I have an assignment where I need to increment an alphanumeric string by one. For example AAA123 + 1 = AAA124. I'm okay with incrementing alpha or incrementing numbers, but incrementing them all together is where I am stuck. Should I just convert the entire string to ascii and increment there?
View RepliesI am in need of regex for alphanumeric (uppercase only) values which will verify string of length 5below
ABCCD - False
AB12C - True
ABC12 - True
12ABC - True
12345 - False
If it contain any lowercase then it should result in false as well.
My regex ^[A-Z0-9]{5}$ is not working for above type of values.
I am currently take a class, and trying to increment the count of employees I enter into an ArrayList by 1 for every entry. However, instead of incrementing by 1 each time, the current number of employeeIDs adds itself to itself, then adds 1, giving a non-sequential number (i.e. an employeeID of 75 will add itself to 75 + 1 to get a new employeeID of 151).
The following code is what I have done in terms of incrementing. (More coding has been done, but it is not used to increment, so I have omitted it.
public class Employee
{
// instance variables
private String firstName;
private String lastName;
private int employeeID;
static int newEmployeeID = 0;
[Code] ....
public Map<Integer , String> Timeinterval(int value) {
int i = 1440/value ;
Map<Integer, String> timeInt = new HashMap<Integer, String>() ;
DateTimeFormatter formatter = null ;
for(int a=0 ; a< i ; a++) {
[Code] .....
The argument value gets it value from jsp at rumtime
The moment the control reaches at :- formatter = DateTimeFormat.forPattern("HH:mm");
it could not go beyond this . I executed this part
DateTimeFormat.forPattern("HH:mm"); by pressing cntrl+shift+I
and got this message :- could not resolve type: org.joda.time.format.DateTimeFormat
Basically what I want to do is increment time for eg: if time is 09:00 and I want to increment it by 30 then it should become 09:30 and this goes on till the time loop condition is satisfied, when i researched on net, I found out that Joda library is easirer to work with for such tasks.
I am trying to understand the following code.This return statement should actually return the char at myArray[index] first, then increments the index afterwords correct?
Public char next(){
return myArray[index++];
}
I have been trying to implement a alphanumeric security code in JAVA. Here are my specifications:
1) Numbers and letters
2) There is user input
3) In the format of NNN-LL-NNNN where N=Numbers and L=UPPERCASE letters
4) If it is incorrect print out INVALID CODE
5) If it is correct print out VALID CODE
Here is what I have produced so far...
import java.util.*;
import java.io.*;
//Class Declaration
class WorkingWithStrings
{
//Main Method
public static void main(String[] args)
{
//Takes input from user
[Code]...
I have taking the approach of invoking a separate method that will check the validity of the security code. However I am having an issue with creating a statement that checks if the middle two characters of the security code are capital letters. This could possibly tie in with my understanding of strings.
I have a header in file like below:
EMP_ID|EMP_NAME|DEPARTMENT|SALARY|ACTIVE1
passed to a string
String test = "EMP_ID|EMP_NAME|DEPARTMENT|SALARY|ACTIVE1";
I have to check if the header has only alphanumeric and pipedelimiter is allowed.
Other than these i need to raise an error.
How can I write a method that takes a string with duplicates letters and returns the same string which does not contain duplicates. For example, if you pass it radar, it will return rad. Also i would like to know how can I Write a method that takes as parameters the secret word and the good guesses and returns a string that is the secretword but has dashes in the places where the player has not yet guessed that letter. For example, if the secret word is radar and the player has already guessed the good guesses letters r and d, the method will return r-d-r.
View Replies View RelatedI am currently trying to make a calculator in Java. I want to use the String split method to tokenize the string of characters inputted. I thought I was using the String split method wrongly, because I had surrounded the characters I wanted to delimit with square brackets. However, when I removed the square brackets, the code threw an exception when I pressed the equal button. The exception was a PatternSyntaxException exception. Am I using the String split method wrongly? And why is the exception thrown? Here is my code:
import javax.swing.*;//import the packages needed for gui
import java.awt.*;
import java.awt.event.*;
import java.util.Arrays;
import java.util.List;
import static java.lang.Math.*;
public class CalculatorCopy {
public static void main(String[] args) {
[Code] .....
