NZEC - Non Zero Exit Code Exception In Java
Mar 5, 2015
This is my code
import java.util.ArrayList;
import java.util.Scanner;
public class Main {
private String[] inputStrings;
private ArrayList<InputField> decodedMessage;
public static void main(String[] args) throws Exception{
new Main().solve();
[Code] ....
This is giving me NZEC exception.I am testing this solution on a online judge.So I don't have any TestCase in which this is failing. So, what are the possible reason of NZEC exception in my code?
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Apr 11, 2015
I am submitting on a online judge. I am getting NZEC exception in my code
this is my code
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class MyProgram {
static int[] arr;
static int sum=0;
static int x,y,N;
[code]...
what are the causes that is showing NZEC to me?
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Mar 12, 2014
I just want to know how I can get my program to end when the user inputs "0." By using: System.exit(0);
import java.util.Scanner;
public class TestCode
{
public static void main (String [ ]args ) {
Scanner console =new Scanner(System.in);
System.out.println("To exit program input 0");
for (int y = 1; y < 11; y++ ){ // Executes output 10 times
[code]....
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Dec 16, 2014
This is a simple DFS question on spoj. click it here. i am getting nzec error on java. If possible,
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.Scanner;
import java.util.StringTokenizer;
[code]....
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Apr 17, 2014
How do i exit a java program is the user input is nothing "",This is my code
Java Code:
import java.util.Scanner;
public class MyQueue<T> implements Queue<T> {
private T[] ringbuffer;
static int capacity = 0;
int mysize = 0;
[code]....
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Feb 27, 2015
I am trying my code which catches exception when mismatch variable is inputed as i read it with Scanner. It seems right for me but whenever i run it, it keeps leaking memory or something like that
Code :
import java.util.*;
public class Exercise10_1 {
static Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
boolean exception;
do
[Code] .....
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Feb 13, 2015
So I'm learning java having been using c#. I based this code off an example from class. It compiles fine with no errors, but I'm getting this:
Which model do you want? + Standard,Electrum,CurveHilted, or Tonfa Standard
Exception in thread "main" java.lang.ClassNotFoundException: Standard
at java.net.URLClassLoader$1.run(URLClassLoader.java:366)
at java.net.URLClassLoader$1.run(URLClassLoader.java:355)
at java.security.AccessController.doPrivileged(Native Method)
[Code] .....
How/where to point the correct class.
package com.company;
import com.sun.java.util.jar.pack.*;
import java.util.Scanner;
class LightSaberFactory {
static LightSaberFactory lsf;
ChooseLightSaberColor saberColor;
[Code] .....
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Dec 8, 2014
It doesn't work and I always get UnknownFormatConversionException...
public class studentPoll {
{
public static void main( String[]args)
{
int[] responses = { 1, 2 , 5, 4, 3 , 5, 2, 1 , 3, 3, 1, 4, 3, 3, 3,
2, 3, 3, 2, 14 };
[Code] .....
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May 8, 2014
I am getting a nullpointer exception after "cleaning" up my code by putting repetitive stuff in a method.
The error points to this: ai.getItRight(n, answer);//make sure the user enters yes or no..
The error occurs at lines 19 and 25.Here is the relative code:
public boolean AskQuestions(Node n, String yesOrNo, String answer, String question){
if(yesOrNo.equalsIgnoreCase("no") && n.getRight() == null){//i guessed the wrong answer
System.out.println("I give up. Who is it: ");
answer = input.nextLine();
[code]....
My previous code, which use to have the contents of getItRight in place of lines 19 and 25 worked just fine. So why am I getting this error? I dont want my methods to be crazy big like how they usually end up.
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Apr 16, 2014
If a user inputs nothing the code should end ... How Should i do it?
import java.util.Scanner;
public class MyQueue<T> implements Queue<T> {
private T[] ringbuffer;
static int capacity = 0;
int mysize = 0;
[Code] ....
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Aug 18, 2014
/* Jessie Garza
* 08 / 18 / 14
* ModCalculator
*/
import java.util.Scanner; // program uses Class Scanner
import javax.swing.JOptionPane;
public class ModCalculator
{
// main method begins execution of Java application
[code]....
