In the following piece of code Iam confused as to where the InputMismatchException in the catch block is thrown on the first place? Is the InputMismatchException thrown automatically with declaring to throw the exception?
import java.util.*;
public class InputMismatchExceptionDemo {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
boolean continueInput = true;
[code]....
There is a method taken from a class with several try and catch blocks. If you think it is possible, add one more catch block to the code to catch all possible exceptions, otherwise say 'Not possible' with your reason.
public String getCountyCode(Address inputAddress) throws AddressNormalizationException
{
String retval = null;
try
{
retval = this.normalizeAddress(inputAddress).getCountyCode( );
}
catch(InvalidAddressException e)
[code]...
Is it a best practice to return from try block or place return statement after try-catch when we intend to return a value from a method(* Catch block is being also used to rethrow the exception)??
View Replies View RelatedRegarding return statements within methods. So I have a method containing try and catch block (as required) and much like when you have an if else statement... I noted you have to return an object for both the try and catch blocks. Now in my case my method should return a List object.
The way I have tried to overcome this:
- I've initialised a List object to null as an attribute of the class I'm working in.
- Therefore in the catch block would just simply return the null List object, where as the try block would return the non-empty List (which is what I want).
- I then just test to see if the List != null, when the method is invoked... and that is that.
However the method always seems to return null (when it shouldn't).
Any way to pass parameter between try/catch block.
In other word:
I have a method:
public void invia(OiStorto invioaca) throws Exception {
Long id=0L;
try {
//some code
for (VElenpere elenpere : elenperes) {
popolaScompiute(anno, inviaEOI0, param, opempiute, elenpere,id);
[Code] ....
And finally the method in which the error can occur (the method poputa is called for every id)
private void poputa(ElOpeIncType opereIncompiute, OpeIncType operaSingola, OiOpera opere) {
try {
//some code
} catch (NullPointerException e) {
e.printStackTrace();
//return id;
}
So method invia call the method popolaScompiute, inside popolaScompiute there is an iteraction through some id and for some id can occur an error; what i want is the getting the value of id in the first method invia, using the block try/catch. Is there a way to accomplish this?
consider this program :
public class hello {
/**
* @param args
*/
public static void main(String[] args) {
int s = new hello().h();
System.out.println(s);
} public int h(){
try{
int g = 10/0;
[Code] .....
the output is 7. how the flow is working. i understand that there is a divide by zero exception after which the control goes to catch. what about the return statement in catch . why is it overridden by finally..........
I came across a code where the exceptions can be thrown from catch and finally block too. I never gave a thought on what scenarios that can be required. Some practical examples when/where it can be required to throw the exception from catch and finally blocks.
View Replies View RelatedI want to use a try catch block, but I am not sure how to fix this problem:
int a;
try{
a = Integer.parseInt(A.getText());
}
catch (Exception e){
Output1.setText("Error");
}
//do someting with a here
The purpose of the try-catch is to catch blank input.The problem with this is that underneath the try - catch I get an error saying that the variable might not have been initialized. I know why this happens. I know I could initialize the varaible before the try - catch, but there is no default or null I can set an int as. If I initialized it as 0, the blank input will no longer be catched.how to make this problem disappear?
import java.io.*;
class Base
{
void get()throws Exception{}
}
class Excep extends Base
[code]....
In above even though exception is handled in catch block still it shows an error?
If I put the highlighted text in try/catch block it is throwing NullPointerException , if I am using command line arguments then also it is showing the same exception.
public static void main(String []args)
args = null;
args[0] = "test";
System.out.println(args[0]);
java 7 feature (Multicatch and final rethrow ).. how to print user defined message in catch block with respect to multiple exceptions in single catch block...
Ex:
}catch (IOException | SQLException ex) {
System.out.println("Exception thrown");
/**
* i want like this, if IOException is thrown then System.out.println("File not Found");
* if SQLException is thrown then System.out.println("DataBase Error");
*/
}
how to do this without using if-else block?
