JSP :: Pass Array From Servlet In Response To JavaScript Call?
Oct 16, 2014
I have an arraylist in my servlet which i need to pass to jsp as a response for a javascript call. This is an arraylist of DTOs. There are 24 DTO objects in the list. The DTO has an int variable and a HashMap. And i need to pass this into the javascript code in my jsp page. Do i use json? Do i send the entire list as a json object or should i iterate through the arraylist (from servlet) and serialize all the DTOs and pass that to the jsp?
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Aug 20, 2014
In my jsp, I have a table with some file paths with this I have to get the file and send it to server. I am able to read the file name, size and file as binary using files of javascript. But after that I need to send those files by storing in a byte array to servlet which I am not able to that. Is there any way I can send that. My requirement is I need to upload those files to server side.
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Dec 12, 2014
I'm trying to pass an integer array,
int[] fibSequence;
From my Fibonacci servlet to a jsp page called "result" but when I pass the array in the redirect I get the following output:
[[I@63cf2179]
I figured out that this is because the array is being converted to string before it is passed over and then converted again on the jsp page.
How I can pass the array over and print the contents, ie an array of integers?
This is how I'm sending the array in the result page:
resp.sendRedirect(("result.jsp?fibSequence=" + fibSequence));
And this is how its being retrieved and printed on the result.jsp page:
<%String[] fibSequence = request.getParameterValues("fibSequence");%>
<input type="text" name="fibNum" value="<%=java.util.Arrays.deepToString(fibSequence)%>" size="40px" style="font-size:30pt;height:60px">
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Jul 29, 2014
I am trying to print the response of servlet as pdf. Below is my codeI am able to generate the response but not quite sure how should I write it to a pdf.
package com.Hardik;
import java.io.*;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.ConnectException;
import javax.net.ssl.HttpsURLConnection;
[Code] .....
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Apr 12, 2014
I work on SSH for creating a external tool to manage remote OS.
I find out the JSch library and i create the java GUI project as jar application, and worked for me very well. (i am working on Netbeans ).
I introduce the JSch library with Netbeans as follow. Right click on the Project-> Properties -> Libraries ->Compile ->Add JAR/Folder.
After that i try to transform the project to applet in order to work it form web server.
I made the transformation in all the code.
When i run the applet through the Netbeans it worked for me. When i build the project to create the jar file.
I create a folder with the my.jar file, index.html, a folder named (lib) which contains the jsch-0.1.50.jar file.
Then try to run the index.html, the GUI appear but cannot connect to the remote with the SSH, and does not give any error.
I think that the problem is that my.jar cannot communicate with the jsch-0.1.50.jar.
Why the project runs trough the Netbeans an does not run when i call it from the next html code.
index.html
Java Code:
<Html>
<Head>
<Title>Java Example</Title>
</Head>
<Body>
This is my page<br>
Below you see an applet<br>
<br>
<Applet Code="AppletUI.class" archive="my.jar" width=600 Height=700>
</Applet>
<Body>
</Body>
</Html> mh_sh_highlight_all('java');
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Dec 21, 2014
I an using a pop out java script and in the notes it says
if later on you want to open / close a specific item you could do it like so:
ExpandingMenu.openItem(3); // toggles item 3 (zero-based indexing)
*/
How to call the function from a button click. I have some button already on my page like so
<li><a href="#">Menu3</a></li>
And from what I have read I should be able to do this:
<li><a href="#" onclick="ExpandingMenu.openItem(3)">Menu3</a></li>
But I don't get any response ..... no error message NOTHING
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Mar 18, 2015
i don't need ordinary javascript alert box. so i was use the jquery modal alert box for different action like success, error etc.but i have problem to call the alert box within servlet.
out.println("<link href="css/jquery.modal.css" type="text/css" rel="stylesheet" />");
out.println("<script type="text/javascript" src="js/jquery-latest.min.js">");
out.println("<script type="text/javascript" src="js/jquery.modal.min.js">");
out.println("<script type="text/javascript" src="js/jscript.js">");
out.println("<script type="text/javascript" src="js/success.js">");
out.println("<script type="text/javascript">");
response.getOutputStream().println("success();");
out.println("</script>");
how to call the modal function in the js file?
otherwise how to show the modal alert box?
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Feb 14, 2014
I am a JSP/Servlet newbie currently adding the first servlets to a web site that had been static all along. My local instance worked great but the servlets did not respond on the test instance. Apparently, my hosting service provider requires me to use an invoker servlet mapping.
