If / Else Statement - Sum Of Integers Inside And Outside Of Range

Feb 13, 2014

Write a program that asks the user for the low and high integer in a range of integers. The program then asks the user for integers to be added up. The program computes two sums:

The sum of integers that are in the range (inclusive) and the sum of integers that are outside of the range. The user signals the end of input with a 0.

In-range Adder
Low end of range:
20
High end of range:
50
Enter data:
21
Enter data:
60
Enter data:
49
Enter data:
30
Enter data:
91
Enter data:
0
Sum of in range values: 100
Sum of out of range values: 151

Here is my code:

import java.util.Scanner;
class addRange
{
public static void main ( String[] args )
{
Scanner scan = new Scanner( System.in );
System.out.println("The In-Range integer is; ");
int inR = scan.nextInt();

[Code] ....

I'm getting an error on the line with the first else if saying nextNum might not have been initialized. but it's initialized on the line directly above that....

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Print Range Of Integers From X To Y With Increment Of 5

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Working on problem in my book in which I have to print a range of integers from x to y with an increment of 5. I thought I had the right idea when writing out this code, but apparently, it only gives a few of the numbers in the range, not all, what I am doing wrong?

import java.util.Scanner;
public class Ranges
{
public static void main (String[] args) {
Scanner input = new Scanner (System.in);
System.out.print("Enter a value for x and y: ");
int x = input.nextInt();

[Code]...

import java.util.Scanner;
public class Ranges
{
public static void main (String[] args) {
Scanner input = new Scanner (System.in);
System.out.print("Enter a value for x and y: ");
int x = input.nextInt();

[Code]...

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[code]....

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{
public static void main(String [] args)
{
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[code]...

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/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package javaapplication19;
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[code]...

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[code]....

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