I/O / Streams :: File Size Comparison
May 20, 2014
I would like to create a component to detect the file being modify before process.is it the right way to detect the file modification based on file size value?
Below are the flow:
1. Get the file size of a file
2. Used file size value encrypt it with MD5 algorithm, and say it generated us encrypted value "0123sdf"
3. to avoid user modify the file content, before file process, we take the file and do the encryption with md5 again, if it return value "0123sdf", then we are sure it doesn't have modification.
my question:
a. is it the right approach to detect file modification?
b. what the library advise to use or using java.security.DigestInputStream will do?
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Jun 13, 2014
Does printwriter always truncates the existing file to 0 size before adding any new data ??
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Mar 14, 2014
I have two big text file with approx 16 Lakh (1.6 Million) records in each. Both file contains Strings in each line. I would like to compare two files and find the descripencies and print them into separate file.
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Jul 28, 2014
i have a folder which contains two types of files (for eg: .csv and .tiff) with same names like, abc.csv and abc.tiff.How to compare the list of files with same names while ignoring their extensions.And my second task is to copy the content from csv file and i have to use that name as file name of .tiff file(Ex: if i have a1 as content in csv file, i have to change .tiff file name from abc.tiff to a1.tiff)
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Apr 22, 2014
I am creating a web application that runs on server X(unix) and it has another unix system mounted on it. I want to generate the file tree structure of this mounted unix file system and show it on to a web application so that users can select a file and move it onto this current unix machine.
I know this sounds stupid and you may want to say why cant we directly copy the file, I am doing a proof of concept and using this as a basis.
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Jun 25, 2014
Let's say I have a text file and in the text file exists file directories as such:
'assets/picture1.png'
'assets/picture2.png'
And so on...
How would I then read from this text file and then create those files using 'new File()'?
Here is my code:
private void getFiles() throws IOException{
files = new File[10];
Scanner scan = new Scanner(new File("files.dat"));
int count = -1;
[Code]....
It does print out those files, but it doesn't create them.
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Sep 22, 2014
I know that it's possible to retrieve a line from a txt file but say for example my file looked like this:
staff id = 1
firstname
surname
age
staff id =2
firstname Kate
surname Hollar
age 33
staff id =3
firstname Daniel
surname Hong
age 21
It is possible to retrieve just the staff id's?
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Aug 12, 2014
I have a code that clear old text then add new text to text file afterthat download the file but the problem my code dose not add new text
FileInputStream fileToDownload ;
private static final int BYTES_DOWNLOAD = 1024;
response.setContentType("text/plain");
String name = request.getParameter("n");
String text = new String(request.getParameter("text").getBytes("iso-8859-1"), "UTF-8");
[Code] ....
How to clear old text then add new text to text file
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Aug 25, 2014
I have a problem with € symbol ... an application write a String content on the file system with following code:
out = new FileOutputStream(strPath + "import.xml");
out.write(trp.getTrpXMLModel().getBytes("ISO-8859-1"));
It's correctly wrote on the file system:
TT;Pierre-H€enri;;Orange Grove;zefezfezfez, Directeur Juridique;TT;;azdaz;01 53 33 56 87;ezfezfez;01 53 33 51 59;.....&ée&ée;;;;;;132;CORDIAL;aaa
But when the application try to read the previous file with following code:
BufferedReader in = new BufferedReader(new InputStreamReader(inStream,"ISO-8859-1"));
String line = in.readLine();
The application isn't able to properly read the symbol ... and return following line, without "€":
TT;Pierre-Henri;;Orange Grove;zefezfezfez, Directeur Juridique;TT;;azdaz;01 53 33 56 87;ezfezfez;01 53 33 51 59;.....&ée&ée;;;;;;132;CORDIAL;aaa
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Jul 30, 2006
I want to create hidden files, some sample code for doing this.
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May 13, 2012
I am looking for a pure java api that can read metadata from an mp4 file, I have looked online but all apis I found are wrappers to native code. How to read mp4 with java .....
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Jul 17, 2014
I have a log file which goes like this..
