Do not want to use loop and Character.isLetter to validation string , not sure at how to using regular expression?
If I want 8 characters string length, the first 3 is letter, the remind character is number ...
^[a-z0-9_-]{8}$
^[a-zA-Z]{3} + [/d]{5} $ ??
I have written below regex for two lines.
String LN1Pattern = "^((?=.{1,35}$)(/([A-Z]{1,5})(|(//[a-zA-Z0-9]+))))$";
System.out.println("/ABC//FGhiJkl012345".matches(LN1Pattern));
String LN2Pattern = "^(|((s+(//[a-zA-Z0-9]{1,33})){1,2}))$";
System.out.println("".matches(LN2Pattern));
s+ is a newline character.
But when I combines both as below, its not giving me expected result.
^(((?=.{1,35}$)(/([A-Z]{1,5})(|(//[a-zA-Z0-9]+))))(|((s+(//[a-zA-Z0-9]{1,33})){1,2})))$
For string "/ABC//FGhiJkl012345
//abCD01EF02" - returns False. Expected is True
I think there is some problem in lookahead placed.
Regular expression which I want to use to split a string. The string could look similar to this:
"a = "Hello World" b = "Some other String" c = "test""
The String is read from a file where the file contents would be:
a = "Hello World" b = "Some other String" c = "test"
After splitting I would like to get the following array:
String[] splitString = new String[] {"a", "=", ""Hello World"", "b", "=", ""Some other String"", "c", "=", ""test""}
I know I could just write a simple text parser to go over the string character by character, but I would rather not do it to keep my code clean and simple. No need to reinvent the wheel.
However, I just cant seem to be able to find the right regular expression for this task. I know that a RE must exist because this can be solved by a finite automaton.
I need a pattern that matches Hello Smith (STL Terminal) (15.0).
View Replies View RelatedI need a regular expression in java for phone number which that does not allow any character special character only numbers should be allowed.. My sample program is
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class c {
public String removeOrReplacePhoneNumber(String input) {
if (null == input)
return input;
[Code] ....
but this is allowing characters like a,b,c..
I need to parse an html web page to extract specific information from the tags in Java. For example,
<b>Species </b> Strain </td>
I need to look for the Strain info (Strain is variable in length) in the page. The whole web page is stored as a huge string. I need a regular expression that can identify all the Species and retrieve their corresponding strain info. how to do this or can propose some clever string manipulation methods in Java.
I am trying to implement an example (Book* : Java SE 7 ..By S G Ganesh) for validating an IP address but it fails to validate a valid IP addresses. I found another example on the internet(**) and it works super fine, no problem at all. I edited the code (the one I got from internet) into the exact format like book and it still works super but i don't understand why the books' example doesn't work though both look exactly the same now ,further more, how can i compare String x and y for equality?
public class TestClass {
void validateIP(String ipStr) {
String one = "((25[0-5]|2[0-4]d|[01]?dd?)(.)){3}(25[0-5]|2[0-4]d|[01]?dd?)"; //copied from internet and edited
String two = "((25[0–5]|2[0–4]d|[01]?dd?)(.)){3}(25[0–5]|2[0–4]d|[01]?dd?)"; // copied from book
String x = "((25[0-5]|2[0-4]d|[01]?dd?)(.))";
String y ="((25[0–5]|2[0–4]d|[01]?dd?)(.))";
[Code] ....
I have a text file that has the following lines:
the boy is smart
He is from Australia
** Highly important line
That's all
Now, I need a regular java expression that would match a line in this file that begins with the ** characters. That is, when I match the text with the regex, I should get only this line :
** Highly important line
How would I write this regex in java?
I have to match pattern like 76XYYXXXX mean x can be 4or 5 and Y can be 6 or 7. All x and y should be same .i.e. 764664444
View Replies View RelatedI am currently enrolled in my first Java class. I have taken C# in the past so I've messed with some regular expressions, but I am having trouble finding a good website for Java. Is the syntax the same?I want to create a regular expression to only allow the following characters: c C f F [and any 1-3 digit number].