I am writing a code that I want only to accept numbers 1 through 8 and to recognize when it isn't an integer being put in. I tried the following:
Java Code: int classSelect = keyboard.nextInt();
try
{
while( (classSelect<1 || classSelect>8))
[Code]....
Working on chapter 10 of my book which covers exceptions and file I/O. The only part that does not work is line 40 where it is supposed to print getMessage(). It print's null instead of the more verbose error message.
import java.io.*;
import java.util.*;
import java.text.DecimalFormat;
public class SalesReport2
{
public static void main(String[] args)
{
String filename = "SalesData.txt";
int months = 0;
[Code] ....
temp.txt
123.33
asdf
549.85
dsaf
8456.23
21588.22
652.00
My output when using my test file.
ERROR: SalesData.txt does not exist.
Enter another filename: temp.txt
Nonnumeric data found in file: null
The invalid record will be skipped.
Nonnumeric data found in file: null
The invalid record will be skipped.
Number of months: 5
Total Sales: 31,369.63
Average Sales: 6,273.93
I then removed the try catch so that I could get a stacktrace
import java.io.*;
import java.util.*;
import java.text.DecimalFormat;
public class SalesReport2a
{
public static void main(String[] args)
[Code] ...
This was the output.
ERROR: SalesData.txt does not exist.
Enter another filename: temp.txt
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextDouble(Unknown Source)
at SalesReport2a.main(SalesReport2a.java:32)
I also pulled the copy of the code from the CD that came with the book and it's output is the same as my code.
The image in the book shows that the error should be more informative though.
what I get
Nonnumeric data found in file: null
vs
what I should get
Nonnumeric data found in file: For input string: "asdf"
Not sure why it isn't working.
I'm working on an assignment for my java class and I am currently stuck with an error/exception,
Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Scanner.java:864)
at java.util.Scanner.next(Scanner.java:1485)
at java.util.Scanner.nextInt(Scanner.java:2117)
at java.util.Scanner.nextInt(Scanner.java:2076)
at BabyNames.search(BabyNames.java:45)
at BabyNames.main(BabyNames.java:20)
I input my name, which is able to get my name from the names.txt, however after that, it hits an exception and does not go further on.Also please use the names,
JIMMY
JIMMIE
JIMMU
JIMI
(All can be lowered case), because I am unable to upload the full file for it is very big.
import java.util.*;
import java.awt.*;
import java.io.*;
//Jimmy
//Programming Assignment #6: Baby Names
//This program is going to scan a file with data
//about names and their popularity starting from the 1890's
//and will display their popularity over the years in 10 intervals.
[code]...
For this program, I have to run a slot machine. It runs until right before the do while loop and then I receive the error: Exception in thread "main" java.util.InputMismatch.Exception. Searching around, someone said it was a scanner error and adding a call keyboard.nextLine(); fixes the problem- however with that I receive the same error.
Code :
import java.util.Scanner;
import java.util.Random;
import java.io.*;
public class SlotMachineSimulation
{
public static void main(String[] args) throws IOException
{
int number;
[Code] .....
I wrote a program using switchcase.I used do while to show the menu to the user until the user decides to exit the menu.I used try catch to prevent ant exception and it worked properly.But i got one problem.When exception occurs,desired msg is printed but i am unable to display the menu to the user.So user wont be able to continue after an exception is caused.
View Replies View Relatedclass Arg
{
public void rt()throws Exception
{
System.out.println("hi");
throw new RuntimeException();
}
public static void main(String args[])
[code]...
the way to handle the exception that has been in the catch block{b.rt()} .
public class ThrowException {
public static void main (String[] args) {
var x=prompt("Enter a number between 0 and 10:","");
try {
if (x>10){
throw "Err1";
} else if (x<0){
throw "Err2";
} else if (isNaN(x)){
throw "Err3";
}
}
catch(er){
[code]...
It's telling me where catch(er) is: <identifier> expected..I've watched videos, but no one seems to encounter this error....am I missing a segment of code?
I'm asking if there is a way to pass parameter between try/catch block.
I have a method:
public void invia(OiStorto invioaca) throws Exception {
Long id=0L;
try {
//some code
for (VElenpere elenpere : elenperes) {
[Code] ...
