How To Put All Char In Loop To String
Mar 16, 2014
I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:");
String printingString = "a";
for (int i = 0; i < 50; i++)//loop to obtain 50 random characters
{
char randomChar = (char) ((Math.random() * 255) +32);
System.out.print(randomChar);
printingString = Character.toString(randomChar); }
return printingString; }
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Apr 15, 2015
How can I display this result.aJohny
I have array contain numberi create new char array and i want to check if a number is >= 90 in array then input A at the same index in char arraythen second part i want to check if char array contain "A" then a = a + 1.
The result is like this:
A: 5
B: 29
C: 38
D: 24
E: 12
F: 17
public class Test {
public static char[] grades(int[] getMarks) {
char[] grade = new char[getMarks.length];
for (int i = 0; i < getMarks.length; i++) {
if (getMarks[i] >= 90) {
[Code] .....
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Oct 14, 2014
I need making char[] to a string im not entirely sure what to change i'm just suppose to use a string value but the upperclassmen used char:
char[] number = clear.toLowerCase().toCharArray();
for(int c = 0; c < number.length; c++) {
if(digit[c] < 'a' || digit[c] > 'z')
continue;
[code]...
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Oct 21, 2014
I found a fun program online and something so simple is giving me an issue. I c++ it is pretty simple fix, I can just call the strings location like an array. In java this is not the case. So far i have tried:
myString.charAt();
myString.indexOf();
There are a few other I found on google but I forget at the moment. I am just trying to close the gap on a string. It was a full sentence and I used replaceAll a few times to get several words I didn't want in the file out.
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Apr 30, 2014
what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a";
String name = "Angelina";
char c = code.charAt(0);
char n = name.charAt(0);
[code]...
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
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Jun 5, 2014
I am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
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Aug 3, 2014
import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.
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Mar 30, 2014
I want to cut my string from space char but i am getting exception....
Java Code:
import java.util.Scanner;
import java.util.StringTokenizer;
public class NameSurname {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String s0,s1=null,s2 = null,s3=null;
s0=sc.next();
[Code] ....
Console:
Lionel andres messi
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at java.util.StringTokenizer.nextToken(Unknown Source)
at com.parikshak.NameSurname.main(NameSurname.java:15) mh_sh_highlight_all('java');
I/p -O/p:
my s0=Lionel andres Messi
And I want to break it as soon as i find space and save it in s1,s2 and s3
s1=Lionel
s2=andres
s3=messi
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Apr 1, 2014
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
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Apr 3, 2015
I have a simple doubt. I was studying and create some code to check the result and I found out a strange situation.
Whats wrong with this code? Why it does not print anything?
char = 0; //integer value
System.out.println( c +" String ");
and why this next works very well?
char = 1; //integer value
System.out.println( c +" String ");
I know that char is stored as a positive integer and assign with 0 is different of assign with '0'.
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Feb 13, 2015
I'm trying to find a word in an array of char.....but I'm stuck. How to formulate the code to step through the array and pick out the word. This is what I have so far...
public static void searchAcross(String string, char[][] puzzle) {
// Gets the number of rows in the matrix
int rowLength = puzzle.length;
//Gets the number of columns in the matrix.
int colLength = puzzle[0].length;
[Code] ....
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Feb 8, 2014
What I'm trying to do is compare String input to a char array. Let me make it a little more plain, I'm working on a cipher assignment, and my line of thought is this: I will get String input from the user, COMPARE the characters in the string input to an alphabet array, which will then be compared to the cipher array so that the cipher's counterpart can be chosen over the alphabet's. Any way that I might compare the random input keyed in by the user to that alphabet array?
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Aug 25, 2014
I am trying to figure out how to convert a string of ASCII code into char.I know that you can use (char) to convert it, but the issue is you cannot really just it for Strings.
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Apr 17, 2015
Processing a string. How would I only return a given char that matches the input string e.g. v and/or n and/or m.
Everything else that does not match will return a '*' - e.g. user input = t result = *
I assume I need to also iterate through this input string using charAt() ?
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Jan 6, 2014
I have written the code:
Java Code:
public static void main(String[]args)
{
Scanner input = new Scanner(System.in);
System.out.print("Type your text: ");
String text = input.nextLine();
int counter = text.length();
if(text.length()> 16)
[Code] ....
And input is: abcdefghijklm
output is:
Java Code:
a b c d
e f g h
i j k l
m x x x mh_sh_highlight_all('java');
So all i want is, if i type: abcdefghijklm
I want this output:
Java Code:
a e i m
b f j x
c g k x
d h l x mh_sh_highlight_all('java');
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Apr 12, 2015
I have an array of Strings, one on each line and I need to convert them into an array of char's.
For Example:
This
is
an
Example
of
what
my
input
is.
In order to accomplish that I did the following-
String[] lotsOfText = a.gettingAnArrayAsAReturn();
char [][] myCharArray = new char [lotsOfText.length] [lotsOfText.length];
for(int i=0; i<lotsOfText.length; i++){
for(int j=0;j<lotsOfText[i].length();j++){
myCharArray[i][j] = lotsOfText[j].charAt(j); }}
But whenever I try this and then try to print the output :
for (int i = 0; i < lotsOfText.length; i++) {
for (int j = 0; j < lotsOfText[i].length(); j++) {
System.out.print(myCharArray[i][j]);
}
}
I get nothing. I'm not sure what's the flaw in my logic, is it the char array initialization that's wrong or is it something else ?
