Placing JPanel From A Class Into Frame Of Another Class
Aug 19, 2014
I can't figure out how to place a JPanel from a class(Game) in to a another class(Core). I have bean stuck on this for about three days now I bean doing my research but no luck so now I think I should ask directly so here I am. Now to state clearly I am trying to place a JPanel named Game_Screen witch is in another class named Game into a JFrame named frame witch is in a another class named Core.
Now both of this classes are with in the same package and my IDE Is Eclipse.The JPanel Game_Screen has other swing pieces attached to it that should also be added with the panel on to the frame.But the change is screen should only happen when I click the buttons New Legend(N),Load Legend(L),Help(H) what already happens is that when you click any of this buttons menu.setVisible(false); is activated making everything on screen at the time disappear from the screen but the panel does not a pear.
Here's my code:
//Class - Core-------
package Source;
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
public class Core {
static Game GG = new Game();
public static void main(String[] args) {
JFrame frame = new JFrame();
This is my frame class, now I want to be able to change the name of the frame, and get the name with frame.getName() in another class. But I'm not sure how to do this, i tried making a new frame in that class but i feel it's just another frame and not the one i made, also tried something like
I have made four apps and I want to put each of them in one project to make a big app.So,I have made a JFrame which has a lot of Jpanels inside.My question is how I can write different class for every Jpanel because I try to put all of them in one class,and it was not a good idea. Also, I do not want to open an other window when I choose an app. I want to have a Jpanel for every app. I use Cardlayout, I have read the tutorials but I can not understand. Also,I thought to make a different JFrame but I do not want to open a different window when I open a different app.
I have a JPanel class that creates a left panel and a right panel. the left panel and right panel both have one button each. What I’m trying to accomplish is when I click on the button in the left panel that it updates the button in the right panel. I have to do this without changing anything in the right panel.Basically I have to have LeftPanel have a way to keep track of an instance of RightPanel and I would have to do this through the JPanel class. But I have no clue where to begin on even accomplishing this.
I've constructed 4 different levels and allow the user to select the level they want to play from a central JPanel in a Card Layout system. My problem is that once a level is completed, I can't switch the JPanel which is displayed to start the next level, since I don't know how to access the original JPanel which acts as a driver for the other panels.
I've been trying to draw a panel on a frame with simple drawString drawRect and oval but when i run it the frame shows up with the exit on close stuff but nothing will show inside . this is my code :
import java.awt.Graphics; import javax.swing.JPanel; import javax.swing.JFrame; class Draw extends JPanel{ public void paintcomponents(Graphics g){ super.paintComponent(g); g.drawLine(10,15,20,30);
[Code] .....
I'm not sure what's wrong , probably something to do from this pc ? since in the lab work at uni it worked fine .
How do you declare methods for a class within the class whilst objects of the class are declared else where?
Say for instance, I have a main class Wall, and another class called Clock, and because they are both GUI based, I want to put a Clock on the Wall, so I have declared an instance object of Clock in the Wall class (Wall extends JFrame, and Clock extends JPanel).
I now want to have methods such as setClock, resetClock in the Clock class, but im having trouble in being able to refer to the Clock object thats been declared in the Wall class.
Is this possible? Or am I trying to do something thats not possible? Or maybe I've missed something really obvious?
I am building a GUI application which consists of two panels "panel" and "panel1". "panel1" have a button "addTimer" when clicked it should add the "panel" to the frame if i gain click the button it should again add the "panel" without overlapping the previous "panel" rather it should be created below the previous "panel". If i click on the button "addTimer" n times it should add the panel n times. Along with this the frame size has to dynamically change depending on the number of panels produced. Below is the code i tried my level best to satisfy the above conditions.
package superTimerV2; import javax.swing.*; import java.awt.*; import java.awt.event.*; public class SuperTimer extends JFrame { private static final long serialVersionUID = 1L;
Regarding the lifecycle of servlet , in headfirst servlet i can find :
You normally will NOT override the service() method, so the one from HttpServlet will run. The service() method figures out which HTTP method (GET, POST, etc.) is in the request, and invokes the matching doGet() or doPost() method. The doGet() and doPost() inside HttpServlet don’t do anything, so you have to override one or both. This thread dies (or is put back in a Container-managed pool) when service() completes.
