Looping Through While Loop With Switch Statement?
Sep 23, 2014
I am having a problem with looping a while loop that contains a switch statement. Here is my code:
package hw4jenningsd;
import javax.swing.*;
public class HW4JenningsD {
[Code].....
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Dec 8, 2014
I am trying to add a while loop into my switch statement. If you run the program, it will ask to enter the class grade (9,10,11, or 12). If you insert 5, it will say to try again. But, if you enter a wrong number twice, it will continue on to the next part of the program, which is asking how many students are in the class. Therefore, I believe a while loop would work, but it is not working at all. The program still runs, just doesn't fix the error. The program is below:
import java.util.Scanner;
public class stephProject {
public static void main(String[] args) {
//call method
welcomeMessage(); //method 1 of 3
[Code] ....
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May 5, 2015
cannot break from while loop. Whenever I am trying to exit from startCustomerManagement-> backEnd() -> mainScreen()..It gets stuck between mainScreen and backEnd screen. However I can exit from backEnd()->startCustomerManagement() screen
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package javaapplication19;
import java.io.BufferedReader;
[code]...
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Sep 28, 2014
I'm trying to create a switch statement inside of a counter controlled (while) loop that asks for an input of...
"How many characters would you like to convert?"
Then you type in a number > 0, and then it should convert letters into the "1337" equivalent.
This is an example on what it should do.
How many characters would you like to convert? 5
Enter character #1 to convert: !
!-
Enter character #2 to convert: $
$-
Enter character #3 to convert: #
#-
Enter character #4 to convert: *
*-
Enter character #5 to convert: ,
, -
Whenever i try to run the program, i only get the- How many characters would you like to convert- i input 5 but then nothing else prints..
My codes..
System.out.print ( "How many characters would you like to convert?: " );
int convertCounter = 1;
char ch;
ch = input.next().charAt(0);
while (convertCounter > 0)
switch ( ch ){
[Code] ....
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Jun 19, 2014
So from what iv learnt in Java and programming in general is that using a case statement is far more efficient that using multiple IF statements. I have an multiple IF statements contained within a method of my program, and would like to instead use a case statement.
public String checkPasswordStrength(String passw) {
int strengthCount=0;
String strengthWord = "";
String[] partialRegexChecks = { ".*[a-z]+.*", // lower
".*[A-Z]+.*", // upper
".*[d]+.*", // digits
".*[@#$%!]+.*" // symbols
[code].....
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Nov 18, 2014
So I want to make a simple Java that ask the user to pick a powers and it has two options.If the user picks magic then execute the first if statement then ask the user again which type of magic the user wants.I can't make it work it keeps printing the else statement. Why is that?
import java.util.Scanner;
public class Variable {
static Scanner zcan = new Scanner(System.in);
public static void main(String[] args)
[code]....
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Apr 10, 2015
this is what code i have so far i want to try and get the computer to output a String type result rather than a number and i wonder if there is a way to output the score after the user is done with the game. I couldn't really see if there was a way to incorporate a switch statement.
import java.util.Scanner;
import java.util.Random;
public class RPSLS {
public static void main(String[] args) {
[code]...
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Jun 22, 2014
I was learning looping in Java and decided to try this code and then I encountered an endless loop of 2s. why is that? I believe this line count=count++ caused it.
class ForDemo{
public static void main(String []args){
int count;
for(count=2;count<=5;count=count++)
System.out.println("count is:"+count);
System.out.println("Done!");
}
}
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Oct 4, 2014
Write a program to calculate sales and visually display. An online Cowboy retailer sells five products whose retail prices are as follows:
Product 1: Cowboy Boots, $74.99
Product 2: Wranglers, $25.99
Product 3: Cowboy Hats, $24.95
Product 4: Chaps, $ 34.89
Product 5: Spurs, $12.50
Write an application that reads the quantity for each product until user has completed their order. Your program should use switch, if, for, while and do while statements to read, calculate and display the total retail value of all pro ducts sold for each user transaction. The user should be able to start a new transaction after the first transaction is completed. The user can make no more than 3 total orders
public class Merchandise {
private int bootsQTY;
private int wranglersQTY;
private int hatsQTY;
private int chapsQTY;
[Code] ....
