Ignore Certain Characters In A String
Apr 5, 2014
I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.
else if(message.charAt(i) == 'L' && message.charAt(i+1) != 'O' | message.charAt(i+1) == 'Y'){
JLabel localLabel = new JLabel();
localLabel.setIcon(lantern);
panel.add(localLabel);
panel.revalidate();
panel.repaint();
But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.
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Sep 27, 2014
I am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
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Sep 16, 2014
how we can handle the string with special characters. For instance:
123456789BNJKNBJNBJKJKBNJKBJKNBJK"VJKNBJNHBJNJKBVJ KBJKNB"VHBVBBVNBVNBVBVBVBNBVNBNBJHFBVFJB FNVJBNVJNVJDFNVJKNVJKNVJKVNNVJ NN"
I get some user inputs with double quotes and i need to split to 80 chars line.
.length fails to get the length if it contains special characters like double quotes and ?
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Apr 8, 2014
like i have String s="11222ddeefs"
so here i want program output like 1=2
2=3
d=2
e=2
f=1
and s=1
it has to show no of duplicates in each character in string
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Oct 17, 2014
As of right now my code can take characters from a string to an array from a string like "ABCD" but the project says I have to take it from a string like "A B C D" how can I correct my code to grab the characters from a single spaced line?
Scanner sc = new Scanner(System.in);
System.out.println("Enter Order of Cars:");
String carsInput = sc.next();
int x = carsInput.length();
int[] cars = new int[x];
for (int i=0; i < cars.length; i++) {
cars[i] = carsInput.charAt(i)-64;
}
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Sep 10, 2014
So what my program is supposed to do is take a number inputted by the use and then take a phrase. It then changes that phrases letter by the number inputted prior for example if you type in 2 as your int and Hello as your phrase you should get JGNNQ, which i can do. but the problem is that when i run it, it outputs like this:
J
G
N
N
Q
As separate characters how can I combine those characters in 1 string so it looks like JGNNQ? this is my code
import java.util.Scanner;
public class Dcod_MAin {
private static final Object[] String = null;
public static void main(String[] args){
Scanner input = new Scanner (System.in);
System.out.println("What is the day of the month");
int shift;
[Code] ....
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Jul 5, 2014
I need to make a string filled with naughts and crosses like this one : "xxx ooo xox". There are 3 groups separated with a space. how to fill the string randomly ?
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May 7, 2014
I just need to write a simple program/function that replaces certain letters from a string (i.e. censor( "college", "aeiou" ) returns "cllg"). I'm trying to get the code right first, and then write a function for it.I basically just thought that I would iterate over the first string, and once I had the first character, I would then iterate over the second string, to see if the character exists. I'm getting a "dead code" error on my second loop because I put the second "break."
public class ap {
public static void main(String [] args){
String s = "Hello";
String s2 = "aeiou";
[code]....
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Oct 2, 2014
I have to check a String input from the user in the form of firstName lastName (i.e. John Smith). I have to check for an exception called NonAlphabeticCharacterException that gets thrown if there is anything but a number in that string. This is what I have right now but should I create an array of char for the alphabet and then check the whole string for non alphabetic characters?
for(int i=0; i<name.length(); i++) {
if()){
throw new NonAlphabeticCharactersException("Non-alphabetic character found");
}
}
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Nov 4, 2014
I am trying to count the number of non_blank characters in a string. If there are no leading blank spaces it works fine but say i add three spaces in front it doubles the non blank characters.
import java.io.*;
import java.util.*;
public class countCharacters
{
public static void main(String[] args) throws Exception
{
String str1;
int count;
count = 0;
[Code] ....
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Oct 1, 2014
I am trying to do a program that takes all of the chars from a string and orders them in alphabetical order. It works fine, but when a is a last letter of a string it isn't being sorted.
Example: bcba = bbca, omnibus = bimnous (here u is in wrong place)
Here is my code:
public class sorty{
public static void sort(char[] a, int low, int high){
int i = low;
int j = high;
if (j - i < 2) return;
int m = (j+i)/2;
char p = a[m];
[Code] .....
