I need to display button based on the condition in xhtml page.
using JSF2 & richface 4.0
<c:forEach items="#{empList}" var="emp">
How to check condition like empList.size > 0 in xhtml?
if list is having value, need to show buttons.
Is it possible to wait for an input for a user and check in the meantime if something else is true?
Now if the server in the meantime says: there is no input needed and tells it the client.
Could the client now somehow change from
input.readLine() to another Method say: quit() ?
I am stuck there because I know the server sends: quit to the client1 but the client2 cannot react because it still waits for an input for the user.
Maybe something with Thread.sleep ?
I am working on eclipse kepler, JSF 2.2 with PrimeFaces 4.0 / Mojarra 2.2 library.
actually there are 2 Problems:
I still get this server message no matter what I do.
(( javax.el.PropertyNotFoundException: /Order.xhtml @28,76 value="#{kk.refugee.id}": Target Unreachable, 'refugee' returned null))
and if I delete the input text puls the hidden, the message keeps pop up for 'material' selectOneMenu. -
I have no chance to examin : ((is this javascript code correct, to copy the value of one component to the other.)) these are my xhtml file and java calsses.
**kk.java**
-----------
package khldqr.beans;
import javax.faces.bean.ManagedBean;
import javax.faces.bean.SessionScoped;
@SessionScoped
@ManagedBean
public class kk {
[code]....
My code of start.xhtml is:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html lang="en"
xmlns="http://www.w3.org/1999/xhtml"
xmlns:h="http://xmlns.jcp.org/jsf/html"
xmlns:f="http://xmlns.jcp.org/jsf/core">
[Code] .....
when I deploy the app(glassfish) I get this message only:
hi #{user.minimum} a #{user.maximum} .
Instead of a picture: wave.med.gif and message:
hi 0 a 10 .
file hierarchy is attached
In my Icefaces 3 application I have a ManagedBean ancestor that defines common attributes to those they spread it. Including CSS styles to be apply at the menu as icons depending on whether they are selected or not. Classes that extend the CommonMBean class define styles. My question is what do I have to put in the language experssion styleClass to tell him that the getter to use is that of the parent class.
CommonMBean.java
package com.omb.view;
public class CommonMBean
private String menu1Css = "";
private String menu2Css = "";
[code]....
I want do do something like this:
Define custom facelets tag in xhtml file:
myDatatable.xhtml
<?xml version='1.0' encoding='UTF-8' ?>
<!DOCTYPE composition PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<ui:composition xmlns="http://www.w3.org/1999/xhtml"
xmlns:ui="http://java.sun.com/jsf/facelets"
[Code] ....
And I want to use my tag like this: (name of tag in definition is myDatatable) and it was defined on page as customTag
page using my myDatatable tag
<customTag:myDatatable datamodel="#{userListDataModel}">
<p:column>
<f:facet name="header">
[Code] ....
My question is what can I put into !!!???!!! line of my custom tag to process/rendered body of my customTag:myDatatable
I have 2 JSF applications - Let me say A and B.
Application A uses JSP and Application B uses XHTML.
Now, I want Application B also get the same look and feel as Application A.
For this purpose, I have to recode the complete JSP page (of Application A) into XHTML (in Application B).
My question: Is there any better way, like reusing all the content of JSP in XHTML or something like that.
Could I replace the existing XHTML content with the JSP content with some minor modifications?
I am new to JSF and when i try to implement a sample application im getting this wierd error of page not found(.xhtml). Here is the code i have created..
Bean class :
package com.trail.beans;
import javax.faces.bean.ManagedBean;
import javax.faces.bean.SessionScoped;
@ManagedBean
@SessionScoped
public class UserLoginBean {
[Code] .....
These are the jars ive used :
commons-logging 1.1.1
myfaces-api 2.0.7
myfaces-impl 2.0.7
If I had this code:
<h:dataTable value="#{customer.customerList}" var="c"
styleClass="order-table"
headerClass="order-table-header"
rowClasses="order-table-odd-row,order-table-even-row"
>
And in the server getCustomerList() accessed to database, how many times getCustomerList() would be called from I request the xhtml page?. I have read this would be called several times because of JSF internals and It would be better to store it in a variable and access this variable.
1. Is this true this would be called several times? why?
2. If the previous statement was true, how to avoid it, I mean not call the method from a service?
My project consists of a web app where a user can select a area from a picture and f.e. if it is a office layout he can input the worker name and any peace of hardware that the area might have. In this case there are two categories: Hardware and Computer. Hardware - it has 5 dropdown lists consisting of printer, scanner and etc. Computer - like Hardware consists of many dropdown lists which add up to components such as processor, motherboard and etc. For me, considering this is my first ever web app project, is a huge step towards web development, I have used various mixes of Java, javascript and primefaces code.
