How To Split String When Delimiter Also Is In The String
Mar 25, 2015
I have the the string value similar to the one which i have to split based on the delimited ","
String SampleString=" 'ab,c', 'xyz', lm,n,o "
I know I can easily call split function which will eventually split the above string. But in my case the delimiter "," , is also a part of the string. If I call the function SampleString.split(',') I will get the output as listed below
ab
c
xyz
lm
n
o
but the expected output is
abc
xyz
lmno
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Sep 27, 2014
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
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Jan 8, 2014
How can I change the value of
String str = "1234|U||45|||"
into
String str = "1234|U| |45| | |"
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Jan 23, 2010
I am trying to split a string based on length(example length 5) of the string. But I am having a issues with this substring(start, end) method. I get all substring which are of length 5. But if the last substring is less than 5 then I am not getting that last substring. But I need the last substring even if it is less than 5.
String s = "fjdjfdfjgffgjhfjghfjkhjhjh";
String spLine;
for(int i=0; i<s.length(); i=i+5){
spLine = s.substring(i, (5+i));
}
>
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Sep 21, 2014
So I'm creating a class which when given three inputs uses them as sides of a triangle and tells ther user what type of triangle it is, or if the input is invalid, tells them why it is invalid. I'm readin the input as a string and then trying to split it into a string array, from there checking to see if it has 3 elements.. in which the data is good at that point, and then converting them to ints and checking to see if they're negative ansd finally checking to see if they can work as sides of a triangle ie a+b >c, a+c >b , b+c >a.
I'm trying to split it into an array of strings but am getting an error, and can't seem to figure out why as this should be working from what I've read of the string.split method online.
import java.util.*;
public class TriangleTest{
private int sideA;
private int sideB;
private int sideC;
public static void main(String[] args){
TriangleTest triangle = new TriangleTest("3 4 5");
[Code] ....
The output reads [Ljava.lang.String;@15db9742
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Apr 20, 2014
Working on my java skills. The is Delimiter function is suppose to return true if there is a delimiter in the string and false otherwise. The main is suppose to call this function and count the number of words in the string:
Here is what I came up with:
import java.util.*;
public class NumberOfWordsInString {
public static void main (String[] args){
Scanner in= new Scanner (System.in);
String s;
[Code] ....
Somehow my method isn't being successfully called by my main and the following error msg was received:
Exception in thread "main" java.lang.Error: Unresolved compilation problems:
length cannot be resolved or is not a field
The method isDelimiter(char) in the type NumberOfWordsInString is not applicable for the arguments (char[])
at javaimprovements.NumberOfWordsInString.main(Number OfWordsInString.java:10)
line 10:
char ch [] = new char [s.length];
and the main doesn't call the isDelimiter function
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Jun 10, 2014
I know adjacent delimiters create empty token but is there any exception regarding last pair of delimiters ??
String a[]=":ab::cde :fg::".split(":"); // Creates 5 tokens
String a[]=":ab::cde :fg:: -Space-".split(":"); // Creates 7 tokens
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Sep 15, 2014
I have a string that look like this
"dfhsdfhds | dsfdsfdsfd dsfjkhdskjf ||ER|| jdkshfuiewryuiwfhdsfsd er dsfjsgrwhfjkds ||ER|| jkshruiewryhijdknfjksdfhdksg | "
I want to split it by "||ER||"
I try this but it splits the single "|" to not just the "||ER||" like I want.
String[] separated = response.split("||ER||");
Log.d("token",separated[0]);
Log.d("token",separated[1]);
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Nov 11, 2014
String path = "/AUTOSAR/Os_0?type=EcucModuleConfigurationValues";
String path1[] = path.split("?type");
I want to split string in such a way that I should get the content before "?" in an another variable. I tried various way but some how I am not getting expected behavior.
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Aug 30, 2014
I have a String as follows: "the|boy|is|good"
now, I want to split this string using the "|" delimeter.
I tried this :
String line = "the|boy|is|good";
line.split("|");
But it didn't split it. Is there some regex for "|"?
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Mar 30, 2014
I want to cut my string from space char but i am getting exception....
Java Code:
import java.util.Scanner;
import java.util.StringTokenizer;
public class NameSurname {
public static void main(String args[]) {
Scanner sc=new Scanner(System.in);
String s0,s1=null,s2 = null,s3=null;
s0=sc.next();
[Code] ....
