JavaFX Get Coordinates From Path?
May 8, 2014
I'm working on a project right now in JavaFX, and got stuck. I am drawing a path consisting of CubicCurveTo's and I wonder if there's any way to get the X and Y coordinates from certain parts of that path.
Imagine following a curve (path) with a pencil slowly, and every second you take note the X and Y coordinate. I mean I'm not interested in the control points or start and end points, but the points "in between", preferably at a certain interval.
I've searched for many things online, but have trouble knowing exactly which words to search for. "Paths" often bring up file paths, traversing, coordinates etc. all fail to give me any good results.
I tried to be as specific I could, and I don't think my current code is of any interest in this matter.
(The point of it all is that the path should simulate the path a person walks, and I will store the coordinates in a database for every second).
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Dec 3, 2014
I done a small application with Javafx that start an Embedded Jetty. All works fine in Windows also with native package. Instead in Mac it works only before native packaging. Seems that the problem is how relative path are considered.
The tree of the content is this:
myfile.jar
webapp (folder)
libs (folder)
Look at this code:
String webAppDir = "webapp";
File f = new File(webAppDir);
log.debug("Path webapp folder: " + f.getAbsolutePath());
if (!f.exists())
throw new Exception("The folder " + f.getAbsolutePath() + " doesn't exist");
[Code] ....
The problem is that before the packaging in Mac the relative path is that where the main .jar is located an so the code works because the webapp folder is found. Instead after the bundle the path became /Users/MyUser/webapp and of course the folder is not found because it is bundled inside the file.app near the libs folder.
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Nov 7, 2014
I am copying the xml files from one folder to other folder, in the source folder, i have some files which have some content like "backing File="$IDP_ ROOT/metadata/iPAU-SP-metadata.xml" but while writing to the destination folder.i am replacing the "$IDP_ROOT" with my current working directory. The entire copying of files is for deploying into tomcat server. The copying is done only when server starts for the first time.Problem: If i change the folder name from my root path in my machine after i run the server,the entire process will be stopped because the destination folder files already contains the content which is with existed files names or folder names.
So i want to change it to relative path instead absolute path. What is the best way to do it? Please look at code below:
[ // Getting the current working directory
String currentdir = new File(".").getAbsoluteFile().getParent() + File.separator;
if(currentdir.indexOf("ControlPanel")!=-1){
rootPath=currentdir.substring(0, currentdir.indexOf("ControlPanel"));
}else{
rootPath=currentdir;
[code]....
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Jul 4, 2014
I am planning a race simulator car and I have a problem to get the x and y coordinates from the graph (or circuit). I explain the problem better. If I for example, drawing an arc using the library DRAW2D how do I get all the points in x and y coordinates of that arc?
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Oct 29, 2014
A triangle is defined by the x- and y- coordinates of its three corner points. Compute the following the following properties of a given triangle: the lengths of all sides, the angles at all corners, the perimeter and the area. The program must prompt a user for the point coordinates. I have created a class Triangle and a class TriangleSimulator, I am stuck and can't figure out why my program won't run correctly.
import java.util.Scanner;
public class Triangle {
Scanner in = new Scanner(System.in);
private int x1;
private int x2;
private int x3;
[Code] ....
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May 8, 2014
What are the x- and y-coordinates of the Points referred to as p1, p2, and p3 after the following code executes? Give your answer as an x-y pair such as (0, 0). Recall that Points and other objects use reference semantics.
PHP Code:
Point p1 = new Point();
p1.x = 17;
p1.y = 9;
Point p2 = new Point();
p2.x = 4;
p2.y = -1;
Point p3 = p2;
p1.translate(3, 1);
p2.x = 50;
p3.translate(-4, 5); mh_sh_highlight_all('php');
P1:
P2:
P3:
My guesses were: P1:(20,10) //Correct
P2:(50,-1) //Incorrect
P3:(0,4) //Incorrect
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Mar 25, 2015
How to find coordinates of transparent area in the image. I working on .png image which has transparent background and transparent area in the middle of the image. The transparent area in the middle look a like ellipse, so i want to find coordinate of top, bottom, left, and right of that area. I am using opencv.
I have tried to find pixels and from result that i got, i understand that pixel with rgb that equal to 255.0 255.0 255.0 is transparent. what i have in my mind is, if rgb with value that equal to 255 255 255 detected, i will put 1 into arraylist named transparent, and if it not equal to 255 255 255 i will put 0 into the list. So when i look into the list, if there is 1 0 or 0 1 it means that border between transparent area and colored area or vice versa. But, how to know if that border is between transparent area in the middle of image and the image, and not between background and the image. Am i doing this correctly?
