value1 = text1.getText();
value2 = text2.getText();
Connect c = new Connect(value1,value2);
if(c.check()== true)
{
Menu start = new Menu(c.getID());
dispose();
[code].....
I get an error "unreported exception java.SQLException; must be caught or declared to be thrown" how can i solve this I have taken a few basic classes but never got to exceptions.
I am practicing OCPJP ....
import java.lang.*;
class InvalidValueException extends IllegalArgumentException {}
class InvalidKeyException extends IllegalArgumentException {}
class BaseClass {
void foo() throws IllegalArgumentException {
throw new IllegalArgumentException();
[Code] .....
Which one of the following options correctly describes the behavior of this program? And the answer is (definitely) --> The program will print : InvalidKeyException exception, but when i saw the explanation, it tells
It is not necessary to provide an Exception thrown by a method when the method is overriding a method defined with an exception (using the throws clause).
I don't know, but i think it will compiled because the Exception that is thrown by the foo method in DeriDeri class is inherited from unchecked exception.. so it is not necessary to declare throws statement on its method.. and if the exception was checked exception the answer must be different right?
I am just learning how to throw exceptions, and I'm stuck on the last part,
Here is where I created the exception that receives a string consisting of ID and wage.
public class EmployeeException extends Exception
{
public EmployeeException(String Employee)
{
super(Employee);
}
}
Here is where I created the Employee class with the two fields. I also believe I am throwing the exception if the hourly wage is < $6 or > $50.
public class Employee
{
int idNum;
double hourlyWage;
public void Employee(int empID, double empWage) throws EmployeeException
{
idNum = empID;
hourlyWage = empWage;
[Code]...
Now, I need to write an application with three employees and display a message when an employee is successfully created or not. This is what I have so far... I'm trying to get it to work with one employee, and then I can easily go back and add two more.
import javax.swing.*;
public class ThrowEmployee
{
public static void main (String[] args)
{
try
{
Employee one = new Employee(542, 15.20);
}
[Code
The current compile error that I'm receiving is: ThrowEmployee.java:12: error: constructor Employee in class Employee cannot be applied to given types;
Employee one = new Employee(542, 15.20);
^
required: no arguments
found: int,double
reason: actual and formal argument lists differ in length
1 error
I have public void Employee(int empID, double empWage) in my Employee class, so why is it saying that no arguments are required? Not sure if I'm missing a step with throwing exceptions, because this error has always been a simple fix when I've come across it in the past?!?
There are times that my methods need to report the caller about many kinds of errors, represented as checked exceptions. This makes my methods look like very convoluted. It happens mostly when I work with stateless EJBs and databases. Sometimes I end throwing even 8 different exceptions! Are they too many?
Many of them inherit from common exceptions, so I've been tempted to throw the parent classes. But I've quickly discarded that option because I've read that it's a bad practice, since a method may throw only a subset of the children of that parent class, not all.
Finally, I've studied these possibilities:
1. Throwing the parent class (mentioned above).
2. Throwing a common exception with an error ID or code as message.
3. Throwing a common exception with an enum as member, as if it were an ID or code (safer than the #2).
All them show the same defect that the #1. However it's more a conceptual problem than a technical one, because my callers always use the same mechanism to treat every "specialization" of the same exception, without worrying about if the method really can return it or not.
public class ThrowException {
public static void main (String[] args) {
var x=prompt("Enter a number between 0 and 10:","");
try {
if (x>10){
throw "Err1";
} else if (x<0){
throw "Err2";
} else if (isNaN(x)){
throw "Err3";
}
}
catch(er){
[code]...
It's telling me where catch(er) is: <identifier> expected..I've watched videos, but no one seems to encounter this error....am I missing a segment of code?
imagine I build this this device that takes in impulses... 0 and 1..but I need an interface with buttons to decide when to throw a 0 or a 1...would java be a good language to control this?I'm having difficulty to make this path... interface to circuit...
View Replies View RelatednumHitslocs
public class simpleDotCom {
int numHits=0;
int[] locationCells;
public void setlocationCells(int[] locs){
locs=locationCells;
[Code] ....
Dice are used in many games. One die can be thrown to randomly show a value from 1 through 6.
Design a Die class that can hold an integer data field for a value (from1 to 6).
Include a constructor that randomly assigns a value to a die object. Appendix D contains information on generating randomnumbers. To fully understand the process, you must learn more about Java classes and methods. However, for now, you can copy the following statement to generate a random number between 1 and 6 and assign it to a variable. Using this statement assumes you have assigned appropriate values to the static constants.
randomValue = ((int)(Math.random() * 100) % HIGHEST_DIE_VALUE +
LOWEST_DIE_VALUE);
Also include a method in the class to return a die's value. Save the class as
Die.java.
