I have a SplitPane, which is inside another SplitPane in the same tree hierarchy of the Scene. When I set the CSS class of the outer SplitPane, it always overwrites all CSS Settings of the inner one. How can I prevent it, so that e.g. I can assign a red divider for the outer and a green one for the inner SplitPane.
I have defined the CSS with
<code> </code>
I'm having a problem with SplitPane (horizontal Flow). What I'm looking for is to find a way to maintain the left pane in the same position when the main window maximizes. I do not want the left pane to grow on its width. If I go into the AnchorPain Constraint in the Scene Builder and remove the right and left constraints, when I run the application, the left pane keeps its position, but it appears a gap between the two panes (the left pane and the right one).
I need to find the way to expand the right pane to the position where the left pane is.
The link shows an image that illustrates the problem. [URL]
I would like to keep the same values of the positions for dividers (SplitPane) even if the width or the height of the window changes. I want to keep the proportion of the differents dividers. After resizing the window, the values of positions are not the sames ! I use this source without success :
stage.widthProperty().addListener(new ChangeListener<Number>() {
@Override public void changed( ObservableValue<? extends Number> observableValue, Number number, Number number2) {
sp.setDividerPositions(0.40f, 0.02f, 0.54f);
[Code] ....
We're twisting our minds how to use predicate bindings correctly in the real world, i. e. beyond the trivial examples for FilteredList using simply static code but no bindings!
The problem is that our predicate must be bound to a chain of BooleanBindings, of which the final term needs the item injected into the predicate by the FilteredList. Example see purple code:
BooleanBinding a = ...
StringBinding b = ...
ObjectBinding<Predicate> c = Bindings.createObjectBinding(() -> item -> a.or(b.isEqualTo(item.someProperty())).get(), a, b); // Ugly: No "Bindings" style!
myFilteredList.predicateProperty().bind(c);
This code has an ugly smell! It first looks like "Bindings" style, but in fact is plain old lamba mostly! But it also is slow: The code enforces splitting of a and b into separate bindings as it enforces rebuilding the chain a.or(b.isEqualTo(...)) for each single iteration of titem in turn. That induces unnecessarily creating and garbage-collecting Bindings "on the fly", which is not how Bindings are intended -- they shall be created once and simply update their value instead of getting replaced themselves to prevent wasting CPU cycles and keep memory clean.
How to do Predicate Bindings correctly (i. e. without temporarily building Bindings for each "t") ...
I have a TableCell that will hold numbers in a tableview. All is working work nicely, but I want the following behavior:
- when the user begins to edit such a cell, if it doesn't enter a number, the cell will not call commitEdit, but rather display a red border and prevent the user from changing the focus to anything else until he either: enters a correct number or presses ESC.
I don't know how to keep the user in that editting cell if while he has an incorect number. Currently he can click other row/control and he will break the edditing state. I repeat, I don't want the user to be able to click on any row/control until he has a correct number.
Here is my cell implementation:
public class EditableIntegerCell extends TableCell<Person, Integer> {
private TextField textField;
@Override
public void startEdit() {
if (!isEmpty()) {
super.startEdit();
createTextField();
setText(null);
[Code] .....
HOW does threading prevent GUI unresponsiveness?
View Replies View RelatedHow can we prevent SQL Injection in Java Code?..is there any Special cases..
View Replies View RelatedI am trying to prevent data from being overwritten and appended instead when I save it to a file. I already set the append boolean to true on the FileOutputStream, but the data is still being overwritten. My code is below:
public class Main {
public static void main(String[] args) {
LinkedHashMultimap<String, Integer> testMap = LinkedHashMultimap.create();
//ListMultimap<String, Integer> test = ArrayListMultimap.create();
OutputStreamWriter outputStream;
testMap.put("NumberA",1);
testMap.put("NumberA", 33);
[Code]...
I performed a print statement to verify that the LinkedHashMultiMap is not replacing values with the same key (which it was not) and realized that the overwriting was occurring when I wrote the data to a file.
