How To Print Out First 6 Character Of Last Name
Feb 20, 2015How to i print out the first 6 character of a last name even if the last name is and X like Malcolm X or Sung Li. X and Li being the last names
View RepliesHow to i print out the first 6 character of a last name even if the last name is and X like Malcolm X or Sung Li. X and Li being the last names
View RepliesFind three ways to make the program below print 20 copies of the dash character '-' by changing /adding just one character.
int i,n=20;
for(i=0;i<n;i--){
System.out.println("-");
}
I found two solutions but till now not able to find the third one. The two solutions are
int i,n=20;
for(i=0;i<n;n--){
System.out.println("-");
}
and,
int i,n=20;
for(i=0;-i<n;i--){
System.out.println("-");
}
I'm trying to write a method that will print a string of a random number of X's (from 5 to 20) on a line, then another number of X's on the next line, etc. until the random number = 16.
I have to use while loops and probably fencepost algorithms. I'm confused with how to print the number of x's the random number of times over and over.
Right now, I'm pretty sure my for loop is wrong or unnecessary.
So far, this is my code:
public static void randomX() {
int x = 0;
while (x != 16) {
x = (int)(Math.random()*20) + 5;
for (int i = 0; i <= x; i++);
{
System.out.print("x");
}
}
}
Now I am doing dictionary app using files..
Here i want to print the String from Starting character which is given by user..Here i given below the image like my concept..here we put .(dot and enter R)eclipse will print the method name which is starting from R..
i want to have a JLabel that could "robotically" type words character by character.
View Replies View RelatedI use Eclipse (kepler version, with JDK 7) on MacBook Pro (Lion).I want to overwrite a line printed on my console. I used "" for that. I was expecting the cursor to go to the beginning of the line. Instead, it is going to the next line.
Code:
System.out.print("Superman
Sober");
Expected Output:
Soberman
Actual Output:
----------------
Superman
Sober
What I am trying is find the XOR value between charcters of a String here is my code
public static void main(String[] args) {
System.out.println(grayCode("100"));
}
public static String grayCode(String input){
StringBuilder temp=new StringBuilder();
temp.append(input.charAt(0));
for(int j=1;j<input.length();j++){
char previous=input.charAt(j-1);
char current=input.charAt(j);
char xorVal=(char)(previous^current);
temp.append(xorVal);
}
return temp.toString();
}
but I am not getting actual XOR value of two charcters that I am trying to get.
I am trying to build up the alphabet character by character. Like:
a
ab
abc
abcd
Well as of now I can only print out the alphabet with my loop like abcdefg...z.. So here is the code I am trying to use:
public void loop4() {
char alph = 'a';
while(alph <= 'z') {
System.out.println(alph);
alph++;
}
}
I have entered more than one character but output is only one character .....
class InputUser
{
public static void main(String arg[])
throws java.io.IOException
{
char ch;
ch=(char) System.in.read();
System.out.println(ch);
}
}
Basically the class is supposed to have a static variable that keeps track of the number of companies (numberOfCompanies) that have been created and a static method that returns the value of this variable. I need to have a constructor and a method to addEmployee, a method to printCompany, and a toString method. The addEmployee method will check that there is only 1 salesperson, 2 designers, and 4 manufacturing persons at a time and will check that there are no more than 7 employees of the company.
The addEmployee method will return a String indicating what the error is (i.e. "There is already a sales person in this company") or a null if the employee was added. If attempting to name a third company, an error message will be shown. what i have so far but my print company mmethod returns null company class :in which i am obliged to use inputdialog because it says that it cannot return void when i use the showmeassage diaolog.
company class:
import java.util.ArrayList;
import javax.swing.JOptionPane;
public class Company {
private ArrayList<Employees> list ;
private static int numberOfCompanies;
[Code] ....
error message when print button is clicked:
Exception in thread "AWT-EventQueue-0" java.lang.RuntimeException: JOptionPane: parentComponent does not have a valid parent
at javax.swing.JOptionPane.createInternalFrame(Unknown Source)
at javax.swing.JOptionPane.showInternalOptionDialog(Unknown Source)
at javax.swing.JOptionPane.showInternalMessageDialog(Unknown Source)
[Code] ......
I want to create two thread one thread will print odd number and another thread will print even number. but the number should be in a sequence like
1 2 3 4 5 6 7 8 9 10
My program task is if we give a character... the display will print CHARACTER AS CHARACTER Shape
IF WE GIVE LETTER L... IT WILL PRINT LIKE THIS...
