Making Integers Have Limited Numbers?
Aug 14, 2014
I want users to input their phone Number But I want to make sure it is a phone number so they don't just do 1 and then leave it.
public static void main(String[] args) {
// Create the Scanner
Scanner in = new Scanner(System.in);
// Create the Variables
int phone;
if(phone > 100000000000 || phone < 100000000000) {
System.err.println("Error");
}
By the Way there are 12 digits in the if statement so that is 11 0's. Because all phone numbers are 12 digits.But when I run it, it comes up with an error saying The literal 100000000000000000000 of type int is out of range.I don't know how to make it so that the int has a limited number.
View Replies
ADVERTISEMENT
Aug 14, 2014
I want users to input their phone Number But I want to make sure it is a phone number so they don't just do 1 and then leave it.
public static void main(String[] args) {
// Create the Scanner
Scanner in = new Scanner(System.in);
// Create the Variables
int phone;
if(phone > 100000000000 || phone < 100000000000) {
System.err.println("Error");
}
By the Way there are 12 digits in the if statement so that is 11 0's. Because all phone numbers are 12 digits.But when I run it, it comes up with an error saying The literal 100000000000000000000 of type int is out of range.I don't know how to make it so that the int has a limited number.
View Replies
View Related
Oct 22, 2014
so for my computer science class, we have the following problem:
In your documentation be sure to say which loop you thought was easier to implement for this program and why Write a program that produces the following outputs. The first line of output must be written using a For-Loop. The second, using a While-Loop and the third using a Do-Loop.
You look at the program and smile because you see that the series is just the numbers 1-10 squared...just one line is in reverse order. No problem! As you start typing you discover that the number 8 key on your keyboard is not working. For this program you are unable to use the multiplication key
So, back to the drawing board. By staring at the sequence a light comes on and you are able to quickly finish this program WITHOUT using mulitiplication (or the Math class/ solve with arithmetic operators +, - or / ) .
Sample output:
For Loop
1 4 9 16 25 36 49 64 81 100
While Loop
100 81 64 49 36 25 16 9 4 1
Do While Loop
1 4 9 16 25 36 49 64 81 100
I have the "for" done, but I did it with a "for" in the beginning but then had a multitude of nested "if" loops so that I could do 7*7=7+7+7+7+7+7+7
View Replies
View Related
Mar 7, 2015
I am having a bit of trouble making the '+' add two numbers in java. For example:
When the user enters " + 4 5 " I want it to come out as " 4.00e+00 + 5.00e+00 = 9.00e+00 "
Here is what I have so far:
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
while (in.hasNextDouble()) {
double num1 = in.nextDouble();
double num2 = in.nextDouble();
String s = "";
[Code] .....
View Replies
View Related
Nov 19, 2014
I was trying to get sum of numbers between two given integer and managed to do it.
public int sum(int a, int b) {
int sum=0;
while(a <= b) {
sum+=a;
a++;
}
return sum;
}
in here; when I enter the values i.e 2 and 5, it calculates 2+3+4+5 and gives me the result 14.
my question is, how could I exclude a and b in this calculation ( in this case exclude 2 and 5 and return 3+4 )
Bonus question ; how could I only calculate the odd (or even) numbers between those integers?
View Replies
View Related
Sep 12, 2014
I have a code like following. x and y are both Integers and have same values (e.g. 5). But they are interpreted as different values. Then, it validates the following condition.
Java Code: if (x != y) {
"x and y are different..."
} mh_sh_highlight_all('java');
View Replies
View Related
Jul 12, 2014
How can I make the numbers to stay at the textfield of my calculator instead of disappear like when I type 1 then hit the + sign the number 1 disappears from the textfield I would like to have this (1+1) showing in the text field and also if try to press only + , * , - , / to show error.
this is my code
public class Calculator extends javax.swing.JFrame {
private double TEMP;
private double SolveTEMP;
Boolean addBool = false;
Boolean subBool = false;
Boolean divBool = false;
Boolean mulBool = false;
String display = "";
[Code] ....
View Replies
View Related
Mar 7, 2014
I'm trying to generate random 100 numbers, from 0 to 9, in an array using Math.random, but it only outputs 0s which is very confusing to me. Also, I need to be able to count how many different integers there are like 0s, 1s, 2s... 8s, 9s.