I just want to ask about a kind inheritance.Let say I have an interface MachineCode.I also have different classes, Binary, Hex and Octal that implements MachineCode
Question: How can I prevent java to create an Object like this:
Binary bin = new Binary();
Hex hex = new Hex();
Octal octal = new Octal();
those declaration above must be compile error,
I want to create Objects of Binary, Hex, and Octal this way:
MachineCode bin = new Binary();
MachineCode hex = new Hex();
MachineCode octal = new Octal();
I'm using a BorderLayout, with 26 buttons to make up the alphabet from a keyboard. All the spacing looks great, but when you drag the screen out, everything gets jumbled. I would prefer to have everything stretch out, and keep the same positioning, or everything move towards the center still keeping the keyboard style positioning of the buttons but increasing the size of the window. Will a BorderLayout work for what I want, or should I try something else?
Currently to keep the buttons spaced apart I am keeping there preferred size to 25, and using horizontal and vertical struts to get the buttons positioned like I want.
This is how it is if I keep it the width and height 400, 400.
ex1.jpg
This is what happens when its stretched or shrunk.
ex2.jpg
This is an example of one of the ways I would prefer it
ex4.jpg
This is would also be acceptable.
ex3.jpg
import java.util.*;
public class DungeonsAndDragonsRedux {
public static void main(String[] args) {
Scanner s = new Scanner (System.in);
Scanner t = new Scanner (System.in);
t.useDelimiter("\n"); // Prevent scanner from reading code after nextLine().
[code]...
I have this program that is attempting to randomly equip the player with items that are randomly chosen from a list. I don't know how to prevent it from picking the same item twice though. I also don't know how to display the items that haven't been equipped, which is another requirement of this program.
Should the piece of code below set prevent the comboBox from being used? All it does at the minute return a null pointer exception. See I am using the same window but I have an if statement so if a condition is true then it will change certain aspects of the window. I want it to be true if it equals export which is does and it's populated fine but when I try and hide it if the condition equals import it returns a null pointer?
comboBoxEnv.setEnabled(false);
I have a JSF page (called MainPage) with a commandButton: clicking on it, I open a modal panel with a <Rich:fileUpload> component, related to a listener in corresponding bean.
When I start to upload a file, page MainPage starts to refresh, but I would like to prevent this because it's not necessary.
I tried to "play" with <Rich:fileUpload> property values, but nothing seems to work and I don't know what to do anymore.
Here is file upload component
<rich:fileUpload fileUploadListener="#{pannelloUploadBean.uploadListener}"
id="#{cid}_input"
ajaxSingle="true"
immediateUpload="true"
listHeight="200px"
listWidth="458px">
[Code] .....
I am making a very simple 2D array game where the player is asked what size they would like the game board to be. After entering, it displays the board and the player 'P' starts at index [0][0]. After that, they are asked for an action, which can be "up", "down", "left", "right", or "exit". I will be including some extra later (like a treasure at the end, or random obstacles), but for now this is what the game consists of.
I was instructed to "do nothing" when/if the player attempts to go out of bounds. I am trying to simply print an error, such as "Out of bounds! Try again.", then prompt the player again for an action. I even tried to make a boolean method to catch it, but to no avail.
I don't want the exception to occur at all. I just simply want the error message to print to the player and ask for another action. I would prefer not to use try/catch, or try/catch/finally since I already tried that and it still gave the exception error.This program consists of two classes. I will show the class containing the main first, then the client-server type class second.
import java.util.Scanner;
public class Driver {
public static void main(String[] args) {
World world = new World();
boolean keepPlaying;
keepPlaying = true;
boolean isOutOfBounds;
isOutOfBounds = false;
int height = 0;
int width = 0;
int x = 0;
int y = 0;
[code]....
If some one add script in my URL, I want the script not pop up, we have tomcat 6 [URL] .....
View Replies View RelatedI am generating java script tag and javascript code in servlet and displaying it in each jsp page. i include this in every jsp in my application. I am preparing the following javascript content and diplayin each jsp
<script type="text/javascript"> BOOM.addVar (clientId = SOME universal unique ID ) </script>
the clientid will be uniqueid it gets generated every time.
Here my question is, is there any possibility the clientId will be store in browser cache or third party cache server. if yes how to prevent clientId from cache.
I don't want to prevent the whole jsp file from cache. i just want to prevent only that particular field. so that i can use advantages cache and also prevent particular header field to be cached.
Also can we prevent particular http header attribute from cache.
I have a jsp page that generate a hashtable and display its key-value pairs back to the browser. The problem is that it takes on an average about 15 minutes to build this hashtable, and as a result, I always get a timeout error. What can I do to avoid getting the timeout error without changing the server configuration for timeout
View Replies View RelatedTried creating a simple sample but all works as expected.