The method called in the for:
private void popolaScompiute(Long anno, InviaEOI inviaEOI0, _4IntegerType param, ElOpeIncType opereIncompiute,
VElencoOpere elencoOpere,Long id) {
try {
//some code
for (OiOpera opere : oiOpere){
[Code] ....
And finally the method in which the error can occur (the method poputa is called for every id)
private void poputa(ElOpeIncType opereIncompiute, OpeIncType operaSingola, OiOpera opere) {
try {
//some code
} catch (NullPointerException e) {
e.printStackTrace();
//return id;
}
So method invia call the method popolaScompiute, inside popolaScompiute there is an iteration through some id and for some id can occur an error; what i want is the getting the value of id in the first method invia, using the block try/catch. Is there a way to accomplish this?
I've been assigned to write a program that will convert binary to decimal that uses the try/catch block. In the program that I have written, I was wondering if it is possible to write an addition catch statement that will present an error if any number other than a 0 or 1 is entered by the user. I have already done this in the binaryToDecimal method, but I am just messing around to see if it is, in fact, possible.
Java Code:
import java.io.IOException;
import java.util.Scanner;
public class BinaryToDecimal {
public static void main(String[] args){
Scanner input = new Scanner(System.in);
[Code] .....
So I'm pretty sure this is correct, as it follows most examples I can find online, but I keep getting an error that my return variable cannot be resolved. The error is on the return conn; statement. It says conn cannot be resolved. If I place it above within the try block it allows it but then I receive an error saying the method getDBConnection must return type Connection.
import java.sql.*;
public Connection getDBConnection() {
try {
Class.forName("org.sqlite.JDBC");
String path = "jdbc:sqlite::resource:project.db";
[Code] .....
I don't want to create this method. Basically I want to connect to the database in the main program, but I do want methods that can access the DB too. But however I place it, it doesn't let me touch any of the DB variables outside of the Try block.
I want to catch the exception in my program is the below way:
class Temp
{
public static void main(String s[])
{
try
{
int x=10/s.length;
System.out.println(x);
[Code] ....
I am expecting my program should give output as "java.lang.ArithmeticException: / by zero" but is giving
Temp.java:11: error: ')' expected
catch (ArithmeticException e | ArrayIndexOutOfBoundsException e)
^
Temp.java:11: error: ';' expected
catch (ArithmeticException e | ArrayIndexOutOfBoundsException e)
^
Temp.java:16: error: 'catch' without 'try'
catch (Exception e)
^
Temp.java:22: error: reached end of file while parsing
}
^
4 error
I have used FileInputStream class but its not working properly to divide the bits into blocks.I will attach the coding
public static void main(String[] args) {
ReadFileExample newclass = new ReadFileExample();
System.out.println("cryptography");
[Code].....
I'm trying to place a try/catch into a Actionlistener that will detect other characters other than alpha.
private class printbuttonHandler implements ActionListener {
public void actionPerformed(ActionEvent e) {
//Object src = namesinput;
//String message = "Insert Message Here";
notesinput.setText("");
JOptionPane.showMessageDialog(null, notesinput, "Receipt",
JOptionPane.PLAIN_MESSAGE);
}
I'm not even sure if I'm trying to place it in the correct area in the code. However I like to perform this prior to the receipt being displayed so if there a issue the user can correct this before the final receipt has been sent .......
Right now we are learning about arrays and using the try/catch. Code below, I am trying to just display information about buildings. The application is good but not with the try and catch statement. I'm trying to just display the message of "please enter a building number" when a user puts a letter instead of a number(InputMismatchException) and then the user would have to put in one of the numbers. But when it runs and i put in a letter, it reads the message, but it always outputs the first building information ...
package username;
import java.util.InputMismatchException;
import java.util.Scanner;
//TallBuildings
public class TallBuildings {
//compare heights of buildings
[Code] .....
I'm doing project in area of "Cryptography and Network security". I'm having a file with binary Unicode (mean file contain Unicode value of corresponding data (text file)), want to divide that as blocks with the size of 144bits.
View Replies View Related