JSF :: PF Not Displaying Value For Password Type Input?
Mar 10, 2015
I am trying to get through JSF /PF tag for h:inputSecret but its not taking or displaying value. Please see the code snippet below
demo.xhtml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:h="http://java.sun.com/jsf/html"
[code]....
I am using JSF 2.2.
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Aug 14, 2014
class Passenger{
String name;
int age;
char gender;
int weight;
public Passenger(){
[Code] ....
This is showing error.....error it gives isthat it cannot change from string type to passenger type......... How to do it??????
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Jul 21, 2014
This is the java code that I wrote for a password:
// java application that asks the user to enter a password
import java.util.Scanner; //program uses class scanner
public class password{
//main method used to execute java application
public static void main(String args[]){
//create scanner to obtain input from command window
[Code] ....
here is the output of the code when I run it :
entered the passwordreason
Try againPress any key to continue . . .
The code compiles without errors. The problem is when , I entered the actually password that I declared in my code, it doesn't output "You entered the correct password" but it instead outputs "Try again", which is supposed to be the output if you've entered the incorrect password. What did I do wrong?
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Dec 3, 2014
My homework is asking me to write a program that prompts the user to enter a password and displays "valid password" if the rule is followed or "invalid password"
Sample
enter a string for password: wewewx
valid password
It's being graded on
Design of my GUI
Dialog box
User friendliness
Creativity
My current issues with the current code I have written is simply the password doesn't work unless it starts with 2 digits, the other order it displays as wrong. and I have no idea how to add a GUI.
import java.util.*;
import java.lang.String;
import java.lang.Character;
[code]....
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Oct 21, 2014
I'm trying to get data from a GUI input window into an ArrayList and back out via a JTable. I can get the array lists to print to the console within the input class, but I need to wire it to a data container and out through a different class. Here is code from one input class, and its corresponding output class:
Input:
public class AddClassroom extends JFrame implements java.awt.event.ActionListener {
// UI components
// are declared here...
[code]....
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Sep 13, 2014
I'm working a an assignment for my IT/215 class and I'm having a little trouble with my arrays. My code compiles just fine but when it comes to displaying the information I've input into my array it doesn't seem to want to and I'm not sure what I'm doing wrong here. On line 136 originally I had [DVDs [count] = count+1]] but it wouldn't compile. I then put line 136 to [ DVDs[count] = new Inventory();] and I think that's were my issue is but I'm not sure....
// Purpose:the purpose of this software is to display inputs as wells as the stocks and price of inputs.
class Inventory
{
private double ItemNumber; //to store Item number
private String ItemName; //to store Item name
private double UnitsInStock; //to store number of units in stock
private double UnitPrice; //to store Unit price
private double InventoryValue; //to store Inventory value
private double TotalInventory; //to store Total Inventory value
[Code] .....
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Nov 16, 2014
I have a Homework that's on Polymorphism and inheritance. The problem is of a triangle class. The super class is GeometricObject and the subclass Triangle. I have the parent and child classes compiling, now it's the test program.
The problem is the examples in the book don't show anything about prompting input for objects. The objects in the Triangle class are: side1, side2, and side3 and so I created objects in the test: Triangle sideOne = new Triangle(); . I've tried to compile but jGrasp doesn't like anything I do and the instructor in my class hasn't shown us examples yet. Can I prompt input for reference type and not just primitive type?
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Apr 4, 2015
username works perfectly, but when I enter password I get this error.
Java Code:
OKbtn.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
if(Usernametxt.getText().equals("Admin") &&
(Passwordfld.getPassword().equals("Admin2"))){
System.out.println("permition granted");
}else{
System.out.println("permition Rejected");
[code]....
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Aug 26, 2014
I am new to JAVA GUI programming and was wondering how you go about getting and testing if a password field text equals something. For example, if the password equals "password" then do something.
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Apr 5, 2014
I have written some error checking code
File name ErrorPage.jsp
<%@ page language="java" isErrorPage="true" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Error</title>
</head>
[code]...
I have put error.jsp and badpage.jsp file in public access folder that is web content in eclipsewhen I am running the code I am status code of 500 and not the errorpage.jsp message .