Write an application that randomly "throws" two dice and displays their values. After you read the chapter Making Decisions, you will be able to have the game determine the higher die. For now, just observe how the values change as you execute the program multiple times. Save the application as TwoDice.java.
I have a superclass used for all the other entity
@MappedSuperclass
public abstract class BssStandardEntityLaravel extends BssStandardEntity
implements InterfacciaBssStandardEntity, Cloneable{
private static final long serialVersionUID = 1L;
@Column(name = "created_at", nullable=true)
@Temporal(TemporalType.TIMESTAMP)
protected Date created_at = new Date();
[Code] ....
When i try to read some data with a JPA controller, this error is raised:
Persistent class "com.bss.libbssabstract.database.entity.BssStandardEntityLaravel" has no table in the database, but the operation requires it. Please check the specification of the MetaData for this class.
org.datanucleus.store.rdbms.exceptions.NoTableManagedException: Persistent class "com.bss.libbssabstract.database.entity.BssStandardEntityLaravel" has no table in the database, but the operation requires it. Please check the specification of the MetaData for this class.
at org.datanucleus.store.rdbms.RDBMSStoreManager.getDatastoreClass(RDBMSStoreManager.java:702)
[Code] ....
It requires BssStandardEntityLaravel table like a normal entity. I used the same entity package in other applications and it works perfectly. Why this error is raised?
I use jpa2.1.0 and datanucleus to enhance classes
I got one task from my manager, regarding browser back button, refresh button. He asks me the web application has to work like Banks site... means if I refresh or click on Back button(Browser's) then it has to throw the user out of session, I checked lot in internet. But I found like only disabling back button of disabling F5 keys like that. But he’s not accepting that.
How to approach for this? Can we throw the user out of session when he clicks on browser back button or refresh button. I think its possible . But i don't know how to implement.
I was giving a quick skim to some tutorials on the internet where I have found the exception that is handled is also declared in the throws clause of the method wrapping the try-catch block. For a code representation consider the following:
public void methodName() throws IOException {
try {
...
} catch (IOException ex) {
.... TODO handle exception
}
}
Right, so I got this program. It takes input from the user and assigns it to fields on an object. But, it's meant to check the users input. If the user enters bad input, it's supposed to throw this exception. For each of these exceptions, theres a class specifically for it.
public class PayrollDemo
{
public static void main(String[] args)
{
Payroll pr = new Payroll ("Test Name", 234);
System.out.println("Current Employee Information.
");
System.out.println("Name: " + pr.getName());
System.out.println("ID: " + pr.getID());
System.out.println("Hourly Pay Rate: " + pr.getHourlyPayRate());
[Code] ....
And this is the exception class.
public class InvalidNameException extends Exception
{
/**
No-arg constructor
*/
public InvalidNameException()
{
super("Invalid name");
}
}
PayrollDemo.java:43: error: cannot find symbol
InvalidNameException.InvalidNameException();
^
symbol: method InvalidNameException()
location: class InvalidNameException
1 error
It's just meant to tell the user that they entered an invalid value, which would mean if they entered an empty string instead of a name.
I have a program which runs perfectly fine in Eclipse. however, the same program after exporting to jar in desktop and then executing in cmd gives exception.
why is this difference.
in eclipse. it is built up 1.6 JDK and run using 1.6 JRE.
in CMD, it runs by 1.7 JRE.
can this JRE version make a difference. Technically should not i believe.
I want to encrypt and decrypt a txt file by using PGP.I completed my PGP Encryption.I'm getting an error in PGP Decryption. The error msg as follows
Quote:
Exception in thread "main" java.lang.IllegalArgumentException: Invalid PGP message
at com.newpackage.bouncy.PGPUtils.getDataList(PGPUtil s.java:502)
at com.newpackage.bouncy.PGPUtils.decryptFile(PGPUtil s.java:198)
at com.newpackage.bouncy.PGPFileProcessor.decrypt(PGP FileProcessor.java:56)
at com.newpackage.bouncy.Tester.testDecrypt(Tester.ja va:46)
at com.newpackage.bouncy.Tester.main(Tester.java:61)
I am getting this error in the following line of my code.
PGPObjectFactory factory=new PGPObjectFactory(PGPUtil.getDecoderStream(is));
=>> Object obj=factory.nextObject();//here i am getting obj as null
if (obj == null) {
//System.out.println("Invalid PGP Message");
//System.exit(0);
[Code] .....
So I've been working on this program to make tournament matches for beach volley.
First little info: (I'm Belgian so some words are Dutch)
-Class Speler: has arraylist with information with which player already has been played (codesLijst)
-Class Inschrijvingen: makes players sign up with their level and name
-Class Wedstrijd: makes matches, checks with Inschrijvingen if the players already have played together. If so, gives message that they need to change partner. If not, makes them a team.