INFO: Jul 07 00:00:15 DataSource 2zvw8p93107gev14wko86|34e51ca2: Total connections 4 idle 4 busy 0 unclosed orphans 0 pool unknown
PERFORMANCE: Jul 07 00:00:15 Garbage Collection: ParNew 5 51ms in 59 seconds. [SpeedoLoggingBean] Thread SpeedoBean
INFO: Jul 07 00:00:15 Speedo: 2,222,786K of 4,054,528K - 1,831,741K free, 4,952epm, 1 buffered, 216 threads, 49.1% CPU, permgen 173,731K of 262,144K - 88,412K free
Jul 7, 2014 12:00:15 AM org.geotools.data.wfs.v1_0_0.WFSTransactionState commit
SEVERE: number of fids inserted do not match number of fids returned by Transaction Response. Got:1 expected: 0
[code].....
What I need is to grab only the last hour data from this log file?
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Nov 8, 2014
I have a binary file that has identifiers for the start of each record
You can see here that the record starts with 00 00 and the next record starts with 00 00 etc...
How do I read between these two points throughout the file?
RandomAccessFile database = new RandomAccessFile(databasePath, "r");
int start = 0;
int end = 0;
database.setLength(start);
database.seek(end);
The first start would be the start of the file, the next start would be the end of the first start and so on..
I'm just not sure how to put that into a loop.
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Aug 28, 2014
I have been going over my code line by line, over and over again for nearly and hour now...When I execute method `file.createNewFile()`, the method returns true and throws no exceptions. It even says that the file exists. However, the file is not created and cannot be accessed until the program has exited.
File portLib = new File("");
private class RememberPortAction extends AbstractMenuItemAction
{
methods...
protected void actionPerformed() {
LibraryCreator creator = new LibraryCreator(self, logger);
File newPortLib;
[code]....
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May 25, 2014
My program creates a file but cannot write to it and i cannot figure out why.
How can i fix this code so that the FileOutputStream writes the String "Output" to the file HighScore.
public boolean ScoreWriter(int HighScore, int ScoreNum){
boolean writ = true;
System.out.println(HighScore + " " + ScoreNum);
try{
File ScoreFile = new File("HighScore");
if (!ScoreFile.exists()){
ScoreFile.createNewFile();
}else if (ScoreFile.exists()){
ScoreFile.delete();
ScoreFile.createNewFile();
[code].....
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Jul 24, 2014
I do most of my file I/O with {Scanner} for input and {PrintWriter} for output. I've got lots of places in my code that looks like:
Scanner source = new Scanner( new File( sourceName));
PrintWriter dstntn = new PrintWriter( new BufferedWriter( new FileWriter( dstntnName)));
But when I call the constructor for {PrintWriter} up above, it overwrites whatever the original contents of the file designated by {dstntnName} were, doesn't it? Is there a way to call the constructor so that any future writes to it simply append to the original contents, instead of overwriting them?
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Oct 23, 2014
When my app starts up is it possible to create a blank xml file in the c drive? so I can use it later on down the line
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Feb 7, 2006
I have to divide a text file into blocks of 128 bits. I think i must use the ByteArrayInputStream and ByteArrayOutputStream classes. is there any website showing how to user these two ByteArrayInputStream and ByteArrayOutputStream classes in detail. or it would be much better if you could show me a portion of the code.
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Jun 17, 2014
how to get the file size of an email attachment.
I used the following code to get this information.
l_EndUserObj.attachmentSize = mailAttachments.length();
The output is constant 2 even though the file size for each email attachment differ.
When I tried to use the getsize() I'm just getting an error that it is not a function.
I'm using BPM Studio during my coding.
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Jul 16, 2014
When I am trying to read data from BufferedReader and writing into excel using FileOutputStream object with POI APIs then i am getting the data in excel file in bad formats. you can check the log file and excel file attached for more information.
Here my problem is I cannot use BufferedWriter in place of FileOutputStream because POI class XSSFWorkbook only have one write method and we can only pass FileOutputStream class object there.
public void readFile()throws IOException {
BufferedReader inputStream = null;
FileInputStream fis=null;
InputStreamReader isr = null;
//Blank workbook
XSSFWorkbook workbook = new XSSFWorkbook();
[Code] .....
