Java Program To Find Index Of Greater Element Whose Value Is Sum Of Remaining Elements
Aug 25, 2014
I need to write a java program to find the index of the element whose value is the sum of the remaining elements. Recently I have been asked this question in an Interview which I couldnt solve properly.
Im working on my homework and it mentioned element for one exercise and an index in another, what is the difference, If Any, Between An Element And An Index?
I am just studying over ArrayLists and i have encountered a problem, i'm trying to get the index of an element but it keeps returning -1. Here's the code
Java Code:
import java.util.ArrayList; public class PhoneEntry { String name; String phone; public PhoneEntry(String name, String phone) {
[Code] ...
I know the list is not empty because it returns a size.
I'm trying to iterate through an array of integers and find the start position of the part of the array containing the most consecutive 1s.
For example given the array {1,3,1,1,1,1,5,3,2,1,1}, the method should return 2 and given {1,4,5,1,1,1,5,1} the method should return 3.
So far, I've managed to retrieve the element where the consecutive 1s begin. However, I'm unsure how to get the index of this element and this implementation doesn't work if there is more than one set of consecutive 1s.
public class GetIndex { public static int getPosition(int[] myArray) { int index = 0; int tracker = 0; int mostOnes = 0; for(int i = 0; i < myArray.length; i++) {
So in my code, I have the user input a number, and the program will then display that element in the array (I've done this bit). However I need to write code to check that the user is entering a valid index number, and if they don't, I need to prompt them that the number they have entered is incorrect and let them retry, and I don't know how to.
This is my full code, I have added a comment underneath where I need to add the code:
import java.util.Arrays; import java.util.Scanner; public class StudentNames { public static void main(String[] args) { String[] names = new String[8]; Scanner s = new Scanner(System.in); for (int i = 0; i < 8; i++) {
I develop a finite element code at java. I am looking for efficiency solver and fast for large, sparse , symmetric and positive define matrices .
i used in jblas but i encounter in problem when the matrix has high condition number(ill condition number) and i get error for singular matrix while in mathematica i succeed to solve that system without problems...
Any good solver and fast solver package in java can i use for solving that system?
import java.io.IOException; public class Largestcolumn { public static void main ( String[] args ) throws IOException { int largest = 0; int newnumber = 0; int[][] data = { {3, 2, 5},
[Code] ....
When I run this code, I get this following output: The largest element in column 0 is: 9. Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at largestcolumn.Largestcolumn.main(Largestcolumn.java:27) Java Result: 1
It outputs the first column's maximum element but then throws an out of bounds error. I'm new to Java and I can't figure out how to fix my code so that it will work for this multidimensional array and output the maximum elements in all of the columns.
I am trying to write a code that asks the user to input ten numbers and then finds and displays the smallest number out of the ones given. I am supposed to implement arrays into the program to do this. But the problem I have run into is that when I compile the code in jgrasp, I am given several error messages and I am not quite sure what I have done wrong. I'm assuming it is either a syntax or a logical error on my part but reading over the code I do not understand what is causing these errors.
This is the most current draft of my code:
import java.util.Scanner; public class Exercise7_9 { public static void main(String[] args) { double[] numbers = new double[10]; //Enter ten double numbers: Scanner(System.in) java.util.Scanner input = new java.util.Scanner(System.in); System.out.println("Please enter ten numbers: ");
[Code] ....
/* Sample Run: Enter ten numbers: 1.9, 2.5, 3.7, 2, 1.5, 6, 3, 4, 5, 2 */
And these are the exact error messages:
----jGRASP exec: javac -g Exercise7_9.java Exercise7_9.java:35: error: '.class' expected if (double m > list[i]) { ^ Exercise7_9.java:35: error: illegal start of expression if (double m > list[i]) {
I have two ArrayLists and I want to compare them for common elements, and based on the result I want to update the first Arraylist to only have these elements. sort of like the opposite of RemoveAll() which removes elements in common and keep the ones that are unique. so far I thought of using for loop and .contains() in case it was fault,element not present, remove from list. but I was wondering in what other ways, perhaps APIs i can use to do that?