When I run my program all of my quantities and the total are 0, I have been stuck for a while trying to figure out how to get values assigned to them...
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Sep 6, 2014
What I want to happen is to add 2+ contacts by entering "a" from the menu. Then I want to enter "c" and have it display those contacts. But it doesn't seem to remember that I changed the arrayList masterList.
Java Code:
public class ContactListApp2 {
public static void main(String[] args) {
boolean quit = false;
while (quit == false) {
System.out.println("Main Menu:");
[Code] ....
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May 19, 2014
I am stuck with two switch statements that I feel I am close to achieving. My first switch statement is to generate random mathematical operators for the math questions in the game (generated randomly) My second switch statement is to determines which action the system will take upon the correct or incorrect answer. For the first switch statement I have a variable called num. Num is a random integer. I have an operator mapped to each outcome of num. In my second switch statement I am trying to use the variable answer as a variable in the first case but do not know how.
package pkgnew;
import java.util.Scanner;
import java.util.Random;
public class New {
public static void main(String args[]) {
//Declare and construct variables
[Code] ....
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Sep 10, 2014
In switch case statement string expression whether it will work or not ???
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Feb 21, 2015
I'm using jsoup to parse a calendar page.
I want to use a switch or if/else statement to filter out the data I don't need for the app. This is by no means anything more than a draft because java is easier to work with than android.
Element table = doc.getElementById("launch_calendar");
Iterator<Element> iterate = table.select("td").iterator();
if(iterate.hasNext()){
for(iterate.hasNext();;){
counter++;
[Code] ....
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Feb 23, 2014
I am trying to write out a program that takes numerical input from the user and converts it to a date using the English month name. I am experimenting with the method of a "switch" statement without using the "break" clause. However, I seem to be missing something, as Eclipse is telling me I have a syntax error with my block. My curly braces seem properly placed. Also, I made sure to follow guidelines to make my code fit on the screen and remain easy to read.
import acm.program.*;
public class MethodsThatReturnNonNumericValues extends ConsoleProgram {
public void run() {
int month=readInt("Enter month number");
int day=readInt("Enter day");
int year=readInt("Enter year");
[Code] ....
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Nov 4, 2014
// GradeBook class uses switch statement to count A, B, C, D and F grades.
import java.util.Scanner;
public class GradeBook
{
private String courseName;
private int total;
private int gradeCounter;
private int aCount;
[Code] .....
Then eclipse told me that:
"Exception in thread "main" java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at chapter5_control_statements_II.GradeBook.inputGrades(GradeBook.java:52)
at chapter5_control_statements_II.GradeBookTest.main(GradeBookTest.java:11)"
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Nov 10, 2014
//Use a Switch statement to determine outcomes for letter grades
switch (Letter)
{
case 'A': outFile.println("
Good Work! You have met the pre-req for CIS 220.");
break;
case 'B': outFile.println("
[Code] ....
is not printing the information on the next line in my output file.
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Dec 3, 2014
We're told to make a cash register program for 5 products using Java. It loops until "-1" is entered on the "Continue?" input dialog box.There should be a:
1. Main Menu - where the user will pick what to buy (one product at a time) like the sample code below and prompt the user if he will buy another product or not. If yes, the program will go back to the main menu to buy another product and if not, continue to the program. And it looks something like this: LEvFOwQ.png
2. Receipt - at the end of every transaction.
3. Daily Sales Report where it shows all receipts then grand total like:
Transaction 1
-subtotal
Transaction 2
-subtotal
and so on then,
GRAND TOTAL
4. Inventory Report where it shows the Items Available before the Selling, Items Sold, and Items Available after Selling in table format.
Below is the code for a simple cash register for only one product that I made but I need to upgrade it for it to work for 5 products. That code will serve as the basis for this program.make the switch or if-else statement for the main menu first and if I got it right I try doing the rest.
int userQty1 = Integer.parseInt(JOptionPane.showInputDialog(
"Product ID Product Name Product Quantity Product Price"
+prodID1 + " " +prodName1 + " " + prodQty1 + " " +prodPrice1 "
"
+ and so on until prod5));
[code].....
