Letter Count - Ignore All Numbers Or Punctuation Marks
Nov 13, 2014
I'm trying to make a program that will count each letter like if I put the word
e-1
h-1
l-2
o-1
The problem I'm running into is that if I put something like How now, brown cow? It should give me something like this
b - 1
c - 1
h - 1
n - 2
o - 4
r - 1
w - 4
but it doesn't instead the whole program crashes because of the punctuation marks and the spacing. Is there a way for me to fix that? All I know is that it has something to do with the alphabet[pos(letter)]++;
import java.util.Scanner;
public class CharCount {
static Scanner keyboard = new Scanner(System.in);
//this method should allow the user to enter a line of text (that should all be lower case) and then go to the printResults method
public static void main(String[] args) {
String text, character;
int count;
char letter;
int[] alphabet;
System.out.println("Enter a line of text:");
text = keyboard.nextLine().toLowerCase();// any text entered will be lower case
alphabet=countLetters(text);
In c++, I'm aware that you can use the ignore function to ignore numbers after space, but in string how do I ignore a number after space is found for instance, "109 33" how would I ignore 33?
import java.util.Scanner; public class CountStringNumbers { // show the number of Strings that were numbers . . .. public static void main(String []args){ int count = 0; int countNumbers=0; Scanner input=new Scanner(System.in);
[code]...
can count the numbers from 0-9 if the user puted but if it is 10 it doesnt count it , and i need to write all the numbers to have that option. . . . Is there an easy way that includes all the numbers? like if(word.equals(number)){<<<???? (numbers) i know htat doesnt work but is there anything similar ?? ??
countNumbers++; } System.out.println("Type Something , , , and to end the the termination type STOP"); word=input.nextLine(); count++; } System.out.println("You wrote "+count+" lines wich from those lines "+countNumbers+" were numbers and the programe terminated "); } }
i am trying to turn an int number etc. 6 into 6 symbols the result would be "------". how can i transform int=6 into "------"? what function do i have to use to do this count?
public class Diagram { public static void skrivDiagram() { Random rand = new Random(); int[] frequency = new int[13]; {
for (int roll = 1; roll <= 100; roll++)
[code]....
Here i want to transform the frequency[face] into "-".
import java.util.Scanner; public class main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int number; System.out.println("Input a number");
[code]....
What i want to do is that if the number is greater than 50 to count until 100. else if the number is less than fifty to count for example from 36 to zero.
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays; public class countDigits { public static void main(String[] args) { //Create random generator and values int numbers = (int)(Math.random() * 10); int arrayCount = 1;
I have a problem with functions connected to strings.
I have a random String, e.g. "Hello World!" and I have to change every capital Letter into a small letter and vise versa. This alone would be fairly simple, but I have to do it with two other strings.
lowercase= "abcde...z" and
uppercase="ABCDE...Z". Every small letter stands at the very same position as the capital letter, but in the other string.
There should be a letter for letter search in lowercase and uppercase for the letters of "Hello World".
How I could solve the task, however I need a way to search the first string, here "Hello World", according to position. A statement which does: "Give me the letter of position x". This found letter should be able to be stored in a variable or else be able to be used by another statement. And it should be compatible with a for lope.
Example : I have code and name but my code must start with the first letter of the inputed name if the 2 input is match it will be inserted into database
code = "A"001 name ="Angela" = success this will inserted into database
else
code ="B"002 name="Angela" =failed this will not inserted into database
else
code="A"003 name="Andy" =success still accepts the input cause they have diff code number
What I am thinking on this was compare the code the name? if == it will be inserted but how do i get the 1st letter of the input name?
Write an application, HiFour that prompt for four names and then prints the greetings, but with the names in reverse order and with punctuation as shown in the example.
How do i write a method in java that will add a <b> or <em> tag to a specific word regardless of case or punctuation for example for "run forest RUN!" adding bold to run would be
<b>run<b> & <b>RUN!<b> public void addTag(String word, String tag) {
I'm trying to loop through a string and depending on the character, add a JLabel to a game. The problem is the character 'L' represents a lantern but is also used in the reply the game gives which is "LOOKREPLY". I've tried to use some code to ignore the LOOKREPLY bit but it's not working. Here's what I've tried.
But the first image on all of the JLabels is always a lantern, which is what L represents. As it's only 1 lantern this leads me to believe that it's ignoring the first 'L' but for some reason it's not ignoring the 'L' at the end of LOOKREPLY.
Write a program that continuously asks for an alphabet letter, and stops when a non-alphabet letter is entered. Then output the number of upper case letters, lower case letters, and vowels entered ....
