Java N-node Tree
Mar 30, 2015
I'm trying to write Java code for the following figure. Where, if node:4 will create following separate 4 trees. Number of node in
LEVEL1 (yellow) : n node.
LEVEL2 (green) : n-1 node.
LEVEL3 (blue) : n-2 node.
See image for node:4.
4node.jpg
The example out for node:4 :
012
013
021
023
031
032 and so on.
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May 12, 2014
I have requirement of sorting the files in tree structure with name and timestamp of creation, i am new to swings...
Here we are using FileTreeModel.
Root Folder:
folder1;
file1
file2
.
.
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Mar 29, 2015
I have some work where I have to create a binary tree. Anyway I am stuck on one of the classes which has several methods I must fill in! The code is below
The headers for each method are: public Node find (member p1)The method find(Member p1) is used to return the node which contains a particular member. It is a private method because the interface to CabinetTree should not provide direct access to the internal nodes. It makes use of the method Node findNode (Member p1, Node current)
and the next method is : Node findNode(Member p1, Node current) which searches the tree from current node to find a node whose value is equal to the Member p1, i.e. a node in the tree such that p1.equals(current.getMember()) is true. If there is no such node then the method should return null.
public class CabinetTree {
private Node head;
CabinetTree(Member p1) {
head = new Node(p1, null);
[Code] ....
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Jun 10, 2014
I have a TreeView insight TabPane
treeView.setOnMouseClicked(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent mouseEvent) {
if (mouseEvent.getClickCount() == 2 && mouseEvent.getButton() == MouseButton.PRIMARY) {
// Some action
}
}
});
For some reason when I click on a tab body I can also perform the listener action. How I can add additional statement to perform the action only if I select node?
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Jan 6, 2015
I used tomahawk t:tree for showing my data in tree structure and displayed that very fine. But my problem is how can we find the node id in bean side when we select one node .Because i want to show some data based on that node.
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Apr 1, 2015
So in my binary search tree I'm trying to write a method that deletes the idem but for some reason it's not working. I have two things, I have the method and then another piece of code that tests the deletion method. Here's the actual method
public void delete(String word) {
root = deleteItem(root, word);
}
protected TreeNode deleteItem(TreeNode r, String word) {
if (r == null){
return r;
}
if(word.compareTo(r.item.getWord()) < 0){
[Code]...
Here's the test code
message = "Test: deleting 'word' -- ";
t = new BSTRefBased();
try {
t.delete("word");
result = t.getRootItem().getWord().equals(null);
} catch (Exception e) {
result = false;
}
System.out.println(message + (result ? "passed" : "FAILED"));
So for some reason it keeps saying that the test failed. Why does it keep saying that.
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Jun 20, 2014
I want to develop simple example in which I can select TreeView Nodes with Buttons(in some cases clicking on image and etc). I created this simple sample:
<pre style="" _modifiedtitle="true" jivemacrouid="_14032555963537721" ___default_attr="java" jivemacro="code" class="jive_text_macro jive_macro_code jivemacrouid_14032555963537721">
import javafx.application.Application;
import static javafx.application.Application.launch;
import javafx.geometry.Insets;
[Code] ....
The question is how I can select tree Node when I click on a button. For example when I click on a button Item A1 I want to select tree idem Item A1.
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Feb 10, 2015
the problem was :
i wrote it on paper with my examples.and just for laughts , i uploaded another picture that dont belong to my problem. its just my way to understand binary search tree implementation , so i wanted so share.just for laught : looks like the map of the universe.
now my problem : why after i changed Current to Current.left, Parent still has the value of root. i draw and wrote it on a paper. to be clear as possible - picture 2 :
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Apr 5, 2015
I'm trying to use LinkedBinarySearchTree but a lot of the variables are protected in BinaryTreeNode. I am creating a BinaryTreeNode object but it still isn't allowing me to use them. The variables I am trying to use are element, left, and right.
import ch11.exceptions.*;
import ch10.LinkedBinaryTree;
import ch10.BinaryTreeNode;
/**
* LinkedBinarySearchTree implements the BinarySearchTreeADT interface with links.
*/
public class LinkedBinarySearchTree<T> extends LinkedBinaryTree<T>
implements BinarySearchTreeADT<T>
[Code] ....
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Jun 17, 2014
How to do draw the original binary tree based on traversal results?
A binary tree has this pre-order traversal result: A,B,D,H,I,E,F,C,G,K,J (TreeNodes) And the same tree gives the following in-order traversal: B,H,I,D,A,C,F,E,K,G,J. Can you draw the tree structure?
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May 4, 2014
I'm working on a lab for my class. I need to create a Priority Queue in Java using an array list. The kicker is that each node has to have a "handle" which is just an object which contains the index of of the node that it's associated with. I know that sounds weird but we have to implement it this way. Anyway, my priority queue seem to work fine except the handle values apparently aren't updating correctly because I fail the handle test. Also, I run into problems with handles only after extractMin() is called, so I figured the problem would be somewhere in that method but I've been through it a million times and it looks good to me.
