Program That Continuously Asks For Alphabet Letter And Stops When Non-Alphabet Letter Entered
Oct 8, 2014
Write a program that continuously asks for an alphabet letter, and stops when a non-alphabet letter is entered. Then output the number of upper case letters, lower case letters, and vowels entered ....
I have a problem with functions connected to strings.
I have a random String, e.g. "Hello World!" and I have to change every capital Letter into a small letter and vise versa. This alone would be fairly simple, but I have to do it with two other strings.
lowercase= "abcde...z" and
uppercase="ABCDE...Z". Every small letter stands at the very same position as the capital letter, but in the other string.
There should be a letter for letter search in lowercase and uppercase for the letters of "Hello World".
How I could solve the task, however I need a way to search the first string, here "Hello World", according to position. A statement which does: "Give me the letter of position x". This found letter should be able to be stored in a variable or else be able to be used by another statement. And it should be compatible with a for lope.
Example : I have code and name but my code must start with the first letter of the inputed name if the 2 input is match it will be inserted into database
code = "A"001 name ="Angela" = success this will inserted into database
else
code ="B"002 name="Angela" =failed this will not inserted into database
else
code="A"003 name="Andy" =success still accepts the input cause they have diff code number
What I am thinking on this was compare the code the name? if == it will be inserted but how do i get the 1st letter of the input name?
/** * Auto Generated Java Class. */ import java.util.*; public class Hangman { public static void main(String[] args) { Scanner input = new Scanner (System.in); int guess; boolean revealed[] = {false, false, false, false, false}; String word [] = {"c", "a", "n", "a", "d", "a"};
[Code] ....
I am not sure how to make the program check if the letter entered by the user matches the one in the array. also i am not sure how to make the program run again with a new word.
I want to create a java program that can be encrypt-decrypt alphabet from characters . Which is the shifting of the alphabet is starting from the the first character to increase 4 and 5 increased in the second character, increasing 6 at the third character, and so on..
Then when one of the characters increasement is more than the ascii code of 'z', that character will decrease from the variable i from the loop. This is the output of the program that i want:
Write a method named secondHalfLetters that accepts a string as its parameter and returns an integer representing how many of letters in the string come from the second half of the alphabet (that is, have values of 'n' through 'z' inclusive). Compare case-insensitively, such that uppercase values of 'N' through 'Z' also count. For example, the call secondHalfLetters("ruminates") should return 5 because the 'r', 'u', 'n', 't', and 's' come from the second half of the alphabet. You may assume that every character in the string is a letter.
I have an encoder that will shift the character of a string X places. Im trying to account for the possibility of the shift being larger than alphabet array length. I've come up with the following, but I still get an ArrayIndexOutOfBounds Error and it never gets past the if statement.
SO for my project, we have to create a program where we input two four letter words, and using a list of words our teacher provided us and only changing one letter at a time, make the words match.For example, you input BALD and CALL and it would output BALD BALL CALLWe have to use recursion to do this, and I'm totally lost as to where to even begin.
i am new to programming skills it may be silly question for experience but for me it's new thing. actually i tried a lot but i am facing problem when i trying to take input through Scanner. if i will take input a sentence directly as a string it's working . but when i am trying with Scanner the first word is showing next are not showing
public class Demo2 { public static void main(String[] args) { String s1="hi how are you"; s1=s1.replace('a', 'A'); s1 =s1.replace('e', 'E'); s1 =s1.replace('i', 'I');
[Code]...
this is working properly.
but when i trying with Scanner i am facing problem.
public class Demo2 { public static void main(String[] args) { java.util.Scanner scn= new java.util.Scanner(System.in) String s1=scn.next(); s1=s1.replace('a', 'A');
I wrote a java application that coverts number grades to letter grades. Here is what it looks like:
/java application to That corresponds the letter grade with the number grade import java.util.Scanner; //program uses the class scanner public class gradescore{
How to replace correct letter with the blanks in the program. Last method in program used to print correct letters.
