I suppose I could google on the .jar files and get the ones that belong to the 5.5.0 final and put them into the directory to see if Apache Tomcat 6.0.39 likes that better. And then start the server. If it doesn't like them, I guess I could remove them and continue, but I would prefer to have the Jasper Reports up and running.
My second question about the Jasper Reports is how do you tell the IDE where the Reports are located?
I need to access and view files/foldersand if possible i can download from shared folder from other system using java
View Replies View RelatedI have JSP application naming myProject ,which has been deployed in webapp folder in tomcat. I want to provide security for myProject folder. I mean, I want to protect it from copying by someone else. Is there any way to do the same. I tried by hiding the folder using one of hiding software, but when I do that, I was not able to access those files in web browser.
View Replies View RelatedFile dir = new File("file"); //creates folder named file
File dir1 = new File("file.txt"); //creates file
But I want to take in a file name from user e.g.
BufferedReader br = new BufferedReader(is);
String filename = br.readLine( );
File dir = new File(filename + ".txt");
its expecting a string literal is there a way round it to take a string???
In my java app there is a code which reads the properties file from src/main/resources folder.
Java Code:
@Component("mailerProperties")
public class MailerProperties {
private static Properties properties;
public MailerProperties() {
properties = new Properties();
[Code] ....
Now I need to create a jar file and also remove the properties file from src/main/resources folder and place it outside the jar file(in the same location as jar file) so that data inside it can be changed easily in future.
Question: Currently it uses ClassPathResource("mailer.properties") to read the prop file. What change I need to make to read it from outside the jar file...
I have uploaded file into specified folder.So I have to download it..
View Replies View Relatedi have to save some particular info of a pdf file info into a database.there are lots of folders with tons of pdf files to be analized and then getting that info saved. make the process incremental? i need the program to stop at some point. and then continue to analize the resting files in the folders (i dont want the program to start all over again from 0 )my ideas are..sorting all the files using apache commons sort (by date) method (iv seen it somewhere) and saving the last file analized in the dabatase to then continue. OR just adding some extra character to the pdf file name that has been analized like for example xx-xxx.pdf to xx-xxxa.pdf.
View Replies View RelatedI am working in jsf application, in that one requirement is present. If we click "Take picture" button using webcam from web browser, image has to be captured and displayed in the screen. Finally by clicking save button picture has to be stored either in Database or in File Folder.
View Replies View RelatedI'm trying to read images and draw them on JLabel. This code snippet below is reading images from a folder
private ArrayList<ShowItem> getData() {
int score = 0;
ArrayList<ShowItem> item = new ArrayList<ShowItem>();
File dir = new File(getImageFolderPath());
if (dir.isDirectory()) {
for (final File f : dir.listFiles(IMAGE_FILTER)) {
BufferedImage img = null;
try {
[Code]...
ShowItem is a class that extends Image. DisplayImage extends ShowItem.
One of the overridden methods in ShowItem is
@Override
public Graphics getGraphics() {
return null;
}
I'm not exactly sure what to do here so I left it.
In another class, where I draw the images on Jlabel. This is what I have:
ShowItem theImage;
private ArrayList<ShowItem> listofImages;
theImage = listofImages.get(random.nextInt(listofImages.size()));
ImageIcon icon = new ImageIcon(theImage);
label.setIcon(icon);
I tried to run it, and check if I'm actually getting the images, and did system out and it listed all the jpg images I have but it's not displaying on the panel.
How to allow the user to select several files from one folder in the JFileChooser and copy them in a subfolder in the same folder, or another folder?
View Replies View RelatedI want to execute a class from src folder in JSP page. But i have receiving the error only..,
Java Code:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<%@page import="ServerInitiator" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
[Code] ....
My package structure is :
I have try by using the above, is their any perfect way to call this..
I need to execute a perl file from a resource folder, So that i can able to run the perl file after changing the project to a jar file. And also i need to pass an argument also.
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