Program To Detect Number 7 And Its Multiples
Apr 25, 2015
I just started learning Java, I was asked to write a simple program that prints a message if it encounters the number 7 or its multiple.
This should be achievable using simple loops and simple operations...
Here is my attempt:
Java Code:
Scanner scan = new Scanner(System.in);
int i, j, temp;
i = scan.nextInt(); // Awaiting user input
j = scan.nextInt(); // Awaiting user input
if (i > j){ // i = 10 j = 0
temp = i; // temp = 10
[Code]...
Now it works fine for numbers that are less than 70...
Example for output with i = 15, and j = 25:
Java Code:
15
16
!!!
18
19
20
!!!
22
23
24
25 mh_sh_highlight_all('java');
I am not sure what to do in case if for example 'i' and 'j' are very big numbers
I mean, I need it to detect the 7s even if it in the thousands place, actually - no matter how big is the number... So far I only made it to work for numbers that are less than 70...
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I'm trying to get this program to work but it keeps giving me all multiples, including ones over 1000 when I want it to not go over 1000. What am I doing wrong?
* A program that will prompt the user to enter a number and
* then print out all the multiples of that number that are less than 1000.
*
*/
import java.io.*;
import java.util.Scanner;
import java.text.*;
[code]....
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import javax.swing.JOptionPane;
public class CorreiaFranciscaA1Q1 {
public static void main(String[] args) {
String ManuscriptTitle =
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String AuthorName =
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String TotalWords =
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[code]....
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What ever positive value which has multiples keeps on displaying " No multiples ........ where found, and the answer.how can i fix the colored part ?
import java.util.Scanner;
public class Problem4 {
public static void main(String[] args) {
Scanner input=new Scanner(System.in);
int n;
boolean x=true;
System.out.print("Enter an integer n: ");
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[code]....
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Jun 20, 2014
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Welcome to this first-ever mind-guessing program!
Please pick a range (higher than 1 and no larger than 50): 32
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My guess is too high?
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*** I am unlucky this round. I give up.
Let's play!
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etc..
import java.util.*;
import java.lang.Math;
public class numguessprac1 {
// Declaring variables
public static String input;
public static int quit;
public static int guess;
public static int wins;
[Code] ....
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package com.java2novice.algos;
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public void printBinaryFormat(int number){
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[Code]...
Bugs on:
Line 13
Line 17
Line 23
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ex
Sample input:2340980
Sample Output:23498
this is the program i have tried but is dosent work
import java.util.*;
class zero
{
public static void main(String args[])
{
[Code]....
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[code]...
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[code]....
i have just a couple of issues when running my program.
-First, When i enter 0 it should print..
Please enter a possible perfect number: 0
0:NOT PERFECT
-Second, when i get a perfect number. it should show the answer in descending order..
Please enter a possible perfect number: 6
6:3 2 1
mine shows: Please enter a possible perfect number: 6 6: 1 2 3
**everything else compiles correctly with no errors
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Dec 2, 2014
how many integers the user wants to use. The user will enter for example a 4. The user inputs a 2, 4, 6, and 10. So then we get our outputs...Then the code will ask if you want to run this program again. My question is, if the user inputs a -1 for example 2, 4, 6, -1....the code will not continue. I wanted to use a while loop, such as while (scores != -1) but it doesn't work.
Enter the amount of integers you want to use4
Intenger # 1 2
Intenger # 2 4
Intenger # 3 6
Intenger # 4 10
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Variance = 8.75
Standard Deviation = 2.96
Do you have another set of numbers?
[code]....
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f = 6
g = 7
h = 8
i = 9
j = 10
k = 11
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m = 13
n= 14
o = 15
p = 16
q = 17
r= 18
s = 19
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u = 21
v = 22
w = 23
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