I have to put values in a FloatBuffer at different times. How can I ensure that I put the current value in the lowest free position, that is, the values be in a row, not spaced and of course not overwritten. I guess I have to use buffer.position() but how? I've never used buffers before.
View RepliesI need a way to store the pixels values currently on the screen and compare them to the values on the first frame. Right now I'm using glreadpixels as follows:
currentBuffer= BufferTools.reserveByteData(mapSize);
glReadPixels(mapStartX, mapStartY, mapWidth, mapHeight, GL_BLUE, GL_UNSIGNED_BYTE, currentBuffer);
for (int i = 0; i < mapSize; i++) {
if (currentBuffer.get(i) != baseBuffer.get(i)) {
//Do nothing
continue;
}
//Do something
}
This works perfectly fine but turns out to be a real bottleneck, dropping the fps to a third of what it was. Is there any quicker way? All I'm after is speed, I don't even need to show it on the screen if the comparison is made "behind the scene".
I have a question in mind that this is my registration form. I am sending these values from HTML form to server and database. I have question that in my case if I click next to Add Another Mobile no in HTML.then a block is genereated and each time a new name is generated.
My Question is if I click 6 times then 6 name attribute are generated. How can I send and differentiate them on my server side.
Because at their I will use something request.getAttribute("Attr_Name");
But they are same. How to do this?.
I can't figure out how to print this string only five times. I tried to use the * operator, but that doesn't work with strings apparently, unles i'm not importing correctly.
import java.lang.String;
public class Looparray
{
public static void main(String args[] {
for (String myStr= "Hello there!";;) {
System.out.print (myStr);
System.out.print("
");
}
}
}
I'm trying to save to a table in a database that has only 2 fields, (id, nota) . I want to save the data several times just to click on "save" one look . The code that I have is this:
<h:form id="frmPerso" style="font-size: 13px;">
<h:outputText value="Id 1" />
<h:inputText value="#{vistaEjem.notas.id}" />
<h:outputText value="Nota 1 " />
<h:inputText value="#{vistaEjem.notas.nota}" />
[Code] ....
I was told to use a foreach or for the insertDatos, but not as used..
I have this code that prints the run time for each for loop iteration but how do I find the fastest time store it in a variable and the print that variable at the end? This is what I have currently.
for (int i = 1; i <= 14; i++) {
int n = (int) Math.pow(2, i);
int[] list = new int[n];
for (int j = 0; j < list.length; j++) {
list[j] = (int) (Math.random() * 2000);
}
int length = list.length;
double radixTime = radixSort(list, length);
System.out.println("For base " + i + " the time was " + radixTime);
}
I am trying to set my setter and getter various times o that I can store a name, price and value but i can only set it once. Once i try to set again the previous entry resets.I have tried
job = sc.next();
jobdetails.setjob(job);
wage = sc.next();
wageD.setwage(wage);
hours = sc.next();
hourd.sethour(hour);
This sets the values for me and i receive the input i entered but if i try to enter again the input from before is removed.I have searched array lists and tried
[code] List<Object> list new ArrayList<Object>();
list.add(jobname)
list.add(price)
list.add(Event)
out.println(list.get(0));
for (Object s : list) {
out.println(s);
}
For this to work I would have to keep adding list.add. Is there a way I can use the array to add a new item to the list so that when I try to display what I have stored in the setter and getter it will display what I have entered in each time instead of only the last input? or any other way that may be possible to do this?
I have made a basic math game that asks you questions and tells you if you have answered them correctly or incorrectly. The game runs great! The thing is that it asks you a question one time and after you answer you have to run the program again. I want to get the program to ask ten questions. After that I want to figure out a scoring system for it but the first step is to get it to ask my ten questions. Here is my code.
package pkgnew;
import java.util.Scanner;
import java.util.Random;
public class New {
public static void main(String args[]) {
[Code] .....
I'm working on a problem that requires me to generator all possible word combinations based on a 7-digit number as input. Many of the generated "words" will be nonsense, but some with be "NEWCARS", "TAKEOUT", etc... This problem mimics the phone number a company would use to support clients remember that number.
I completed the exercise, but I would like to explore more elegant solutions. Specifically, I've used an IF-THEN-ELSE condition inside of a FOR loop. Here is my working code:
package com.johnny_v.exercises.telephone;
public class WordGenerator {
public static void main(String[] args) {
int numOfTimes = 2187;
String two = "ABC";
String three = "DEF";
String four = "GHI";
[code].....
I receive StringIndexOutOfBoundsException exceptions. I it's because multiple conditions are matched. For example, the indexSix is reset to 0 when row is a multiple of 9. Because row is also a multiple of 3, this condition also executes and then increments "indexSix".
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
I created a new servlet to download a pdf-file from a unix-server and display it in an iFrame. The servlet gets called, downloads the pdf, throws away the session parameters and then... starts over again. The session parameters aren't there anymore and the servlet returns an error. The strangest thing is, in our development environment the thing works.
web.xml
<servlet>
<servlet-name>iframeservlet</servlet-name>
<servlet-class>Enviro.DownloadIframeContent</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>iframeservlet</servlet-name>
<url-pattern>/jsp/servlet/iframeContent.pdf</url-pattern>
</servlet-mapping>
[code]....
I have this code but I can't seem to get it to work. It keeps saying that "count" cat be found and that it cannot return a value whose type is void.
Java Code: public class Cuantos {
static int getPosition(double listOfValues[], double targetValue ) {
int i,count,
position = -1;
for (i=0; i < listOfValues.length; i++) {
if (listOfValues[i] == targetValue)
[code]....
