I'm trying to iterate through an array of integers and find the start position of the part of the array containing the most consecutive 1s.
For example given the array {1,3,1,1,1,1,5,3,2,1,1}, the method should return 2 and given {1,4,5,1,1,1,5,1} the method should return 3.
So far, I've managed to retrieve the element where the consecutive 1s begin. However, I'm unsure how to get the index of this element and this implementation doesn't work if there is more than one set of consecutive 1s.
public class GetIndex { public static int getPosition(int[] myArray) { int index = 0; int tracker = 0; int mostOnes = 0; for(int i = 0; i < myArray.length; i++) {
I'am new to java, this question may have been asked earlier but I'm not getting the exact answer.I want to add data from database into at and display it through jsp. But empty or null values is shown i.e no data is being displayed and when I execute the same sql query which is used in code in sql server then required output is displayed. My java code is:
Java Code:
public List < Alarm_Bean > get_Count(String system_Name) { if (system_Name.equals("MPS")) { try { con = getConnection(); stmt = con.createStatement();
I would like getting a specific parameter name from the set of request parameters. In particular the name of the 4th parameter in the request parameter set.
I am receiving an ArrayIndexOutOfBoundsException for the following code, which moves a creature through a 2D array maze. I have altered the clauses of the first if statement for the four direct methods (north, south, east, and west) multiple times (i.e. x + 1 >= 0 && x > 0 && x - 1 > 0 && x < array.length...etc). However, while the code occasionally runs, more often than that it returns this exception. Catching the exception seems like a poor workaround though if worst comes to worst I'll do that.
I included only the relevant functions of the code:
public boolean goNorth(char[][] array) { boolean success = true;; x = getX(); //x = this.x; y = getY(); //y = this.y; if ((x - 1 >= 0 && x - 1 < array.length) && (y >= 0 && y < array[x].length)) {
I am currently working on a project where I have a dataTable, containing some of the information for a specific database table, with commandLinks at the side which I need to bring me to a new page(another jsf file that I have to display the relevant information there) and display only the row of data selected. I've been racking my brain about this and have been unable to figure out a way to do it.
i am fairly new to java but have made a few projects so i do know most aspects that would allow me to complete the task its just i have been stuck at the same place now for 2 days.The project is to create a java program that can read specific data within a csv file to work out the averages etc. The csv file is a database of different weather stats . an example of the first 12 months of the csv file is below..
I know that once the data is indexed i can than use a double to find the average of the 12 specific pieces of data and so on. once this is complete i should than be able to transfer the data to a simple graph.
I searched online for this error and found out it's because the array is smaller than the index but I am not sure how I can fix this error....
public Lamborghini[] getCarsWithHorsepowerRange(double lowHP, double highHP){ int i = DEFAULT_ZERO; Lamborghini[] carWithinHPRange = new Lamborghini[i]; for (Lamborghini lambos : inventory){ double horsePower = lambos.getHorsepower();
[Code] ....
I tried
Lamborghini[] carWithinHPRange = new Lamborghini[i+5];
//which works sometimes because once I boost up the range and so there'll be more result then the error came up again....
My project was to create an array holding 10 integers and populate the array with 10 random numbers. Then ask the user to guess the number. Prompt the user with a while loop if their input is out of range. Determine if the users number is in the array, and display which index location the number is in. I got most of the code done but am having trouble displaying the index location.
import javax.swing.*; public class Homework4 { public static void main(String[] args) { int[] numarray = new int [10]; char repeatcode = 'y';
I am trying to make different arrays each being filled with random numbers from 0 to 2000, however when I run this code I get the error mentioned in the header. here is part of my code
for (int i = 1; i <= 14; i++) { int n = (int) Math.pow(2, i); int[] list = new int[n]; for( int j = 0; j <= list.length; j++){ list[j] = (int) (Math.random() * 2000); } }
I want to find a certain element in array I have to scan through the array index starting from 0 until I find the number I am looking for. Even in data structures which use hashing like HashMap and Hashtable we will have to scan through the keys until we find the key we are looking for. So what is the use of hashing over index based searching? I mean how is hashing an advantage over an array?
I am getting error array index out of bound ... Error detail is :
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 at abhiExample.arraytwodiam.main(arraytwodiam.java:27 )
And program is
Java Code:
package abhiExample; import java.util.Scanner; public class arraytwodiam { public static void main(String [] args) { char[][] Atrace={}; int i,j,k,l=0,row ,characters;
class test{//class public static void main(String[]args) { String booking [][]= new String [30] [6] ;//two dimensional array System.out.println("Enter the seat column you want");//column entry char column=Keyboard.readChar(); System.out.println("Enter the seat row you want");//row entry int row=Keyboard.readInt();
I am trying to understand the following code.This return statement should actually return the char at myArray[index] first, then increments the index afterwords correct?
What program needs to find is the most biggest number. It does the job, but another task of the program is to find the index of that number . The second loop should do just that, but for some reason, as the loop goes further, it passes through the if statement even though answer "a[i]" is not equal to "answer". The idea is that if a[i] and answer are equal, the "i" should represent the index number.
import java.util.*; public class DungeonsAndDragonsRedux { public static void main(String[] args) { Scanner s = new Scanner (System.in); Scanner t = new Scanner (System.in); t.useDelimiter("\n"); // Prevent scanner from reading code after nextLine().
[code]...
I have this program that is attempting to randomly equip the player with items that are randomly chosen from a list. I don't know how to prevent it from picking the same item twice though. I also don't know how to display the items that haven't been equipped, which is another requirement of this program.