Now if I run the program with fresh players, none of them have had a partner, it works fine. If I make just one new team and the other already exists, it also works fine. It's when I make the two teams with existing records (to see whether they already played together), that the error comes.I know there's a lot of code duplicate, will clear out eventually, this is just a raw version.
CLASS SPELER
import java.util.ArrayList;
public class Speler {
private Wedstrijden wedstrijd;
private Inschrijvingen inschrijving;
private String naam, ploeg;
private int setPunten, winPunten;
private long time;
private String code;
private ArrayList<String> lijstCodes = new ArrayList<String>();
[code]....
class Arg
{
public void rt()throws Exception
{
System.out.println("hi");
throw new RuntimeException();
}
public static void main(String args[])
[code]...
the way to handle the exception that has been in the catch block{b.rt()} .
I have the below code :
public class Beyond {
static Float i;
public static void main(String[] args) {
float y = 7 * i;
}
}
It gives : Exception in thread "main" java.lang.NullPointerException : Line 5...Why is it giving NPE? Isnt the variable defaulted with 0.0f? Also, I am not performing any dot operation, it's just a multiplication operation.
Why I have this out of bounds exception? I highlighted the code that the error is in
public String encrypt() {
//TODO: Complete this method
int groupMoves = 0;
int testing = 0;
String encrypted = "";
//a b c d e f g h i j k l
//1 2 0 1 2 0 1 2 0 1 2 0
[Code] ....
i rewrote this code from head first java book . but every time i try to compile it it gives me this exception
java.lang.ExceptionInInitializerError
Caused by: java.lang.RuntimeException: Uncompilable source code - simpleFrame is not abstract and does not override abstract method actionPerformed(java.awt.event.ActionEvent) in java.awt.event.ActionListener
at simpleFrame.<clinit>(simpleFrame.java:6)
how can i instantiate simpleFrame class if i shoild make it abstract?
public class simpleFrame implements ActionListener{
JFrame f;
public static void main(String[] args){
simpleFrame s = new simpleFrame();
[code]....
I was trying to contact many servers. The lookup was successful, but the procedure call caused the error:
java.rmi.ConnectException: Connection refused to host: 127.0.1.1; nested exception is:
* java.net.ConnectException: Connexion refusée*
What would cause this error during the call.
I'm trying to insert numbers in a array of Integer neatly. When i try to insert the following numbers i have this exception.
Exception in thread "AWT-EventQueue-0" java.lang.NullPointerException
at time.Historico.insere_ordenado(Historico.java:35)
Line 35 in my code is:
"while (num >= arry[i] && arry[i] != null && i < arry.length - 1)"
Numbers:
71516357248031
I have this exception when i try to instert 80.
public Integer[] insert_neatly(Integer[] arry, Integer num)
{
Integer i, acum, aux, temp;
i = acum = 0;
if (arry[i] == null)
[Code] ....
What is wrong with this code?
I have studied that Generics are used to shift the Class Cast Exception into Compile time errors , So that we get errors at compile time error and we do correct them before executing ,but Here is a program in which i am getting Class Cast Exception
class Animal
{
}
class Dog extends Animal
{
}
class Cat extends Animal
[code]..
Getting Exception at line no 29 which i know why it occurs but just wanna ask that isn't it should be caught at compile time According to Generics ?
Is there any connection between packages and exception handling in java. Means is it necessary to create a package before trying exception handling examples?
View Replies View Relatedhow inheritence and exception work together ?? what are the rules ??
View Replies View RelatedIs there a special mechanism through which exception can be handled in a constructor?
Suppose while creation of an object there occurred an exception while creating an object, and the object is half constructed. How do we make sure we handle this kind of exceptions in a constructor?
I am trying send email .So I have downloaded javaEE and javamail jar files and added buildpath.And wrote this code below .But I am getting this exception.
Exception in thread "main" java.lang.RuntimeException: javax.mail.AuthenticationFailedException: 534-5.7.14 <https://accounts.google.com/ContinueSignIn?sarp=1&scc=1&plt=AKgnsbskV
534-5.7.14 ggcPi6MBZ4h8CCyCk2TG9EhiTGyE5MVBv7B3k7DsCldqjCuFvMTQG6aAbatrAWggH29muG
534-5.7.14 dzVh1kUYgMgNHAN558QRCnTjrNtUGv34Ul4pzUaansBuBfB0Kpz6_q7JTbrUuAmlZplouA
534-5.7.14 AHDXpFtuCkd-W17tHrZS5mqgVVxAcuKc-7TkhCDGShnfRBWU2R8v-gfvIQShszqsZmCl0i
[Code] .....
What am i missing here.
public static void main(String[] args) {
final String username = "mymail@gmail.com";
final String password = "mypass";
Properties props = new Properties();
props.put("mail.smtp.auth", "true");
[Code] .....