Console:
Lionel andres messi
Exception in thread "main" java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at java.util.StringTokenizer.nextToken(Unknown Source)
at com.parikshak.NameSurname.main(NameSurname.java:15) mh_sh_highlight_all('java');
I/p -O/p:
my s0=Lionel andres Messi
And I want to break it as soon as i find space and save it in s1,s2 and s3
s1=Lionel
s2=andres
s3=messi
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Oct 19, 2014
In this exercise, create a program that asks a user for a phrase, then returns the phrase with the words in reverse order. Use the String class's .split() method for this.
Example input
The rain in Spain falls mainly on the plain
Example output
plain the on mainly falls Spain in rain The
While I understand the assignment, nowhere in the text is it covered how to reverse the order of the words in the string. I understand using the .split method, but not for this exercise.
Here is my code so far.
import java.util.*;
/**
* Java class SplitString
* This program asks for a phrase, and the code allows the phase to return in reverse order.
*/
public class SplitString {
public static void main (String[] args){
//set phrase input and mixed which will be the result
[Code] ....
As you can see, I have been googling this method and have come up nearly empty. My text does not cover the .reverse() method. The only thing it covers with .split() is how to split a string. I also tried StringBuilder with no success.
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Mar 15, 2014
I am trying to get resultset into a string and then use split method to store it in an array but it is not working. i tried to work it seperately as java program but it throws exception "could not find or load main class java."
String ar = "This.is.a.split.method";
String[] temp = ar.split(".");
for(int i=0;i<temp.length;i++){
System.out.println(temp[i]);
}
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Jun 23, 2014
I am encountering a problem while running this small piece of code.
public class TestSplit{
public static void main(String[] args){
String myWords[]="My.Home.Is.Being.Painted".split(".");
for(int i=0;i<myWords.length;i++)
System.out.println(myWords[i]+" ");
}
}
The problem is: it does not run at all. No error message is displayed. It just returns to the command prompt when i run it. Where am i wrong?
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May 10, 2014
String str = "#11* 1# 2*12# 3"
required o/p in array as
#11
* 1
# 2
*12
# 3
i.e splitting the strings for every 3rd string and storing it in an array of strings ...
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Mar 3, 2014
Regular expression which I want to use to split a string. The string could look similar to this:
"a = "Hello World" b = "Some other String" c = "test""
The String is read from a file where the file contents would be:
a = "Hello World" b = "Some other String" c = "test"
After splitting I would like to get the following array:
String[] splitString = new String[] {"a", "=", ""Hello World"", "b", "=", ""Some other String"", "c", "=", ""test""}
I know I could just write a simple text parser to go over the string character by character, but I would rather not do it to keep my code clean and simple. No need to reinvent the wheel.
However, I just cant seem to be able to find the right regular expression for this task. I know that a RE must exist because this can be solved by a finite automaton.
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Nov 15, 2014
I am trying to split the contents of the text file and assign the value on the left of the separator to a variable and the value on the right of the | separator to another variable. Thus I tried out a sample code to print all the values in the split [] first, and ended up with problems. This is the content of the text file:
Crazed Boy|20
Hello|5
MSB|6.5
public class Main {
public static void main(String[] args) {
try {
BufferedReader infile = new BufferedReader(new FileReader("test1.txt"));
for (int i =0; i < 3 ;i++) {
String s = infile.readLine();
String[] ss = s.split("|");
[code]....
I keep getting IOException in my sample code, why is this so ? I assumed the split() method is supposed to output for the 1st iteration:
ss[0] = Crazed Boy
ss[1] = 20
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May 4, 2014
I have included split() to put a string read from a given file into indexed array. Looking for a word position (not char position number in addition to the line number I have already written. Line number works fine, however word position isn't quite right.Below is my code:
import java.io.*;
public class Word implements Comparable, TreeComparable{
String word;
int count;
int wordpos;
ObjectList lines;
private SuperOutput so;
[code]....
