import java.util.concurrent.TimeUnit;
import java.util.concurrent.atomic.AtomicInteger;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
public class tree_lock_test{
int total_instances;
int thread_instances = 0;
int N;
[Code] .....
this is compiled with another Peterson class which has implemeted peterson lock for two threads ...
How to do draw the original binary tree based on traversal results?
A binary tree has this pre-order traversal result: A,B,D,H,I,E,F,C,G,K,J (TreeNodes) And the same tree gives the following in-order traversal: B,H,I,D,A,C,F,E,K,G,J. Can you draw the tree structure?
I have been trying to make a good tree structure for my Electrical Distribution network.. How to create two "subfolder" of my Voltage level folder.
Here is the code
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Container;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JApplet;
import javax.swing.JButton;
[Code] ....
I am new to jsf i have been given a task to create a tree structure in jsf but cant use richfaces and primefaces. I need a complete project for reference as i am to totally new to this.
View Replies View RelatedI have an excel file with data listed as the following, i m trying to parse down using POI
A
B
C
D1
D2
F
G1
G2
G3
M
S1
R
T
U
L
X
Y
Z
is it possible to generate an output like the following
A
A-->B
A-->B-->C
A-->B-->C-->D1
A-->B-->C-->D2
A-->B-->F
A-->B-->F-->G1
A-->B-->F-->G2
A-->B-->F-->G3
A-->B-->M
A-->B-->M-->S1
A-->R
A-->R-->T
A-->U
L
L-->X
L-->X-->Y
L-->X-->Y-->Z
I have been trying from quite some time but havent figured out the logic ...
I never used tree, node etc. Consider an array of strings that come from html tags. This needs to be turned into a tree structure. Here, any Hn is the child of the most recent Hn-1
String[] Headers = {"H1", "H1", "H2", "H3", "H3", "H2", "H2", "H3",
"H4", "H2", "H2", "H2", "H1", "H2", "H2", "H3", "H4", "H4", "H2" };
Desired output -
ROOT
H1
H1
...H2
......H3
......H3
...H2
...H2
......H3
.........H4
...H2
...H2
...H2
H1
...H2
...H2
......H3
.........H4
.........H4
...H2
ANSWER -
class Example {
static class Node {
final String name;
final int indent;
Collection<Node> children = new LinkedList<> ();
[Code] .....
I have written several simple data classes that I serialized manually by converting to text. At this point I need to serialize a more complex data structure. which will include lists of the simpler elements. Can serialize store and reconstitute this type of structure automatically or do I need to do this one manually as well? Consider the pseudocode below for a clarification of my question;
Java Code:
Class Hops{
String Name;
float Alpha Acid;
float Beta Acid;
};
Class Malt{
String Name;
float extract;
};
Class Recipie{
String Name;
CList HopList;
CList MaltList;
};
CList RecipieList; mh_sh_highlight_all('java');
I read the article on Serialization presented at tutorial point, but the example only showed a simple class, not lists of class members. What I want to do is serialize RecipieList, which consists of a CList of Recipies, which in turn consist of CLists of various ingredients.
I am creating a web application that runs on server X(unix) and it has another unix system mounted on it. I want to generate the file tree structure of this mounted unix file system and show it on to a web application so that users can select a file and move it onto this current unix machine.
I know this sounds stupid and you may want to say why cant we directly copy the file, I am doing a proof of concept and using this as a basis.
So everything in my program is working EXCEPT when it comes to calculating the result. I am supposed to evaluate the expression using postorder traversal to return the answer. I am honestly not sure how I would get the postorder traversal to return the answer to the expression since the only thing we really went over was how it re-ordered the expression so that it would end in the postorder/postfix order. Anyways, currently the way that I have the public int evaluate(Node node)method set up is giving me a result of 0, which obviously is not correct.
Here's the section that I'm having issues with:
public int evaluate(Node node){
if(node.isLeaf()){
return Integer.parseInt(node.value);
}
int result = 0;
int left = evaluate(node.left);
int right = evaluate(node.right);
[code]....
I have a list of people with a matching telephone extension number, the people are organised in a hierachy tree with some colleagues at the same level and then some junior colleagues. I have been trying to write code that can find the tree height of any given member but I am unable too. Here is my code so far but the left and right are not working because I have not declared them any where in my code.
Java Code:
//hierarchy rank section 7
// **Depth** from node to root (bottom up)
public int rank(Member p1){
//to do
[code]....