i am trying to write a class method which will take in a string and returns a string which is the reversed version of that string. it compiles fine but when i try to run it it states Main method not found in class StringReverse,please define the main method as public static void main(String[]args). I am new to java and cannot figure out
import javax.swing.JOptionPane;
public class StringReverse {
public String reverseString(String str){
JOptionPane.showInputDialog(null,"Please enter word");
char c = str.charAt(str.length()-1);
if(str.length() == 1) return Character.toString(c);
return c + reverseString(str.substring(0,str.length()-1));}}
I'm having trouble with the last few lines of the code. It's supposed to take a replacement string entered by the user and print out the new string. For some reason it's now allowing me to enter a replacement string
import java.util.Scanner;
public class Project02 {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter a long string: ");
String lString = keyboard.nextLine();
[Code] ....
Output:
Enter a long string: the quick brown fox jumped over the lazy dog
Enter a substring: jumped
Length of your string: 44
Length of your substring: 6
Starting position of your substring in string: 20
String before your substring: the quick brown fox
String after your substring: over the lazy dog
Enter a position between 0 and 43: 18
The character at position 18 is x
Enter a replacement string: Your new string is: the quick brown fox over the lazy dog <------ isn't taking user input
I have a method for a button so when a user inputs something it then will get the string value and check it against the string value within the properties file to see if it exists.
The properties file is called GitCommands.properties that contains -- > key = value <-- in it
I realised I have not used it correctly hence why I keep getting errors - I am lost on how to use it, I think perhaps that may be the issue here? I need to reference the file but I am doing it wrong? When I do use that piece of code I get null pointer exception too...
textFieldSearch.getText().equals(GitCommands.keys());
This is my button:
JButton btnSearch = new JButton("Search");
btnSearch.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
FindSelectedKey();
[code] .....
I understand I am missing my piece of code where it states "//determine whether the string is equal to the property file key string" I understand the logic fine but not actually coding it.
I am trying to split a string based on length(example length 5) of the string. But I am having a issues with this substring(start, end) method. I get all substring which are of length 5. But if the last substring is less than 5 then I am not getting that last substring. But I need the last substring even if it is less than 5.
String s = "fjdjfdfjgffgjhfjghfjkhjhjh";
String spLine;
for(int i=0; i<s.length(); i=i+5){
spLine = s.substring(i, (5+i));
}
>
Code a Java method that accepts a String array and a String. The method should return true if the string can be found as an element of the array and false otherwise. Test your method by calling it from the main method which supplies its two parameters (no user input required). Use an array initialiser list to initialise the array you pass. Test thoroughly.
public class test {
public static void main(String[] args) {
Printhelloworld();
String[] verbs = {"go", "do", "some", "homework"};
printArrays(verbs);
[Code] .....
I'm having trouble to compare two string from my LinkedList. I took me 2 days now trying figure out how to compare the current string to previous string in the linkedlist. Here is my code.
public int compareTo(LinkedListNode n){
//Compare two string
String myHead = data.toLowerCase();
String comparableHead = data.toLowerCase();
return (myHead.compareTo(comparableHead));
}
How do I compare a String to each element of a string array?
For example:
int headscount = 0;
if (coins[i].equals("heads")){
headscount++;
System.out.println("b" + headscount);
}
This doesn't give me the right value because the IDE says that equals() is an incompatible type. I also tried changing the "heads" to an variable, but the results remains the same.
I would prefer using an Array!
So I'm creating a class which when given three inputs uses them as sides of a triangle and tells ther user what type of triangle it is, or if the input is invalid, tells them why it is invalid. I'm readin the input as a string and then trying to split it into a string array, from there checking to see if it has 3 elements.. in which the data is good at that point, and then converting them to ints and checking to see if they're negative ansd finally checking to see if they can work as sides of a triangle ie a+b >c, a+c >b , b+c >a.
I'm trying to split it into an array of strings but am getting an error, and can't seem to figure out why as this should be working from what I've read of the string.split method online.
import java.util.*;
public class TriangleTest{
private int sideA;
private int sideB;
private int sideC;
public static void main(String[] args){
TriangleTest triangle = new TriangleTest("3 4 5");
[Code] ....
The output reads [Ljava.lang.String;@15db9742
I've a problem in encoding a URL string.
I know to encode a string we use,
URLEncoder.encode(stringname,"UTF-8");
But when I use this I'm getting an error telling that the encode method will accept only 1 String argument.
