How To Handle String With Characters

Sep 16, 2014

how we can handle the string with special characters. For instance:

123456789BNJKNBJNBJKJKBNJKBJKNBJK"VJKNBJNHBJNJKBVJ KBJKNB"VHBVBBVNBVNBVBVBVBNBVNBNBJHFBVFJB FNVJBNVJNVJDFNVJKNVJKNVJKVNNVJ NN"

I get some user inputs with double quotes and i need to split to 80 chars line.

.length fails to get the length if it contains special characters like double quotes and ?

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String Split Method To Tokenize String Of Characters Inputted?

Sep 27, 2014

I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:

import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {

[Code] .....

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Ignore Certain Characters In A String

Apr 5, 2014

I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.

else if(message.charAt(i) == 'L' && message.charAt(i+1) != 'O' | message.charAt(i+1) == 'Y'){
JLabel localLabel = new JLabel();
localLabel.setIcon(lantern);
panel.add(localLabel);
panel.revalidate();
panel.repaint();

But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.

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How To Find Different Characters In String

Apr 8, 2014

like i have String s="11222ddeefs"

so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1

it has to show no of duplicates in each character in string

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Oct 17, 2014

As of right now my code can take characters from a string to an array from a string like "ABCD" but the project says I have to take it from a string like "A B C D" how can I correct my code to grab the characters from a single spaced line?

Scanner sc = new Scanner(System.in);
System.out.println("Enter Order of Cars:");
String carsInput = sc.next();
int x = carsInput.length();
int[] cars = new int[x];
for (int i=0; i < cars.length; i++) {
cars[i] = carsInput.charAt(i)-64;
}

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Sep 10, 2014

So what my program is supposed to do is take a number inputted by the use and then take a phrase. It then changes that phrases letter by the number inputted prior for example if you type in 2 as your int and Hello as your phrase you should get JGNNQ, which i can do. but the problem is that when i run it, it outputs like this:

J
G
N
N
Q

As separate characters how can I combine those characters in 1 string so it looks like JGNNQ? this is my code

import java.util.Scanner;
public class Dcod_MAin {
private static final Object[] String = null;
public static void main(String[] args){
Scanner input = new Scanner (System.in);
System.out.println("What is the day of the month");
int shift;

[Code] ....

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Jul 5, 2014

I need to make a string filled with naughts and crosses like this one : "xxx ooo xox". There are 3 groups separated with a space. how to fill the string randomly ?

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May 7, 2014

I just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."

public class ap {
public static void main(String [] args){
String s = "Hello";
String s2 = "aeiou";

[code]....

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How To Check A String For NON-Alphabetic Characters

Oct 2, 2014

I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?

for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}

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Nov 4, 2014

I am trying to count the number of non_blank characters in a string. If there are no leading blank spaces it works fine but say i add three spaces in front it doubles the non blank characters.

import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
count = 0;

[Code] ....

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Characters From String In Alphabetic Order Using Quicksort

Oct 1, 2014

I am trying to do a program that takes all of the chars from a string and orders them in alphabetical order. It works fine, but when a is a last letter of a string it isn't being sorted.

Example: bcba = bbca, omnibus = bimnous (here u is in wrong place)

Here is my code:

public class sorty{
public static void sort(char[] a, int low, int high){
int i = low;
int j = high;
if (j - i < 2) return;
int m = (j+i)/2;
char p = a[m];

[Code] .....

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String Characters Display First Three Multiple Times

Sep 26, 2014

I am trying below challenge to display first three characters three times if the size of the string is greater than 3.

Say if i send hello i should get helhelhel

if i send xyz i should get xyzxyzxyz

I wrote as below

public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}

I am getting error as below

Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String

Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.

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Jun 30, 2014

In this simple example, I print a byte array to String:

Java Code:

import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
public class PrintByteArray {
public void print(){
System.out.println(Charset.defaultCharset());
byte[] arr = {1, 2, 3, 4};

[Code] ....

However, Eclipse prints out strange boxes, which I was unable to copy into this message.