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Mar 11, 2014
Below code I am using to typecast int to char.
char escapeValue = (char)0;
char cha = (char) 10;
escapeValue = (char)(escapeValue * cha); // Here am getting the above error.
I have 38 similar issues in my workspace.
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Apr 30, 2014
If you have final int i = 1;
short s = 1;
switch(s) {
case i: System.out.println(i);
}
it runs fine. Note that the switch expression is of type short (2 bytes) and the case constant is of type int (4 bytes).My question is: Is the type irrelevant as long as the value is within the boundaries of the type of the switch expression?I have the feeling that this is true since:
byte b = 127;
final int i = 127;
switch(b) {
case i: System.out.println(i);
}
This runs fine again, but if I change the literal assigned to i to 128, which is out of range for type byte, then the compiler complains.Is it true that in the first example the short variable and in the second example the byte variable (the switch expressions) are first implicitly converted to an int and then compared with the case constants?
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Apr 22, 2014
Got a problem with generics, which I'm still pretty new at. Here's a program that compiles fine:
import java.util.ArrayList;
import javax.swing.JComponent;
public class Experiments {
public static void main(String[] args) {
ListHolder holder = new ListHolder();
[Code] ....
It's useless, but it compiles. If I change Line 14, however, to add a generic type parameter to the ListHolder class, Line 10 no longer compiles:
import java.util.ArrayList;
import javax.swing.JComponent;
public class Experiments {
public static void main(String[] args) {
ListHolder holder = new ListHolder();
[Code] ....
I get this error:
Uncompilable source code - incompatible types: java.lang.Object cannot be converted to javax.swing.JComponent
at experiments.Experiments.main(Experiments.java:10)
Apparently, the introduction of the type parameter leaves the compiler thinking that aList is of type Object. I can cast it, like this:
JComponent c = ((ArrayList<JComponent>)holder.aList).iterator().next();
That makes the compiler happy, but why is it necessary? How does adding the (unused) type parameter to the ListHolder class end up making the compiler think the aList member of an instance of ListHolder is of type Object?
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Mar 22, 2015
I have a String repersentaion of some Object.I want that object convert back into some class type how can I do this?
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Dec 4, 2014
I'm trying to parse and compare the content of a zip file. However I'm stuck at what SHOULD be a very simple problem, however I can't seem to find a solution. I have done the following:
ZipInputStream zin1 = new ZipInputStream(fin);
ZipEntry ze1 = null;
fin2 = new FileInputStream(fileName2);
ZipInputStream zin2 = new ZipInputStream(fin2);
ZipEntry ze2 = null;
//fin.close();
ze1 = zin1.getNextEntry();
ze2 = zin2.getNextEntry();
Which gives me the first entry of each zipfile as a ZipEntry type object. I have tried getting the path of the file (inside the zip file) and using this to create a File type object. This does not seem to work though I get:
Exception in thread "main" java.io.FileNotFoundException: My DocumentsmetadatacoreProperties.xml (The system cannot find the file specified)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileReader.<init>(Unknown Source)
And this is because I get a null return from trying to create the File file1 = new File(correctLocation);
I guess I cannot access the file inside a zip file this way. So my question is how can I make a ZipEntry type object into a File type object?
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Dec 30, 2014
The objective of the code is to add new records based on existing records with a partial change to the key. I'm getting "type of the expression must be an array type but it resolved to DstidArray" on dsTidRecTbl[i]
String stMajor = request.getParameter("stMajorVersion");
String stMinor = request.getParameter("stMinorVersion");
String stPatch = request.getParameter("stPatchVersion");
StringBuffer stKeySB = new StringBuffer(stMajor+stMinor+stPatch);
String stKey = new String(stKeySB.toString());
DstidArray dsTidRecTbl = new DstidArray(stKey);
request.setAttribute("dsTidRecTbl", dsTidRecTbl);
[code]....
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Sep 3, 2007
method passing null to the called function, compiler would take that parmer as what type of paramer???
