Java-8 :: Lambda Expression Throws IllegalAccessError

Oct 16, 2014

I have the following structure and want to use lambda expressions with it, but an exception occurs:
 
class SuperClass // (package private)
public class SubClass extends SuperClass // in same package as SuperClass
  
I have a functional interface (a listener), which has one argument of type SubClass.
 
public interface MyListener() {
    void myMethod(SubClass e);
}
 
When I use the old-school Java 7 style:
 
addListener(new MyListener() {
     @Override
     public void myMethod(SubClass e) {
         System.out.println(e);
     }
});

Everything works fine! If I use Java 8 lambda expression instead:
 
addListener(e -> {
    System.out.println(e);
});
 
It will throw an exception:
 
java.lang.IllegalAccessError: tried to access class SuperClass

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