How can I call the doGet method of the subclass from the superclass. i am not getting this .
I have a quick polymorphism question. I have a parent class and a sub class that extends the parent class. I then declare an array of parent class but instantiate an index to the sub class using polymorphism. Do I have to have all the same methods in the child class that I do in the parent class? Here is an example of what I mean.
public class ParentClass { public ParentClass(....){ } public String doSomething(){ } } public class ChildClass extends ParentClass { public ChildClass(....)
[Code] ....
Is polymorphism similar to interfaces where the child class needs all the same methods?
I want to know is there any way we can call parent class method using child class object without using super keyword in class B in the following program like we can do in c++ by using scoop resolution operator
class A{ public void hello(){ System.out.println("hello"); } } class B extends A{ public void hello(){ //super.hello(); System.out.println("hello1");
i want to write a class in such a way that i should get the current execution time of another class which is running. I searched in net but it shows only how to calculate the time duration of the current class which is running. But as per my way, i need the execution time of one class from another class. How to do this ?
I am working on a program that simulates a bug moving along a horizontal line, My code works correctly when I test it in it's own class but when I tried testing my constructor and methods in a test class I received an error saying, "package stinkBug does not exist" on lines with my methods. However, stinkbug is not a package.
Java Code:
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */
How to create object for "class B" and call the "function_B" from other different class D where class D has no connection with class A? Here is my program.
public class A(){ void print(){} } class B{ void function_B(){} } class C{ void function_C(){} }
Here, A, B, C are in the same package. But class D is in different package.
I am a beginner here at JAVA and I am trying to program a Gratuity Calculator using both interface class and object class but it keeps on compiling with errors saying "cannot find symbol".I tried everything to fix it but it just keeps on stating symbol.
[CODE] public class GratuityCalculator extends JFrame { /* declarations */
// color objects Color black = new Color(0, 0, 0); Color white = new Color(255, 255, 255); Color light_gray = new Color(192, 192, 192);
I was doing coding exercise from a book ('OCP Java SE 6 - Practice Exams' by Kathy Sierra and Bert Bates). I came to a question that told to demonstrate the difference between 'default' and 'protected' access rules by creating/making a directory structure and putting a couple of classes in different packages.
For this, I made a total of four classes, out of which, three classes are-Car, TestingCars, CarDimensions. (The fourth is not yet used in testing code till now, so, I am giving only the other three classes.) Their coding is given below.
Out of these classes, the classes- TestingCars and Car - are in a directory (say, FolderName). And, the class- CarDimensions is in FolderName's sub-folder.
The class 'CarDimensions' is public (and its components too are public). And, I am testing all the classes from the class- 'TestingCars'. But, this class (TestingCars) is not able to find the public class- 'CarDimensions' which is in its sub-folder and gives two 'Cannot find symbol' errors citing the class-CarDimensions. Also, If all three classes are put in one single directory, the programs work, without any error.
Coding: Class TestingCars:class TestingCars { public static void main(String[] args) { Car c = new Car(); c.setType("FourWheeler");
[Code]....
I could not find why the public class- CarDimensions- is not getting found by the TestingCars class.
I want to write an app that declares a class Person(String name, int age), and an Account class, Account(int code, double balance).But, additionally, every Person has at most 3 accounts, and each account has a Peron associated with it.
my code so far...
public class Person { private String name; private int age; private Account[] accounts; private int numOfAccounts; public Person(String name,int age){ this.name=name;
[code]....
My problem is:When I make data input for a person, and additionally I want to read data for the account(s) that this rerson has, what code should I write to create a new Account object as account[numOfAccounts].And, what is the code to assign an owner to a new created Account object?
There exists a relationship between the two classes, but I cannot find the way to implement this relation....