Here snippet of code.
Mat imgMask = Highgui.imread(imgfile);
double[] pixels = new double[3];
System.out.println("channel " + imgMask);
for(int x = 0; x < imgMask.cols(); x++) {
for(int y = 0; y < imgMask.rows(); y++) {
pixels = imgMask.get(y, x);
[Code] .....
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Apr 3, 2014
-7984749.593824852,5368675.690126911 -7984392.035620423,5367570.791302501 -7983220.843257783,5366848.500158152 -7982343.534350842,5364796.5795687605 -7980293.251969412,5363408.488192292 -7980621.978425723,5361760.555707421 -7979175.604281852,5359233.088002191 -7977402.284793513,5358332.850725802 -7976513.843937492,5357665.108234091 -7976472.321767421,5357241.582554582 -7974834.812057852,5357842.933691362 -7973351.925120993,5354420.819505452 -7973743.435770122,5354147.992005592 -7973309.512395002,5352911.428583422 -7973639.9086436825,5352740.575552852 -7972698.034432082,5350359.050518452 -7972255.539456172,5350294.883494262 -7971909.001881332,5349519.720176511 -7970907.683061652,5349775.605440161 -7970575.617020612,5348986.585139751 -7970013.342272613,5349482.445545332 -7969898.683197102,5350177.703443532 -7968337.649977702,5350328.647515352 -7967111.243147633,5351652.264468962 -7966171.150047882,5351373.1018466605 -7966125.286417683,5352115.720678982 -7964626.258154663,5351707.120082232 -7955765.449326492,5345109.379313592 -7954159.443032822,5343966.704795052 -7942364.363746833,5335522.893249432 -7929990.868386692,5326092.063381992
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Jul 23, 2014
I extracted columns from database and made calculations inside while loop. I know i need to make array to get from it coordinates for points. I want to draw them in interface created in another class but i have black hole and don't know how to get datas from while loop to array which is below.
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Mar 16, 2015
how to create coordinates in a two-dimensional grid, in the end it shall look like A5, F6 and so on. The aim is to place 3 DotComs in this grid by coincidence. To do this one uses two arrays. One array represents one DotCom, the other represents the grid's size, in this case 49 (7x7).The code ends like this:
ArrayList<String> alphaCells = new ArrayList<String>();
...
int x = 0;
int row = 0;
int column = 0;
while (x<comSize) {
grid[coords[x]] = 1; // mark master grid points as used
row = (int)(coords[x] / gridLength);
column = coords[x] % gridLength;
temp = String.valueOf(alphabet.charAt(column));
alphaCells.add(temp.concat(Integer.toString(row));
x++;
}
return alphaCells;
}
why row and column are calculated like this. Furthermore I don't understand why the column is used to generate a character, because columns are marked with numbers and rows are marked with characters.
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Apr 26, 2014
//Design/write a class named MyPoint to represent a point with x and y coordinates. The class should contain:
//->Two variables, x and y, that represent the coordinates
//->A no-arg constructor that creates a point (0,0)
//->A constructor that constructs a point with specified coordinates
//->Two getter (accessor) methods for the variables x and y
//-> A method named distance that returns the distance from a point to another point of the MyPoint type
//-> A method named distance that returns the distance from a point to another point with specified x and y coordinates.
//Draw the UML Diagram for the class. Implement the class. Write a test program that creates two points (0,0) and (10, 30.5) and displays the distance between them.
I have written the program but not I have to do it with user input ....
class MyPoint {
private double x;
private double y;
public double getx()
{
return x;
}
public double gety()
[Code] ....
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Jan 27, 2015
The code is used to find coordinates of an image and i cannot understand how it works.
for (int y = 0; y < height; y += 2) {
for (int x = 0; x < width; x += 2) {
int px1 = secureRandom.nextInt(4);
int px2 = secureRandom.nextInt(4);
while (px1 == px2)
px2 = secureRandom.nextInt(4);
int px1x = (px1 < 2) ? px1 : px1 - 2;
int px1y = (px1 < 2) ? 0 : 1;
int px2x = (px2 < 2) ? px2 : px2 - 2;
int px2y = (px2 < 2) ? 0 : 1;
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Oct 31, 2014
I am writing a java program that takes a FROM image, a TO image, and a ratio (this is a slide bar in the GUI). Here's my code:
Java Code:
public static BufferedImage rollUp (BufferedImage from,
BufferedImage to,
double ratio) {
BufferedImage finalBufferedImage = new BufferedImage(from.getWidth(),
from.getHeight(),
from.getType());
int packedColor = 0;
for (int r = 0; r < from.getHeight(); ++r) {
for (int c = 0; c < from.getWidth() ; ++c) {
[code]...