I am having troubles with allowing the user to input operations/digits until they want to exit, I have tried looping, but I was unsuccessful, came here hoping to figure this out.Currently I have it ending with Break statements after each switch so that they don't coincide all together.. I can't figure out how to keep the Break statement AND loop to previous code of System.out.println( "Please enter an operand which you would like me to calculate with :");
String st = input.next();
c = st.charAt(0);
System.out.println( "I will need for you to input two integers and I will output the result.");
System.out.print( "Enter first integer to calculate: " ); // prompt
number1 = input.nextInt(); // read first number from user
System.out.print( "Enter second integer to calculate: " ); // prompt
number2 = input.nextInt(); // read second number from user
and allowing it to run through the rest of the program with the options still in tact, while having an if statement of an exit keyword.
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Aug 28, 2014
I have been going over my code line by line, over and over again for nearly and hour now...When I execute method `file.createNewFile()`, the method returns true and throws no exceptions. It even says that the file exists. However, the file is not created and cannot be accessed until the program has exited.
File portLib = new File("");
private class RememberPortAction extends AbstractMenuItemAction
{
methods...
protected void actionPerformed() {
LibraryCreator creator = new LibraryCreator(self, logger);
File newPortLib;
[code]....
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Oct 1, 2014
Description of the program: read a sequence of positive integers from terminal. When user types
-1, the program will print out the largest number and exit.
Program mid.java
import java.util.Scanner;
public class test
{
public static int num;
public static void main (String[] args)
{
Scanner in = new Scanner(System.in);
num = in.nextInt();
int large = num;
while(num > 0);
{
if(0 > num && num > large)
large = num;
}
System.out.println("The largest number is : " + large);
}
}
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Mar 13, 2014
I've spent ages trying to implement an exit button into this code. Its the start of a GUI for a slot machine, the actual machine code is in a separate class and I haven't linked them yet. My question is where/how would the exit button be added? I've tried and failed a lot of times....
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class SlotMachineGUI
{
public static void main (String[] args)
{
//create new jframe
JFrame frame = new JFrame ("Slot Machine");
[Code] .....
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Jan 24, 2015
This is my first java program,i am using eclipse IDE-----
package day1.example;
public class MyFirstJava {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("hi");
}
}
When i saved it,it shows no error.when i run it then a pop-up says "could not find the main class.the program will exit" and in the console it says---
java.lang.UnsupportedClassVersionError: day1/example/MyFirstJava : Unsupported major.minor version 51.0
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClass(Unknown Source)
at java.security.SecureClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.access$000(Unknown Source)
[Code] ......
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Feb 18, 2014
My question is how can I make the program repeat until the user enters the number 4 to exit?
/**
* Write an application for a furniture company; the program determines the price of a table. Ask the user to choose 1 for pine, 2 for oak, or 3 for mahogany. The output is the name of the wood chosen as well as the price of the table. Pine table cost $100, oak tables cost $225, and mahogany table cost $310. Also ask the user to specify a
(1) large table or a
(2) small table.
Add $35 to the price of any large table and add nothing to the price for a small table. Display the output. Your program must repeat until the user chooses to exit.
*/
import java.util.Scanner;
public class Wood {
public static void main(String[] args) {
Scanner input = new Scanner (System.in);
System.out.println ("Table Prices");
[Code] .....
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Apr 22, 2014
I have a Single Frame Application and I simply want to prompt the user with a dialog confirming they really want to close before they actually close the program, specifically when they click the X in the upper right. I THOUGHT it was like any other java application, with the slight added complexity of having to target the program-created-JFrame with: ".getApplication().getMainFrame()".
MyApp.getApplication().getMainFrame().setDefaultCloseOperation(JFrame.DO_NOTHING_ON_CLOSE);
With that code, DO_NOTHING_ON_CLOSE is set on the JFrame, yet the program closes anyways. Which I don't understand.So I did some reading and found this: URL....That lead me to the configureWindow override, where I successfully tried this:
root.addWindowListener(new WindowAdapter() {
@Override
public void windowClosing(WindowEvent e) {
// write your code here
System.out.println("Window Closing");
}
});
But as far as I can tell that will only let me react to the window closing, not to the command to close it, where I could then kill the command in the dialog if they so "no I'm not ready to quit yet", if that makes sense. So, how to give a prompt before closing?I am using netbeans IDE to create this app - not sure if that is relevant, since maybe it is an oddity with the IDE and not Single Frame Applications.