I need to create an algorithm that finds the common element(s) in all arrays that has a signature of public Comparable[] findCommonElements(Object[] collection) that has an efficiency of at most O(knlogn), uses a query array, and accepts as input a collection of arrays. I am aware my time would be better spent learning how to use array lists and hash sets, but I am supposed to use concepts already covered, and these have not been.
I feel like this code should work, but it is returning null for the array of common elements. Which means it obviously is not working correctly. I am also likely going to need implementing the sort algorithm, but I wanted to get the part of finding the common elements set first.
public class CommonElements2<T extends Comparable<T>> { Comparable[] tempArr; Comparable[] common; Comparable[] queryArray; /* sort algorithm goes here */ public Comparable[] findCommonElements(Object[] collections)
So in this program, which is a grading program, I am trying to compare all the students averages to find who has the highest one and list the grades and the student's names from least to greatest. Yes, I see there are other problems in the program but it is nowhere near finished.
import java.util.Scanner; public class Main { public static void main(String[] args) { String[] studentName = new String[20]; int[] studentAverage = new int[20]; Scanner input = new Scanner(System.in);
Is there any way to find how many number of elements are landing in same bucket in HashSet. I know Reflection could be one way but i am not able to design a program for that.
Write a program that prompts the user for an input number and checks to see if that input number is greater than zero. If the input number is greater than 0, the program does a multiplication of all the numbers up to the input number starting with the input number. For example if the user inputs the number 9, then the program displays the following sum:
9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 362880
That's the question I'm getting and so far all I've got is
import java.util.Scanner; public class Lab4Q3 { public static void main (String[] args) { int keyboard;
I finished a game in Java and sent it to a friend. Launching the program in my computer worked just fine.
But he got this error : "Could not find the main classs: Main. program will exit"
My JRE version is the most updated one. His JRE was version 1.6. He updated his JRE, and the problem was solved.
This is a bit worrying for me, because as far as I know, 1.6 isn't a very old version of the JRE. It's not the most recent one, but not that old.
This is worrying because I'm planning on sending my game to a lot of friends, and trying to distribute it on the internet.
A lot of people don't have the most updated JRE. And they are mostly non-programmers, so I can't expect them to update to the newest version of Java upon downloading my game. They might not know what Java is, even though they got it on their computer, and upon receiving an error, they'll just give up on the game.
If my game wouldn't work with a significantly old JRE, that would be reasonable. It's part of the nature of working with Java. But the fact that a relatively updated JRE, 1.6, doesn't work with my game, is worrying.
*(Please note: My game isn't implementing anything "special". Swing and KeyBindings are the 'newest' additions to Java that I can think of inside my game)*.
In short, I'd like to know that my game works on most of the computers it tries to run on. Knowing that it doesn't work on a relatively new JRE, is worrying.
So I have two questions:
1. Is it normal, for a Java program, to have such "high" demands for the JRE version? Do a lot of Java games demand at least version 1.6 of the JRE? Is this common?
2. How can I find out the minimum JRE version requirement for my program? Is there a methodical way to do this, or do I just have to go through all the libraries I use in my game and figure out what's the JRE release version for each one?
Write a program that prompts the user to enter an integer m and find the smallest integer n such that m * n is a perfect square. (Hint: Store all smallest factors of m into an array list. n is the product of the factors that appear an odd number of times in the array list. For example, consider m = 90, store the factors 2, 3, 3, 5 in an array list. 2 and 5 appear an odd number of time in the array list. So, n is 10.)
so far my program is just like this.
import java.lang.Math; import java.util.Scanner; public class PerfectSquare { public static void main(String[] args) { Scanner m = new Scanner(System.in); int Fint;
[Code] .....
how do i make the program find the smallest integer n?
I'm supposed to calculate and display the number of total days, and then the number of months, and days from now (when the program is run) to when the person's next birthday is (no leap year). Here is my code:
import java.util.Scanner; import java.text.*; import java.lang.System; import java.util.Date; import java.util.Calendar; public class CSCD210Lab3 { public static void main (String [] args)
[Code] .....
