I'm new to programming and I would just like to know what happens inside the memory once you run a java application. How do the memory allocate space for your objects or variables? Where does it start?does it start in memory location 1 first when I create my first variable or object? What is the use of variables and how is it used by the memory?Also if I create a variable named String s1 then I created another variable again named s1= "myString" Did I create a new object or I just edited the value of the s1 variable??
And if I create a variable int num1 = 10 then I created another variable int num1 = 12 did I create another one or I just edited the num1 variable?? Also how much memory would an object have? Does it depend on how many primitives objects like arrays or strings it have?Also I want to develop 3D games also, in the future is Java going to be great as I know machines in the future will have massive amounts of RAM and the JVM will be better...
I am trying to display two JComboBoxes side by side. I can successfully display them as part of a BorderLayout if they are in the North and East, but when I try to display them side by side in the same area, eg North, only one of the combo boxes gets displayed.
I'm using SchedulerExecutorServices to Schedule a task. My Question is how can i schedule more than one task side by side:
Here is what I'm doing:
public class Scheduler { public Scheduler(Runnable thread, int startAfter, int iterateAfter, TimeUnit timeUnit, int length) { ScheduledExecutorService scheduler = Executors .newSingleThreadScheduledExecutor(); final ScheduledFuture<?> timeHandle = scheduler.scheduleAtFixedRate(
I am trying to align the core/middle side color of a cube, index 4, with the bottom middle color of the same side, index 7. (Each side has values 0-8 where 0 - is the top left corner, 1 is the top mid corner, 2 is the top right corner, 3 is the middle left corner, etc).
In addition to lining up those two colors, I am also making sure that the neighbor color of index 7(the color that it is attached), in this case the bottom color, matches with the top core/middle color. I will attach some pictures and a print out to show what I am talking about...
However, in my code when I am trying to align all of these up together, it does not go into the while loop. Each of the loops essentially is trying to get a match of same color with index 4 and 7, as well as making sure that index 7's neighbor color (the bottom color, in this case) matches with the top color.
Here is what I have tried:
private void alignSideColor(){//make the bottom colors neighbor match with a middle side value and rotate it to the top, for the top cross
if(cube.bottom.square[1].charAt(0) == topColor){ while(cube.front.square[7].charAt(0) != frontColor && cube.bottom.square[1].charAt(0) != topColor){ rotateBottomClockwise(1); System.out.println("Trying to align side color...");
[Code] .....
The print out of the ELSE IF is: alignment is: W-G and tops: R-R NOW ITS ALIGNED even though the sides, index 4 and 7, are NOT aligned with each other
I have also tried the same thing but with out the 2nd condition in each while loop, and although is DOES enter the while loop, it does not perform correctly -- index 4 and 7 WILL have matches colors, but it does not check to see if index 7's neighbor matches with the top color.
Here is how it prints out ** ** ** G7 B6 Y1 ** ** **//this portion is the back of the cube ** ** ** R6 W5 O4 ** ** ** ** ** ** R3 W2 O1 ** ** ** B3 G4 Y9 W9 O8 Y7 W3 B4 G9//this portion is the left, top, and right of the cube B2 G5 R8 W4 R5 Y6 O2 B5 G8 O7 W8 R9 B7 B8 B9 R1 R4 R7 ** ** ** O3 O6 O9 ** ** **//this portion is the front of the cube ** ** ** Y2 Y5 Y8 ** ** ** ** ** ** B1 G6 W7 ** ** ** ** ** ** Y3 Y4 G1 ** ** **//this portion is the bottom the cube ** ** ** R2 O5 G2 ** ** ** ** ** ** W1 W6 G3 ** ** **
Here is the cube showing the top, left and front side
Here is the left and bottom side. As you can see index 4, G5 -- yes that is a 5 lol -- does not have the same color as index 7, W8.
I need to rotate the bottom until W8 is aligned with a middle white value. An examples of a neighbor is: W8-R2
I am trying to create an array list without using the built in arrayList class that java has. I need to start the array being empty with a length of 5. I then add objects to the array. I want to check if the array is full and if not add a value to the next empty space. Once the array is full I then need to create a second array that starts empty and with the length of the first array + 1.
The contents of the first array are then copied into the new array without using the built in copy classes java has and then the new array ends up containing 5 elements and one null space the first time round. The first array is then overwritten with the new array containing the 5 elements and the null space. The process then starts again adding values until the array is full which will be 1 more value then recreating the second array empty and the length of the first array + 1. This is my attempt at creating this but I have run into multiple problems where I get only the last value I added and the rest of the values are null:
public class MyArrayList { public Object arrayList[]; public MyArrayList(Object[] arrayList) { this.arrayList = arrayList;
I was making this program and I ran into an issue which is that I cant seem and understand how to get the numbers to go to the other side of the table
I had to make a program that converted 1-9 miles to kilometers and the other side 25-65 (increments of 5) kilometers to miles and thats the part I am having trouble with.