It's supposed to print out the values of the bytes. What am I doing wrong?

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Dec 11, 2014

I am trying to change an input String to an array of characters, but it only stores the word before the space into the array. Here is the code:

Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);

Just typing hello gives me hello, but when I type hello world it does not type in the word "world".I am trying to change an input String to an array of characters, but it only stores the word before the space into the array.Here is the code:

Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);

Just typing hello gives me hello, but when I type hello world it does not type in the word "world".

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Java Program To Remove Repeated Characters In A String

Jan 27, 2015

I was trying to create a java program which can remove the repeated characters in a String. For ex-

Input: kamehamehaaa
Output: kameh

Here is my code:-

import java.util.Scanner;
class replace {
public static void main (String args[]) {
Scanner br = new Scanner(System.in);
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[Code] ....

On executing the program, StringOutOfBoundsIndex error occurs.

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Feb 18, 2014

I do have a quick question about string manipulation. You see I've been given a simple exercise that involves asking the user to input a number between 1,000 and 999,999 and displaying the result. Simple enough, but the caveat is that if the user keys in the comma, say 24,000 instead of 24000 for example, the program is not to display the comma. I don't see how to do this without an 'if' statement. The book says the 'if' is not necessary but does offer this hint: "Read the input as a string. Measure the length of the string. Suppose it contains n characters. Then extract the substrings consisting of the first n-4 characters and the last three characters."

What good is n-4 going to do if the string's lengths varies?

Here's what I have written thus far:

import java.util.Scanner;
 public class P13
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Please enter a number between 1,000 and 999,999: ");

[Code] .....

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Jul 3, 2014

I'm attempting a small program as I'm teaching myself the ropes. In it, I need to compare one string (the base) to another which is just the base string that's had it's characters shuffled.

Java Code:

String base = "ABCDEFG"
String shuffled = "CDAFBEG" mh_sh_highlight_all('java');

What I need to do is run a loop that shuffles the base string each time, but compares and saves any characters that match in the correct location. For example, if shuffled = "CDAFBEG", then the G would be "locked" in place and the rest of the characters shuffled and looped back to the comparison.

I have all the code I need for shuffling the string, but I'm not sure how I would go about comparing each character and then also locking it in place. I get the basics, I think, of needed to use several variables.

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The problem is i want to replace some string text with foreign characters, but JTextArea returns plainText.

For Example:

str = new String();
str.replace('e', 'é');
textArea.setText(str);

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I'am trying to converting string data into xml data using xml beans and StringEscapeUtils.This is work fine but in one case it if the data contains special characters.
  
Code snippet
--------------------
import org.apache.commons.lang3.StringEscapeUtils;
import org.apache.xmlbeans.XmlException;
import org.apache.xmlbeans.XmlObject;
public class ParseXMLData { 
    public static XmlObject parseXML(String stringXML) {
        XmlObject xmlObject = null;

[Code] ....
 
success case
---------------------------
i/p------<aaa><bbb>This converts string to xml</bbb></aaa>
o/p---<aaa><bbb>This converts string to xml</bbb></aaa>
 
Failer case
-----------------
i/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
expected o/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
 
Observed that it converts < to '<' but  as per xml rules, if data contains '< ' it fails. I want to convert staring and end tags to xml format and if data in b/w middle of starting and ending tags do'n need to convert it. How to do it.

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I am writing a code that I want only to accept numbers 1 through 8 and to recognize when it isn't an integer being put in. I tried the following:

Java Code: int classSelect = keyboard.nextInt();
try
{
while( (classSelect<1 || classSelect>8))

[Code]....

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Another approach is too allow the JPA exceptions to be thrown and catch them in a try-catch block, and then throw my custom exception from the "catch" block. However it requires to call EntityManager.flush () at the end of the "try" block. Otherwise the exception throw could be deferred and never be caught by my block.

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I am trying to execute the a command using process builder. But that command is having some Japanese Character. So it is executing the command but result is not as expected.

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See here a sample code which i tried ...

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[Code] ....

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