I have an array with the following characters {'E', 'L','E','P','H','A','N','T','P','O'}
now, I need an array that will store the first array such that only the occurence occurs e.g {'E','L','P','H','A','N','T','O'} Notice that the characters 'E' and 'P' occur twice and as a result were not repeated the second time in the new array.
How would one go about this using the counting elements technique?
I tried this but not sure how to use the counting elements technique.
char [] arr = new char{'E', 'L','E','P','H','A','N','T','P','O'}; char[] bucket = new char[(arr[0] * arr.length)]; for (int i = 0; i < len; i++) bucket[arr[i]]++;
I have this piece of code, which adds marks into 2 different arrayLists, one for homework marks, and one for examination marks..
ArrayList<Double> homeworkMark = new ArrayList<Double>(); ArrayList<Double> examinationMark = new ArrayList<Double>(); boolean markCheck = true; do{ // the purpose of this try catch is to make sure that the entered mark is a valid number. If the program encounters an exception markCheck will become true and the loop will begin again asking the user to enter the marks. If the marks are all encountered correctly markCheck will be false and the loop will end.
try{ for (int i = 1; i <= amountAssignment; i++ ) { sc.reset(); System.out.print("Homework Mark for Assignment " +(i) + ": "); homeworkMark.add(sc.nextDouble()); System.out.print("Examination Mark for Assignment " + (i) + ": "); examinationMark.add(sc.nextDouble()); markCheck = false;
I have made a program, where the user types in a letter M, C or I to identify their major, if the user types m, c or i, my code does not work.
How could I make my program ignore if the letter is upercase or lowercase? My code is posted below. Can I do this in any easier way then adding this type of code for each lowercase letter?:
Java Code:
if (s.charAt(0) == 'm') System.out.print("Mathematics "); mh_sh_highlight_all('java');
My current code:
import java.util.Scanner; public class c4e18 { public static void main(String[]args){ Scanner input = new Scanner(System.in); System.out.print("Enter two characters: "); String s = input.nextLine(); if (s.charAt(0) == 'M')
I wrote code to remove question marks and exclamation points from some text. However, one can find those in my output file. Interesting enough, the periods (full stops) were removed.
import java.util.Scanner; public class TextTokenizer { private Scanner scanner; private String[] removableCharacters = { ".", "?", "!", ":", ";", """, "'" }; public TextTokenizer(char[] texts) { scanner = new Scanner(new String(texts));
I'm new to Java, & am using Eclipse Helios. How do I change the text colour within the Quotation marks "Try Again" to red, or any other colour, so when I run it, it will display the new colour.
public static void main(String[] args) { Scanner Keyboard = new Scanner(System.in); System.out.print("Please enter your name."); String name = Keyboard.next(); name = "name";
I have several Buttons wrapped into a VBox. I used setOnSwipeUp and setOnSwipeDown for up and downs the buttons. But when there is no more buttons the scroller continues but shows nothing, is empty. How do I do when there are no more buttons ignore swipe gestures?
[Java] // Menu Swipe Up menubox.setOnSwipeUp(new EventHandler<SwipeEvent>() {
So if I wanted to tell the user that the fifth letter they entered is "____" how would I do that.
I am prompting the user to enter a word and then displaying the length of the String. Now I want to display to the user what the fifth letter of the String they entered is.
import java.util.Scanner; public class StringPractice { public static void main(String [] args) { Scanner input = new Scanner(System.in); String word; int lenght;
I'm writing a java program in eclipse of a tic-tac-toe game. I have to create it using JTextField's only I'm having trouble where the JTextField will only accept one letter and will only accept X and O is there any particular way to do this I started off with this piece of code
String text=tf1.getText(); if(text.length()>1) { System.out.println("this is not allowed"); tf1.setText("");
But it doesn't work so is there something I'm missing....
I'm trying to figure out the correct way to replace number into letter. In this case, I need two steps.
First, convert letter to number. Second, restore number to word.
Words list: a = 1, b = 2, f = 6 and k = 11.
I have word: "baafk"
So, for first step, it must be: "211611"
Number "211611" must be converted to "baafk".
But, I failed at second step.
Code I've tried:
public class str_number { public static void main(String[] args){ String word = "baafk"; String number = word.replace("a", "1").replace("b","2").replace("f","6").replace("k","11"); System.out.println(word);
[Code] .....
Result for converting to number: baafk = 211611 But, result for converting above number to letter: 211611 = bkfk
What do I miss here?
How to distinguish if 11 is for "aa" and for "k"? D