Image Path Java To Exe / Jar File
Sep 30, 2014
I already done my program with images on it but when i convert it to exe , the images is not appearing.
Usually my images are located at documents netbeansprojectprojectimage.jpg
When i run the code on netbeans the images are appearing but when i convert it to exe or jar file run on a computer without netbeans.. images is not appearing ...
import java.awt.*;
import javax.swing.*;
import javax.swing.event.*;
import javax.swing.ImageIcon;
class Phonebook extends JFrame {
private static final int WIDTH = 430;
private static final int HEIGHT = 200;
public Phonebook()
[Code] ....
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Jul 3, 2014
Gyazo - e5663e8da42ac46a642895d72836b933.png
As you can see I have specified a file path, as it is needed to draw the image.
The image "sun" is in a certain folder inside the directory of my jar file.
But If I were to send the whole package to my teacher to review. The file path would still remain the same, local to my computer making the image, unloadable.?
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Dec 1, 2014
In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
Below the drop-box upload code with java.
File inputFile = new File("New Text Document.txt");
System.out.println("inputFile.getAbsoluteFile(): " + inputFile);
FileInputStream inputStream = new FileInputStream(inputFile);
try {
DbxEntry.File uploadedFile = client.uploadFile("/magnum-opus.txt",
DbxWriteMode.add(), inputFile.length(), inputStream);
System.out.println("Uploaded: " + uploadedFile.toString());
} finally {
inputStream.close();
}
In the above code the place New Text Document.txt we have to provide total path of file.
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Apr 8, 2014
I'm a Java beginner and I've been trying to scan a file using the Java Scanner. I've tried searching online for this error and I only find people's questions who have entered an incorrect relative path. I'm entering in an absolute path and I'm using Eclipse Standard Edition on a 2013 MacBook Pro with Mavericks 10.9.2.
Anyway, the error message I'm receiving on Eclipse is: Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException
at App.main(App.java:12)
public class App {
public static void main(String[] args){
String fileName = "/Users/Student/Documents/index.html";
[code]...
Why it cannot find this file. I've checked the absolute file path of index.html on my Mac and I've copied and pasted it into my code.
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Jun 18, 2014
currently I am doing my java web application project ,and it has following steps 1) Upload the txt files 2) java servlet gets the txt file's url , read the data and do the calculation 3) pass the results
I almost finished the second step , and working on the first step .Since there are so many input files at a given time , i have to use drag and drop method to get the file's location.how to pass file's path to servlet.( servlet code can read the data from the given txt file path )software used - tomcat and netbeans 8.0
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Mar 15, 2014
I want to do the followings:
-When i press "choose the Image Path" a window open like a picture 2.
-I want also satisfy the condition written in red.
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Mar 15, 2015
All I want to do is load an image into a swing JLabel and display it, but I'm going to have to make a JAR of the program and submit it for grading, so I need to be able to get the path of the image file relative to the JAR (at least I think that's how it works - I've never made a JAR before. Right now I'm just trying to load it from a path relative to my netbeans project). I've tried at least 20 different combinations of paths, file locations within the project, etc., but nothing works.
Anyways, here's the test class I've been using to try to figure this out in its current iteration. Right now the image I want to load is in src/resources and the class is in
src/imagedisplaytest
package imagedisplaytest;
import javax.swing.*;
import java.awt.*;
public class ImageDisplayTest extends JFrame {
private JLabel testLabel;
public ImageDisplayTest()
[Code]...
What's the best way to do this?
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Mar 21, 2015
I wanna make a simple Java SE application which is only one jar file, but unfortunately there is an image which I want my app access it, what I have in mind is carrying that file with the app, but I don't know how to do it and how to access it in run-time.
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May 6, 2014
I am facing a problem while executing a task. My task is to make such a code which will search for my source code file (abc.java) in all directories and then displays the code in textarea inside frame and along with that i also have to display the path of the file in text field. I have coded something but i am really not getting anywhere near my task.
import javax.swing.*;
import java.awt.*;
import java.io.*;
import java.util.*
public class Lab extends JFrame {
[Code] ....
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Dec 24, 2014
I had string url for image in mysql database and I want show image in mu jsp file bu I can't.
<c:forEach var="urun" items="${listUrun.rows}">
<tr>
<td><c:out value="${urun.kitapresim}" /></td>
<img src="<c:url value="${urun.kitapresim}" /> " width="270" height="190"/>
URL...
