Removing Duplicate Elements From Array

Dec 18, 2014

I was trying remove duplicates element from my array without using collection API but i didn't got any output from my code.Although it is compiled successfully but on execution it didn't give any output. I guess there must be some problem in function Duplicate

Java Code:

class Union {
public static void main(String...s) {
Union M=new Union();
int x[]=new int[]{1,0,1,4,10,10,10,3,567,4,3,33};
int y[]=new int[]{5,4,5,4,5,4,2,3,3,1,0};
int []w=M.merge(x,y);

[Code] .....

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remove duplicate elements in array using with java

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public class werek4d {
public static void main(String[] args) {
int counter = 1;
int[] anArray = new int[101] ;
for (int i = 0; i <= 99; i++){
anArray[i] = i + 1;
System.out.println(i + ": " + anArray[i] + " ");

[Code] ....

My aim is to generate a lists containing 1 to 100. I will then count the number of integers divisible by 3. After doing so, I want to delete the integers that are NOT divisible by 3 in the lists. I tried doing it, but I seem to keep on getting the same lists.

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Aug 24, 2014

Referring Code 1, the book says line 16 of the code removes the element "Three" but line 17 does not remove the element "Four" because of Statement 1. The question is does remove(Object o) method invoke the == or the equals method because statement 1 and 2 seem to be in conflict

Statement 1:

Two objects are equal if their object references point to the same object. (which is nothing but definition of ==)

Statement 2:

The author refers to Statement 1 and says "As mentioned earlier, the method remove compares the objects for equality before removing it from ArrayList by calling method equals."

Java Code:

import java.util.ArrayList;
public class DeleteElementsFromArrayList {
public static void main(String args[]) {
ArrayList<StringBuilder> myArrList = new ArrayList<>();
StringBuilder sb1 = new StringBuilder("One");

[Code] ....

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import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class array
{
public static void main(String[] args)

[Code] ...

Is there a way to write this, where, alpha is one array.

Write a program that declares an array "alpha" of 50 elements of type "double". Initialize the array so that the first 25 elements are equal to the square of the index variable and the last 25 elements are equal to three times the index variable. Output the array so that 10 elements per line are printed.

If I have an array of 50 integers, can I break that to read in lines of 10?

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Write a method that returns a new array by eliminating the duplicate values in the array using the following method header: public static int[] eliminateDuplicates(int[] list). The thing is that I found the working solution that is written below, but how it works. How to eliminateDuplicates method done with flag and flag2.

Here is the code:

Java Code:

import java.util.Scanner;
public class Exercise06_15 {
public static void main(String[] args) {
java.util.Scanner input = new java.util.Scanner(System.in);
int[] numbers = new int[10];
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[code]....

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Apr 6, 2014

I have a java file 'Arithmetic.java', in which i have 2 overridden method.Now i wanted to read this file and i need to print all the method signature lines,if i found same(overridden method)signature then i have to print "overridden method found". once i find the overridden method i have to suffix the method name as methodName_overridden1, methodName_overridden2 and so on...

package com.abcd.arithmetic;
public class AllArithmatic
{
public Integer add(int x,int y,int z)
{
return (x+y-z);
}
public Float substract(float x, float y)

[code]....

till now i am able to read the lines, able to read the method names as well. but while putting the entire method signatures into an string array and the suffixing part , i am not able to proceed. The condition i have put to find out oerridden method is nnot working.i am stucked in comparing the duplicate method

//Finds Method Name, Method Return Type
if(indexOfMethod >-1 && indexOfOpenBrace >-1){
int uniqueWordsInFile=0;
//Method signature Start
//System.out.println("method line="+line.trim());
List<String> methodList = new ArrayList<String>();
methodList.add(line.trim());

[code]....

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//this is one of my fill sort arrays

public void fillSelectionArray(int index, long countSum) {
//rand = new Random( );
//for ( int i = 0; i < listsize; i++) {
selectionList[ index -1] = countSum;
// }

[Code] ....

I know I am missing something just not sure what.

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Jul 8, 2014

I am working on this project that wants me to write a program that inputs 20 numbers, each of which is between 10 and 100, inclusive. As each number is read, display it only if it is not a duplicate of a number already read. The only part I am confused about is how to go about checking for duplicate values that the user may enter. And IF the user does input a duplicate value, it should not be stored again.In addition, the value entered should be printed out after it is entered along side the value that have been previously entered by the user such as:

23
23 45
23 45 67
23 45 67 12
and so on.

I am still fairly new at java programming.

import java.util.*;
public class NumberArray
{
public static void main(String[] args) {
// declare an array with 5 elements

[code]....

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Mar 28, 2014

I have a practice program (written with NetBeans IDE 7.4) that calls methods to:

(1) fill an array with user input values

(2) sort the array values into ascending order

(3) print the array in assorted order.

(4) print the array without any duplicates

Method (4) prints the contents of the array without printing any duplicates. That is, if a number in the array has already been printed, it will not be printed again.

Method (4) seems to work, but may be inefficient or I may have done too much work making it difficult on myself or making the logic too confusing.

Is there a better way to do this WITHOUT using built-in functions in Java's library?

(Such as writing this method using for loops and counter variables: As practice I am supposed to avoid using Deleting functions for duplicates)

Here is my code:

public static void Duplicates(int [] array){
int duplicates = 1;
String Output = "";
for(int i = 0; i < array.length -1; i++) {
if (array[i] != array[i+1]){
duplicates ++;

[Code] .....

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Nested for-loops always throw me in a loop.I found a snippet that uses 2 for-loops to check if there is a duplicate element in the array:

/*
* brute force way of checking if array contains duplicates in Java comparing each elements to all other elements of array complexity on order of O(n^2) not advised in production
*/
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return true;
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Let us say we have:
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I am stuck on this exercise and I don't know what exactly is wrong. I think it's something with the .remove and the for each loop, but I am not sure.

public class seven {
public static void main(String[] args) {
ArrayList<String> list = new ArrayList<String>();
list.add("aaa");
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list.add("unni");

[Code] ....

This is what i get

Exception in thread "main" java.util.ConcurrentModificationException
at java.util.ArrayList$Itr.checkForComodification(Unknown Source)
at java.util.ArrayList$Itr.next(Unknown Source)
at seven.removeDuplicates(seven.java:24)
at seven.main(seven.java:18)

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[code]....

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[Code] ......

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[Code] ....

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[Code] ....

I've been trying to experiment with different ways such as checking to see if there any duplicate elements such as,

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[Code] ....

Error message:
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Will I need to appoint those characteristics in the constructor after initializing fish = new boolean[30]?

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