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Jan 17, 2015
I used the string split method in the following lines of code like this:
String[] numbers = out.split("[^d.]", 0);
String[] operations = out.split("[.d()]", 0);
When out is equal to the String "2x2.5", the array operations ends up looking like this when it is printed using the toString method:
[, , , x]
As you can see, before the array element x, there are three String variables which only contain whitespace. Why does this occur, and how can I prevent this from happening?
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Sep 28, 2014
I am having a problem with the following code. It compiles and runs fine however my output is wrong.
public class SplitString {
public static void main(String[] args) {
String[] string1 = split("ab#12#453", "#");
String[] string2 = split("a?b?gf#e", "[?#]");
for (int i = 0; i < string1.length; i++) {
System.out.print(string1[i] + ",");
[code]....
The split method in the String class returns an array of strings consisting of the substrings split by the delimiters. However, the delimiters are not returned. Implement the following new method that returns an array of strings consisting of the substrings split by the matching delimiters, including the matching delimiters.public static String[] split(String s, String regex)For example, split("ab#12#453", "#") returns ab, #, 12, #, 453 in an array of String, and split("a?b?gf#e", "[?#]") returns a, b, ?, b, gf, #, and e in an array of String.
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Nov 7, 2014
How can I write a method that takes a string with duplicates letters and returns the same string which does not contain duplicates. For example, if you pass it radar, it will return rad. Also i would like to know how can I Write a method that takes as parameters the secret word and the good guesses and returns a string that is the secretword but has dashes in the places where the player has not yet guessed that letter. For example, if the secret word is radar and the player has already guessed the good guesses letters r and d, the method will return r-d-r.
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Dec 16, 2014
i am trying to write a class method which will take in a string and returns a string which is the reversed version of that string. it compiles fine but when i try to run it it states Main method not found in class StringReverse,please define the main method as public static void main(String[]args). I am new to java and cannot figure out
import javax.swing.JOptionPane;
public class StringReverse {
public String reverseString(String str){
JOptionPane.showInputDialog(null,"Please enter word");
char c = str.charAt(str.length()-1);
if(str.length() == 1) return Character.toString(c);
return c + reverseString(str.substring(0,str.length()-1));}}
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May 22, 2014
I'm having trouble with the last few lines of the code. It's supposed to take a replacement string entered by the user and print out the new string. For some reason it's now allowing me to enter a replacement string
import java.util.Scanner;
public class Project02 {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter a long string: ");
String lString = keyboard.nextLine();
[Code] ....
Output:
Enter a long string: the quick brown fox jumped over the lazy dog
Enter a substring: jumped
Length of your string: 44
Length of your substring: 6
Starting position of your substring in string: 20
String before your substring: the quick brown fox
String after your substring: over the lazy dog
Enter a position between 0 and 43: 18
The character at position 18 is x
Enter a replacement string: Your new string is: the quick brown fox over the lazy dog <------ isn't taking user input
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Aug 28, 2014
I have a method for a button so when a user inputs something it then will get the string value and check it against the string value within the properties file to see if it exists.
The properties file is called GitCommands.properties that contains -- > key = value <-- in it
I realised I have not used it correctly hence why I keep getting errors - I am lost on how to use it, I think perhaps that may be the issue here? I need to reference the file but I am doing it wrong? When I do use that piece of code I get null pointer exception too...
textFieldSearch.getText().equals(GitCommands.keys());
This is my button:
JButton btnSearch = new JButton("Search");
btnSearch.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
FindSelectedKey();
[code] .....
I understand I am missing my piece of code where it states "//determine whether the string is equal to the property file key string" I understand the logic fine but not actually coding it.
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Mar 18, 2014
Code a Java method that accepts a String array and a String. The method should return true if the string can be found as an element of the array and false otherwise. Test your method by calling it from the main method which supplies its two parameters (no user input required). Use an array initialiser list to initialise the array you pass. Test thoroughly.
public class test {
public static void main(String[] args) {
Printhelloworld();
String[] verbs = {"go", "do", "some", "homework"};
printArrays(verbs);
[Code] .....
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Mar 2, 2014
I'm having trouble to compare two string from my LinkedList. I took me 2 days now trying figure out how to compare the current string to previous string in the linkedlist. Here is my code.
public int compareTo(LinkedListNode n){
//Compare two string
String myHead = data.toLowerCase();
String comparableHead = data.toLowerCase();
return (myHead.compareTo(comparableHead));
}
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