Here is my Priority Queue Class:
package lab3;
import java.util.ArrayList;
/**
* A priority queue class supporting operations needed for
* Dijkstra's algorithm.
*/
class PriorityQueue<T> {
final static int INF = 1000000000;
ArrayList<PQNode<T>> queue;
[Code] ....
I can post the tests too but I don't know if that would do much good. Just know that the queue works as is should, but the handles don't point to the right nodes after extractMin() is utilized.
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Sep 9, 2014
how to create a tree data structure in java.I tried with a class consisting of node field and arraylist child nodes. but it does not satisfy the requirement.the requirement is that,
root: child1,child2,child3
child1:child4,child5
child2:child6,child7
on traversing it should print all the nodes as given above.no node should have same elements as child.
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Apr 11, 2014
My task is to implement a B-Tree data structure in Java using no libraries.
My current problem is inserting when the root is full, thus the middle key goes to root.keys[0] and then it get the left and right side which are new Nodes separating and inserting their keys. My problem is that for some reason there is a random second number when in the root and secondly my boolean leaf is always false meaning it never detects that the Tree is deeper than root.
The coding makes sense to me and I have tried printing everywhere but still can't seem to find the problem.
public class BTree {
/*
1. You may not modify the public interface of this class. You may however add any additional methods and/or field which you may require to aid you in the completion of this assignment.
2. You will have to design and implement a Node class. The BTree should house Integer objects.
3. You will notice that there are some overloaded methods, some of which work for Integer objects and some with primitive type int. You have to find a way to implement the methods to work with both types.
*/
class BTreeNode {
boolean leaf = true;
int numKeys = 1;
int mOrder;
Integer keys[];
[Code] ....
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Apr 11, 2014
My task is to implement a B-Tree data structure in Java using no libraries.
My current problem is inserting when the root is full, thus the middle key goes to root.keys[0] and then it get the left and right side which are new Nodes separating and inserting their keys. My problem is that for some reason there is a random second number when in the root and secondly my boolean leaf is always false meaning it never detects that the Tree is deeper than root.
The coding makes sense to me and I have tried printing everywhere but still can't seem to find the problem.
public class BTree {
/*
1. You may not modify the public interface of this class. You may however add any additional methods and/or field which you may require to aid you in the completion of this assignment.
2. You will have to design and implement a Node class. The BTree should house Integer objects.
3. You will notice that there are some overloaded methods, some of which work for Integer objects and some with primitive type int. You have to find a way to implement the methods to work with both types.
*/
class BTreeNode {
boolean leaf = true;
int numKeys = 1;
int mOrder;
Integer keys[];
[Code] ....
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Apr 5, 2014
I have written a code to get all the nodes below a current Node and it is working but I need to get it to look better if possible. To get the number of nodes below I have created an Array List, which I then go to the first Node below and add all the people to the Array list on the same level till I get to the end of the level, then I go down again until I cannot go down any more. Is there a way I can have my code without having to use an array List? I have put my code below. The brieff about the tree is that you have a parent and below the Parent are children who can have brothers and sisters next to them and after that they also have children below that. The method is trying to find the number of children below any given child
private LinkedList<Node> TempQueue = new LinkedList<Node>();
public int noOfYoungerChildren(Member p1){
Node tmp = find(p1);
return countYoungerChildren(tmp);
[code]....
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Jun 26, 2015
I have an excel file with data listed as the following, i m trying to parse down using POI
A
B
C
D1
D2
F
G1
G2
G3
M
S1
R
T
U
L
X
Y
Z
is it possible to generate an output like the following
A
A-->B
A-->B-->C
A-->B-->C-->D1
A-->B-->C-->D2
A-->B-->F
A-->B-->F-->G1
A-->B-->F-->G2
A-->B-->F-->G3
A-->B-->M
A-->B-->M-->S1
A-->R
A-->R-->T
A-->U
L
L-->X
L-->X-->Y
L-->X-->Y-->Z
I have been trying from quite some time but havent figured out the logic ...
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Mar 20, 2015
I am using the following code: But doesn't work fine. I try to find the Minimum spanning and print it out from house to which hose.
public class MinimumSpanning {
public static void main(String[] args) {
// [][] edge= are price between each hose edgs.
int [][] edge= {{0,7,9,12,0,0,0},
{7,0,0,10,0,0,0},
{10,0,0,12,0,0,0},
{12,10,12,0,11,0,10},
{0,0,0,11,0,4,8},
{0,0,0,0,4,0,6},
{0,0,0,10,8,6,0}};
[code]....
It should only print one time. Example between K to L prints many time.
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Mar 24, 2014
So, managed to get my Binary Search Tree to work properly:
package SystemandDesign.BinaryTree;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.List;
import java.io.ObjectInputStream;
import java.util.Scanner;
[Code] ....
No matter how many times I keep rewritting the testInsert method I get a chock full of errors.