<servlet-mapping>
<servlet-name>invoker</servlet-name>
<url-pattern>/servlet/*</url-pattern>
</servlet-mapping>
Adding this to local web.xml broke the application but the servlets respond on test instance (when their calls are not preceded by another servlet call). A Servlet fails when it is called immediately after another servlet has been called.
What I saw happening on test is URL for first call is of the form:
xxx.org/<app-name>/servlet/<servlet-name>?Id=1
And URL for the second call became:
xxx.org/<app-name>/servlet/servlet/<servlet-name>?Id=1
The servlets are invoked using "href=servlet/<servlet-name>?Id="
How can I avoid the inclusion of 'servlet' in the URL and reset the URL to the JSP page it navigates to after processing of the servlet?
P.S.: I am also trying to enable the Invoker servlet on local so I can troubleshoot easier. I went through the changes to Tomcat's web.xml and context.xml. However, my local servlets did not respond even after calling them using "href=<servlet-name>?Id=". Is there a way I can check if my invoker is active?
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Feb 20, 2015
I want to call a servlet variable in jsp page textfields.Actually in servlet I fetch a jasper report properties in servlet variables and then this variable call from jsp page and after changing properties values this report saved.my servlet code is:
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
JasperReport jasperReport=null;
Connection con=null;
JasperDesign jasperDesign=null;
[code].....
so how to fetch servlet variable from jsp page textfields on load page and after edit that values then again save this values in jasper report on save button.
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Oct 14, 2014
I am trying to remotely call one servlet and getting below exception:
java.io.StreamCorruptedException: invalid stream header: 3C21444F
at java.io.ObjectInputStream.readStreamHeader(ObjectInputStream.java:785)
at java.io.ObjectInputStream.<init>(ObjectInputStream.java:282)
at com.deere.isg.dm.web.controller.StatsController.getOtherAdminStatsBeanFromConnectURL2(StatsController.java:224)
at com.deere.isg.dm.web.controller.StatsController.main(StatsController.java:122)
As per my program i am just simply calling this:
URL url = new URL(controllerPath + STATS_PATH);
httpURLConnection = (HttpURLConnection)url.openConnection();
httpURLConnection.setRequestMethod("GET");
httpURLConnection.connect();
inputStream = httpURLConnection.getInputStream();
objectInputStream = new ObjectInputStream(inputStream);
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Jun 9, 2014
A method is declared to take three arguments. A program calls this method and passes only two arguments.Will it take the third argument as
1 null
2 void
3 zero
4 Compilation error
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Aug 3, 2014
So if I assigned values in arrays like the below:
This is the method in main class:
public static void trainer(){
trainer[] trainerArr = new trainer[4];
trainerArr[0] = new trainer("Ben Yap", "Male", "Kuala Lumpur", 10000, "Yoga");
trainerArr[1] = new trainer("Wilson Ting", "Male", "Kuala Lumpur", 10001, "Kick-boxing");
[Code] .....
How can i pass these arrays into another method in the main class?
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Feb 6, 2015
How do I pass the data within an initialized array from inside one method to another method of the same class? Will I need to return the array, assigning it to a temp array, which will then be passed as an argument to the other array? The idea is to create an array for an entire year, and be able to manipulate or edit data for a particular month using the other method.
public class Temperature {
static Scanner input = new Scanner(System.in);
static String [] monthArray = {"January", "February", "March", "April", "May",
"June", "July", "August", "October", "November", "December"};
public static void main(String[] args) {
[Code] .....
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Jan 9, 2014
Is this possible in Java?
public void doSomething(int[4] year){
}
What I am trying to do is to get the person who is using the method to send a year in the format 1998 and so on.
What would be the best way to accomplish this?
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Sep 27, 2014
I have a question about an error I am getting when trying to pass a two dimensional array to a method. I keep getting the "incompatible types, int cannot be converted to int[][]". I am getting the error in a few different place (see comments - at the first call of the method, at a recursive call, and at the return statement. I believe I am passing the same type of array in all cases to the type of array defined in the method parameters.
Below is my code.
// this is a call from the main method
int[][] c = new int[temp1.length][temp1.length];
c = MatrixMultiply(a,b); // this is first place the error occurs
} // end main
public static int MatrixMultiply(int[][] A, int[][] B) {
// throw new UnsupportedOperationException("Not supported yet.");
int a[][] = A;
[Code]....