Here is what I have so far
import java.util.Scanner; public class MilesAndKilos { public static void main(String[] args) { int miles; double kilometers=1.60934;
[Code] ....
and this is how I want it to look
MilesKilometersKilometers Miles 1 1.609 | 25 12.430 2 3.219 | 30 15.538 3 4.828 | 35 # here 4 6.437 | 40 # here 5 8.047 | 45 # here 6 9.656 | 50 # here 7 11.265 | 55 # here 8 12.875 | 60 37.290 9 14.484 | 65 40.398
I want to ask that, when a server listen to A port and it accepts a request from a client then the server accepts the request using accept method,but how does the server get the info about the client like wat is the port no and ip address of the client,I read a answer regarding this that Server never gets the port no of client only the ip address and it connects to client using a connection stream but as far I know from networking, a device must have the ip address and port no of the device it wants to connect to.
for measurement of application security isn't not allow to change this parameter to client , so the problem when I access for application and I open a new page via linker for print for example and I would access for my initial page to make change or modify my initial page it s no possible to make any modification because I have a empty bean , but if the state saving is a client I haven't a problem because a tree map is stored in client browser, so my version of JSF is 1.1.1 ,
I have been following a 2d side scroller tutorial in java and have got the basics working, I changed the code a bit to make it so that the tiles and background are always moving, this worked as i intended.Within the character class:
if (speedX < 0) { centerX += speedX; } if (speedX == 0 || speedX < 0) { bg1.setSpeedX(0); bg2.setSpeedX(0);
[code]....
I wanted a way to make it so that if the character moves left, the tiles + background move slower. I am having issues with variable scope and setters/getters. Within the main game class, I have the code:
case KeyEvent.VK_LEFT: character.moveLeft(); character.setMovingLeft(true); break;
How can i include an if statement within the tile class that reads whether the character is moving left (determined from a keyPressed event in the main game class) and adjusts the speed of the tiles accordingly?I want to write something to the effect of:
I have a Registration Form in which I am registering user to perform some sort like Entering messages I want to perform some Server Side validation.
Like suppose a user has Enter an Id then as soon as he start entering the Id then I want that this Id should be checked in database that if this Id exists in database or not.
and similar types of validation I want to apply on other fields to.
I am calling a SOAP based webservice using JAX-WS and a client jar. I want to get a request and response somehow and save it for audit purposes. How I can do this?
When I google it, only Handlers come up, but, as far as I understand, it is not applicable on client side.
I have some data in the database and values can be added on demand. so when ever the value added to the database i need to promt that message to all users which are accessing my website, so how can i acheive this....
I used tomahawk t:tree for showing my data in tree structure and displayed that very fine. But my problem is how can we find the node id in bean side when we select one node .Because i want to show some data based on that node.
Below is a picture of a frame which needs is formed/opens as result of the button-click event of a button. I am copying the code of the entire action listener as well. The problem is that the size of the frame set by setSize(x, y), but the components don't appear accordingly. The size of the frame has increased (by setSize(x, y), i had set a different size earlier which was smaller) and so the components appear at one side on the frame.
Java Code:
static class btninstr_Action implements ActionListener{ public void actionPerformed(ActionEvent arg0) { JFrame frame2= new JFrame(); frame2.setVisible(true); frame2.setSize(500,500);// add custom panel to get perfect work
I need to write server side program(Servlet) which must be access by several requests at same time.how to handle this using java? Do i need to use queue or multiple instance of same class. Any example server method which returns the results based on ID
public String getResut(int id){
1)get db connection 2)get the result from db 3) retun the result }
1. All jsf tags like datatable, form, etc.. will generate UIComponents in server side, right?
2. All non JSF tags will not generate UIComponents in server side, right?
3. If you want something in a view that will be the same across users and requests, I mean, It will not change like a label tag, it doesn't make any sense to create it with a JSF tag in order to save memory in server side, right?
I have to show more than one images on a jsp page which are frequently refreshed. I am getting images in stream from client end and i want to show them on jsp. How can show them on jsp and refresh them after getting new image from client side?
I am very much new to jsp and servlet. I want to set global error page for every exception occured at server side. I am trying with following code , but something is going wrong and I am not able to c error page.
I need to implement Oauth2 with facebook to get authencation. I tried to write a servlet with the method Service, and i got the code thah i have to use in a second request.
Now i need to send a request at this URL :
1) [URL] .....
and wait for a responce with an URL that have the access_token to use with facebook
2) [URL] ....
Is it Possible in a single Servlet after i receive the "code" to send a second request to the URL in 1 and get the response with URL in 2 to retrieve the access_token?? if yes....how??
As you can see instead of displaying the champion name it is displaying the memory location and I do not know how to fix it.
class Champions { String name; Champions [] weak = new Champions [3]; Champions [] strong = new Champions [3]; String [] items = new String [3]; public static void main (String [] args) {
For some reason my code returns the memory address of the array when its a print statement with a string, but it works fine when its in a separate print statement all by itself. Why? Do I need to create a toString method that converts a char array to a String to something? The reason why I ask that is becuase on Eclipse line 10 has a warning stating "Must explicitly convert char[] to a String".
public class Ex { private String word; public Ex(String word) { this.word = word; } public char[] Display(){ char[] wordChars = this.word.toCharArray(); return wordChars;
[Code] .....
Result:
Hello world The word is: [C@1db9742
I also tried this, knowing that it's a long shot, but that didnt do anything...
public String toString(){ Ex ex = new Ex(this.word); char[] word = ex.Display(); String updated = word.toString();//counter intuitive? return updated; }