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Sep 26, 2014
I am trying below challenge to display first three characters three times if the size of the string is greater than 3.
Say if i send hello i should get helhelhel
if i send xyz i should get xyzxyzxyz
I wrote as below
public String front3(String str) {
if(str.length()==3){
return str+str+str;
}
if(str.length()>3){
String str2=new String(new char[]{str.charAt(0),str.charAt(1),str.charAt(2)});
return str2;
}
}
I am getting error as below
Error:public String front3(String str) {
^^^^^^^^^^^^^^^^^^
This method must return a result of type String
Possible problem: the if-statement structure may theoretically allow a run to reach the end of the method without calling return. Consider adding a last line in the method return some_value; so a value is always returned.
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Jun 30, 2014
In this simple example, I print a byte array to String:
Java Code:
import java.io.UnsupportedEncodingException;
import java.nio.charset.Charset;
public class PrintByteArray {
public void print(){
System.out.println(Charset.defaultCharset());
byte[] arr = {1, 2, 3, 4};
[Code] ....
However, Eclipse prints out strange boxes, which I was unable to copy into this message.
It's supposed to print out the values of the bytes. What am I doing wrong?
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Dec 11, 2014
I am trying to change an input String to an array of characters, but it only stores the word before the space into the array. Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".I am trying to change an input String to an array of characters, but it only stores the word before the space into the array.Here is the code:
Scanner scanner = new Scanner(System.in);
System.out.println(" Enter text: " );
String text = scanner.next();
char[] characterArray = text.toCharArray(); // convert string to array of characters
String char = "";
for( i = 0; i < characterArray.length; i++) {
char = char + characterArray[i]
} System.out.println(char);
Just typing hello gives me hello, but when I type hello world it does not type in the word "world".
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Jan 27, 2015
I was trying to create a java program which can remove the repeated characters in a String. For ex-
Input: kamehamehaaa
Output: kameh
Here is my code:-
import java.util.Scanner;
class replace {
public static void main (String args[]) {
Scanner br = new Scanner(System.in);
System.out.println("Enter a word");
[Code] ....
On executing the program, StringOutOfBoundsIndex error occurs.
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Feb 18, 2014
I do have a quick question about string manipulation. You see I've been given a simple exercise that involves asking the user to input a number between 1,000 and 999,999 and displaying the result. Simple enough, but the caveat is that if the user keys in the comma, say 24,000 instead of 24000 for example, the program is not to display the comma. I don't see how to do this without an 'if' statement. The book says the 'if' is not necessary but does offer this hint: "Read the input as a string. Measure the length of the string. Suppose it contains n characters. Then extract the substrings consisting of the first n-4 characters and the last three characters."
What good is n-4 going to do if the string's lengths varies?
Here's what I have written thus far:
import java.util.Scanner;
public class P13
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Please enter a number between 1,000 and 999,999: ");
[Code] .....
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Jul 3, 2014
I'm attempting a small program as I'm teaching myself the ropes. In it, I need to compare one string (the base) to another which is just the base string that's had it's characters shuffled.
Java Code:
String base = "ABCDEFG"
String shuffled = "CDAFBEG" mh_sh_highlight_all('java');
What I need to do is run a loop that shuffles the base string each time, but compares and saves any characters that match in the correct location. For example, if shuffled = "CDAFBEG", then the G would be "locked" in place and the rest of the characters shuffled and looped back to the comparison.
I have all the code I need for shuffling the string, but I'm not sure how I would go about comparing each character and then also locking it in place. I get the basics, I think, of needed to use several variables.
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Feb 12, 2014
In c++, I'm aware that you can use the ignore function to ignore numbers after space, but in string how do I ignore a number after space is found for instance, "109 33" how would I ignore 33?
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Oct 18, 2014
I have made a program, where the user types in a letter M, C or I to identify their major, if the user types m, c or i, my code does not work.