import java.util.*; import java.io.*; public class Hangman { public static Scanner keyboard; public static final int MAXSIZE = 15000; public static final int NUM_GUESS = 8; public static final int WORD_LENGTH = 20;
Write a program that translates a number between 0 and 4 into the closest letter grade. For example, the number 2.8 (which might have been the average of several grades) would be converted to B. Break ties in favor of the better grade; for example 2.85 should be a B. Use a class Grade with a method getNumericGrade. why when I type .3 it tells me "Exception in thread "main" java.util.InputMismatchException" Or if there is an easier way to do this.
import java.util.Scanner; public class Grades { public static void main(String [] args) { System.out.println("Enter a number between 0 and 4"); Scanner input = new Scanner(System.in);
I have the code below that just keeps getting the user's name and displaying it until the user enter's an empty string. Well, to simulate that, I just hit the keyboard instead of entering any name but for some reasons I am not seeing in my code, the programme just keeps looping.
System.out.println("Enter your name : "); Scanner st = new Scanner(System.in); while(st.hasNext()){ System.out.println("Enter your name : "); String name = st.nextLine(); System.out.println(name); if(name==" ") break; } System.out.println("you are out of the while loop now!!");
So if I wanted to tell the user that the fifth letter they entered is "____" how would I do that.
I am prompting the user to enter a word and then displaying the length of the String. Now I want to display to the user what the fifth letter of the String they entered is.
import java.util.Scanner; public class StringPractice { public static void main(String [] args) { Scanner input = new Scanner(System.in); String word; int lenght;
I'm writing a java program in eclipse of a tic-tac-toe game. I have to create it using JTextField's only I'm having trouble where the JTextField will only accept one letter and will only accept X and O is there any particular way to do this I started off with this piece of code
String text=tf1.getText(); if(text.length()>1) { System.out.println("this is not allowed"); tf1.setText("");
But it doesn't work so is there something I'm missing....
I'm trying to figure out the correct way to replace number into letter. In this case, I need two steps.
First, convert letter to number. Second, restore number to word.
Words list: a = 1, b = 2, f = 6 and k = 11.
I have word: "baafk"
So, for first step, it must be: "211611"
Number "211611" must be converted to "baafk".
But, I failed at second step.
Code I've tried:
public class str_number { public static void main(String[] args){ String word = "baafk"; String number = word.replace("a", "1").replace("b","2").replace("f","6").replace("k","11"); System.out.println(word);
[Code] .....
Result for converting to number: baafk = 211611 But, result for converting above number to letter: 211611 = bkfk
What do I miss here?
How to distinguish if 11 is for "aa" and for "k"? D
The point of this program is to search for a specific character in a text file. I want the program to find a character in the file "letterCounter.txt".
The purpose of this project is to determine the letter grade of students. The program needs to accept two command line arguments:
The first being the name of a disk file that contains the names of students, and their test scores, separated by commas followed by one or more spaces. Each line in the file will contain scores for one student.
The second argument is the name of an output disk file. The program is supposed to create a new output disk file using that name.
The number of students in the input file is unknown during compile time. The name of input and output files could be anything and only known during run time. Additionally, the average scores, along with the minimum and maximum scores for each test are to be displayed in the console.
Calculation: Final Score = quiz1 * .10 + quiz2 * .10 + quiz3 * .10 + quiz4 * .10 + midi * .20 + midii * .15 + final * .25 Final Score >= 90% then letter grade is A, 80%-89% B, 70%-79% C, 60-69% D, <= 59% F
I need to know how many four letter strings I can generate that begin with the letter "v". Now I had been testing many ways to do this but anm stuck. I can generate a single line up only a certain amount. I need it to continue till it reaches the max number. So since it needs to always start with V i eliminated the need for four and only a 3 letter string.
package javaapplication4; import java.util.Random; public class JavaApplication4 { /** * @param args the command line arguments */ public static void main(String[] args) { Random r = new Random(); int c = r.nextInt(26)+ (byte)'a';