I used tomahawk t:tree for showing my data in tree structure and displayed that very fine. But my problem is how can we find the node id in bean side when we select one node .Because i want to show some data based on that node.
View RepliesI have some work where I have to create a binary tree. Anyway I am stuck on one of the classes which has several methods I must fill in! The code is below
The headers for each method are: public Node find (member p1)The method find(Member p1) is used to return the node which contains a particular member. It is a private method because the interface to CabinetTree should not provide direct access to the internal nodes. It makes use of the method Node findNode (Member p1, Node current)
and the next method is : Node findNode(Member p1, Node current) which searches the tree from current node to find a node whose value is equal to the Member p1, i.e. a node in the tree such that p1.equals(current.getMember()) is true. If there is no such node then the method should return null.
public class CabinetTree {
private Node head;
CabinetTree(Member p1) {
head = new Node(p1, null);
[Code] ....
I'm trying to write Java code for the following figure. Where, if node:4 will create following separate 4 trees. Number of node in
LEVEL1 (yellow) : n node.
LEVEL2 (green) : n-1 node.
LEVEL3 (blue) : n-2 node.
See image for node:4.
4node.jpg
The example out for node:4 :
012
013
021
023
031
032 and so on.
I have requirement of sorting the files in tree structure with name and timestamp of creation, i am new to swings...
Here we are using FileTreeModel.
Root Folder:
folder1;
file1
file2
.
.
I have a TreeView insight TabPane
treeView.setOnMouseClicked(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent mouseEvent) {
if (mouseEvent.getClickCount() == 2 && mouseEvent.getButton() == MouseButton.PRIMARY) {
// Some action
}
}
});
For some reason when I click on a tab body I can also perform the listener action. How I can add additional statement to perform the action only if I select node?
So in my binary search tree I'm trying to write a method that deletes the idem but for some reason it's not working. I have two things, I have the method and then another piece of code that tests the deletion method. Here's the actual method
public void delete(String word) {
root = deleteItem(root, word);
}
protected TreeNode deleteItem(TreeNode r, String word) {
if (r == null){
return r;
}
if(word.compareTo(r.item.getWord()) < 0){
[Code]...
Here's the test code
message = "Test: deleting 'word' -- ";
t = new BSTRefBased();
try {
t.delete("word");
result = t.getRootItem().getWord().equals(null);
} catch (Exception e) {
result = false;
}
System.out.println(message + (result ? "passed" : "FAILED"));
So for some reason it keeps saying that the test failed. Why does it keep saying that.
I want to develop simple example in which I can select TreeView Nodes with Buttons(in some cases clicking on image and etc). I created this simple sample:
<pre style="" _modifiedtitle="true" jivemacrouid="_14032555963537721" ___default_attr="java" jivemacro="code" class="jive_text_macro jive_macro_code jivemacrouid_14032555963537721">
import javafx.application.Application;
import static javafx.application.Application.launch;
import javafx.geometry.Insets;
[Code] ....
The question is how I can select tree Node when I click on a button. For example when I click on a button Item A1 I want to select tree idem Item A1.
the problem was :
i wrote it on paper with my examples.and just for laughts , i uploaded another picture that dont belong to my problem. its just my way to understand binary search tree implementation , so i wanted so share.just for laught : looks like the map of the universe.
now my problem : why after i changed Current to Current.left, Parent still has the value of root. i draw and wrote it on a paper. to be clear as possible - picture 2 :
I'm trying to use LinkedBinarySearchTree but a lot of the variables are protected in BinaryTreeNode. I am creating a BinaryTreeNode object but it still isn't allowing me to use them. The variables I am trying to use are element, left, and right.
import ch11.exceptions.*;
import ch10.LinkedBinaryTree;
import ch10.BinaryTreeNode;
/**
* LinkedBinarySearchTree implements the BinarySearchTreeADT interface with links.
*/
public class LinkedBinarySearchTree<T> extends LinkedBinaryTree<T>
implements BinarySearchTreeADT<T>
[Code] ....
Im running into some problems with the Java compiler. This is my code:
public class DoublyLinkedList<T> implements SimpleList<T> {
protected Node dummy;
protected int n;
public DoublyLinkedList(){
dummy = new Node();
dummy.next = dummy;
dummy.pre = dummy;
n = 0;
[Code] ....
I want to use a dummy node in my implementation of the Doubly Linked List, so it will be easier to code all the methods I need to write. I keep on getting a problem with line 14 and 15:
dummy.next = dummy;
dummy.pre = dummy;
// cannot find symbol variable next (compiler error)
// cannot find symbol variable pre
I am trying to display two JComboBoxes side by side. I can successfully display them as part of a BorderLayout if they are in the North and East, but when I try to display them side by side in the same area, eg North, only one of the combo boxes gets displayed.
package selectingshapes;
import java.awt.Graphics;
import java.awt.Color;
import javax.swing.JPanel;
import java.awt.Graphics2D;
import java.awt.FlowLayout;
import java.awt.event.ItemEvent;
[Code] .....