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Apr 25, 2014
I am completing a USACO online problem and am trying to create a print writer to write to my file(ride.out). I did this:
PrintWriter out = new PrintWriter(new BufferedReader(new FileWriter("ride.out")));
However, a load of undefined constructor errors come up for PrintWriter(BufferedWriter) and BufferedWriter(FileWriter). I have imported java.io.* so I don't know what the issue is. This has worked before.
edit: bufferedreader? i give up(not literally)
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Sep 26, 2014
If I'm using an xml file and the piece of data I want from the file looks like Staff id ="Test";
Is it something like this? Only seen two examples of it but I'm not sure they were reading from a file like myself.
Staff id = """ + Test + """;
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Oct 11, 2014
I'm having a bit of trouble with using the Scanner and the Printwriter. I start with a file like this (1 = amount of Houses in the file)
1
FOR SALE:
Emmalaan 23
3051JC Rotterdam
7 rooms
buyprice 300000
energylevel C
The user gets (let's say for simplicity) 3 options:
1. Add a House to the file,
2. Get all Houses which fullfil requirements (price, FOR SALE / SOLD etc.) and
3. Close the application.
This is how I start:
Scanner sc = new Scanner (System.in);
while (!endLoop) {
System.out.println("Make a choice);
System.out.println("1) Add House");
System.out.println("2) Show Houses");
System.out.println("3) Exit");
int choice = sc.nextInt();
Then I have a switch for all of the three cases. I keep the scanner open, so Java can get the user input (house = for sale or sold, price = ... etc). If the user chose option 1, and all information needed is inputted and scanned, the House will be written to the file (which looks like what I typed above).
For this, I use try (PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("Makelaar.txt", false)))). This works perfectly (at least so it seems.)
If the user chose option 1, and all requirements are inputted and scanned, the Houses will be read (scanner) from the file and outputted. For this I use the same Scanner sc. This also works perfectly (so it seems atleast).
My problem is as follows: If a House has been added, I can only read the House(s) which were already in the file. Let's say I have added 2 houses, and there were from the start 3 houses. If option 2 is chosen, the first 3 houses will be scanned perfectly. An exception will be caught for the remaining 2 (just added) Houses. How can I solve this? I tried to close the Scanner, and reopening it, but apparently Java doesn't agree with this
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Apr 8, 2014
I need to generate reports for huge data (around 2 to 5 lakh records) in different file formats (PDF , XLS , RTF , XML) in my web application.
Data will be fetched from database.
I have been searching for a best open source report generation tool and ended up on choosing on Dynamic Reports.
Aspose , is licensed and unluckily we could not afford to at this moment.
Whether i can use Dynamic Reports , or is there any other tool available.
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Nov 29, 2014
My code below creates the 2 files successfully, but it is not able to write the sample data into the newly created file. I can't figure out the reason why.
Another strange thing is that when I tried inserting System.out.println calls for debugging, nothing prints out.
try{
// stuff here
}
catch(FileNotFoundException fileNF){
String dirString = System.getProperty("user.dir");
String defaultFile = "config";
String currentFile = "currentconfig";
Path filePath = Paths.get(dirString, defaultFile);
Path filePath2 = Paths.get(dirString, currentFile);
[Code]...
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Jun 25, 2014
I'm getting an IllegalArgumentException returned when I try to get a file using guava library.
I previously had the function working when the file was in a different location, before I switched to running JBehave, my steps run but it fails to find the resource, even after I've moved it.
The code being executed is (this worked previously before using JBehave):
String xMLTemplateFileName = "OBOE-confirmation"
public static void setXMLTemplateFile(String xMLTemplateFileName) throws IOException {
URL url = Resources.getResource(xMLTemplateFileName+".xml");
The file I'm looking for is in the root folder for src/main/resources and also src/test/resources, previously I had it within a completely different location before I switched over to JBehave. I've tried it within a subdirectory in the same locations too.
I've recently updated the pom.xml to try to include the location required.
Extract from pom is below:
<!-- JBehave Build Details -->
<build>
<pluginManagement>
<plugins>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>jaxb2-maven-plugin</artifactId>
<version>1.6</version>
[Code] ....
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