View Replies View RelatedI have a string "We have 7 tutorials for Java, 2 tutorials for Javascript and 1 tutorial for Oracle" I need to replace the numbers based on the below condition.
if more then 5, replace with many
if less then 5, replace with a few
if it is 1, replace with "only one"
below is my code, I am missing the equating part to replace the numbers
private static String REGEX="(d+)";
private static String INPUT="We have 7 tutorials for Java, 2 tutorials for Javascript and 1 tutorial for Oracle";
//String pattern= "(.*)(d+)(.*)";
private static String REPLACE = "replace with many";
public static void main(String[] args) {
// Create a Pattern object
[Code]...
I have some problems about performing regular expression. In the following code, the output as a result is being "valid last name". But in my opinion, it should be "invalid last name". Because "Doe" has not any space, apostroph or any hypen. Look at the regular expression statement: "[a-zA-Z]+([ '-][a-zA-Z]+)*"
package deneme;
public class Deneme {
public static void main(String[] args) {
String lastName = "Mc-Something"; // Mc-Something
if(!lastName.matches("[a-zA-Z]+([ '-][a-zA-Z]+)*"))
System.out.println("Invalid last name");
else
System.out.println("Valid last name");
}
}
I know that the asterisk qualifier means character(s) in any number.(Is this wrong?) So for "Mc-Something", 'M' corresponds to [a-zA-Z], 'c' corresponds to +, - corresponds to [ '-], 'S' corresponds to [a-zA-Z], "o" corresponds to +, and finally "mething" corresponds to *, doesn't they? But for "Doe", there is no any space, apostroph or hypen.
I am new to java coding. so, reading the log file using java code.
1) I wish to parse a file, and find a value for variable e.g. [StorageVersion].
2) After finding the value, it will be pushed to database.
Following is the code that i have written till now.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.io.*;
import java.lang.*;
import java.util.*;
import java.util.regex.*;
[code]....
1) I don't know what regular expression can i use.
2) I want a line to check that preceding line should have //StorageVersion .
3) n then i will check any string between := K[' and '];. From above log file "'706146.0.22106932'" is the value that i am looking for.
I have to read a text looking for value related to certain variable. The variable are always DE plus identifier from 1 to 99 or DE plus identifier from 1 to 99 and SF plus identifier from 1 to 99. The value can be alphanumeric. How can I get these values? As a start point, I try to use split("DE") but I can get something that is wrong if there is "DE" inside the text that doesn't me interest. I look for scanner but it doesn't work. I guess that there is some way, maybe using regex but I am completely lost ( I have never used regedix before and I am in rush to fix this).
Basically, the text is similar to the below where DE means data element and sf sub field. Some data elements have sub fields while others don't. I guess that there is a way to split with something like DE+anyNumberFrom1To99 = theValueAimed in some array and DE+anyNumberFrom1To99+,+SF+anyNumberFrom1To99 = theValueAimed in other array.
DE 2, SF 1 = 00 SOME TEXT THAT DOESN'T INTEREST ME
DE 22, SF 1 = 0 SOME TEXT THAT DOESN'T INTEREST ME
DE 22, SF 4 = 1 SOME TEXT THAT DOESN'T INTEREST ME
DE 22, SF 5 = 0 SOME TEXT THAT DOESN'T INTEREST ME
DE 22, SF 6 = 11 SOME TEXT THAT DOESN'T INTEREST ME
DE 22, SF 7 = 90x SOME TEXT THAT DOESN'T INTEREST ME
DE 22, SF 7 = 12ab SOME TEXT THAT DOESN'T INTEREST ME
DE 99 = 1234 SOME TEXT THAT DOESN'T INTEREST ME
I have a header in file like below:
EMP_ID|EMP_NAME|DEPARTMENT|SALARY|ACTIVE1
passed to a string
String test = "EMP_ID|EMP_NAME|DEPARTMENT|SALARY|ACTIVE1";
I have to check if the header has only alphanumeric and pipedelimiter is allowed.
Other than these i need to raise an error.
I am a beginner want to compile servlet with following path
javac -classpath Program FilesApache Software FoundationTomcat 5.5commonlibservlet-api.jar;classes:.-d classes srccomexamplewebBeerSelect.java
Problem arises as follows:
javac: invalid flag: FilesApache
Usage: javac <options> <source files>
use -help for a list of possible options
In switch case statement string expression whether it will work or not ???
