I was asigned to make a code that would limit the input to 1 character when asked for the initial of your middle name. So far I have the code ask for your first name then your last name and out put "Hello" firstname+last name. Im trying to add an 1 character middle itnitial in there.
View RepliesI would like to limit my bandwidth usage when accessing/downloading files (similar to the --limit-rate 50K option for curl and wget) as the website has limited bandwidth. I am not exactly sure how to implement this, but I'm guessing it be accomplished via the BufferedReader? I have attached the current code below.
import java.io.OutputStream;
import java.io.BufferedReader;
import java.io.InputStreamReader;
[Code]....
I defined a java class thus:
class Info{
public String name;
public String version;
public String arch;
double CPUSpeed;
double ranUtil, CPUUtil;
};
But each object of such a class takes many bytes. How can I limit it to one fourth of a Kilo-Byte?
When casting a char which is read from a file to an int, can i assume that the mapping used will be ASCII? I've learned that unicode uses ASCII mappings for the characters that overlap.
Are there any other possibilities for int values of one character? I still have trouble understanding character encodings.
I was reading about the char data type in Java. I know that an unsigned 16 bit integer is used to represent a char. So we can write the assignments below:
char a = 65; // a will get the value 'A'
But the limit of the char value is 65535.
So I've tried out a few things with char and trying to understand them but I'm not sure how they work.
char a =(char) 70000;
char b = (char) -1;
In the first case I thought that 70000 % 65535 would happen internally and the unicode character present at that location would get stored in 'a' but if I do that I get the answer of 70000 % 65535 as 4465. But when I display 'a' it shows me the output as '?'. Clearly '?' isn't at 4465.
In the second case I have no clue what's happening but somehow when I display 'b' it shows me '?' again.
I need making char[] to a string im not entirely sure what to change i'm just suppose to use a string value but the upperclassmen used char:
char[] number = clear.toLowerCase().toCharArray();
for(int c = 0; c < number.length; c++) {
if(digit[c] < 'a' || digit[c] > 'z')
continue;
[code]...
I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:");
String printingString = "a";
for (int i = 0; i < 50; i++)//loop to obtain 50 random characters
{
char randomChar = (char) ((Math.random() * 255) +32);
System.out.print(randomChar);
printingString = Character.toString(randomChar); }
return printingString; }
I'm trying to write something to will convert my Scanner input which will be either a string or a char toUpperCase but it is not working.
import java.io.File;
import java.util.Scanner;
public class UpperCase {
public static void main(String [] args) {
Scanner kb = new Scanner(System.in);
char reply;
[code]....
Goal this time is to take a charArray, copy it into another charArray while reversing the things in it.
E.g. charArray["!ollaH"] into charArrayNew["Hallo!"]
My first idea was to revert the stuff in the Array with a ! cause i saw earlier that u can work with that too revert booleans. Sadly i didnt happen to make it work.
Next thing i thought of was a for loop to go trough the charArray and copy every section into charArrayNew just at the opposite end.
Java Code:
import java.util.Arrays;
public class aufgabe43 {
public static void main(String[] asgr){
char[] charArray
[Code] .....
Eclipse doesn't show any errors, and as u told me last time i did include import java.util.Arrays; to output the array in the end.
When i try to compile the code eclipse returns with an error
Java Code:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 68
at aufgabe43.main(aufgabe43.java:8) mh_sh_highlight_all('java');
Which I frankly don't understand since the array . Length is exactly the same.
I am trying to get user input for a char value and am having some difficulty getting input for a char value.
Java Code:
//imports packages
import java.io.*;
import java.text.DecimalFormat;
class ModuleCulminatingTask {
public static void main (String args []) {
//declares variables
float var3, var4;
long var5 = (int)(Math.random()*10);
[code]....
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
int hours = getHours(kb);
char major = getMajor(kb);
[code]....
I'm trying to return a char c,o, or x if that is their "major code" that the scanner grabbed.
I what to check if value is not equal to CharSequence value
I try this but getting error:
Java Code:
private CharSequence testvalue = "";
if (!isEqualTo("BCDEF".contains(testvalue))){
}
public boolean isEqualTo(String s_src, String s_compareTo) {
boolean flag = false;
[Code] .....
I need to understand the java Conversion.
I have a char[] containing ASCII characters that need to be converted into int value and double value.
The int value are always stored in 1 char size like 'j'. I extracted it succesffully by converting the char in a ascii bytearray and then used: Integer.parseInt(sb.toString().replace("0x", ""), 16);
How can I get the Value as double when i used the char[] with size 2 or 4 ?
Example : final char[] charValue = { 'u', ' ', '}','+' }; what is the associate Double value ?
Example : final char[] charValue = { 'T', ' ' }; what is the associate Double value ?
Example : final char[] charValue = { 'T', ' ' }; what is the associate int value ?
You can also use an escape code if you want to represent a character that can't be typed in as a literal, including the characters for linefeed, newline, horizontal tab,backspace, and single quotes.
char d = '
'; // A newline
char c = '"'; // A double quote
But for the newline code that is escaped above, it still gives me a new line. Is this a typo? Shouldn't it be '' for it to be escaped?
