Random User Names

Nov 9, 2014

Program is running fine. I can create usernames and everything but somehow I cannot quit or exit the program when I enter my sentinal value "QUIT". Here is my program question: Create an application that will create a username for a school computer system. Input a user’s first and last name. The username will be the first letter of the first name followed by the first 5 letters of his last name followed by a random 3 digit number. Continue to create and display usernames until a sentinel value is entered.

import java.text.*;
import java.util.Random;
import java.text.DecimalFormat;
public class username

[code]...

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PrintWriter - Ask User For The Names Of Two Files

Jun 30, 2014

Write a program that asks the user for the names of two files. The first file should be opened for reading and the second file should be opened for writing. Ihe program should read the contents of the first file, change all characters to uppercase, and store the results in the second file. The second file will be a copy of the first file, except that all the characters w ill be uppercase. Use Notepad or another text editor to create a simple file that can be used to test the program

Here is my code. I Also made two text document files that are located in the same directory as the .class file (the code file) that are named OriginalFile and UpperCase respectively. Please let me know what I need to do. Here is the code.

import java.util.Scanner;
import java.io.FileReader;
import java.io.IOException;
import java.io.PrintWriter;
public class UpperCaseFile
{
public static void main (String [] args) throws IOException
{

[Code]...

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May 21, 2015

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My idea for a solution is to create an ArrayList<String>, read each name, i.e., line, entered and then to see if that name is already in the ArrayList. I created a for loop to check each element in the ArrayList but when I try to assign an element to a string variable I get the error "Type mismatch: cannot convert from Object to String". Not sure why that is happening because the ArrayList is defined as a String list.

Here is the code so far.

/*
* File: UniqueNames.java
*/
import acm.program.*;
import java.util.*;

[Code].....

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import java.util.Scanner;
public class PhoneBook{
public static void main(String[] args){
String name;
int phoneNumber;
final int nameAmount=20;

[Code] ....

I can't seem to get it correct, every time I correct a compiler error, another set of them appear.

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int maxRange1;
int minRange1;
static int range;
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Then in my mail argument:

gen = new Random();
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[Code] ....

I am able to return both the user prompts and get the inputted answer to appear but I am not getting a response for the prompt "The random number is: ".

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public static void main(String[] args)throws IOException {
// TODO code application logic here
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int num1=(int)(Math.random()*(9-0));
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[Code] ....

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import java.util.Scanner;
import java.util.Random;
/*SentenceEncryptionProgram
*/
public class SentenceEncryption {
string sentence; //sentence entered by user

[Code] ....

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I have been assigned to write a program that has a user input random numbers then the program is to sort them in different ways. I have the coding for the different sorts but, I have an error saying that I am missing a return statement in the "Bubble" method. I am trying to return "arr[i]" in the "for loop" which gives me this error, and when I try to take the "return arr[i]" outside of the "for()" loop the error reads the it cannot locate variable "i".

import java.awt.* ;
import java.awt.event.*;
import javax.swing.*;
public class SwingSorts extends JFrame implements ActionListener
{
JRadioButton bubble;
JRadioButton selection;

[Code] .....

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Dec 8, 2014

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So far I have gotten the random number generation part working. I have up to here:

import java.util.Random;
public class test4 {
public static void main(String[] args) {
Random random = new Random();
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import java.util.Random;
import java.util.Scanner;
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public static void main(String args[])
{
String choice="y";

[Code] ......

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enum enum1{
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[Code] .....

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Here is my code thus far:

public class Room {
private String name;
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} public void addAnimal(Animal a){
for(int i = 0; i < 10; i++){

[code].....

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String[][]data=new String[28][5];
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//sheet.setBounds(10, 36, 527, 214);
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In a spreadsheet, alphabetical letters are column names and numbers represent rows. I have named the columns and I need to name the rows in the same way. Or if I am to set the first column in every row as row headers, how can I make then non-editable by the user? In addition to that, how can I make the table appear bigger? There's a lot of space but the table appears to be small.

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Object child=table1.getChildAt(i);
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DataFactory

So, I can get a random name like so:-

package domainentities;
import java.util.Random;
import java.util.Collections;
import org.fluttercode.datafactory.AddressDataValues;

[Code] .....

But - it always prints 'Lindsey'. I need a way of completely randomizing but I can't see the class has a method to let me do this? I can use the randomize method but this takes an int argument which will always bring back the same index value (same name).

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import javax.swing.JOptionPane;
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Java Code:

setseatpos: function(previouspos, position) {
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how i can do this ?

My code are as follows :

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Nov 4, 2014

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I want the result to be sth like this:

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and a table of mappings

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....

I give my dataset in csv (or text) format to my program but it says "(The system cannot find the file specified)" even though the file exists.

what should I do?

here is my code:

Java Code: public class ReadCSV {
HashMap<String, Integer> authorList = new HashMap<>();
File file = new File("d:/Course/thesis/predict/whole.scv");
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class Foo
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}
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