Im trying to create a checkerboard pattern with 2 nested for loops . I need to output asterisk characters. Im supposed o use an n int so I dont know if im limited to that 1 int. Im only getting 1 line of asterisk.
* * * * * * * * * * * * * * * * * * * * package checkerboard; public class Checkerboard { public static void main(String[] args) { for (int row = 1; row < 6; row++){ System.out.print("* "); for (int col = 6; col < col; col++) {
The program I'm working on is supposed to read input from a file and using recursion, print the pattern of asterisks for each value until the value is either < 0 or > 25.For example, if the value was 4, the pattern would look like this
* * * * * * * * * * * * * * * *
The values are stored in a file entitled prog3.dat which looks like this
4 3 15 26 0
I've never used recursion before and haven't been able to find anything showing how it would work with this particular type of problem.Here is what I've been able to come up with so far, but I'm having problems still which I will show following the code.
import java.util.Scanner; import java.io.*; public class Program3 { public static void main(String[] args) throws Exception { int num = 0; java.io.File file = new java.io.File("../instr/prog3.dat"); Scanner fin = new Scanner(file);
[code]...
It appears to be reading the file correctly, but is only printing the top half of the pattern. Also, like I said, I'm not very familiar with recursion, so am not sure if this is actually recursion?
just trying to learn it on my spare time and I'm doing do-while loops
public class help { public static void main (String args[]) throws java.io.IOException { char choice, ignore; do{ System.out.println ("Choose one:"); System.out.println("1. if"); System.out.println("2.switch");
[code]....
It makes no difference in the program wither i delete this block or keep it..how while (choice < '1'| choice >'2'); translates? I would assume it would be while (choice >= '1'| choice =<'2');?
Question: you are only allowed to use numbers from 1-6. Write a program to find all the permutations when three numbers are multiplied together to give a result 8. one number cannot occur twice in any permutation.
public class number4 { public static void main(String[] args) { for(int a=1; a<=4; a++) { for(int b=1; b<=4; b++) {
[Code]...
my program also prints out 2 2 2. but i'm not allowed to do that. how can I stop it from printing 2 2 2 ?
Here's what "Why doesn't this work?" question. It concerns a small method which is part of a card game.
I'm trying to check a condition from a section of an array, without a predetermined number of times any given call to this method will require a check. How much of the array I'm checking could vary greatly.
Is it at all possible to nest a for loop yielding a variable number of boolean && conditions inside an if? Am I just missing the right bracketing or is this nesting (if that's the word) even possible in the language?
To clarify, below is broken code. Compiler isn't letting me accomplish this goal as I envision it.
public boolean isFlanking() { boolean f; int reach = Math.abs(selectorX - targetX); if(rival.getDeck()[selectorX].getPile().isEmpty() == true &&
//Main method public static void main(String args[])throws IOException{ boolean runProgram = true; Scanner keyboard = new Scanner(System.in); //runs program while runProgram is true while (runProgram){
I was told that the answer when this code segment is printed look's like this: $$$$ $$$ $$ $
Here's what I did:Looking at the outer for loop, (i) 0 < 4 so I went into the first inner nested loop. (k) 0 is not less than (i) 0 so I went to the 2nd inner nested loop and found that it worked, and I was able to repeat this loop 3 more times and then I exited the loop and printed the line out (giving me the first line of four $). I then went back to the outer for loop, increased i by 1 and (i) 1 < 4 so I went to the 1st inner nested loop. I used the 0 for the k first and (k) 0 < 1 so I printed out a space (now here's where I get lost) I then incremented k by 1, so k = 1, but 1 is not less than 1 (i) and so I moved on to the next nested for loop. So when this line is printed, I'll only have one space when there should be 4.
Implementation of the nested for loop. I thought it was going to go smoothly but apparently not.Purpose: This program is meant to print out all the prime numbers up to a certain range using the algorithm Sieve of Eratosthenes.
Update output: Works as expected.
Java Code:
import java.util.Scanner; import java.util.ArrayList; public class PrimeFactors { static ArrayList<Double> primeList = new ArrayList<>(); static double range = 0; static double maxPrime = 0; static double primeTester = 0;
I just started playing around with Java for awhile, but got caught up in a problem when using ArrayList.
CinemaAppMain public class CinemaAppMain { public static void main(String[] args) { new CinemaApp().start();
[Code]....
I am trying to get the movie name and theatre title from their ArrayList, and I know I need to go through the movie list & theatre list to find their name & title, and compare it with the user input and print out the result.
I use for(int i=0;i<movies.size();i++) to go through the the movie list, and I tried using for(int i=0;i<theatres.size();i++) to go through the theatre list. But when I printing multiple time with different user input value, it will show me strange result (screening have same movie name & theatre name, the else if statement is printed below the user input, user input is printed more than once after the first time).
Edit: I know its wrong for me to use nested for loop,if not, another solution is needed to get the item inside both of the list. (getting the "title" from movie list & "name" from theatre list)
I am working on my java program it prints out a table of angles and the sin, cos, and tan. For extra credit he wanted us to use nest loops to create a space after every five lines. I have come real close to getting this to work but have a problem with the very end of the table. The table needs to stop at 180...
public static void printTable(double angle,double sin,double cos,double tan) { // Method to create a table for the values for (double j = 0; j <= 180;) { for (double i = 1; i <= 5; i++) {//loop to print five lines of code angle = Math.toRadians(j);
I've made my loop, but I am unable to get more then a 1 1 1 checkerboard properly. I am stuck on how to divide the filler characters to make the proper square size. As of now they are all one lined.
import java.util.*; public class Checker{ public static void main(String[] args) { int col, row, size; char filler; System.out.println("Please enter 3 numbers and a character."); //output
Now I have to write a method called printDesign that produces the following output but i am not even entirely sure how to start it out now of course i know how to make a for-loop but and i guess if i was to do something for this i would do this .....
Four experiments are performed, each consisting of six tests. The number of test results for each experiment is entered by the user. Write a Java program using a nested loop to compute and display the average of the test results for each experiment.
You can run the program by entering the following test results:
I am writing a program that has to do with ciphers and cipher shifts. The program itself works fine, but I am having trouble printing out the answers to JOptionPane. I know the basics of JOptionPane, but my problem is this:
Majority of my program takes place in a for loop, and resolves the cipher (it is a basic cipher program) 1 digit at a time. So, only the last DIGIT (I don't know how to convert a digit to a CHAR in JOptionPane) is printed to JOptionPane. Here is my code:
public static void main(String[] args) { String cipher = JOptionPane.showInputDialog(null, "Please enter a sentence or word that you wish to encode or decode. This program uses " + " a basic cipher shift."); int answer = 0; String upperCase = cipher.toUpperCase(); char[] cipherArray = cipher.toCharArray();
