JavaFX 2.0 :: Input Latin Letters With Macron Using Keyboard Layout That Uses Tilde Or Apostrophe Deadkeys?
Feb 25, 2015
I can not enter Latin letters with macron (Latvian specific characters) in JavaFX programs. Instead something like Latin letters with acute are entered.
what I need to enter is characters like this: Latin letter "a" with macron
Browser Test Page for Unicode Character 'LATIN SMALL LETTER A WITH MACRON' (U+0101)
what is actually entered: Latin letter "a" with acute
Browser Test Page for Unicode Character 'LATIN SMALL LETTER A WITH ACUTE' (U+00E1)
There are several keyboard layouts available for Latvian language input. Problem persists only on Windows OS for layouts using tilde key or apostrophe key as deadkeys. There are no problems with Microsoft Latvian (QWERTY) layout that uses ALTGR key as deadkey. There are also no problems on Linux OS using keyboard layouts that causes problems in Windows OS. I also noticed that character input works as expected int SceneBuilder 2.0 (I believe it has been build with javaFX). There are no problems also in java Swing GUI framework. So could this be a bug in JavaFX or am I missing some configuration settings?
How can I enter latin letters with macron using keyboard layout that uses tilde deadkey?
I'm using HTMLEditor in my simple test application and I'm showing html text generated. I noticed that accented letters (à,è,ì, ect) are not escaped (àect ect). Looking at the source code I arrived to the class
com.sun.webkit.WebPage
In which the method I thinked is used is this:
public String getHtml(long frameID) { lockPage(); try { log.log(Level.FINE, "getHtml"); if (isDisposed) { log.log(Level.FINE, "getHtml() request for a disposed web page.");
I created a scanner object but it's not asking for any input. when I create a new scanner and then tell it to print it it just prints a bunch of weirdness when AFIK it should be asking me to type something and then it should repeat what i entered.
I noticed that when building a UI programmatically in several steps the width/height of the Pane I use for layout is -1/-1. I read that this is the case until the actual rendering happens. Is there a way to force that earlier? Suppose I wanted to size other UI components (which are not visible initially) according to the size of another pane. How do I do that? Binding the properties does not do the job in the case that those components are not necessarily visible at the same time. Is there a trick to achieve that?
so i'm working in a chat program and i'm trying to make it so that you are able to open another tab yet still be able to chat.
right now the client that the user download uses the keyadapter to get the keyboard input, but whenever the user un-focus the chat window, the keyadapter no longer gets the keyboard input.so is there another way i can get the keyboard input? so it doesn't matter what window you are focused on, you get the keyboard input either way?
I have a stage,it has two layers scene, if user click the button,then change to another layer, and also can change back. It just like swing cardlayout. How can i implement cardlayout in JAVAFX?
import java.util.Scanner; public class main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int number; System.out.println("Input a number");
[code]....
What i want to do is that if the number is greater than 50 to count until 100. else if the number is less than fifty to count for example from 36 to zero.
I want to write a java program which displays to get the GPA of a student as a keyboard input. Then display the class of the degree according to the following criteria using a switch-case statement (if-else statements cannot be used). If the user insert an invalid gpa you should display a message Invalid GPA.
gpa ≥ 3.50 First Class Hons 3.49 ≥ gpa ≥ 3.00 Upper Second Class Hons 2.99 ≥ gpa ≥ 2.50 Lower Second Class Hons 2.49 ≥ gpa ≥ 2.00 Pass 2.00 ≥ gpa Fail
Here is my code:
import java.io.*; public class q7 { public static void main(String[] args) { InputStreamReader ISR=new InputStreamReader(System.in); BufferedReader BR=new BufferedReader(ISR);
[code]...
.But when I use Command console to run this it says: 1111.jpg. I also wanna know is there another way to do this with switch- case statements.
I need to design, implement, and test a program to input and analyze a name. The program begins by retrieving a user input string from the keyboard. This string is intended to be the user's name. These are the errors we have to search analyze the user input for: No blanks between names firstName and lastName, Non-alphabetic characters in names, Less than two characters in first name, and Less than two characters in last name. Each of these errors must be thrown. All exceptions must be derived from a programmer-defined class called NameException. Each exception should use a detailed message to differentiate among the file types of errors.