Here's my code, I only got as far as the array then got stumped on the counting part.
import java.util.Arrays;
public class countDigits {
public static void main(String[] args) {
//Create random generator and values
int numbers = (int)(Math.random() * 10);
int arrayCount = 1;
[Code] ....
and my results
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0
View Replies
View Related
Apr 22, 2014
I'm making a method to take an array of integers and rearrange the numbers from least to greatest, using for loops.
I'm getting the error "java. lang. ArrayIndexOutOfBoundsException: 8,
Portion of the ArrayMethods class with the sorting method
Java Code:
public static Integer[] sortArray (Integer[] a)
{
int swap;
for (int i = 0; i < a.length; i++)
[code]....
View Replies
View Related
Nov 9, 2014
I don't want to use an array. I do not know of a function built into Java to allow me to do this.
View Replies
View Related
Jan 21, 2015
This program simply adds integers to an ArrayList and then prompt the user if they would like to delete specific numbers that they don't want.
The output that I get when I want to delete numbers like 2 and 4 from 1 2 3 4 5 is 1 2 3 4 5 instead of 1 3 5.
Java Code:
import java.util.ArrayList;
import java.util.Scanner;
public class AL
{
// A regular array like int arr[] has to have its size declare before run-time and it's not dynamic which mean it can not grow or expand on its own.
static Scanner input = new Scanner(System.in);
// You have to use reference types(Integer, Double, Float); not primitive types(int).
[Code] .....
View Replies
View Related
Aug 22, 2014
I tried to create file and write the output of my program in it in java when i use WriteLong then the file does not contain long value, how I create this file my program is to print prime numbers between 500000 to 10000000
public class primenumber {
public static void main(String[] args) {
long start = 5000000;
long end = 10000000;
System.out.println("List of prime numbers between " + start + " and " + end);
for (long i = start; i <= end; i++) {
if (isPrime(i)) {
System.out.println(i);
[Code] ....
View Replies
View Related
Apr 24, 2014
I've just written a program that generates 100 numbers that range from 0 ~ 25 using arrays, the program calls another method that sorts the even numbers into a separate array and returns the array. I need it to display both arrays, however, when I run my program, the numbers of both arrays are mixed together, and I'm not sure how to separate them.
[ public class Array1
{
public static void main(String[] args)
{
int array [ ] = new int[100];
for (int i = 0; i < array.length; i++)
{
array[i] = (int) (Math.random() * 26);
[Code] .....
View Replies
View Related
Feb 1, 2015
I'm trying to make a program that generates 20 random integers between 1 and 20 and then prints the list of random numbers to the screen. After that, I want to print a different list to screen with the same numbers from the first list only skipping any number that has been already printed to the screen. So two lists are printed to the screen. The first one has 20 random numbers. The second one has those same 20 numbers but only prints the numbers in the first list that aren't duplicated. So if m
y list of 20 random integers contains three 2s and two 14s, only one 14 and one 2 is printed to the second list. Currently, my code generates 20 numbers from 1 to 20 and stores those numbers in an array but I don't know how to print solve the second part of my problem. I don't know how to print the s different list only without duplicate numbers. As a result, my output is nothing because it doesn't print any number from the first list as oppose to skipping only duplicate one.
public void randomNum(){
System.out.println("Twenty random integers: ");
int max = 20; // max value for range
int min = 1; // min value for range
Random rand = new Random();
int[] all = new int[20];
[Code] ....
View Replies
View Related
Nov 23, 2014
I have to make a program that prompts the user to enter 10 numbers and at the end it prints out the distinct numbers and then the other numbers that weren't repeated...
I have the part where it prints out the distinct numbers but I stuck on how to make it print out the other numbers that didn't repeat...
import javax.swing.JOptionPane;
public class DistinctNumbers {
public static void main(String[] args) {
String getInput;
int input;
int[] numbers = new int[10];
[Code] ....
View Replies
View Related
Mar 10, 2015
Create an integer array with 10 numbers, initialize the array to make sure there are both positive and negative integers. Write a program to generate two arrays out of the original array, one array with all positive numbers and another one with all negative numbers. Print out the number of elements and the detailed elements in each array.
public class problem3 {
public static void main(String[]args){
int[] numbers = {1, 2, 3, 4, 5, -1, -2, -3, -4, -5};
for (int i = 0; i<numbers.length;){
if(i>0){
System.out.println(numbers);
}
else
System.out.println(numbers);
}
}
}
View Replies
View Related
Jul 31, 2014
I tried out doing number (generated randomly) != (another number) but that does not work. If I for example want a number between 1 and 10, but I do not want the number 5, what can I do in order to make this happen?