When I call daysFromMillis in the print statement, if I enter in a birthday of 02/17/1993, I will get an answer of "our birthday is 5435 days from now."
I want to run a program to add an element as the third element of stack without changing rankings, I am trying to use two stack and I don't know how to push the top of first stack in the second: push(top(); this line
public void ADD(int element,int i ){ if(isEmpty(true)){ push(element);} else{ makeNull(); while((i<=3) && (isEmpty(false))){ push(top(); }
I am taking the Class Algorithms and Datastructures and got an assignment for Lab that really throws me off. The goal is to create an Array out of a given CSV file, implement several Methods that get the size of array, etc.
I am still stuck in the first part where the CSV has to be imported into the Array. My problem is that I need a mechanism that figures out the needed size for the Array, creates the array, and only then transfers the data from the CSV.
The list consists of the following wifi related values:
MAC-Adress, SSID, Timestamp, Signalstrength.
These are on the list, separated by comma. The Columns are each of these, and the rows are the four types of values making up the information on a certain wifi network.
The catch is, we are not allowed to use any of the following:
java.util.ArrayList java.util.Arrays and any class out of java.util.Collection.
So far I used the BufferedReader to read in the file and tried to implement the array, but I get an arrayindexoutofboundsexception.
Below is my Code (Its still an active construction zone):
public class WhatsThere { public WhatsThere(String wifiscan) throws IOException { } public static void main(String[] args) throws IOException { // WhatsThere Liste = new WhatsThere(String wifiscan); String[][] arrayListe = new String[0][0];
i'm trying to do a program that memorizes the elements formed by a word and a number. For example, if I write ABB 3, AB 2, ABB -2, ABC 5, ZZ 2 the program will write:
ABB 1 (the result of abb (3-2)) ABC 5 AB 2 ZZ 2
Also, should write:
2 AB ZZ 5 ABC 1 ABB
I've tried to do it with a TreeMap but i don't know how it works.
import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class array { public static void main(String[] args)
[Code] ...
Is there a way to write this, where, alpha is one array.
Write a program that declares an array "alpha" of 50 elements of type "double". Initialize the array so that the first 25 elements are equal to the square of the index variable and the last 25 elements are equal to three times the index variable. Output the array so that 10 elements per line are printed.
If I have an array of 50 integers, can I break that to read in lines of 10?
My Computer Programming teacher has given the class a problem that requires the use of var.charAt(), var.length() and while/for. Basically, the problem is that we have to create program that'll show a mirrored or reverse version of the entered word. Like for example, if your input is the word "Hello" (the quotation marks aren't included), the output will be "olleH".
Here's the code:
import java.io.*; public class StringMirror {public static void main (String [] args) throws IOException {BufferedReader scan = new BufferedReader (new InputStreamReader(System.in)); String enteredWord = ""; int lengthOfTheWord = 0; int lengthOfTheWordMinusOneVersion = 0;
[code]....
It is working, but the problem is that after the output, there's this error that says String index out of range: -1.
the program is working but I kind of wanted it to have no errors in the end.
I'm trying to search a library program by book index and running into some trouble with my HashMap. Here's the code in question:
Java Code:
public String searchByBookIndex(int input) { NumberFormat fmt = NumberFormat.getCurrencyInstance(); Map<Integer, Book> bookMap = new HashMap<>(); for (int i = 0; i < author.booksByAuthor.size(); i++) { bookMap.put(author.booksByAuthor.get(i).getBookIndex(), book);
[Code] ....
The search itself works fine; however, the problem is that the values of everything in the HashMap are overwritten by the last book entry. For example, let's say there are four books (index in parenthesis):
The Book (1), A Wonderful Book (2), A Great Book (3), A Bad Book (4).
Once the code above iterates, the HashMap out is this (via println):
1 = A Bad Book, 2 = A Bad Book, 3 = A Bad Book, 4 = A Bad Book.