So from 0 to 1 (ratio is a double between 0 and 1) the image will "roll up". The effect works completely in the GUI, but the console freaks out at about 0.33 ratio.. This program runs for testing in a class Main and uses a class Splittinimage.. this method is in class TwixPix. When the main class is run, a box pops up with a combo box and a slider. You pick an effect (in this case, roll up) and then slide the slider to set the ratio. The image below those two things performs the effect that was selected. Imagine a PowerPoint presentation slide effect.
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Feb 15, 2014
Ok, so I am relatively new to datagrams etc. I have three projects set up right now: Client, Client2, and Server, which all interact with each other to send coordinates of player1 and player2 back and forth (X, Y, this is in 2D space not 3D). I have everything set up perfectly except for one problem: I can only send the X coordinate back and forth for each player. I am getting the weirdest error, a parsing error. The way I communicate is I have everything sent back and forth in one string. Then I use the .split() function to turn that string into an array that contains the x and y coordinates. I've done several tests and to no avail. Here's my code:
Server:
Java Code:
package theGame;
import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import java.net.SocketException;
import javax.swing.JOptionPane;
public class Main {
static String p1X;
static String p1Y;
[Code] ....
Lines 177 on Client1 and 172 on client2 are where the debugger is saying that I parsed wrong.
Also, if your are going to test this you will need to have the LWJGL libraries in your build path.
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May 24, 2014
I'm having a random x and y coordinate generate and I need to check if the coordinates are inside of a right triangle on this imaginary coordinate plane.
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Mar 6, 2015
The idea I'd like to present, concerns the correction of "designer" drawings - those done by the design consultants - against "site/construction" drawings - them being used on site by the workers to build the project itself.
This is normally a laborious process, involving being sat at a desk with two large folders, checking each detail and measurement against the design drawing.What I'd like to present is an idea, where the co-ordinates of the design or "mother" drawing, are transferred into a usable Java program, and they could be then used to ensure correct dimensions have been applied by the the sub-contractors in their "construction" drawings.Like I said, this can normally be a process of days for a site engineer to check - process known as "QA, quality assurance".
Basically, I just need to make a presentation of having a genuine interest in Software Design and Development. It could be applied in a range of areas in terms of construction site application - checking drawings, writing up work orders, dig orders etc - but the principle of having the co-ordinates of the mother or "design" drawing scanned into an array in Java as a means to output those site drawings/orders etc, applies to each potential application.
So - in short - and not looking for crystal clear detail, just general pointers - what programs or methods could transfer a plethora of co-ordinates from a design program like Auto-Cad, to a Java program, where I assume I would then be using a program containing a complex series of loops to ensure the correctness of the derived "construction" drawings; derived from the "mother" or designer drawings, that is.
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Feb 1, 2015
Basically I'm looking for a way to make one object follow another. For example, if I move object A to one area of the screen I want object B to to move to object A's location but I also want object B to move at a fixed speed (movement variable). How do I go about doing this?
Both the x and y coordinates of object B would need to know the coordinates of object A to calculate the distance between the two and to determine how much of which axis to increment/decrement (if that makes sense?) with the inclusion of the speed variable. In other words I'm just trying to create a homing object.
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May 29, 2014
(Corner point coordinates) Suppose a pentagon is centered at (0, 0) with one point at the 0 o’clock position. Write a program that prompts the user to enter the radius of the bounding circle of a pentagon and displays the coordinates of the five corner points on the pentagon. Here is a sample run:
Enter the radius of the bounding circle: 100
The coordinates of five points on the pentagon are
(95.1057, 30.9017)
(0.000132679, 100)
(-95.1056, 30.9019)
(-58.7788, -80.9015)
(58.7782, -80.902)
What we know , we know both the radius of the circle(user inputted) and the side of the pentagon from formula (double side = 2 * radius * Math.sin(Math.PI/5)) .We also know that one point is (0 .100) Also i know that the distance between 2 points is Math.sqrt(Math.pow(x1 - x2 ,2) - Math.pow(y1 -y2 ,2)) .