L
L
L
L L L L
I finally made the app to draw 10x10 map out of 50x50 pixel blocks.Now I can't imagine how to make a camera and lock it on character. I know how to make a character, but I just want to understand how locking the camera on character would look.
package tiled;
import org.newdawn.slick.*;
import org.newdawn.slick.state.*;
public class play extends BasicGameState {
int xSize = 10;
int ySize = 10;
[code]....
I'm trying to use the split method to split a string for a calculator, but it keeps throwing this Exception:
Exception in thread "main" java.util.regex.PatternSyntaxException: Dangling meta character '+' near index 0
+
public class exp {
private static String ques="88+12";
private static String [] splitCalc;
public static void main(String[] args) {
splitCalc = ques.split("+");
for(String s : splitCalc){
System.out.println(s);
}
}
}
import java.io.*;
public class Q2{
public static void main (String[] args) throws IOException,
ClassNotFoundException
[code]....
For this program, i successfully did create an output.txt, but i have some weird characters in front of "hello" when i open it in notepad or wordpad.
How To Take 1 Milion's Of Character As A Input
View Replies View RelatedI am trying to remove a character from string as below
public String reomveChar(String str, int n) {
if(0<=n & n<=(str.length()-1)){
//str.charAt(n)
char o=str.charAt(n);
return str.replace("o","");
//a.replace("o","");
}
return null;
}'
what is the best way to remove it.
If i call like
removeChar("hello", 1) i should see hllo.
When there are more than one way to do a challenge in java which one to choose as best way.
What is the criteria to decide one particular way of writing code is best among say 'n' different number of ways.
String charAt() method returns a particular Character at the specified index in the String.
How is this function implemented internally?. How a particular character can be retrieved from String?.
I am trying write a program that accept an input and present the input with every 5th character replaced with X (count spaces also).
For example:
input: "hello my name is mario"
outpu: "hellX my Xame Xi maXio"
I only manage to replace specific letters, e.g every "m" letter.
I am trying to swap given string first and last character. If I pass world i should get 'dorlw'
I found link and code [URL]....
String str="hello";
char[] charArray=str.toCharArray();
int indexOfLastChar=charArray.length-1;
for(int i=0;i<charArray.length/2;i++){
char temp=chatArray[i];
charArray[1]=charArray[indexOfLastChar-i];
charArray[indexOfLastChar-i]=temp;
}
String reversedStr=new String(charArray)
System.out.println("reversed string"+str+reversedStr);
I wonder Is there is any easy simple way to do it.
I noticed it is a huge success to have the backgrounds of games move and the character just move up and down and dodge obstacles.How Do I make a background that scrolls horizontally to the left? I know how to keep the character in place with up and down to move, but not sure how to go about making the background move with obstacles.
View Replies View RelatedWhat I'm trying to do is say if the array contains the character a, then output: this letter is already in the array. I tried
if(arrayList.contains(a)) {
System.out.println("This is already in the array!");
}
but it's not working. What should I use?
I was just trying to figure out why when I hold down a movement key, that my character doesn't move. It only moves if I continuously press the movement key. Here is my code:
package game;
import java.awt.*;
import TileMap.TileMap;
import Handlers.Keys;
public class Player {
private double x;
private double y;
[Code] .....
char c=(char)-65;
This is legal but how ?? what is the value actually being stored in c ? The output is shown as .
When addition operation is performed on the character variables ,then it specifies actually that the ASCII values are added because the character variable stores ASCII value of the character constant ,then why after the addition the result cannot be stored inside a character variable ,why it needs to be stored in an integer variable only ,when actually the character variable stores the ASCII value then why is it an error to store the added result in an character variable.
View Replies View Relatedso my task is to write a code which would ask user to input the year as integer and first three letters of the month with first being an upper case letter. Than the program would determine the number of days for given year and month.
Currently I have a brain crash on how to check, if the user has provided the month with first character being upper Case. If not, than the program would automatically correct the character. Problem starts at line 17.
import java.util.Scanner;
public class DaysOfMonth4_17 {
public static void main (String[] args) {
//Initiate scanner
Scanner input = new Scanner (System.in);
//Ask for year input and use is as INT
System.out.println("Enter the year");
[code]...