JVM Failed To Initialize

Apr 29, 2014

What's up with this. Just trying to test my hands on java packages, and had this error(by java) after successful compilation:

Error occurred during initialization of VM
java.lang.Error: Properties init: Could not determine current working directory.
at java.lang.System.initProperties(Native Method)
at java.lang.System.initializeSystemClass(System.java :1119)

Main.java

package com.aceix.simplecalc;
import com.aceix.simplecalc.inputhandler.InputHandler;
import com.aceix.simplecalc.mathoperation.MathOperation;
 public class Main {
 public static void main(String[] args) {

[Code] ....

Any suitable way to accept input from console.

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JavaMail - OAuth Connection Failed

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I tried to connect oAuth2 with gmail. In command line, no problem. But with Javamail it failed.

The source of the exemple are here : [URL] ....

Last modified is in 2012 then, maybe, this code is obsolete.

In command line it works fine :

Java Code:

openssl s_client -crlf -connect imap.gmail.com:993
A002 AUTHENTICATE XOAUTH2
+
my_token_who_end_with__
Response : A002 OK myaddress@gmail.com ForName Name authenticated (Success) mh_sh_highlight_all('java');

For information :

- it failed with token and refresh token

- here are the logs :

Java Code:

DEBUG: getProvider() returning javax.mail.Provider[STORE,imap,com.sun.mail.imap.IMAPStore,Oracle]
DEBUG IMAPS: mail.imap.fetchsize: 16384
DEBUG IMAPS: mail.imap.ignorebodystructuresize: false
DEBUG IMAPS: mail.imap.statuscachetimeout: 1000
DEBUG IMAPS: mail.imap.appendbuffersize: -1
DEBUG IMAPS: mail.imap.minidletime: 10

[Code] ...........

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What I'm having trouble with is that I can add the first song fine (song1), but when I try to add another song, the information entered into song1 is gone. I've worked out that this is because every time I call upon the addNewSong() method, I'm creating four Song objects that are brand new with the line:

Song song1 = new Song();
Song song2 = new Song();
Song song3 = new Song();
Song song4 = new Song();

How to fix this problem is where I'm stuck because if I move these lines elsewhere, I get a 'cannot find symbol - variable song1' error.

Here is my code:

public class SongDatabase {
Scanner console = new Scanner(System.in);
public void addNewSong() {
Song song1 = new Song();
Song song2 = new Song();
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[code]....

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</Scanner scan = new Scanner (System.in);/>
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The corresponding line in the xml document is:

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And in the server log there is a long list of comments, the first which looks to be of significance to this issue is:

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There are others further down the list which might also be significant such as:

SEVERE [http-apr-8080-exec-59] org.apache.catalina.core.ContainerBase.addChildInt ernal ContainerBase.addChild: start:
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The corresponding line of code for the first warning that I listed is for the DataSource object and I wrote it as follows:

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I'm pretty sure the issue has something to do with connecting to the database since it ran fine before I added the database related code.

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HTTP Status 500 -

type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

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[code]....

i found that jstl1.1 jar didn't have the above mentioned class.I replaced jstl1.1 with jstl1.2 jar.i verified that jstl1.2 jar had JstlCoreTLV calss.but even after this replacement of jar i am facing the same issue.

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The corresponding line of code for the first warning that I listed is for the DataSource object and I wrote it as follows:

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the issue has something to do with connecting to the database since it ran fine before I added the database related code.

update: my server.xml file is as follows:

<?xml version='1.0' encoding='utf-8'?>
<!--
Licensed to the Apache Software Foundation (ASF) under one or more contributor license agreements. See the NOTICE file distributed with this work for additional information regarding copyright ownership.The ASF licenses this file to You under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at

[code]....

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