Is there a way we can open a .chm file stored at server through jsp application without downloading the file and saving it to the local machine.
What I googled is : we cannot download .chm files from a web browser and simply click Open. Download the .chm file to your computer first, right-mouse click it in Windows Explorer and select Properties. Then click Unblock.
But I want my users to simply view the file without downloading it.
i have an older file I was working on 2 months ago and when i try to open it in eclipse I get a message corruption error. I know this is not possible since I was just working on it a while back, and it's the same program version as what i am currently using..Or would I do a file import instead?
i dont know how to write main that would open the input file and read using this method...
[/package AssignmentSeven; import java.io.*; import java.util.Scanner; public class Assignment7 { public static void Towers(int nTowers, int fromTower1, int workTower2, int toTower3) { if(nTowers == 1)
I was just wondering how would I create a jar file that would open 3 other jar files when I open the jar file with my batch file it and when I type stop in the batch file it will out put the stop command into all 3 of the other jar files.
This is for my Minecraft server so I can launch them all at the same time and inStead of having to enter the commands in all the server batch files I just have to do the command in 1 I know their is things like multi craft to do this but I want the code so I don't have to use multicraft.
I am trying to write a java code for a homework problem in my intro java class but im having problems. This is the problem:
Write a program that open the MyFile.txt and read from a file with these criteria.
1)-The program should display the first five lines of the file’s contents only.
2)-If the file contains less than five lines, it should display the file’s entire content. You must check for end of file and less than 6 lines on the loop iterations.
3)- your program should use loop to read the line by line of the file MyFile.txt.
The serperate myfile.txt has this
I can still remember, at the end of that year, we sat for the last time in our circle together. She played us her favorite song, "like a bridge over troubled water" and quietly passed out a gift she had made for each of us.She had made each of us a pottery heart with our name and the date on it on the back each read "I believe in ME".We all cried including her. She told us she would always remember US. We believed she would.
and this is what the code is suppose to look like after you run it : Java33.png
And this is what i have so far : Java22.png
what needs to go next to complete the javascript to show the first 5 lines of the text files?
I have recently taken up some java after a period of time learning batch scripting. the issue I have run into is that my build compiled and ran just
fine when invoking from within the netbeans IDE but after that I 'cleaned and built' the jar and the IDE stored it in the directory that I specified while installing.
I went to that folder, double clicked on my gui and go nothing. So then I opened a command prompt did, "java -jar myapp.jar" and got the following of which has me completely lost:
Exception in thread "AWT-EventQueue-0" javax.persistence.PersistenceException: No Persistence provider for EntityManager named
at javax.persistence.Persistence.createEntityManagerF actory(Persistence.java:85) at javax.persistence.Persistence.createEntityManagerF actory(Persistence.java:54) at my.numberaddition.NumberAdditionUI.initComponents( NumberAdditionUI.java:31) at my.numberaddition.NumberAdditionUI.<init>(NumberAd ditionUI.java:18)
I am currently working on an application with java and I want to do is upload and download details in .xlsx file. Uploading process is successfully worked but the problem is that when I download the file .xlsx with details at opening the file it gives me the following message :
Excel cannot open the file '(filename)'.xlsx' because the file format or file extension is not valid. Verify that the file has not been corrupted and that the file extension matches the format of the file.
I am trying to make a japplet that has open, zoom in and zoom out buttons for pictures. I am not sure how to go about an open button that will read the file. I have the picture url hard coded in the file to open but would like an open button with a file/folder dialogue.
So I am trying to open a file and store the contents into a two dimensional array. I seem to have no problem using this same basic code to read the file and output it. But when I try to change it so that all the data is stored into the array, it does not work.
