If Interface Can Be Default Then Why Not Protected?

Mar 9, 2014

I was just wondering.. my understanding from everywhere I have read is interface cannot be private or protected (not at the top level) but when we declare an interface without any modifier it is default.

We know default modifier has more restricted access than protected.. public > protected > default > private

Now since an interface can be public and default then why not protected as clearly if they were allowed to be protected they could be implemented by a subclass..?

While typing this question I figured how would an interface know which is it's subclass? that is why Java allows only public i.e. any class can implement it or default i.e. any class within the package can implement.. am I right?

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Difference Between Protected Or Default

Mar 28, 2015

I am new in java. Is there any difference between protected or default when we are talking about one package?

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Default Method In Interface

Feb 7, 2014

interface I1{
void show();
void display();
default void put(){
System.out.println("I am from interface I1");

[Code] ....

This code is not working..

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Interface - Syntax Error On Token Default

Jul 14, 2014

I am following this article : [URL] ....

And I have created 4 different types of Interfaces and Classes

Interface:-Flyer,Mythical
Class:-Horse,Pegasys.

But on Interface

I am getting error on line

default public String identifyMyself()
"Syntax error on token "default" delete this token"

Here is code for all 4 interfaces and classes

public class Horse {
public String identifyMyself() {
return "I am a horse.";
}
}
public interface Flyer {
default public String identifyMyself() {

[Code] ....

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Feb 1, 2015

Why is it that a protected method cannot be accessed polymorphically outside its package. I suspect the reason is that some compile-time checks have to be performed. Is this correct?

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Why Protected Method In Class Object

Nov 1, 2005

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Class Cannot See Its Own Protected Variable From Another Package

Jan 30, 2014

how access levels work from subclasses and other packages, and I have discovered that a class cannot see it's own protected variable from another package which I thought it would be. I know that it says in the java docs "The protected modifier specifies that the member can only be accessed within its own package (as with package-private) and, in addition, by a subclass of its class in another package." but I thought that would also include it's own class.

Java Code:

package food;
import food.fruit.*;
public class Food {
protected int protecte = 5;
private int privat = 5;
protected void method(){

[Code] ....

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Jan 26, 2014

What is the real purpose of using Protected access specifier in Java?

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File Download From Password Protected FTP Server

Jun 16, 2014

I have also tried above code with few changes but I got error. Code and error show below.

Java Code:

package practice;
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.net.MalformedURLException;

[Code] .....

Error:

Java Code:

Jun 16, 2014 6:21:33 PM practice.TestFTPProgram main
SEVERE: null
java.net.ConnectException: Connection refused: connect
at java.net.DualStackPlainSocketImpl.connect0(Native Method)
at java.net.DualStackPlainSocketImpl.socketConnect(Unknown Source)
at java.net.AbstractPlainSocketImpl.doConnect(Unknown Source)

[Code] .....

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Aug 1, 2014

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package com.excel.utility;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.security.GeneralSecurityException;

[code]..

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Nov 26, 2009

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Encapsulation - Protected Attributes Should Be Visible To Child Classes

Jun 7, 2013

I found the following inheritance and encapsulation issue . Suppose you have a parent class with a non-static protected attribute.

package package1;
public class Parent{
protected int a = 10; // this is the non-static protected attribute in question
public static void main(String args[]){
// whatever logic
}// end Parent class
}// end main()

Now suppose you have a child class in another package and you have imported in the parent class.

package package2;
import package1.Parent;
public class Child extends Parent{
public static void main(String[] args){
Parent p = new Parent();
Child c = new Child();

System.out.println(p.a); //should print out 10 BUT DOES NOT
System.out.println(c.a); //should print out 10
}// end main()
}// end Child class

My observation is that p.a produces an error even though, to the best of my knowledge, it should not. I believe the statement "System.out.println(p.a);" should print out a 10.

Am I misunderstanding something about inheritance and encapsulation?

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May 19, 2014

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JRE :: Java Applications Certificate Check With Password Protected Proxy

Jul 29, 2014

I have a problem with several java applications. When I start them Java wants to connect to the certificate authority, to check if the certificate is still valid and not on a blacklist.

The problem is: my whole internet is behind a password protected proxy. If I open my browser i get a windows with username and password. I enter it and internet in the browser works. But for Java it isn't working, because I see no point, where I can enter the password and username for the proxy. I can enter the proxy ip and port in the java settings, but not the password and username. So I get a error screen from java, telling me, that java could not connect. I can disable the check in the java settings, but I don't wont that.
 
Is there a way to tell java, that java uses my proxy with my password and username? I already googled this problem and found nothing except tutorials for connecting with proxy in the java code. But these applications are not from me, I can't change the code ...