I am using the following code: But doesn't work fine. I try to find the Minimum spanning and print it out from house to which hose.
public class MinimumSpanning {
public static void main(String[] args) {
// [][] edge= are price between each hose edgs.
int [][] edge= {{0,7,9,12,0,0,0},
{7,0,0,10,0,0,0},
{10,0,0,12,0,0,0},
{12,10,12,0,11,0,10},
{0,0,0,11,0,4,8},
{0,0,0,0,4,0,6},
{0,0,0,10,8,6,0}};
[code]....
It should only print one time. Example between K to L prints many time.
I'm using SchedulerExecutorServices to Schedule a task. My Question is how can i schedule more than one task side by side:
Here is what I'm doing:
public class Scheduler {
public Scheduler(Runnable thread, int startAfter, int iterateAfter, TimeUnit timeUnit, int length) {
ScheduledExecutorService scheduler = Executors
.newSingleThreadScheduledExecutor();
final ScheduledFuture<?> timeHandle = scheduler.scheduleAtFixedRate(
[Code] ....
I am doing this
@Startup
@Singleton
@ConcurrencyManagement(ConcurrencyManagementType.CONTAINER)
@Lock(LockType.READ)
public class ResourceBean {
[Code] ....
And I call this singleton bean from a stateless session bean like this
@Stateless
public class ClientBean {
@EJB
ResourceBean resource;
public String create(String r)
{
String res=resource.returnString(r);
return res;
}
}
But resource.returnString(r); gives a org.apache.jasper.JasperException: java.lang.NullPointerException I started the glassfish server in debug mode and found out that "resource" was null. but @PostConstruct in singleton does print which means singleton bean exists.
Can we call singleton beans with no interface in such a way form a session bean? I actually want to acquire instance of singleton bean when a client invokes method in Client bean...
I'm new to JSP but I've to use it to grab data coming from an external site, pass data to a Bean, write data in a DB and redirect the user to another page. Follow the JSP page.
<%@page import="EJB.getResponse"%>
<%
long paymentID = Long.parseLong(request.getParameter("paymentid"));
String responsecode = "9999";
getResponse g = new getResponse();
[Code] ....
This is the bean:
@ManagedBean
@RequestScoped
public class getResponse implements Serializable {
private Long paymentId;
private String result;
private String auth;
[Code] ....
On the console I see the prints but I receive the NullPointerException
WARNING: StandardWrapperValve[jsp]: PWC1406: Servlet.service() for servlet jsp threw exception
java.lang.NullPointerException
at EJB.getResponse.printData(getResponse.java:72)
at org.apache.jsp.notify_jsp._jspService(notify_jsp.java from :60)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:111)
[Code] ....
I am trying to align the core/middle side color of a cube, index 4, with the bottom middle color of the same side, index 7. (Each side has values 0-8 where 0 - is the top left corner, 1 is the top mid corner, 2 is the top right corner, 3 is the middle left corner, etc).
In addition to lining up those two colors, I am also making sure that the neighbor color of index 7(the color that it is attached), in this case the bottom color, matches with the top core/middle color. I will attach some pictures and a print out to show what I am talking about...
However, in my code when I am trying to align all of these up together, it does not go into the while loop. Each of the loops essentially is trying to get a match of same color with index 4 and 7, as well as making sure that index 7's neighbor color (the bottom color, in this case) matches with the top color.
Here is what I have tried:
private void alignSideColor(){//make the bottom colors neighbor match with a middle side value and rotate it to the top, for the top cross
if(cube.bottom.square[1].charAt(0) == topColor){
while(cube.front.square[7].charAt(0) != frontColor && cube.bottom.square[1].charAt(0) != topColor){
rotateBottomClockwise(1);
System.out.println("Trying to align side color...");
[Code] .....
The print out of the ELSE IF is:
alignment is: W-G and tops: R-R
NOW ITS ALIGNED
even though the sides, index 4 and 7, are NOT aligned with each other
I have also tried the same thing but with out the 2nd condition in each while loop, and although is DOES enter the while loop, it does not perform correctly -- index 4 and 7 WILL have matches colors, but it does not check to see if index 7's neighbor matches with the top color.
Here is how it prints out
** ** ** G7 B6 Y1 ** ** **//this portion is the back of the cube
** ** ** R6 W5 O4 ** ** **
** ** ** R3 W2 O1 ** ** **
B3 G4 Y9 W9 O8 Y7 W3 B4 G9//this portion is the left, top, and right of the cube
B2 G5 R8 W4 R5 Y6 O2 B5 G8
O7 W8 R9 B7 B8 B9 R1 R4 R7
** ** ** O3 O6 O9 ** ** **//this portion is the front of the cube
** ** ** Y2 Y5 Y8 ** ** **
** ** ** B1 G6 W7 ** ** **
** ** ** Y3 Y4 G1 ** ** **//this portion is the bottom the cube
** ** ** R2 O5 G2 ** ** **
** ** ** W1 W6 G3 ** ** **
Here is the cube showing the top, left and front side
Here is the left and bottom side. As you can see index 4, G5 -- yes that is a 5 lol -- does not have the same color as index 7, W8.