Java Code:
public void convertFile() { String filePath = ("C:UsersBradDownloadsFB1.csv"); String [][] rowCol = new String [429][6]; try { BufferedReader br = new BufferedReader(new FileReader(filePath)); StringTokenizer st = null; System.out.println("Your file is being converted to an array. This may take several minutes.");
In our currenr project we have a requirement to open a local/network driver file/folder using JSF 2.0 <h:outputLink> in Firefox browser find the below sample code & correct it, how to achieve the above requirment
I'm working on a problem where I have to use the FileInputStream to opens a file that contains the name of a user's favorite book and then displays it.
If the file doesn't exist, then I prompt for the book title and write it to the file using FileOutputStream. This is what I have so far but I'm lost because if I put a file that exists in line 8 then it closes, but if I don't and the user puts their favorite book nothing happens. Or, as far as I can tell nothing does.
import java.io.*; class DisplayBook { public static void main(String[] args)
How to force browser to open/save/save as the file from server instead of browser cache.
I am creating a csv file through a pl/sql procedure and forwarding the link to user once user clicks on link he downloads the file, however if the same thing is repeated then browser returns the old cached file instead of new file generated on server.
how to open a GUI on top of another GUI? I have built a GUI and have a button that when pressed I want to open a new GUI which is another java application within the project, it seems pretty straight forward and I just need to insert 'new [name of application]()'
Button btnEdit = new Button(shell, SWT.NONE); btnEdit.addSelectionListener(new SelectionAdapter() { @Override public void widgetSelected(SelectionEvent e) { new edit(); } }); btnEdit.setBounds(76, 10, 75, 25); btnEdit.setText("Edit");
This taglib will have to be installed on local environment. How is it referred in jsp ? I dont see any code in jsp, which refers to the location of JSTL. So how does jsp invoke these tags ? Is it through classpath ?If its so , how is classpath set for JSTL ? Is it just as classpath is set for java ?
I am new to EJB; I am writing EJB (3.1) program in JBoss 7.1 - I am using MySQL DB with JPA. While executing the program, I am facing the Generic JDBCException: Could not open connection. It is happening only for certain tables in the database; but NOT for all tables. My code is able to access few of the tables in the same database. Here is my full stack trace: -
Exception in thread "main" javax.ejb.EJBException: javax.persistence.PersistenceException: org.hibernate.exception.GenericJDBCException: Could not open connection at org.jboss.as.ejb3.tx.CMTTxInterceptor.handleExceptionInOurTx(CMTTxInterceptor.java:166) at org.jboss.as.ejb3.tx.CMTTxInterceptor.invokeInOurTx(CMTTxInterceptor.java:230) at org.jboss.as.ejb3.tx.CMTTxInterceptor.required(CMTTxInterceptor.java:304) at org.jboss.as.ejb3.tx.CMTTxInterceptor.processInvocation(CMTTxInterceptor.java:190) at org.jboss.invocation.InterceptorContext.proceed(InterceptorContext.java:288)
i am doing a code using JSTL to fire a query. everything come fine except the resule is not sorted as desired. i am putting the code below--
String sort_order=(String)request.getAttribute("sort_order"); request.setAttribute("sort_order",sort_order); <sql:query var="viewQueryj" sql= "select USER_ID, PERMISSION_ID, USER_NAME from administrator order by ?"> <sql:param value="${sort_order}"/> </sql:query>
now the resule is always sorted by USER_ID. if i want to sort it using USER_NAME i pass parameter from controller to this page in sort_oredr variable which comes fine but the result doesn't sort by name, only by id. if i hardcode USER_NAME in query then the result is as desired.
I have a HashMap returned from the server. There are two conditions
1. HashMap returned with only one set of key value pair or
2. HashMap with multiple set of data key value pairs.
Now in UI I have to display either text box or drop down box depending upon the size of map for that I am using length method
Java Code:
<c:choose> <c:when test="${fn:length(myDto.mayMapInDto) eq 1}"> display text box </c:when> <c:otherwise> display drop box </c:otherwise> </c:choose> mh_sh_highlight_all('java');
I can display drop box by looping but not sure how I can get only one element for text box. Tricky is I can't use key value to access since UI don't know what key will be returned.