I have a string value returned from a background tool that will range from 0 to possibly terabytes as a full number. I want to format that number to use commas and to reduce the character count using an appropriate size modifier (KiB, MiB, GiB, etc). I've tried converting the string number to a Double value using Double.parseDouble() and then performing the math based on the size of the value with this code:
Double dblConversionSize;
String stCinvertedSize;
dblConversionSize = Double.parseDouble(theValue);
if (dblConversionSize > (1024 * 1024 * 1024))
stConvertedSize = String.format("%,.000d", dblConversionSize / 1024 / 1024 / 1024) + " TiB";
...
I've also tried using
String.valueOf(dblConversionSize / 1024 / 1024 / 1024) + " TiB";
However, the formatting is failing and I'm either getting a format exception or the result is displayed as a number with no decimal component.
I have errors in the "if" and both "else if" ... The compiler says "cannot convert from String to boolean and int to String ...
instructions:
1. Add two private instance variables, String courseName and char grade to this class.
2. Add accessor and mutator methods for these instance variables.
3. Add a method register which receives an integer data type and returns String data type according to the argument passed to it ("Math" for 1, "English" for 2, "No course" for any other input)
What I have so far:
package assignment9;
public class BannerUser
{
private int userId;
public int getUserId()
{
return this.userId;
}
public void setUserId(int userId)
[Code] ......
I have the the string value similar to the one which i have to split based on the delimited ","
String SampleString=" 'ab,c', 'xyz', lm,n,o "
I know I can easily call split function which will eventually split the above string. But in my case the delimiter "," , is also a part of the string. If I call the function SampleString.split(',') I will get the output as listed below
ab
c
xyz
lm
n
o
but the expected output is
abc
xyz
lmno
I'm having a hard time with this problem, this is what I have, but I can not use two integers, I have to use one integer and a string...
This is the question:
Write a method called printStrings that accepts a String and a number of repetitions as parameters and prints that String the given number of times. For example, the call:
printStrings("abc", 5);
will print the following output: abcabcabcabcabc
This is what I attempted:
public class printStringsproject {
public static void printStrings(int abc, int number) {
for (int i = 1; i <= number; i++) {
System.out.print("abc");
}
}
public static void main(String[] args) {
printStrings(1, 5);
}
}
What is the difference between string and String (note the case)
View Replies View RelatedAnyways, variable names I have gotten from the code I've gotten from Minecraft using MinecraftCoderPack & Eclipse.
So... I have a string that I am wanting to get a number from.
Example:
public static final String[] exampleLetters = new String[] {"a", "b", "c", "d", "e", "f", "g"};
And, using a public Int (with no variables in the title), I am looking to take numbers for each string letter, to be able to output the value to other code.
Example:
public int letterConversion()
a = 0, b = 1, and so on to g = 6
How would I be able to get the numerical values of each letters using a public Int without any variables in the title?
Actual Code I have right now. Again, please ignore variable names, it's what I got use to while learning.
/** The list of the types of step blocks. */
public static final String[] slabType = new String[] {"stone", "sand", "cobble", "brick", "smoothStoneBrick", "netherBrick", "quartz"};
}
/**This checks slabType for the material and registers a number to each type for other codes to use.*/
public int textureType()
[Code] ....
For what I have now, in the Int...
for ( int var2 = 0 ; var2 < slabType.length ; var2++ )
Is controlling the output. No mater what the 0 is the output...
I'm trying to work out how to get a string from a servlet in to the JSP, The code I thought would work was as follows.
request.getSession().setAttribute("test", "this is a test");
request.getRequestDispatcher("C:myjsp.jsp").forward(request, response);
<%
String s1 = (String) session.getAttribute("test");
%>
<%= s1 %>
This is returning null ...
I have tried a few examples and followed a few tutorials but I keep getting null or nullpointexceptions.
how to have a user input information again if their initial one was incorrect? For example, in this it will have the user go back to select an invoice number within range, but how do you do so if they enter words? I've tried next() and nextLine() but it hasn't worked.
Scanner input = new Scanner(System.in);
System.out.println("What is the invoice number for your purchase?");
invoice = input.nextInt();
System.out.println("What is the sale amount of your purchase?");
amount = input.nextDouble();
while (invoice < 1000 || invoice > 8000) {
System.out.println("You have entered an invalid invoice number.");
System.out.println("Please select a number between 1000 and 8000.");
invoice = input.nextInt();//having trouble knowing how to input this if it were a string.
}