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May 31, 2014
I never used tree, node etc. Consider an array of strings that come from html tags. This needs to be turned into a tree structure. Here, any Hn is the child of the most recent Hn-1
String[] Headers = {"H1", "H1", "H2", "H3", "H3", "H2", "H2", "H3",
"H4", "H2", "H2", "H2", "H1", "H2", "H2", "H3", "H4", "H4", "H2" };
Desired output -
ROOT
H1
H1
...H2
......H3
......H3
...H2
...H2
......H3
.........H4
...H2
...H2
...H2
H1
...H2
...H2
......H3
.........H4
.........H4
...H2
ANSWER -
class Example {
static class Node {
final String name;
final int indent;
Collection<Node> children = new LinkedList<> ();
[Code] .....
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Jul 16, 2008
I am trying to drag and drop tree nodes within the same JTree. I have a code which uses Java 1.2 java.awt.dnd.I would like to use TransferHandler and newer implementation.I have found a code which works when JTree is drop target but there is no code where Jtree is drag source and drop target.
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May 6, 2014
I Write a Java program to parse a syntactically correct arithmetical expression and produce an equivalent Expression TREE. Remember, in an expression tree the terminal nodes are variables and constants, and the interior nodes are operators (such as +,-,*,/).
For instance the expression: (1 + 2) * 3 can be represented by the following tree:
INPUT Expression
(1 +2)*3
POSTORDER Expression
1 2 + 3 *
TREE [root=asd.reg.Node@56ddc58]
But when i Execute the program it Shows only Prefix and postfix .But the requered output is in inorder preorder and postorder so how to solve these error
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;
import javax.swing.tree.TreeNode;
public class InToPost {
private static String str;
[Code] .....
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Nov 17, 2014
Is it possible to convert an int to a node[]?
Node[] expResult = new Node[2];
for(int i: expResult){
expResult[i] = i.;
}
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Oct 23, 2014
I am having an issue deleting a node for a tree for one of the cases.The cases for deleting a node are:
1. if its the root set it to null
2. if its a leaf, have its parent point to null
3. if the node you want to delete does not have a right child, have deleted nodes parent point to delted nodes only child
4. find the nodes predecessor(next largest value), have have predecessor's left child be deletes left, and preds right to be deletes right. then have deletes parent point to pred and finally, delete preds old spot (the one that is giving me an issue, I believe)
The pre order of the tree I am currently on is 50 5 4 10 190 100 100 200 190 201
or------------------50
-------------5--------------190
---------4------10-----100-------200
--------------------100---190--201
I am trying to delete 190 (which should be the first one)but when I try to print out the list after I delete, I get a stack overflow error when I try printing everything out.I am pretty sure that it has something to do with me hooking up the nodes incorrectly since error occurs for case 4, since it prints out just fine when I deleted previous nodes (like a leaf).Here is my delete method: (note, ignore my determineX and checkOtherHalf methods)
public boolean delete (E item) {
if(root == null){
return false;
else if(item == root){
root = null;
return true;
[code]....
I have confirmed that it is a pointer issue: I need to assign replacements old parents left child to null, to stop it, but idk how.Here is a screen shot of it when I debug it
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Jan 28, 2014
I have an add button on my screen to add a new node to tree. So once we click add button a popup comes to provide the new node name and then we press add button and the new node gets added to the tree.So know i want that when ever we add a new node to the tree the value of the new node should get stored in an array at the same time.
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Apr 7, 2014
I am trying to advance to the next node in my linkedList. Below is what i have so far.
/**
* Move forward, so that the current element is now the next element in this sequence.
* @param - none
* @precondition:
* isCurrent() returns true.
* @postcondition:
* If the current element was already the end element of this sequence (with nothing after it), then there is no longer any current element.
* Otherwise, the new element is the element immediately after the original current element.
* @exception IllegalStateException
* Indicates that there is no current element, so advance may not be called.
**/
public void advance( ) {
// student implements
if(!isCurrent())
throw new IllegalStateException();
else{
while(cursor != null){
precursor = cursor;
cursor = cursor.getLink();
}
}
}
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May 6, 2014
I am getting errors when I try setting left and right values (which are String types) for my tree.I tried doing something like:
Node node = new Node("Is it human?", null, null);
node.getLeft().setNode("Is it Zelda?");//the first left Q
node.getRight().setNode("Is it Kirby?");//the first right Q
but that gives me a runtime error of "java.lang.NullPointerException" which points to the line 2. I also tried this:
Node node = new Node("Is it human?", null, null);
node.setLeft(setNode("Is it Zelda?"));//the first left Q
node.setRight(setNode("Is it Kirby?"));//the first right Q
but that gives me another error, pointing to the setNode for both lines 2 and 3,plus it wouldnt make sense since both setLeft and setRight takes in Node types, not String types.
Here is my Node class:
public class Node {
private Node leftPt, rightPt;//left and right pointers for Node
private String node, left, right;
public Node(String node, Node leftPt, Node rightPt){
this.node = node;
this.leftPt = leftPt;
this.rightPt = rightPt;
[code]....
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