I found a fun program online and something so simple is giving me an issue. I c++ it is pretty simple fix, I can just call the strings location like an array. In java this is not the case. So far i have tried:
myString.charAt();
myString.indexOf();
There are a few other I found on google but I forget at the moment. I am just trying to close the gap on a string. It was a full sentence and I used replaceAll a few times to get several words I didn't want in the file out.
So my goal is to build a word search here. The road block I have run into is how to save words, input from user, into an array. Then once I figure that out I need to try and arrange them in such a way so that they will fit into my array without screwing with one another. It does not have to be working exceedingly well I mean really it can be assumed that the users will not try to screw the program up. Ie one or two words and a fairly large table will be all the input. Here is the program as of now:
import java.util.Random;
import java.util.Scanner;
public class BuildWS
{
int r;
int c;
char[][] array;
String query = " ";
[code]....
So I am working on a project for my Java course and for whatever reason, I am absolutely struggling with this assignment. I've made some progress but I can't seem to completely wrap my head around the algorithm I'm being told to use. I feel that everything is correct up to a particular point.I believe I am having issues moving a char array into a char matrix.
package edu.cofc.csci221.ui;
import java.lang.*;
public class Decoder
{
private int[][] M;
[code]...
Would I just need to loop through lsb one at a time and assign them to sequential spots within D? Basically call my get binary value and such in the outer loop and then use the inner to loop through both arrays and reassign values?
Character replacement in string.If I have a String "aaaaa" and what to replace just one "a",with a different character say "J" how can I do this? Everything I've tried replaces all not just one
View Replies View RelatedI'm trying to take the information from one 2d char array and put it into another char array but instead of traversing the array left to right I want the new array to be top to bottom.
Example fg would be fh
hi gi
I'm having trouble getting the information from one to the other.
[code]public static char[][] translateIt(char[][] english){
int rows = english.length;
int columns = english[0].length;
char[][] chinese = new char[columns][rows];
for(int j=0; j < columns; j++){
for (int i = 0; i < rows; i++){
//chinese[i][j] = english; this is commented out because it didn't work.
}//Ending bracket of columns for loop
}//Ending bracket of rows for loop
return chinese;
}//Ending bracket of translateIt[code]
How can I display this result.aJohny
I have array contain numberi create new char array and i want to check if a number is >= 90 in array then input A at the same index in char arraythen second part i want to check if char array contain "A" then a = a + 1.
The result is like this:
A: 5
B: 29
C: 38
D: 24
E: 12
F: 17
public class Test {
public static char[] grades(int[] getMarks) {
char[] grade = new char[getMarks.length];
for (int i = 0; i < getMarks.length; i++) {
if (getMarks[i] >= 90) {
[Code] .....
what will i compare in if statemet is the 1st letter of each if i have code="a" and name="Angelina" first letter of each is "a" and "A" then in convert it to string so that i can make it uppercase but when i compare it in if statement it always go into "not x" but the ouput that im getting is x=A y=A then it always direct me into else statement.
String code = "a";
String name = "Angelina";
char c = code.charAt(0);
char n = name.charAt(0);
[code]...
I was trying to store the content JTextField on char..... Here's the instruction of program--->>create a GUI program that convert letter into corresponding no. EXAMPLE:
if user enter "c" then it will output "3"......
like a=1,b=2,c=3,......
Here's my code
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class convert extends JFrame {
private static final int width = 400;
private static final int height = 300;
private JLabel EN,EQN;
[code]....
I tried to make a program that takes a string str, and char a and checks how many times the char is used in the string.
Example: the string Welcome and the letter e, is 2 times. so the program should print 2.
It compiles but when I run it and enter the information, i cannot get the printing line out.
Heres my code:
import java.util.Scanner;
class program
{
public static void main(String[] args) {
Scanner user_input=new Scanner(System.in);
String str;
String b;
System.out.print("Please enter a word");
[Code] .....
how can i compare two char type variables, ignoring the Case?
View Replies View RelatedI am trying to count each char in a string. For example A = 1, B =2, C=3, I am not looking for their binary value. So the word "At" would
AT= (A=1 +T=20)=21.
I know how to do this in C++ because I am able to treat a string like an array.
Java Code: void printFile()
{
int sum=0;
String line;
for(char cr ='A';cr<'Z';cr++)
{
for(int i=0; i<myList.size();i++)
[Code]...
import java.io.IOException;
import java.util.*;
public class Guesser {
public static void main(String[] args) throws IOException {
char[] alphabet = "abcdefghijklmnopqrstuvwxyz1234567890 .,:;'-".toCharArray();
[Code] .....
I'm writing a program which will take a three letter word (for now) and then try to guess the word over and over again until it finds it, then print the word and the amount of tries it took to find it.
The problem: at the moment the program will find the word but not break out of the for loop when it does. I think it doesn't like the char to String conversion somewhere along the line.