This is the format of my NameException class, is the format itself correct? I will fill in the details of each exception I am just wondering if that is how I should set it up.
public class NameException extends Exception { private String firstName, lastName; public NoBlanksException(String firstName,String lastName) { } public NonAlphabeticalCharactersException(String firstName, String lastName) {
[Code] .....
I was told not to try and catch thrown errors in the main method, would I just create another method in the Driver class to take care of that then?
I decided to code this quiz I took in class about asking the user to input a string and the code is suppose to check for upper case letters. If a upper case letter is found, it should increase a count by one. Once the check is done, it should display the number of uppercase letters. For some reason I am getting this weird compile error stating that symbols can't be found...
Java Code:
import java.util.*; import java.lang.*; public class StringCheck{ public static void main(String[] args){ Scanner input = new Scanner(System.in); System.out.println("please enter a string: " ); String s = input.nextLine();
No problem setting background color for layouts, e.g. bdrPn.setBackground(new Background((new BackgroundFill(Color.BLACK, CornerRadii.EMPTY, Insets.EMPTY))));
But neither of the following are working for me, running JavaFX 8 on latest OS-X
scene = new Scene(bdrPn, winW, winH, Color.BLACK); scene.setFill(Color.BLACK); scene.setFill() worked fine for previous versions of JavaFX.
I can't figure out why my code doesn't work. My task is to replace for example ä=>ae, using this method String.charAt(int index). So here is my code:
public class pich { public static void main(String[] args) { String text = "Die süße Hündin Leica läuft in die Höhle des fülligen Bären "+ "Iliyan (ein Übergrößenträger), der sie zum Teekränzchen eingeladen hat."+ " An ihrem Öhrchen trägt sie modisch eine Ähre."; String textOhneUmlaute = "";
[Code] ....
when I launch my code I get the same String and nothing has changed
I am writing a code that tries to figure out the users password by going through every possible key (brute force). Although I think its going to work, it looks EXTREMELY inefficient to me, since its just a huge switch statement for each character -- 94 total, including the shift values. Is there a built in method in the JAVA API that goes through every key or something?
Here is my code for that segment:
public char[] HackingPassword(){ char[] passChars = this.password.toCharArray();//convert the password to char[] char[] hacking = new char[passChars.length];//make the hacking variable same size as users password int nextCharValue = 0;//this is used to cycle through the keyboard //check each letter of hacking to match with password for(int i = 0; i < passChars.length; i++){
Write a program that extracts words from a file. For the purposes of this program, a word is defined as a series of adjacent letters. Only print words that are at least four and no more than 12 letters long. Print each word on a different line.
The program should read the name of the file from the keyboard.
I need to get the filename from the user for this particular program. Usually I would have the name of the file prewritten into the source code like this....
Scanner input = new Scanner(new File("gettsy_burg.txt");
I tried different ways but I just can't seem to figure it out.... I guess what I'm really asking is how to rearrange Scanner input = new Scanner(new File("gettsy_burg.txt"); since I want the user to input the filename instead of the filename being prewritten by the programmer(me).
This is what I have so far to let the user for input....
Scanner keys = new Scanner(System.in); System.out.println("Enter the filename: "); String fileName = keys.nextLine(); keys = new Scanner(new File(fileName));
Write a program that extracts words from a file. For the purposes of this program, a word is defined as a series of adjacent letters. Only print words that are at least four and no more than 12 letters long. Print each word on a different line.
The program should read the name of the file from the keyboard.
I need to get the filename from the user for this particular program. Usually I would have the name of the file prewritten into the source code like this....
Scanner input = new Scanner(new File("gettsy_burg.txt");
I tried different ways but I just can't seem to figure it out....
I tried this but it only gives me one letter that corresponds to the number
package pkg2911homework.pkg1; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner keys = new Scanner(System.in);
While using generics, are there cases when ? wildcard cannot be replaced with letters [A-Z]? So far , I was able to find only one case, it is when you want to have field pointing on generic instance without making class generic.
class OneClass { private LinkedList<?> myLL; }
In case above, as I understand, you cannot use [A-Z] without generalize OneClass. Are there any other cases, when there is no way except to use ? wildcard instead of letter [A-Z]?
I wanted to make a small program to move a small rectangle by pressing the WASD keys. The program works, except that when I hold a key to move the rectangle, after a second, auto-repeat starts up, and the rectangle motion accelerates. I want to prevent automatic repeat to activate, so that the rectangle moves at a constant speed when I hold a key and stops when I released. Here is the ButtonMotion classe :