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Oct 5, 2014
Write a program using switch statement to allow users to choose an item of a menu. For example, the menu looks like the following.
File menu
1. Open
2. Close
3. Save
4. Exit
Enter your choice:
If you type 1, then your program should print out "Open is selected" (double quotes not included).
Notice:
(1) Using Scanner to get user choice;
(2) If the number user input is not in {1,2,3,4}, your program should let user know that.
Here's what I have:
public static void main (String[] args) {
int user = 1
switch (1) {
case value: 1
System.out.println ("Open is selected");
[Code] .....
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Nov 1, 2014
Alright so I wrote a switch statement that decides what range to print based on the letter grade input.
import java.util.Scanner;
public class SwitchPractice
{
public static void main(String [] args)
{
Scanner scan = new Scanner(System.in);
[code]...
It works fine, but once it the user enters a letter grade and then displays the value, it does not prompt the user for another letter grade so that it can perform the output again. Also if I wanted to display an error message to the user if they enter an invalid letter grade how would I do that. I tried using a while loop and if statement in the switch statement but that didn't work.
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Oct 10, 2014
Basically the problem is I've been trying to loop my switch (if this is even possible) until the user enters a correct number between 1 and 4. But for some reason when the user enters a correct number (1,2,3,4) the loop runs again. Even when the user enters a wrong number the switch ignores the default and repeats what is in the do.
Am I just trying to loop something that cannot be looped or have I gone?
import java.util.Scanner;
class mammals {
int age;
int death;
String name;
[Code].....
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Jul 26, 2014
I cant apply my knowledge of the switch to modify this program.
What i need is that the program runs the same but i can press q to stop the program and it will continue in a loop otherwise. repeating the same process i.e displaying the characters entered until q is pressed.
How do i do it? I think i need to make use of do and while but how to apply those in this case.
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Nov 29, 2014
I've done a basic login GUI for a application, a user enters their name and address and clicks register, a four digit pin is then randomly generated, the pin and name and address are all added to an object of the MemberDetails class , this obj is then added to an array list.
returning customers can then enter a previously generated pin and either get a welcome back message or an invalid pin message.
my issue if i register two new users and get their generated pins, that on the returning members screen it will only show the welcome message for the second new customer i created and not recognizing the first customers pin. heres my code:
taking in new customer details, generating pin , adding obj to arraylist
int randomPIN = (int) (Math.random() * 9000) + 1000;
members = new MemberDetails();
members.name = nameNew.getText();
members.address = addressNew.getText();
members.pin = randomPIN;
[Code] ....
that lest method is a bit of a mess i know, i was going to store the log in attempts in a array but thats probly not a good tactic, and that inner for loop is probly unnecessary ?
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Aug 23, 2014
I am having trouble doing a simple exercise changing a for loop to a while statement, it works fine in the for loop but in the while statement it just prints out 10(it is supposed to count to 0 and print liftoff).
public void run() {
int i = 10;
while (i>=1) {
println(+i+"...");
i--;
}
println("liftoff...");
}
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Apr 26, 2015
Here is my code so far. I am trying to get the WHILE LOOP to work so the user inputs a number, the if statement prints the output and then it returns to ask for another number and goes again and again looping :
import java.util.Scanner;
public class ifwhileloop {
static Scanner sc = new Scanner(System.in);
public static void main(String[] args) {
double nmbr;
[Code] ....
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Dec 12, 2014
I made this calculator in C++ and it worked wonderful so I decided to make it in java. When I run the program it gives me no errors but my if statements inside my while loop don't work
import java.util.Scanner;
public class ohmlaw {
public static void main(String args[]) {
float current;
float resistance;
float voltage;
String calchoice = new String();
Scanner cc = new Scanner(System.in);
[code]....
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Mar 13, 2014
I have to take user input and then count how many times each number that the user input and print each one out. For some reason, I can't even get the for loop statement to print and it's pretty much the same as my other program except for the loop which is a little different.
//User inputs numbers between 1 and 100, program counts how many of each integer is and ends with a 0
import java.util.Scanner;
public class occurrence {
public static void main(String[] args) {
//scanner/values
Scanner input = new Scanner(System.in);
int number = 0;
int c = 0; //array count
[Code] ....
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