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Oct 12, 2014
Why, when I write a right password and nickname, program says that is wrong?
public class Password {
private static String password = "1234";
private static String nick = "artem";
public static void main (String args[]){
JFrame frame = new JFrame("Password");
JPanel pan = new JPanel();
JLabel lab = new JLabel("Password");
JLabel lb1 = new JLabel("Nickname");
[code]....
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Apr 21, 2014
I want to validate username and password in JavaScript. I want to validate username and password with database values. If login failed i want to display alert message...ok. But problem is that i have index.jsp page. After clicking login button control goes to homepage.
jsp..okk.. in index.jsp I have taken dropdown to show designation. I select design then control goes to respective homepage... in homepage. I am checking username and password with database values. If login successful it goes to respective pages but if login failed it has to show me alert message. How can i do that ?
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Nov 12, 2014
i need to develop a java program in which it will ask the user "Username" and "Password" and by which it will login to a wesite.
I have developed a GUI in which the username should be entered in the User "JTextfield" and Password in Password "JPasswordField". I need to make sure that password should not be displayed in the GUI. but I didnt find a way to parse the string (char) entered in the "JPasswordField" to the website.
It is always passing a 'null' character! I tried to search in internet and i found that it wont be able to pass the passwordfield characters but you will be able to check in the main function itself by comparing with another char array in the main program itself whether the password entered is correct or not.
Is there any alternate way for this?
Objective : Parse the password (which is not displayed in the GUI) to a website or some other function where it will use it
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Jan 21, 2014
I Have one query regarding OTP, In my project while registration the otp should be generate and send to the mobile number of user which is registered the form.
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Dec 4, 2014
I have a question but dont know how I could verify the criterias..
The password should be at least six characters long
The password should contain at least one uppercase and at least one lowercase letter
The password should have at least on digit
Write a class that verifies that a password meets the stated criteria. Demonstrate the class in a program that allows the user to enter a password and then displays a message indicating whether it is valid or not.
I have not created a class because I really have no clue what to write in this case. My main method is:
import java.util.Scanner; // Needed for the Scanner class
public class Password {
public static void main(String[] args) {
// Create a Scanner object to read input.
Scanner keyboard = new Scanner(System.in);
String input;// To hold the input
[Code] .....
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Mar 4, 2014
It had no syntax error but if there would be any other error or if i would receive a wrong result
import java.util.*;
class tester {
public static void test() {
Scanner input=new Scanner(System.in);
int size= 0;
System.out.println("Enter your password:");
String enter=input.next();
size = enter.length();
[Code] .....
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Oct 26, 2014
When I enter the wrong password, it says I have successfully logged in.
import javax.swing.JOptionPane;
public class P2H
{
public static void main (String[] args) {
System.out.println("LOGIN");
String usernameStr=JOptionPane.showInputDialog("Enter Username");
[Code] ....
Also I have to limit password attempts to 3. How would I go about that?
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Sep 1, 2014
i have this source code...
import java.util.Scanner;
//I had to use scanner in this program because I had to create objects that were in the Scanner class, such as in row 16.
* This program confirms a password typed into a *
* console window *
*/
public class Homework1 {
public static void main(String[] args) {
//Needs to add a scanner to the program to continue on
Scanner keyboard = new Scanner(System.in);
[code]....
Now I need to create a second version of this program that uses JOptionPane to get the inputs from the user and show the output!
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Aug 30, 2014
Use Java to write and run a simple console-window program for checking passwords. The program must satisfy the following requirements:
-When the program runs, it should first print its name, e.g., Password Checker
-The program should next prompt the user to enter a username, e.g.,
Please enter your username:
-The program should next prompt the user to enter a password, e.g., Please enter your password:
- If the user enters a correct password, i.e., one that matches an internal secret password, the program responds. You are approved by access control!, and quits.
-If the user enters an incorrect password, the program responds
Try again:
-If the user enters a correct password matching the secret one, the program responds. You are approved by access control!, and quits.
-If the user enters an incorrect password, the program responds
package class1;
import java.util.Scanner;
public class class1 {
public static void main(String[] args) {
// TODO Auto-generated method stub
[code]....
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