I'm working on a space invades game and I have a swing timer set up to update the score(number of aliens killed) and for the aliens to shoot. I'm trying to get the score to update at say 100 ms, but the aliens to shoot at 3200ms. I tried to use 2 timers one for the aliens, and one for the score,but the aliens would just use faster score timer.
import java.awt.Color;
import java.awt.Container;
import java.awt.event.ActionEvent;
[Code]......
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string. Example: the string Welcome and the letter e, is 2 times. so the program should print 2. It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
str=user_input.next();
[Code] ....
I am having is not being able to print out the diamond the amount of times the user enters (for example, when it asks how many diamonds, I enter a 2 and only one diamond comes out.)
import java.util.Scanner;
public class Pattern5
{
public static void main(String[] args)
{
// For this pattern program, ask the user how many diamonds
// she would like to print to the screen. The following pattern is one diamond.
[code]...
I am having issues with the first part of my program. When I got to display what is in the textfile, it only gives me one name two times. I cannot figure out what to do with my outer loop in order for it to read and output the entire data file.
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.lang.*;
import java.util.Scanner;
import java.io.*;
import java.text.*;
import java.math.*;
import java.util.StringTokenizer;
[Code] ....
how we can call one class in multiple programs to reduce code redundancy
View Replies View RelatedIi am trying run a do while loop on java a specific amount of times for example if i were to type in "Enter number of years" and enter 4. i need the loop to execute 4 times or if i said 6 times then i would be 6. the program i have repeats it and takes it back to reentering "Enter number of years" i need it to execute by its self x amount of times. here is what i have so far
System.out.println("Enter the number of years: ");
years = keyboard.nextInt();
rainfall = generator.nextInt(10) + 1;
System.out.println("Year " + "rainfall amounts were");;
for (int months = 1; months <= 12; months++)
[Code]...
I am working on splitting a time for a stopwatch and printing it on console,
String splitTimesStr = "";
currentTime = System.currentTimeMillis();
long secsTaken = (currentTime - startTime) / 1000;
long split = secsTaken - startTime;
[Code] ...
it produces
Split time: 00:02
Split time: 00:05
Split time: 00:08
Split time: 00:09
when it should produce
Split time: 00:02
Split time: 00:03
Split time: 00:03
Split time: 00:01
its printing out the time on stopwatch rather than: time on stopwatch - old time, how would i code this?
I'm trying to write a method that will print a string of a random number of X's (from 5 to 20) on a line, then another number of X's on the next line, etc. until the random number = 16.
I have to use while loops and probably fencepost algorithms. I'm confused with how to print the number of x's the random number of times over and over.
Right now, I'm pretty sure my for loop is wrong or unnecessary.
So far, this is my code:
public static void randomX() {
int x = 0;
while (x != 16) {
x = (int)(Math.random()*20) + 5;
for (int i = 0; i <= x; i++);
{
System.out.print("x");
}
}
}
This is my code up to now and I can't do anything to make it work. I want it to tell me how many times the number 3 appears, and the last position it was in. I am getting errors like"Cuanto.java:88: getPosition(double[],double) in Cuanto cannot be applied to (double) ....
a = getPosition(a);" and unreachable statements, and value not found. It's all over the place every time I make a change to it.
Java Code:
public class Cuanto {
static int getPosition(int count,double listOfValues[],
double targetValue) {
int a = 0, i;
for (i=0; i < listOfValues.length; i++) {
if (listOfValues[i] == targetValue) {
a++;
[Code] ....
I can't get my code to print it like it's on the picture.
import javax.swing.JOptionPane;
import java.util.*;
public class BokstavTeller
{
public static void main( String[] args ) {
String input = JOptionPane.showInputDialog(
[Code] .....
I made a heads or tails game but I'm getting a bug when the user says he doesn't want to play anymore. The statistics are printed as many times as the games played. If you want to test the code, write" cap" " pajura" and when the program says "Vrei sa mai joci?" that means "do you wanna play another one?" and you can answer with "da"(yes) or "nu"(nu) Here is the code:
import java.util.Scanner;
public class cap_sau_pajura{
private static int user;
private static int pc;
private static String converted;
static int usermove;
private static int castiguri = 0;
private static int pierderi = 0;
[code]....
I am trying below challenge to display first three characters three times if the size of the string is greater than 3.
Say if i send hello i should get helhelhel
if i send xyz i should get xyzxyzxyz
I wrote as below
public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}
I am getting error as below
Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String
Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.
I know the normal way of naming objects is
Pipe pipe1 = new Pipe
but I want the objects to be made inside a loop and named after how many times the loop have been gone through so I tried
Pipe pipe(numberOfTimes) = new Pipe
where numberOfTimes was a variable counting the loops. This is not working.I need the naming to be pipe1, pipe2, pipe3 etc depending on how many times the loop have been pased
Scanner keyboard = new Scanner (System.in);
String morePipes = ("yes");
int dimRor;
int numberOfPipes = -1;
[code]....
I am trying to make a program to multiplies two numbers without using the "*" operator. My idea was to add x number y amount of times, which is the same as multiplication. I did this with a for loop, but zero is always returned as the answer. How can I fix this?
public class secondMult {
public static void main(String[] args){
System.out.println(multWithSum(4,5));
}
public static int multWithSum(int x, int y){
int sum = 0;
for(int i = 0; i==y;i++){
sum = sum + x;
}
return sum;
}
}