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Nov 16, 2010
I have a string array but each cell in the 1d string array stores each character the text file is :
"START START START
The quick brown fox jumps over the lazy dog 1234567890-= !"$%^&*()_+ QWERTYUIOP{}ASDFGHJKL:@~|ZXCVBNM<><? /.,mnbvcxzasdfghjkkl;'#][poiuytrewq789654123.0
+-*/``""$% hello this is a test file using all the characters availible on the keyboard for input END END END END"
so in the string it is:[0] = S, [1]=A, [2]=R ...ect along the text basically i need to convert each character in each cell of the 1d string array to its hesidecimal value..i have created my own method which will take in a char and return a string containing the charcters hex value.
public static String toHex(char c) {
char char2ascii = c;
int i = 0;
int num = (int) char2ascii;
String hex ="";
[code]...
what i want to do is run each cell through the toHex method so i eventually have a string array containing the hex value of each character in my text.
example..i want:
String[] hexarray = S, T, A, R, T
a run it through my method to convert to hex then it will become
String[] hexarray = 53, 54, 41, 52, 54
Im not allowed to use inbuilt libarys and classes to do the hex conversion thats why i have my own method for it .
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Nov 18, 2014
Here, I want to avoid using the line **return"";** and instead return all of the values I output with **System.out.println();**
I have tried using a **StringBuilder** method, but this outputs nothing when I run my test program. I am guessing that StringBuilder must work differently in a while loop, but I can't find how!
[URL] ....
public String toString(){
int topLine = size;
int topCurrentLine = size;
int bottomLine = 1;
int bottomCurrentLine = size;
[Code] ....
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Jul 24, 2014
The code is supposed to insert HTML formatting on a specified string. (i.e o<b>the</b>r )Most of the code works correctly as I verified the outputs without a while loop. The loop is causing a string out of bounds error. I've tried adding the if statement and also formatting the (result += line) nothing is getting appropriate results...
public static String addFormat(String webpage, String toMatch, String format) {
String result = "";
String insert = "";
format = format.toLowerCase();
switch (format){
case "bold":
insert = "<b>" + toMatch + "</b>";
[code]....
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Apr 26, 2015
I'm trying to code a little text RPG. I've made a little "personality test", with 4 questions (answers a b c), where every letter stands for a type of personality. The analysis of the result is simple counting of the answers, if you have 3 answers a (4 questions), then a has won. If 2 on a, and 2 on b, a simple Random method shows weather result a or b.
Now... the test should give you a "partner" (imagine the pokemon game with 3 different starter pokemon). I have now 3 string variables, like 3 different partners. They are all declared somewhere outside, but i only need one later.
Like...the test is completed, you have your partner and how can i make now that the program is just showing me my partner? Like...when i type " System.out.println(partner); " (outside of the test loop! ) that i only get the one i got through the test?
I was trying to declare in every loop the partner String with every result. But outside the loop java isn't recognising that String, bcs...ofc...it was declared for the loop. So i had in every if or else if clause a " String partner = anwsA;" and answB and answC, thats why i cant declare them outside.
Short: i need a partner String variable that could have 3 possible results... i jut need one
I'm using Eclipse Luna 4.4
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Apr 7, 2014
I am looking to pass a long list of results in a String toString() method,this is my code
public void newlist(){
for(int i = 0 ; i <= nbComposant;i++){
System.out.print(ref+i+" (quantity "+quantity+i+")");
}
}
public String toString(){
return newlist();
}
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Feb 7, 2007
import javax.swing.*;
public class mostFrequent{
public static void main(String args[]){
char index;
String s;
s = JOptionPane.showInputDialog("Enter String here");
int currFrequency = 0;
for(index = 0; index<s.length(); index = index++){
int i = 0;
for(i = 'A'; i<='Z'; i++){
if(i==s.charAt(index)){
currFrequency = currFrequency + 1;
}
}
}
System.out.println("end");
}
}
//my code so far
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Jan 27, 2015
I am trying to print a loop inside an array of a greater size than the loop itself. Like for example I have an array of size 7 but it has only 3 elements.
int[] array=new int[7]
array[0]=2;
array[1]=3;
array[2]=4;
now what I want to do is print these three numbers in a loop so that my array[3]=2;array[4]=3;array[5]=4 ...... till the last one. Also the array could be any size and not just 7.
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Apr 5, 2014
When casting a char which is read from a file to an int, can i assume that the mapping used will be ASCII? I've learned that unicode uses ASCII mappings for the characters that overlap.
Are there any other possibilities for int values of one character? I still have trouble understanding character encodings.
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Oct 20, 2014
I was asigned to make a code that would limit the input to 1 character when asked for the initial of your middle name. So far I have the code ask for your first name then your last name and out put "Hello" firstname+last name. Im trying to add an 1 character middle itnitial in there.
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