So here is the code that I have. The problem is my insert method. It compiles, but it doesn't do so well in the test class I have set up for it.
package SystemandDesign.BinaryTree;
mport java.io.FileInputStream;
import java.io.IOException;
import java.util.List;
import java.io.ObjectInputStream;
import java.util.Scanner;
[code]....
I know that for a binary search tree the insert() method is easy. You just kept comparing the values of the nodes, and you would know whether to go left or right depending on the value of the node.However, I am stumped when trying to figure out how to add a node into a normal binary tree where you just keep adding the nodes to the leftmost side, regardless of value.Here is my attempt at the insert() method:
public class RegularTree extends BinaryTree {
public CompleteTree() {
super();
}
public void insert(Comparable item) {
if(this.isEmpty()) {
this.setRoot(new TreeNode(item));
return;
[code]....
Is there a way that I can view my entire binary tree on Eclipse? I remember the old IDE that I used, jGrasp, had a feature in its debugging that would allow me to see exactly what was going on and I want to know if Eclipse has the same thing.
View Replies View RelatedI have a little problem in my code. Using a threaded binary tree and inorder traversal check if every next element is equal to the previous element + 1. You are allowed to use additional functions as long as they are not recursive. I have implemented everything. Problem is that i cant compare elements as i should. They are type E.
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import java.util.NoSuchElementException;
import java.util.ArrayList;
[code]....
I have written a code to get all the nodes below a current Node and it is working but I need to get it to look better if possible. To get the number of nodes below I have created an Array List, which I then go to the first Node below and add all the people to the Array list on the same level till I get to the end of the level, then I go down again until I cannot go down any more. Is there a way I can have my code without having to use an array List? I have put my code below. The brieff about the tree is that you have a parent and below the Parent are children who can have brothers and sisters next to them and after that they also have children below that. The method is trying to find the number of children below any given child
private LinkedList<Node> TempQueue = new LinkedList<Node>();
public int noOfYoungerChildren(Member p1){
Node tmp = find(p1);
return countYoungerChildren(tmp);
[code]....
I create a binary tree and now I would like to display the result in my jsp with conditions.
Each node has 4 elements (id, question, answer, and leftnode rightnode)
If the user clicks "Yes", the program goes to the left of the tree and if he answers "no" to the right of the tree.
For example, the initial question is "you're a man?" If he answers "yes" we will go to the left and page view "you're a singer?" If he answers "no" page displays "you're French? ".
In java, it would
cursor [i]. GetQuestion ()
to the original question.
Then
cursor [i] getQuestion. GetLeftnode ()
For yes and
cursor [i]. GetRightnode (). GetQuestion
for no.
Until the, everything works normally, but when I want to loop until there is no longer any issue by
<c:when test="${not empty cursor[i].getQuestion() }">
The program stops at the first loop and stops it that cursor is not empty
Here is my complete code jstl
<c:set var="cursor" value="${nodes}" scope="session"></c:set>
<c:set var="i" value="0" scope="session"></c:set>
<form>
<c:choose>
<c:when test="${not empty cursor[i].getQuestion() }">
<c:out value="i vaut ${i } au debut de la boucle"></c:out>
[Code] ....
So, managed to get my Binary Search Tree to work properly:
package SystemandDesign.BinaryTree;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.List;
import java.io.ObjectInputStream;
import java.util.Scanner;
[Code] ....
No matter how many times I keep rewritting the testInsert method I get a chock full of errors.
I am trying to implement a simple binary search tree . How can I make a node in the tree which should store two pieces of information: a String variable called name, and a int variable called mark. ..
public class BinarySearchTree<E> implements Comparable<E> {
public BinaryTree<E> root;
int size;
int mark;
String name;
// Constructor
public BinarySearchTree()
[Code]...
I don't see any nodes that I add. Not sure why getting this error.
duplicate found
Exception in thread "main" java.lang.NullPointerException
at binarysearchtree.delete(binarysearchtree.java:111)
at binarysearchtree.main(binarysearchtree.java:196)
Java Result: 1
public class node<T>
[Code] .....
I have some work where I have to create a binary tree. Anyway I am stuck on one of the classes which has several methods I must fill in! The code is below
The headers for each method are: public Node find (member p1)The method find(Member p1) is used to return the node which contains a particular member. It is a private method because the interface to CabinetTree should not provide direct access to the internal nodes. It makes use of the method Node findNode (Member p1, Node current)
and the next method is : Node findNode(Member p1, Node current) which searches the tree from current node to find a node whose value is equal to the Member p1, i.e. a node in the tree such that p1.equals(current.getMember()) is true. If there is no such node then the method should return null.
public class CabinetTree {
private Node head;
CabinetTree(Member p1) {
head = new Node(p1, null);
[Code] ....