My current problem: When a user selects an area he gets a dialog box where he is prompted to select his desired input, afterwards the user clicks the 'save' button and get's another dialogbox which has a resume of what he has selected so he could check out his input and save it by clicking the 'save' button in the resume box. My problem is that when the user clicks the save button the button calls a method which takes all the input and creates an Area object (Area object consists of various objects such as: Coordinates, Dimensions, Employee, ComputerList and HardwareList) and sends a query to the database, but all the values I get is null.
XHTML code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:p="http://primefaces.org/ui">
[Code] ....
In order to create an xhtml view:
1. All jsf tags like datatable, form, etc.. will generate UIComponents in server side, right?
2. All non JSF tags will not generate UIComponents in server side, right?
3. If you want something in a view that will be the same across users and requests, I mean, It will not change like a label tag, it doesn't make any sense to create it with a JSF tag in order to save memory in server side, right?
For an assignment
-I am too write a program that checks if 3 numbers (scannerinputted) are three sides of a triangle if not just ignore it.
-If they are the 3 sides to a triangle tell what kinda triangle it is Right/scalene/equilateral etc.
-ignore the 3 numbers if they are <=0
if(side1+side2>side3 && side1+side3>side2 && side2+side3>side1)
System.out.println("This is a Triangle.");
else
System.out.println("Not a Triangle.");
How can I make the program stop immediately if the else statement is checked. I have more "if statements afterward.
so it would say.
"This not a triangle"
"This is scalene or isosceles"
how can I get this output.
"This is not a triangle" and stop there.
I m trying to simplify an if condition as much as possible and i m curious if it can be made more short then i managed to .The problem is simple , a integer number with 3 digits is generated and the user is asked to input another 3 digits integer number ... One of the conditions that need to be verified is if all the digits in each number match but not exactly ( aka 123 and 132 ) .Using only an if statement to verify this what is the most short condition that can be checked to identify when the digits in a 3 digits number match the digits of another 3 digits integer number (not interested if they match exactly) .
The simplest condition i managed to find is :
else if (guessDigit1 + guessDigit2 + guessDigit3
== lotteryDigit1 + lotteryDigit2 + lotteryDigit3
&& (guessDigit1 == lotteryDigit1 || guessDigit1
== lotteryDigit2 || guessDigit1 == lotteryDigit3)
&& (guessDigit2 == lotteryDigit1 || guessDigit2
== lotteryDigit2 || guessDigit2 == lotteryDigit3)) {
System.out.println("Match all digits: you win $3,000");}
Is there a better(shorter ) condition that can be used ?
[public static void PrintNum () {
int i;
int j = 0;
for (i =100; j<5; i=i)j=100-(i-=1);
System.out.println(i);
} ]
I'm not following how it calculated to 95 since I'm confused with this
part i=i)j = 100-(i-=1);
public int getIndexOfAMonster(String nameToGet){
int retValue = -1; //default is not found
for (int i = 0; i <= numberOfMonsters - 1; i++)
if (monsters[i].getName().equals(nameToGet))
retValue = i;
return retValue;
}
1.What does the if-condition do?If the name of a monster in the array is equal to the name stored in the variable, return the monster's assigned value.
2.What does the for loop do? The loop condition simply loops through the whole arraylists. (In other words, it simply checks each Monster contained in the lists).
3.Assuming that the driver code compiles, explain what it’s use is? If the name of the monster is the same as the variable passed unto this method, return the number assigned to that Monster.
I'm working on a problem that requires me to generator all possible word combinations based on a 7-digit number as input. Many of the generated "words" will be nonsense, but some with be "NEWCARS", "TAKEOUT", etc... This problem mimics the phone number a company would use to support clients remember that number.
I completed the exercise, but I would like to explore more elegant solutions. Specifically, I've used an IF-THEN-ELSE condition inside of a FOR loop. Here is my working code:
package com.johnny_v.exercises.telephone;
public class WordGenerator {
public static void main(String[] args) {
int numOfTimes = 2187;
String two = "ABC";
String three = "DEF";
String four = "GHI";
[code].....
I receive StringIndexOutOfBoundsException exceptions. I it's because multiple conditions are matched. For example, the indexSix is reset to 0 when row is a multiple of 9. Because row is also a multiple of 3, this condition also executes and then increments "indexSix".
Is there a different logic in Java for if statements when it comes to conditions? I mean my attempt to compare a String variable and a String attribute of a class that is on an array of objects was frustrated someway. It will not enter the if block. The two strings are equal. I displayed the values of each strings before the if evaluation and they are equal. The simbol I used was the ==, and I also tried the string.equals(string variable) as well as the compareTo() == 0 option but none of those worked. I wish I knew what it is the way to compare two strings.