How could I make my program ignore if the letter is upercase or lowercase? My code is posted below. Can I do this in any easier way then adding this type of code for each lowercase letter?:
Java Code:
if (s.charAt(0) == 'm')
System.out.print("Mathematics "); mh_sh_highlight_all('java');
My current code:
import java.util.Scanner;
public class c4e18 {
public static void main(String[]args){
Scanner input = new Scanner(System.in);
System.out.print("Enter two characters: ");
String s = input.nextLine();
if (s.charAt(0) == 'M')
[Code] .....
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Mar 17, 2014
I have the below code with spaces on uri and prefix (directive attribute).
<%@ taglib uri=" news.tld" prefix=" news" %>
how to fix without altering the JSP? Can i handle with web.xml or any other property available.
I have hundreds of jsp like this and wanted to handle without code fixes.
I tried JSP trimSpaces but it fixes the namespace but not the attributes.
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Nov 13, 2014
I'm trying to make a program that will count each letter like if I put the word
e-1
h-1
l-2
o-1
The problem I'm running into is that if I put something like How now, brown cow? It should give me something like this
b - 1
c - 1
h - 1
n - 2
o - 4
r - 1
w - 4
but it doesn't instead the whole program crashes because of the punctuation marks and the spacing. Is there a way for me to fix that? All I know is that it has something to do with the alphabet[pos(letter)]++;
import java.util.Scanner;
public class CharCount {
static Scanner keyboard = new Scanner(System.in);
//this method should allow the user to enter a line of text (that should all be lower case) and then go to the printResults method
public static void main(String[] args) {
String text, character;
int count;
char letter;
int[] alphabet;
System.out.println("Enter a line of text:");
text = keyboard.nextLine().toLowerCase();// any text entered will be lower case
alphabet=countLetters(text);
[code]....
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Jan 28, 2015
I have several Buttons wrapped into a VBox. I used setOnSwipeUp and setOnSwipeDown for up and downs the buttons. But when there is no more buttons the scroller continues but shows nothing, is empty. How do I do when there are no more buttons ignore swipe gestures?
[Java] // Menu Swipe Up menubox.setOnSwipeUp(new EventHandler<SwipeEvent>() {
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May 21, 2014
The problem is i want to replace some string text with foreign characters, but JTextArea returns plainText.
For Example:
str = new String();
str.replace('e', 'é');
textArea.setText(str);
but textArea returns plainText.
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Mar 7, 2014
I'am trying to converting string data into xml data using xml beans and StringEscapeUtils.This is work fine but in one case it if the data contains special characters.
Code snippet
--------------------
import org.apache.commons.lang3.StringEscapeUtils;
import org.apache.xmlbeans.XmlException;
import org.apache.xmlbeans.XmlObject;
public class ParseXMLData {
public static XmlObject parseXML(String stringXML) {
XmlObject xmlObject = null;
[Code] ....
success case
---------------------------
i/p------<aaa><bbb>This converts string to xml</bbb></aaa>
o/p---<aaa><bbb>This converts string to xml</bbb></aaa>
Failer case
-----------------
i/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
expected o/p----<aaa><bbb>This fails if it contains < symbols</bbb></aaa>
Observed that it converts < to '<' but as per xml rules, if data contains '< ' it fails. I want to convert staring and end tags to xml format and if data in b/w middle of starting and ending tags do'n need to convert it. How to do it.
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Mar 7, 2014
Is that the only way to code the JOptionPane? Seems rather similar to Sys.out
--- Update ---
I had more than this, but post was deleted somehow and this was the gist of it:
for(i = 0 ; i < charArray.length; i++){
if(Character.isDigit(charArray(i))){
address.replace("6", "*");
address.replace("7", "*");
Is there a better way to scan a character array for digits and replace any number in the array with another character ("*") in this case? The array is the address, " 1234 Runner Road " .
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May 20, 2015
I am trying to compare the first characters of two strings.
import java.util.Scanner;
public class testIf {
public static void main (String [] args) {
String userInput = "";
char firstLetter = '-';
[Code] .....
in the if statement i get this error Cannot invoke charAt(int) on the primitive type char...
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