Manipulating Strings In A File Scanner

Feb 25, 2014

I was given a text file that has list of names phone numbers, calls in and out etc... Like this

Adams#Marilyn#8233331109#0#0#01012014#C
Anderson#John#5025559980#20#15#12152013#M
Baker-Brown#Angelica#9021329944#0#3#02112014#C

The # are delimiters between data items and each line has the call status as the last item. I need to know how I can display each persons information on the screen in a format such as:

Name Phone Calls Out Calls In Last Call

Marilyn Adams (823) 333-1109 0 0 01-01-2104
John Anderson (502) 555-9980 20 15 12-15-2013
Angelica Baker-Brown (859) 254-1109 11 5 02-11-2014

I have to use substring method to extract the phone number and add parentheses/dashes ect I also must have a while statement and a delimiter...

So Far my code looks like this Also I am in a beginners Java coding class....

import java.util.Scanner;
import java.io.*;
 public class phonedata2_1 {
public static void main (String[] args) throws IOException {
  String Phonefile, FirstName, LastName;
Scanner PhoneScan, fileScan;
 
[Code] ....

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I am having a great deal of frustration trying to use the scanner to get user input from the eclipse console. Here is what I am trying to do.

Print a menu for the user with options, take that (1) char input and run it into a switch statement for processing. I have that done and it is working fine.

If the user chooses to enter strings for storage, They are instructed to enter their string and press enter to complete that string entry. Then enter the next string and press enter, etc.

So I have a While loop for this. Get the scanner input, store it in the LinkedList, get the next scanner input, etc. I get the scanner string and store it in a Linked list. That works fine. The user is instructed to simply enter a blank string to end the entry procedure, like just press Enter on the new line without typing a new string.

The problem is the scanner doesn't seem to return anything for me to Test to close this procedure. How do I TRAP the fact that the user just pressed enter so I can end my procedure? I have tried next() and nextLine() and reset(), etc. And I am getting knowhere.

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PHP Code: String yourName = user.nextLine(); mh_sh_highlight_all('php');

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package jdbc;
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[code]....

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Mar 26, 2014

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10
150.4
88.4
-3.14
499.4
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1299.8
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1900.2
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This is my program

import java.util.*;
import java.io.*;
public class QudratullahMommandi_3_07 {
  Toolkit_General toolKit = new Toolkit_General();
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[Code] .....

This is the error message

QudratullahMommandi_3_07.java:34: error: variable holder2 might not have been initialized
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^
1 error

----jGRASP wedge2: exit code for process is 1.
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Java Code:

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[Code] .....

When I try to read from a file that's 4,075,904 lines long and 41,646KB in size, it wont go past line 1,266,471. The above code is simplified from my actual program, which actually prints out the results to another file. However, the console (Eclipse IDE) and the output file, both show that it's stopping at the same line.

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JFileChooser jfc = new JFileChooser();
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at App.main(App.java:12)
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obj.run();
}
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^
8 errors[CODE
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.
[/CODE]

My code is as follows:

import java.util.Scanner;
 
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
 
[code]....

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Mar 26, 2014

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Apr 24, 2014

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Feb 9, 2015

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Code:

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import java.util.Scanner;
public class Books{
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
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