Overloading With Primitive Types?

Jan 22, 2015

Why the following is happening.

For the below code, when I execute it, it prints

Short method 10 //result 1
Sub class short method 10 //result 2

Which is as expected but if I comment out line 3, then it prints

Integer method 10 //result 3
Integer method 10 //result 4

I can understand result 3 is because of an upcast from short to int, since FunWithOverloading will not have a overloaded method with short now. However, what is happening with result 4? Shouldn't it call methodA of the subclass with the argument type short? If its because I have declared the reference variable, derived, of the type FunWithOverloading, then how come the first result correctly picks the overloaded method of the sub class?

class FunWithOverloading{
void methodA(int x){System.out.println("Integer method " + x);}
void methodA(short x){System.out.println("Short method " + x);} //line 3
} class OverloadedSubClass extends FunWithOverloading{
void methodA(short x){System.out.println("Sub class short method " + x);}

[Code] ....

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I've got a question to ask.

public class AutoBoxingExample {
public void add(Integer intVal){
System.out.println("Wrapper");
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AutoBoxingExample auto = new AutoBoxingExample();
auto.add(12);
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[code]....

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[code]....

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**********
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