View Replies View RelatedHow can we create deadlock condition on our servlet? Does calling doGet() from doPost() and vice versa really cause a deadlock? Or, does it cause a StackOverflowException?
View Replies View RelatedI am using what is known as a Depth First Search to solve a maze using my own Stack created class for an assignment. The reason I believe I am getting this error is because my program is never meeting the `finishSpot` condition. I have used the debugger and it looks like it is infinitely stuck at the Point before the `finishSpot`. My logic seems to be mostly correct except until the point where my maze solver tries to finish the maze, so i just need meeting that last condition that is causing my program to crash.
This is a sample maze:
*****
*s* *
* * *
* f*
*****
Here is my Main which uses my created Stack class.
//Creates a Stack and determines the start and endpoints.
public static void solveDFS( char [][] maze ){
LinkedStack stack = new LinkedStack();
Point currentSpot = findPoint( maze,'s' );
Point finishSpot = findPoint( maze, 'f' );
findPath( maze,currentSpot, finishSpot,stack );
[Code] ....
I made a mistake it says my program is crashing which it is not, but simply not meeting the condition.
how to translate it into Java language due to lack of experience (2 weeks). My solution I've formed in my head is: create a new array for the numbers that are in improvement and then declare a "max" variable. Check which array's length is higher and print that length. What I don't know to do is: I don't know how to create a new array for each numbers that are passing through the condition.
Note: I couldn't find anything on internet about my problem so that's why I'm here.
My code is this one:
class MyClass {
static int progresie=0;
public static void longest_improvement(Integer[] grades) {
for(int i=0;i<grades.length-1;i++){
if(grades[i]<=grades[i+1]){
progresie ++;
}
}
System.out.println(progresie);
}
}
How can I validate the postal code based on this condition...
9999 may not be used for US province .
If the street province is Mexico or Argentina or Brazil the street postal code must be 9999 ....
In my program one of the panel has a background image and I need that background image to be updated/refresh or changed whenever the panel reaches certain number of clicks
here's the code
Constructor/gui
import java.awt.*;
import javax.swing.*;
import javax.swing.text.*;;
public class demo {
JFrame frame = new JFrame ("Idle Game Test!");
JPanel backGroundPanel = new JPanel ();
[code].....
also is there other way to access those static variables? the way i implemented them works but i do think there are other ways that are more suitable or better but i cant figure out.
As per my knowledge, the instance of operator compiles only if the reference type compared to class type are in the same inheritance tree. According to that, below code should not compile but it compiles FINE!!.
Output:No output generated since the if condition fails
public class InstanceOfTest implements Inter{
public static void main(String arg[]){
Inter iot = new InstanceOfTest();
if(iot instanceof Someone) //here Inter(interface) and Someone(class) are not in the same inheritance tree.
System.out.println("iot is a Someone");
}
}
interface Inter{}
class Someone{}
I have a java application which uses Google Maps to analyze the traffic condition. But sometimes it can be run and work properly, sometimes not. On some computers on which there is installed java, the program can be run, and on some, again with installed java (jre), exactly the same version, the program can not be run. For example the application first run well on my desktop computer, connected in a LAN, and then stopped working well when run. But when I use laptop which uses the WiFi and run the same computer using VMWare, if I connect to the desktop on which the program can not be run, on the laptop the same program can be run well, in the same room, but using the Wifi.
View Replies View RelatedI am trying to create a program that first asks the user for an input in the form: condition = value, where condition is a word from the set {limit, deficient, abundant, perfect, prime}, and value is a positive integer. Then it verifies the input. If the input is invalid it prints a message indicating that and terminates. If the input is valid it prints a table with the number of abundant, deficient, perfect and prime numbers less than or equal to N, where N = 1, 2, 3, ..., limit.
My problem is with the input validation. i want it to read the value as a string and verify if it's integer.
Here is my code
import java.util.Scanner;
public class Factors
{
public static void main (String[] args)
{
Scanner scan = new Scanner(System.in);
int n, f, fsum, p=0, a=0, d=0,pe=0,limit=0,abundant=0, deficient=0;
System.out.print("Enter stoping condition (condition = value): ");
String cond = scan.next();
[Code] ....
The Program prompts the user to enter the number of products in the product catalog. The program should then prompt the user for the name and the price of each product in the product catalog. Once all of the products have been entered, the program should output the product information (name and price) of the most expensive product in the catalog. Your solution to keep track of the product with the highest price.
import java.util.Scanner;
public class ProductTester {
private static final String price = null;
public static void main(String[] args) {
Scanner console = new Scanner(System.in);
System.out.print("Enter the number of Products: ");
int count = console.nextInt();
[Code] ....