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Interface Extends More Than One Interface

Jun 9, 2014

Below code gets printed as output?

public interface I1 {
public void method();
}
public interface I2 {
public void method();
}
public interface I3 extends I2, I1 {

[Code] ....

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No Default Constructor

Nov 2, 2014

The LocalStudent class inherits the Student class. The IDE states an error of "no default constructor in Student class".I understand that if a LocalStudent object is created, the default constructor of its superclass (aka Student class) will be called implicitly.there is no LocalStudent object being created, so why is the default constructor of Student being called ?

The default constructor of LocalStudent is also overloaded by the created no-arg constructor containining subjects = null; . So there is no call to the superclass default constructor from the default constructor of LocalStudent.

public class Student {
private char year1;
public Student(String name, char year){
year1 = year;
}
public char getYear(){
return year1;

[code]...

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Feb 4, 2014

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if (stringGQ != null && stringGW != null && stringGP != null){
 stringGQ = gMQ.getText();
stringGW = gMW.getText();
stringGP = gMP.getText(); 
weightPrice_1M = Double.parseDouble(stringGW) * Double.parseDouble(stringGP);

[Code] .....

Note: This is a small part of my code. when I leave it empty it take the 0 as a value, However, when I write in text field it also take the value of a 0 and the finalTotal is also = to 0.what I'm doing wrong.

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Default Literal For Boolean

Mar 31, 2014

what is default literal for Boolean data type?

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Oct 8, 2014

ArrayList l = new ArrayList();
System.out.println(l.size());

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Default Access Modifier

Mar 21, 2014

class Course
{
String courseName;
}
class Entry
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public static void main(String[] args)
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Course c = new Course();
c.courseName="java";
System.out.println(c.courseName);
}
}

I have defined these two classes under same java project in Eclipse IDE with no package. Above two class are having default classes. class Course is also having a instance variable courseName with default access. So when we try to compile the Entry class it will give the errors while accessing the instance variable courseName on Line 6 and 7. As both the classes are having default access modifier. class Course is not visible to class Entry, then why we do not get any compilation error while creating the object of class Course on line 5?

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Mar 20, 2015

I have a question related to q44 of Examlab.

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} else {
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i = "A";
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Feb 20, 2014

I remember reading Instance variables & local variables (in methods) are initialized to appropriate value by the compiler.

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Jan 22, 2015

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Printing Default Value Of Int - When Is Variable Initialized

Nov 12, 2014

In the following code the print method prints the default value of int(zero) for the first time even when the variable i has been assigned a value of 4. Why?

class A1{
A1()
{
System.out.println("Inside constructor of A1()");
print();
}
void print()
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System.out.println("A");

[Code] ....

Output:
Inside constructor of A1()
0
Inside constructor of B1()
4

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How To Add Variables And Default Values To Arraylist

Mar 23, 2015

I am facing difficulties in identifying the proper way to add the selected colors of cards into an arraylist. I am having an arraylist which is:

Java Code: private List<String> selectedCars = new ArrayList<String>(); mh_sh_highlight_all('java'); And one more for the carColors:

Java Code: private List<String> carColors = new ArrayList<String>(); mh_sh_highlight_all('java');

The selectedCards array will store the selected cars ['TOYOTA','MAZDA','NISSAN'] as per the selection from the user.For certain types, there is one default color which is 'Black', however for some of them, the user can select different colors.(ex. if selection is 'Toyota')
Java Code:

String carColor="";
String toyotaColor=""; // The value will be retrieved from the form once the user selected the color
if (selectedCars.contains("MAZDA"))
{
carColor="Black";
}
else if (selectedCars.contains("TOYOTA"))
{
carColor=toyotaColor;

[code]....

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How To Display Default Constructor Values

Sep 13, 2014

I am writing a program that accepts input from the user, I want default values displayed before the input values.

Java Code:

public surfboards() {
surfboardType = "Type not assigned";
shaperName = "Shaper not assigned";
constructionType = "Construction Type not assigned";
surboardSize = 0D;
} mh_sh_highlight_all('java');

I can get the output to display as shown below

(THIS IS WHERE I WANT DEFAULT CONSTRUCTOR DISPLAYED. Currently not displayed)

Type not assigned
Shaper not assigned
Construction Type not assigned
0 Feet

(THIS IS WHERE I WANT DEFAULT CONSTRUCTOR DISPLAYED. Currently not displayed)

input:

Java Code:
Enter Surboard Type:
test
Enter Shaper Name:
test
Enter Surfboard Construction Medium:
test
Enter Surfboard Size:
6.5 mh_sh_highlight_all('java');

Output:
test
test
test
6.5 feet

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