The assignment is meant to understand and practice tree concepts, tree traversals and recursion. I am requested to use the tree to print the expressions by three ways and evaluate the expression in post-order. This is my node class,
package hw10;
public class Node {
String value;
Node left, right;
public Node(String value) {
[Code] .....
When i test my code, some trouble like this:
Enter a prefix expression: - + 10 * 2 8 3
prefix expression:
- + 10 * 2 8 3
postfix expression:
+ 10 * 2 8 3 -
infix expression:
( ( 10 + ( 2 * 8 ) ) - 3 )
[Code] .....
the error lines:
75: double left = evaluate(node.left);
107: evaluate(root);
In the Instruction, which said:
- int evaluate(Node node)
Given the root node of an expression tree, evaluates the expression using post-order traversal and returns the answer. main method Testing logic.
And I found the postfix expression was wrong, it should be: 10 2 8 * + 3 -
I think maybe the tree's order had some problems result in these cases or...
So for an assignment I have to write a method that finds that height of this BST. I wrote this:
public int height(Node node)
{
if (node == null)
{
return 0;
}
else
{
return 1 +
Math.max(height(node.left),
height(node.right));
}
}
Which makes sense in my head. However, I added a couple of nodes in and realized I'm not sure how to call this method.
public static void main(String[] args) {
Tree<String, String> tree = new Tree<String, String>();
tree.add("A", "1");//some added stuff
tree.add("B", "2");
tree.add("C", "3");
tree.add("D", "4");
tree.add("E", "5");
tree.add("F", "6");
tree.add("G", "7");
tree.add("H", "8");
System.out.println(tree);
System.out.println(tree.height());
What exactly do I put in the parenthesis after tree.height? If you need to see more of my code I can do that but it is quite lengthy.
I'm trying to implement a Binary Search Tree that accepts strings. I cannot figure out how to compare the string value in my add method against the node object. While I could make the node class data be the string type I am trying to make the code be as reusable as possible. So my question is this, is there a simple way I can compare the two that I am missing?
public class BTNode<E> {
private E data;
private BTNode<E> left, right;
//constructor
public BTNode(E initialData, BTNode<E> initialLeft, BTNode<E> initialRight) {
data = initialData;
left = initialLeft;
right = initialRight;
[Code] ....
I am trying to make binary search tree...I am trying to construct the left part of binary search tree with root node set as 70...It is not working ...My code is
public class Node {
/**
* @param args
*/
int root;
Node left;
Node right;
public void insertNode(Node node, int num) {
//Node nodeRoot = this;
//root of tree we have set to 70...constructing only left of tree with root=70
[Code] .....
Iva tried flipping the entire code upside down (expression) and No matter what I do the delete function returns a null pointer exception after my while loops takes the pointer right to where it should be.
package bp;
import java.time.LocalDate;
public class BinaryTree implements IBinaryTree {
private Node root = null;
private int sizeOfTree = 0;
[Code] ....
Here is the problem:
Start with the tree.java program (Listing 8.1) and modify it to create a binary tree from a string of letters (like A, B, and so on) entered by the user. Each letter will be displayed in its own node. Construct the tree so that all the nodes that contain letters are leaves. Parent nodes can contain some non-letter symbol like +. Make sure that every parent node has exactly two children. Don’t worry if the tree is unbalanced. Note that this will not be a search tree; there’s no quick way to find a given node. You may end up with something like this:
It also says all Letters must be Leaves
Now I had it almost similar to that picture, but it wasn't right. So ive been working on it but im getting some very strange (and frustrating) output from the following methods.
Ive included the display method just for reference. The book told me to use it so I haven't edited it. I believe my main issue is with my (incomplete) insert() method. The output goes into an infinite loop despite having a return statement break the while loop when a character is inserted.
The way I see to solve the problem is just add a (+) whenever a new subtree needs to be created. Say I add A and B, then it first creates a subtree at the root with a (+) and afterwards lists A and B as its leaves. If I insert a C, it should be able to simply move to the right child of the root and deposit the C there.
package pkg4333_hwk1;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Scanner;
class Main {
[Code] ....