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May 5, 2015
***** start code ***
public class AddArray {
public static void main(String[] args) {
int sum = 0;
sum = addArray(myarray);
System.out.println(" hello");
System.out.println("This program will create an array then pass the array to an method to be totaled");
int myarray[] = new int [6];
[Code] ....
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Feb 7, 2015
I need to pass user input from the main method, which is then validated using another method that is returned as a valid score, and then I pass the valid input to another method that stores the data in an array. The array is initialized within the method. I tried to use an if-else statement to initialize the array, because I originally did this at the beginning of the method. I soon learned that I was creating a new array everything I accessed the method. Needless to say, this isn't working either.
public static void main(String[] args) {
int judges = 7;
float[] validScores = new float[judges];
for (int i = 0; i < judges; i++) {
float score = -1;
[Code] ....
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Apr 8, 2014
prompts user for the grades of each of the students and saves them an int array called grades. Your program shall check that the grade is between 0 and 100. program should then check if the grade is equal to or greater than 50, where 50 is the pass rate.
A sample output :
Enter the number of students: 3
Enter the grade for student 1: 55
Enter the grade for student 2: 108
Invalid grade, try again...
Enter the grade for student 2: 56
Enter the grade for student 3: 57
The average is 56.0
The maximum is 57
The minimum grade is 55
The number of fails is 0
The number of passes is 3
..
I am quiet stuck on this one.
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Jun 8, 2014
in my progrm there are three diff array of objects...namely garments..gadgets and home app...now one who buys from each of these sections will have to make a bill at last...when he choses to make the bill he will be shown the list of products he bought and their details (like price...brand...etc)...so i thought that while he orders each product(which is done in a previous method called purchase()...)....(each product is stored as an object in there diif arrays namely garments...gadgets ...appliances)....each of those object will be copied in a new array in a diif class...then that array print will give me the desired result...
is this approach correct...?and if its correct then how can i pull out a specific obj frm a stored array of object and then save it in a new array....?
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Mar 6, 2014
I am writing a program to take user input in order to create an array, then call a void method that will read in the numbers (from user's input) and fill the array.This method must use a loop to do this.(The array is to be passed to the void method as a parameter)
in theory, this should change the contents of the array, but without returning a result. Because it is a void method, the array is only passed through the method, not returned; Am I correct?How can I return the array and display it without having to change my method type?
Here is my code:
Java Code: package program7array;
import javax.swing.JOptionPane;
public class Program7Array
public static void main(String[] args) { // main method
int howMany = Integer.parseInt(JOptionPane.showInputDialog(null, // user decides how long array is
"How many numbers are there?"));
double [] numbersArray = new double[howMany]; // creating the array
makeArray(numbersArray, howMany); // calling the array
[code]...
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Aug 18, 2014
I am writing a Bingo program for a class and have reached a roadblock. How do I call 5 numbers from the array and where do I store them so I can populate them back into my JLabels on the Bingo card. I'm sure there are more complicated ways to do this, but I'd like to keep it simple so I actually understand the process. I understand that I will need to shuffle the numbers in the array before choosing them, but I also am not sure how to do that.
int [] BArray = {1,2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15};
for (int index = 0; index > 5; index++) {
}
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May 6, 2014
I need to call the method to remove duplicates form my array, but it won't let me call the method, or I'm doing it incorrectly which is probably it.
import java.util.*;
public class C_6_15_EliminateDuplicates {
public static void main(String[] args) {
int[] numbers = new int[10];
Scanner input = new Scanner(System.in);
System.out.println("Enter " + numbers.length + " numbers: ");
for (int i = 0; i < numbers.length; i++)
[Code] ......
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Nov 28, 2014
trying to get into Java and jump into just programming an idea.I want to go through an array of numbers at a certain pace and call different sounds as it goes through.
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Jan 23, 2013
I am a beginner want to compile servlet with following path
javac -classpath Program FilesApache Software FoundationTomcat 5.5commonlibservlet-api.jar;classes:.-d classes srccomexamplewebBeerSelect.java
Problem arises as follows:
javac: invalid flag: FilesApache
Usage: javac <options> <source files>
use -help for a list of possible options
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Feb 19, 2015
Inspite of not returning anything, what is the purpose of response object in servlet? I have typically used or heard of only response.sendRedirect()
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Oct 5, 2014
@RequestMapping(value = { "/mapping" }, method = RequestMethod.GET)
@ResponseBody
public Map<A, List<B>> getAsByB(HttpServletRequest httpRequest) {
return map;
}
when i try to get it by url i get an error. how can i send a response of a map as a json ?
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