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Nov 22, 2014
Working with the winnings and how to spin again or exit.
import java.util.*;
class Wksht5Q1{
public static void main(String[] args){
Scanner in = new Scanner(System.in);//For user input
Random rand = new Random();//For number generator
//Variables for user input
[Code] ....
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Oct 26, 2014
My homework assignment is: Using a do-while statement, write a Java program that continuously requests a grade to be entered. If the grade is less than 0 or greater than 100, your program should display an appropriate message informing the user that an invalid grade has been entered; a valid grade should be added to a total. When a grade of 999 is entered, the program should exit the repetition loop and compute and display the average of the valid grades entered. Run the program on your computer and verify the program using appropriate test data.
When I run it, I don't get the correct average. I know that i'm supposed to enter 999 to exit the loop and to display the average, but 999 is being added with the loop. I'm not sure how to make it not do that.
//stephanie
import java.util.Scanner;
public class gradeAverage
{
public static void main(String[] args)
[code]....
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Oct 24, 2014
I want to develop a Java program that uses OpenScript APIs to test my applications. The OpenScript framework automatically creates the Java Code so I was thinking of either using this code or create my own using the APIs.
I tried both options using NetBeans but I'm getting errors everywhere starting with the library import. I'm pretty new to Java so I'm sure I'm missing a lot of things here. I pasted the code below from the OpenScript framework that want to use in a stand-alone file for your reference.,
import oracle.oats.scripting.modules.basic.api.*;
import oracle.oats.scripting.modules.browser.api.*;
import oracle.oats.scripting.modules.functionalTest.api.*;
import oracle.oats.scripting.modules.utilities.api.*;
import oracle.oats.scripting.modules.utilities.api.sql.*;
[Code] ....
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Jan 24, 2014
I was giving a quick skim to some tutorials on the internet where I have found the exception that is handled is also declared in the throws clause of the method wrapping the try-catch block. For a code representation consider the following:
public void methodName() throws IOException {
try {
...
} catch (IOException ex) {
.... TODO handle exception
}
}
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Dec 30, 2014
I have a Query, what is the exception handling framework used my project, but we actually did not use any framework ,we used just normal try catch and throws, so what is the exception handling framework, when I browsed through net I found something like JEHA, so is there any other framework available.
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Jun 19, 2014
I know I can calculate the sum of squares as such:
// SumSquares.java: calculate the sum of two squares
class SumSquares {
static int sumSquares(int a, int B)/>/> {
int asquare;
int bsquare;
[Code] ....
But how can I modify the code so that it inputs a list of integer values in the range of -100 to 100 from the keyboard and computes the sum of the squares input values. And how would I go about using exception handling to ensure that the input values are in range and are legal integers.
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Jan 18, 2014
I am new to Java Applets.
After upgrading to JAVA 7u51, our application is throwing an uncaught exception.
'Uncaught exception: Liveconnect call for Applet ID <n> is not allowed in this JVM instance.
It works fine with JAVA medium security. With 'High' security, it throws above exception.
*Security level was changed in java control panel.
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Apr 2, 2014
i have a j sf application that is using web-services to communicate to another application and pass some parameters to it.The application has three methods one to call the webservice,another to insert some values into a database and the third method to call the two methods when i click a button in a form.The methods a are
update() this is for calling a webservice and passing parameters to it.
insertt() to in sert to a database.
all() to call the above two.
when i call upadate and insertt in all method am getting an error java lang null pointer exception but when i call just one of the methods it executes successfully.This is my code package softmint.com;
import java.sql.Connection;
//import java.sql.Date;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
//import java.text.SimpleDateFormat;
import javax.xml.ws.WebServiceRef;
[code]....
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Apr 29, 2014
I developed a Java application and it works fine on my computer, but when i tried it on another computers, I have the following errors :
A window named Java Virtual Machine Launcher appears and it says "A Java Exception has occured".
My application don't even launch.
Here is the error lines, but I don't know what to do :
C:UsersAdministrateur_localserveurtimet>java -jar ServeurTimeT.jar
Exception in thread "main" java.lang.UnsupportedClassVersionError: TimeTracking/
ServeurTimeT : Unsupported major.minor version 52.0
at java.lang.ClassLoader.defineClass1(Native Method)
[Code] ....
Java is up to date.
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