View Replies
View Related
Oct 17, 2014
Program is to list all prime numbers between two entered numbers.
import java.util.Scanner;
public class question6 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter lower int:");
int x = input.nextInt();
[Code] .....
View Replies
View Related
May 30, 2006
how this is done using session.setMaxInactiveInterval(); at first, i did not set anything but it expires anyway.so i'm trying not to let the session expire.session.setMaxInactiveInterval(0) does not work.
View Replies
View Related
Sep 17, 2014
I'm making an import/export of xml - I have the import of xml sorted I'm just trying to finish off the export. My export class is called XmlWriter.java. Inside the class I have an updateFile method to update an xml file as such:
public void updateFile(Environment environment,Document doc)
{
// code
}
I then in my main method have
public static void main(String argv[]){
//declare new object of class
XmlWriter xmlWriter = new XmlWriter();
//test testUpdate method
// xmlWriter.testUpdate();
Environment environment = ;
[code]....
I don't know what to make my variables equal to - eclipse keeps trying to use null but obviously that won't work. The Environment is another class that just contains getters and setters for the 3 different databases (that are in the xml file) and the getter/setter for the environment ID (also in xml file).
View Replies
View Related
Jan 10, 2014
How can I make an .exe file for my java project that will work on every computer?
I have a jar file, but the project can not work without installed IntellyJ or other development environment on that computer, i.e. it doesn't work only with installed java runtime.
What can I do to make an .exe file for my java project?
View Replies
View Related
Sep 29, 2014
I have a jsp with an img tag whose src is set to request a servlet to display a chart. This is called from another jsp form where user can select various filters. The first time the request is made all works great. but if the user changes the filter settings and and makes the servlet request a second time the chart stays the same. I have verified the new filter values are being set but the servlet is only being called on the initial request.at the head or called servlet I have(I also call a jquery empty on the div that holds the chart between requests. at the moment it just displays the former chart). It is like it is using cache:
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setHeader( "Pragma", "no-cache" );
response.setHeader( "Cache-Control", "no-cache" );
response.setDateHeader( "Expires", 0 );
View Replies
View Related
Mar 9, 2014
I use JTable and JScrollpane in my java application, and I would like for every selected row in the scroll pane, the pie chart to be made for the values in % that the row contain.
View Replies
View Related
Oct 9, 2014
How would i go about making this NOT resizable?
If I do try to do ChatFrame.setResizable(false); it gives me this error:
Exception in thread "AWT-EventQueue-0" java.lang.Error: Unresolved compilation problem:
Cannot make a static reference to the non-static method setResizable(boolean) from the type Frame
at com.ui.ChatFrame.<init>(ChatFrame.java:37)
at com.ui.ChatFrame$5.run(ChatFrame.java:403)
at java.awt.event.InvocationEvent.dispatch(Unknown Source)
[Code] ....
Here is the code:
package com.ui;
import com.socket.History;
import com.socket.Message;
import com.socket.SocketClient;
import java.awt.event.WindowEvent;
import java.awt.event.WindowListener;
[Code] ....
View Replies
View Related
Jan 22, 2014
I'm going to make Dekstop Based Home Inventory, do you have a tutorial for it ?
View Replies
View Related
Mar 10, 2014
I prompted the user to enter inches of rainfall for seven days and stored them in an array. Now, I am trying to display a histogram of this data using a nested loop, but for each inch, I have to display a * like this:
Rainfall Histogram:
****
***
**
******
********
**********
**
The only way I know how to display a number of *s according to user input is by an if statement. I copied and pasted from a similar class assignment I did, so what I have so far is pretty messy and nonsensical:
static char DetermineRainfall(int inches)
{
System.out.println("Histogram");
//char inches;
for(inches = 0; inches < 7; inches++)
{
for(int j = 0; j < 1; j++)
{
if (rainamount > .9 && rainamount <= 1)
inches = '*';
return inches;
}
}
View Replies
View Related