There might be other ways to solve it but this is my best bet trough i dont remember how to solve linear equations of the form x^2 + y^2 = - radius and radius ^2 = x^2 + (y - 100) ^ 2..
The solution i found is using the radius from the center to the point we want to find out and using the radius to the point we already know ( 0 .100) but i have to solve that damn equation first ...
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May 5, 2014
My OS: Windows 7
Problem:
I've tried where javac in command prompt but it can't locate it. I need to know how to set JDK 8 as PATH.
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May 12, 2014
What I do wrong when I trying to set path to file in my jar app. I have application which work with xml file. I have next project structure:
/project_root_directory
|_ /lib
|_ /resources/file.xml
|_ /src
So, I need to set correctly path to my jar file, because when I running it from IDE, it works nice. By default it seems:
private File file;
private StreamResult streamResult;
file = new File("resources/file.xml");
streamResult = new StreamResult(file);
And methods where I can modify the DOM structure via transformer in end of methods:
transformer.transform(source, streamResult);
So, I trying set path to file:
private URL url;
...
file = new File(url.getPath());
streamResult = new StreamResult(file);
But it didn't not work, because when I trying to get resource by next condition
url = getClass().getResource("resources/file.xml");
url = getClass().getResource("resources/file.xml");url = getClass().getResource(url = getClass().getResource("resources/file.xml");resources/file.xml");
url - is null
Okay..
I tried next solution
InputStream input = getClass().getResourceAsStream("resources/file.xml");
There, I got also null....
Also, I tried made absolute path
filePath = file.getAbsolutePath();
file = new File(filePath);
streamResult = new StreamResult(file);
But it also didn't work. There I got message seems like: "Can't find resource /User/user1/Desktop/program1/resources/file.xml" - but that's really absolute path to a file.
Also, I tried made it via System.getProperty
String filename = "file.xml";
String workingDir = System.getProperty("user.dir");
finalfile = workingDir + File.separator + "resources" + File.separator + filename;
file = new File(finalfile);
I also made unit test which completed with "green light", but in jar its wrong with message "Can't find resource /User/user1/Desktop/program1/resources/file.xm" ....
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Sep 11, 2014
relative path not working if specified folder is outside eclipse IDE, but if i put same folder in current project it is working.
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Feb 25, 2015
I have the Java Development Kit downloaded in my C file and my book tells me to compile the program I need to open command windowand change the directory where the program is stored. I tried the command cd to change directory and received this message "The system cannot find the path specified."
I checked the Environment Variables on Windows 7 and the Path says: C:Program Files (x86)Javajre1.8.0_31in
This is after many tries and i still can't change directory and i keep getting the same message.
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Mar 2, 2014
I have BlueJ installed on my computer and it does the job of compiling the java source code written in it. If I want to write and compile source code outside of BlueJ do I still need to download the Java SDK and set the PATH variable, even though I am apparently able to do it in BlueJ?
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Feb 5, 2014
I have a data.json in my J2EE web app.I need to load it either from local path when unit testing or from url when the server starts up.
so I've set it to get the local path by default and what I'm trying to do is that it is is running on a server, I'd like to change the path to a url.
Here is my code:
public String getUrlBase(HttpServletRequest request) {
URL requestUrl;
try {
requestUrl = new URL(request.getRequestURL().toString());
String portString = requestUrl.getPort() == -1 ? "" : ":" + requestUrl.getPort();
return requestUrl.getProtocol() + "://" + requestUrl.getHost() + portString + request.getContextPath() + "/";
} catch (MalformedURLException e) {
e.printStackTrace();
}
return null;
}
which works fine. The only issue is that I had to place this in the login page. Is there a way I can only set the path to the base url upon server start up?
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Feb 24, 2015
I have the Java Development Kit downloaded in my C file and my book tells me to compile the program I need to open command windowand change the directory where the program is stored. I tried the command cd to change directory and received this message "The system cannot find the path specified." I checked the Environment Variables on Windows 7 and the Path says: C:Program Files (x86)Javajre1.8.0_31in
This is after many tries and i still can't change directory and i keep getting the same message.The book I am using to learn Java is "Java How to Program: Tenth Edition" from Paul and Harvey Deitel.
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Jan 8, 2014
When I write below command:
which mvn
I see below output
/usr/bin/mvn
But it is not the maven installed by me. I think it came with linux
Now I want to change mvn path with following command:
export M2_HOME=/usr/local/apache-maven/apache-maven-2.2.1
export M2=%M2_HOME%bin
But it does not change. I still see
which mvn
I see below output
/usr/bin/mvn
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