View Replies View RelatedI'm trying to work out how to get a string from a servlet in to the JSP, The code I thought would work was as follows.
request.getSession().setAttribute("test", "this is a test");
request.getRequestDispatcher("C:myjsp.jsp").forward(request, response);
<%
String s1 = (String) session.getAttribute("test");
%>
<%= s1 %>
This is returning null ...
I have tried a few examples and followed a few tutorials but I keep getting null or nullpointexceptions.
i have file index.jsp , that approach to reguar java class and call function . in that function i want to get attribute from session like this :
List<Coupon> couponsList = (List<Coupon>)request.getSession().getAttribute("listOfCouponsThatNotExpired");
because this regular java class i get error message ,how to solve this ?
I want to do a simple search and replace regular expression of lines. I am very unfamilar with Java regular expressions, and I'm not sure how to do something as simple as what I want to do. I have lines that look like this...
Java Code : access_log /home/%USER%/access_log mh_sh_highlight_all('java');
I want them changed so %USER% changes to a string, such as "cyrus," so they appear like this ...
Java Code: access_log /home/cyrus/access_log mh_sh_highlight_all('java');
The reason I want to use regular expressions is because I want to use the replaceAll method of the java.lang.String object. If I use replace I have to convert my strings into char arrays, and my code becomes bulky.
In this i Write a Java program to parse a syntactically correct arithmetical expression and produce an equivalent Expression TREE. Remember, in an expression tree the terminal nodes are variables and constants, and the interior nodes are operators (such as +,-,*,/). For instance the expression: (1 + 2) * 3 can be represented by the following tree:
INPUT Expression
(1 +2)*3
POSTORDER Expression
1 2 + 3 *
TREE [root=asd.reg.Node@56ddc58]
But when I Execute the program it Shows only Prefix and postfix .But the requered output is in inorder preorder and postorder ...
import ava.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
import javax.swing.tree.TreeNode;
[code]....
I have the following structure and want to use lambda expressions with it, but an exception occurs:
class SuperClass // (package private)
public class SubClass extends SuperClass // in same package as SuperClass
I have a functional interface (a listener), which has one argument of type SubClass.
public interface MyListener() {
void myMethod(SubClass e);
}
When I use the old-school Java 7 style:
addListener(new MyListener() {
@Override
public void myMethod(SubClass e) {
System.out.println(e);
}
});
Everything works fine! If I use Java 8 lambda expression instead:
addListener(e -> {
System.out.println(e);
});
It will throw an exception:
java.lang.IllegalAccessError: tried to access class SuperClass
The area of a square is stored in a double variable named area . Write an expression whose value is length of the diagonal of the square. Do I use math.sqrt?
View Replies View RelatedI Write a Java program to parse a syntactically correct arithmetical expression and produce an equivalent Expression TREE. Remember, in an expression tree the terminal nodes are variables and constants, and the interior nodes are operators (such as +,-,*,/).
For instance the expression: (1 + 2) * 3 can be represented by the following tree:
INPUT Expression
(1 +2)*3
POSTORDER Expression
1 2 + 3 *
TREE [root=asd.reg.Node@56ddc58]
But when i Execute the program it Shows only Prefix and postfix .But the requered output is in inorder preorder and postorder so how to solve these error
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
import javax.swing.tree.TreeNode;
public class InToPost {
private static String str;
[Code] .....
Modify the program in Assign4 to synchronize access to the instance variable, balance. Save the program as SyncBank.java. Because balance is a double and not an object, it cannot be used as the monitor. Use synchronized methods or synchronized blocks of code as appropriate. Simultaneously test two threads as was done in Assign4. Because the threads can complete too quickly to determine if they are interfering with each other, delay the adding of a deposit by inserting the following code within the synchronized block or method:
try {
Thread.currentThread().sleep(10000); //sleep for milliseconds
}
catch(InterruptedException e) {
}
My code attempt so far:
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
import java.net.*;
import java.text.DecimalFormat;
public class SyncBank extends HttpServlet //throws ServletException, IOException
[Code] .....
I am absolutely new to Java. I am creating a Servlet and getting the error interface is expected here.
I am using IntelliJ 14.
My Servlet code is as follows:-
package ERPdetector;
import javax.servlet.http.*;
import javax.servlet.*;
import java.io.*;
public class ErpServlet implements HttpServlet {
[Code] ....