I need to rotate the bottom until W8 is aligned with a middle white value. An examples of a neighbor is: W8-R2
How to do draw the original binary tree based on traversal results?
A binary tree has this pre-order traversal result: A,B,D,H,I,E,F,C,G,K,J (TreeNodes) And the same tree gives the following in-order traversal: B,H,I,D,A,C,F,E,K,G,J. Can you draw the tree structure?
I have tried this example ([URL].../) with CarDao extending the BaseDao, it works like a charm.However, from the CarDao class, my NetBeans underlined the class name “CarDao” with the error message “A session bean must not extend another session bean.” But I can compile, deploy and run the application without any problem.
I have also heard that a session bean cannot extend another session bean, but why it works here?
I am using Java EE 6, NetBeans 8.0.1 and WebLogic 12c for this code testing.
I was making this program and I ran into an issue which is that I cant seem and understand how to get the numbers to go to the other side of the table
I had to make a program that converted 1-9 miles to kilometers and the other side 25-65 (increments of 5) kilometers to miles and thats the part I am having trouble with.
Here is what I have so far
import java.util.Scanner;
public class MilesAndKilos {
public static void main(String[] args) {
int miles;
double kilometers=1.60934;
[Code] ....
and this is how I want it to look
MilesKilometersKilometers Miles
1 1.609 | 25 12.430
2 3.219 | 30 15.538
3 4.828 | 35 # here
4 6.437 | 40 # here
5 8.047 | 45 # here
6 9.656 | 50 # here
7 11.265 | 55 # here
8 12.875 | 60 37.290
9 14.484 | 65 40.398
I want to ask that, when a server listen to A port and it accepts a request from a client then the server accepts the request using accept method,but how does the server get the info about the client like wat is the port no and ip address of the client,I read a answer regarding this that Server never gets the port no of client only the ip address and it connects to client using a connection stream but as far I know from networking, a device must have the ip address and port no of the device it wants to connect to.
View Replies View Relatedin my web.xml the.STATE_SAVING_METHOD setting is server
<context-param>
<param-name>javax.faces.STATE_SAVING_METHOD</param-name>
<param-value>server</param-value>
</context-param>
for measurement of application security isn't not allow to change this parameter to client , so the problem when I access for application and I open a new page via linker for print for example and I would access for my initial page to make change or modify my initial page it s no possible to make any modification because I have a empty bean , but if the state saving is a client I haven't a problem because a tree map is stored in client browser, so my version of JSF is 1.1.1 ,
I have been following a 2d side scroller tutorial in java and have got the basics working, I changed the code a bit to make it so that the tiles and background are always moving, this worked as i intended.Within the character class:
if (speedX < 0) {
centerX += speedX;
}
if (speedX == 0 || speedX < 0) {
bg1.setSpeedX(0);
bg2.setSpeedX(0);
[code]....
I wanted a way to make it so that if the character moves left, the tiles + background move slower. I am having issues with variable scope and setters/getters. Within the main game class, I have the code:
case
KeyEvent.VK_LEFT:
character.moveLeft();
character.setMovingLeft(true);
break;
How can i include an if statement within the tile class that reads whether the character is moving left (determined from a keyPressed event in the main game class) and adjusts the speed of the tiles accordingly?I want to write something to the effect of:
if (setMovingLeft = true){
speedX = bg.getSpeedX() * 3;
tileX = tileX + speedX - 1; << changed from - 4
i am running unix scp command as below using Runtime.getRuntime.exec();
scp -P10022 -i /home/.ssh/id_ds 2937_filename.xls Username@hostname
following is the syntax in java:
final Runtime r=Runtime.getRuntime(0;
final String[] arg={ "/bin/sh","-c",command};
final Process process=r.exec(arg);
i am getting followin error java.io.IOException: cannot run program "/bin/sh: java.io.IOException: error=12, Cannot allocate memory
what i need to update to allocate memory in windows side.
I want to know what is the best way for server side validation in servlets with JSP.
View Replies View RelatedI have a Registration Form in which I am registering user to perform some sort like Entering messages I want to perform some Server Side validation.
Like suppose a user has Enter an Id then as soon as he start entering the Id then I want that this Id should be checked in database that if this Id exists in database or not.
and similar types of validation I want to apply on other fields to.
How can I acheive this?
I am calling a SOAP based webservice using JAX-WS and a client jar. I want to get a request and response somehow and save it for audit purposes. How I can do this?
When I google it, only Handlers come up, but, as far as I understand, it is not applicable on client side.