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Sep 13, 2014
//compiler error I'm receiving
J:CS3Student Folder Review Lab #2APlusImage.java:41: error: cannot find symbol
xcor.add(read.nexInt());
[Code].....
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May 12, 2014
What I do wrong when I trying to set path to file in my jar app. I have application which work with xml file. I have next project structure:
/project_root_directory
|_ /lib
|_ /resources/file.xml
|_ /src
So, I need to set correctly path to my jar file, because when I running it from IDE, it works nice. By default it seems:
private File file;
private StreamResult streamResult;
file = new File("resources/file.xml");
streamResult = new StreamResult(file);
And methods where I can modify the DOM structure via transformer in end of methods:
transformer.transform(source, streamResult);
So, I trying set path to file:
private URL url;
...
file = new File(url.getPath());
streamResult = new StreamResult(file);
But it didn't not work, because when I trying to get resource by next condition
url = getClass().getResource("resources/file.xml");
url = getClass().getResource("resources/file.xml");url = getClass().getResource(url = getClass().getResource("resources/file.xml");resources/file.xml");
url - is null
Okay..
I tried next solution
InputStream input = getClass().getResourceAsStream("resources/file.xml");
There, I got also null....
Also, I tried made absolute path
filePath = file.getAbsolutePath();
file = new File(filePath);
streamResult = new StreamResult(file);
But it also didn't work. There I got message seems like: "Can't find resource /User/user1/Desktop/program1/resources/file.xml" - but that's really absolute path to a file.
Also, I tried made it via System.getProperty
String filename = "file.xml";
String workingDir = System.getProperty("user.dir");
finalfile = workingDir + File.separator + "resources" + File.separator + filename;
file = new File(finalfile);
I also made unit test which completed with "green light", but in jar its wrong with message "Can't find resource /User/user1/Desktop/program1/resources/file.xm" ....
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Jun 24, 2014
First of all, i am using ubuntu and jdk8. My problem: displaying the current path of a file in my system Approach: I have a file called dummy.txt in a given directory which have enough permissions and i did the following:
File file=new File("dummy.txt");
System.out.println(file.getAbsolutePath().substring(0,file.getAbsolutePath().lastIndexOf("/")));
I expected to see displayed the current path of the file without the name of the file but it is showing a different path. I just want to display the current path of the file without the name.
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Apr 8, 2014
Well I fixed my invalid path problem
Now it is telling me that my file is not found and it is exactly where I put it and told JCreator to look for it.
this is what I get:
javac: file not found: C:Program FilesJavajdk1.8.0docsMyName.java
when I go manually to the address, it is there but for some reason Jcreator cannot find it.
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Nov 3, 2014
I have a GUI that has three jTextFiled's. The first on gets filled in with a file that I choose and shows the path to that file with the file name
i.e. - c:
s34bil.exe
un estrun.i
I want to change the file extension from .i to .r in one jTextField and then .i to .o in another jTextField.
I am slowly learning Java. I have this coded in VB, but not sure how to do it in java.
Here is the VB script :
Dim thefile As String = txtInput.Text
Dim fn1 As String = My.Computer.FileSystem.GetName(thefile)
Dim fn2 As String = fn1.Replace(".i", "")
[Code] ....
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May 20, 2014
I'm using jsf 2 to upload file, first I upload the file in a system directory, then trying to store the path to database with other information, my stuck is that when submitting I upload the file successfully, find it in the right place, find the other information such as description, file name ... in database but don't find the path. this is my managed bean :
package mbeans;
import java.io.File;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.URL;
import java.util.List;
[code]...
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Nov 7, 2014
I am copying the xml files from one folder to other folder, in the source folder, i have some files which have some content like "backing File="$IDP_ ROOT/metadata/iPAU-SP-metadata.xml" but while writing to the destination folder.i am replacing the "$IDP_ROOT" with my current working directory. The entire copying of files is for deploying into tomcat server. The copying is done only when server starts for the first time.Problem: If i change the folder name from my root path in my machine after i run the server,the entire process will be stopped because the destination folder files already contains the content which is with existed files names or folder names.