The following code prevents the cursor from moving when inside a cell of a JTable.
public void keyPressed(KeyEvent e) {
if ( (e.getKeyCode() == KeyEvent.VK_KP_LEFT) || (e.getKeyCode() == KeyEvent.VK_KP_RIGHT)
|| (e.getKeyCode() == KeyEvent.VK_RIGHT) || (e.getKeyCode() == KeyEvent.VK_LEFT) )
{
//Do nothing
e.consume();
}
}
});
When editing a cell, the existing code would use the right/left cursor keys to move from cell to cell as opposed to from character to character when editing a cell. I planned to override the functionality by tossing in the above code as a test to see if it stops the functionality before I override it.
After placing in the above code, the above functionality no longer occurs, but now the cursor moves within the cell as I wanted which is to move from character to character instead of cell to cell. Its great it works, but it really shouldn't. Essentially the default behavior has been restored when it should have really disabled the left/right keys.
I assume there is some underlying class someplace that is doing something to affect the behavior. Since a sample can't be provided I am wondering in what scenarios would the e.consume() restore default functionality?
i am developing a web application and uses jsp page to print a payment receipt.
everything works good, but printer scrolls complete sheet after printing first receipt. so need scroll back manually every time i print a receipt.
So, how to stop printer from scrolling entire sheet.
I'm learning about inheritance and part of my problem is to create an Order with methods, then an UpdateOrder where the total price is changed by adding four dollars to it, and then a main method displaying a few orders. I've copied all three below in order. My question is when I run the program it will display the totalprice() first for the second order followed by name, number, etc.what you override always displayed first regardless of the order you put them in? (The issue is at line 31 on the third code.)
import javax.swing.JOptionPane;
public class Order { //superclass
private String customerName;
private int customerNumber;
protected int quantityOrdered;
protected double unitPrice;
protected double totalPrice;
[code]....
I am new to java i dont understand the difference between the abstract and inheritance i mean we use the abstract class with extends with other class name ,even we do that same in the inheritance pls tell me main difference between abstract and inheritance...
View Replies View Relatedhow inheritence and exception work together ?? what are the rules ??
View Replies View RelatedIf I define a class which contains a few static fields, and then have a few classes who inherit this class, then all these classes would have the static field as well. Now my question is the following: would all those sub classes (and the base class itself) share the same object, or would each class have one object for all it's instances?
View Replies View RelatedI've tried to write a package and two classes this way:
<path>/pack/Aclass.java
Java Code: package pack;
public class Aclass<T> {
private T t;
public void set(T t) {
this.t = t;
[code]....
I am in an intro programming class and we got assigned a problem for creating a super class with about a dozen sub classes for generating a random word(via WordGetter class) and then comparing that word to a variety of different patterns(like: does the word contain "re"). We were given the super class which looks like this...
public class Pattern {
public boolean matches(String text) {
return true;
}
public String toString() {
return "(TRUE)";
[code]...
and from this class, we have to write subclasses that override those three methods. I am struggling to understand inheritance and I am not really sure where to even start. Here is the instructions for the first sub class we need to write...
"CONTAINS" SUBCLASS
Constructor: The constructor accepts a String named ‘letters’.
Matches: This pattern matches any text that contains at least one occurrence of each ‘letter’.
toString: produces the text “(CONTAINS <LETTERS>)” where <LETTERS> is the ‘letters’ string.
getLetters(): this method must return letters.
equals(Object): careful on this one. Two Contains are equal if they have the same letters (order is not relevant).
(Example):
Pattern p = new Contains(“re”);
boolean f1 = p.matches(“renew”); // f1 is true
boolean f2 = p.matches(“zoo”); // f2 is false
String s = p.toString(); // s is “(CONTAINS re)”
boolean f3 = p.equals(new Contains(“er”)); // f3 is true.. really..
The first is clear , new Person().printPerson(); displays Person but for the second : new Student().printPerson(); it accesses the Student constructor that points to the Person class => object. It builds the Person instance then goes back to the Student constuctor .Both methods are private and to my knowledge invisible one to the other , except that you cant run the the Person one because it's private so the only one in the Student class is the Student one . Guess it 's incorrect , but why ? (is because private methods cant be overriden and somehow the super class one always has priority ? , even if it's private?)
public class Test {
public static void main(String[] args) {
new Person().printPerson();
new Student().printPerson();
[code]....