So i want to change it to relative path instead absolute path. What is the best way to do it? Please look at code below:
[ // Getting the current working directory
String currentdir = new File(".").getAbsoluteFile().getParent() + File.separator;
if(currentdir.indexOf("ControlPanel")!=-1){
rootPath=currentdir.substring(0, currentdir.indexOf("ControlPanel"));
}else{
rootPath=currentdir;
[code]....
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Nov 27, 2014
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties);
Properties props = new Properties();
props.load(in);
in.close();
FileOutputStream out = new FileOutputStream(newprop.properties);
props.setProperty("myDirectory","C:Lisa estUpdate" );
props.store(out, null);
out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
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Jan 10, 2015
I'm using a PrimeFaces UploadedFile xhtml page to select a csv file to read and write using a managed bean (SuperCSVParser.java). The file is read and written to an entity class which then persists the data to a database. The application works fine if I specify a file path on the physical server and select a csv file on that file path. But for the production version I want the user to select ANY file name from ANY directory on their local system.
I know about the FacesContext methods and I've looked at some methods from the java.io File class. Most of these methods are about getting the path from the server, where I want to 'pass' the path String from the client machine to allow the uploaded file to go through. When I try with the below code I get:
java.io.FileNotFoundException: data.csv (The system cannot find the file specified)
I'd like to know what I'm doing as I prefer not to explicitly declare a path in the final app. I'm almost sure that's possible.
<h:form enctype="multipart/form-data">
<p:fileUpload value="#{SuperCsvParser.file}"
mode="simple"
auto="true"
[Code].....
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Jun 30, 2014
I have a code that uploads files in server after browsing folders and files then get the paths of files but I have a problem in getting the paths
List items = upload.parseRequest(request);
Iterator iterator = items.iterator();
while (iterator.hasNext()) {
FileItem item = (FileItem) iterator.next();
if (!item.isFormField())
{ fileName = item.getName();
root = getServletContext().getRealPath("/");
path = new File(root + "/uploads");
[Code]...
list1 must has paths that I want but I do not get the paths of upload files
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Mar 2, 2014
I have BlueJ installed on my computer and it does the job of compiling the java source code written in it. If I want to write and compile source code outside of BlueJ do I still need to download the Java SDK and set the PATH variable, even though I am apparently able to do it in BlueJ?
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Sep 4, 2014
I have downloaded jns-1.7 & tried to run an example program "Simulator.java" by specifing the jar classpath while compiling as "javac -cp <path-to-jns-jar-file> Simulator.java". But i got 21 errors as follows:
Simulator.java:3: error: package jns.command does not exist
import jns.command.Command;
^
Simulator.java:4: error: package jns.element does not exist
import jns.element.Element;
[Code] ...
21 errors
I am trying my hand on JNS as i need to deveop a key-distribution scheme (random Key-Distribution scheme) using a simulator. As i have experience in java, i thought to use JNS instead of NS2/NS3 which seems very complex to me.
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Jan 17, 2015
Can I add a variable to Windows PATH from java code?
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Nov 1, 2011
I'm developing a JavaEE system with several applications on a Weblogic AS (10.3.5) using Eclipse indigo with OEPE plugin. I turned my computer off, turned it back on, started the eclipse, and all of a sudden I get class-path errors all over the place (didn't change a thing).
Now let me get this straight:
1. Say I have an application with one EAR project that contains an EJB project and an EJBClient project (both in the deployment assembly).
2. I have written a new regular Java project, and I want to use it in both the EJB and EJBClient projects (it needs to be visible to them).
3. As far as I know, I can simply add this Java project to the EAR project's deployment assembly, and it will be visible to the EJB and EJBClient projects.
4. This has been working for me so far, but now I get class-path errors and I have to add this Java project to the build path of each project.
How should I set the class-path when using JavaEE technology in Eclipse?
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Apr 11, 2015
I have a FileChooser:
JFrame parentFrame = new JFrame();
JFileChooser fileChooser = new JFileChooser();
fileChooser.setDialogTitle(txtPushCode.getText());
int userSelection = fileChooser.showSaveDialog(parentFrame);
if (userSelection == JFileChooser.APPROVE_OPTION) {
[Code] ....
But as you can see, it downloads only to "C:android empcoloricon.png". I want to download it to path where I chose in FileChooser with the name and extension I choose. In short, how can I use dynamic file path names in where ever I want in my applications?
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Feb 25, 2014
how can we rename the scanned image file from scanner which is by default scan_01is their any api which can rename the scanned o/p file
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