My PC runs on Windows XP. When I try to run a java program (written using NetBeans) from the command prompt, the program opens in NotePad but does not run.This is what I have been typing at the command prompt:
C:javahellosrchelloHello.java
The above is the correct path to the Java file on my PC.how to run the program from the command prompt or perhaps link me to a tutorial that explains it?
This is my program: RemoteXMLRead.java
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.apache.commons.io.filefilter.WildcardFileFilte r;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import java.io.File;
[code]....
It is working fine when i run in Eclipse, but is giving error when i run in cmd.. What i need to do to over come this..
C:Users
swarnajar>java -cp C:PROJECTSDCDEDashboard(WorkingCopy)warWEB-INF
lib*.jar -Ddcde.bootstrap.location=C:PROJECTSDCDEDashboard(WorkingCopy)prop
erties -jar qaqc.jar
[Code]....
When I am trying to run an applet in command prompt I am getting an error message saying: System cannot find the file specified.
Initially I compiled my applet using javac BubbleSort1.java it works fine But when I tried running this using: appletviewer BubbleSort1.html I m getting the above error. Anyhow, both the html file n the java file are in same folder in C drive. (windows 7) .....
I've been playing around with this for about an hour.
Java Code:
Runtime runTime = Runtime.getRuntime();
try {
Process process = runTime.exec("notepad");
} catch (IOException e) {
e.printStackTrace();
} mh_sh_highlight_all('java');
So that works. Notepad will open.
However, I'm trying to get other programs to open. Specifically, this program: C:Octave3.2.4_gcc-4.4.0inoctave-3.2.4.exe...However, using that in place of notepad doesn't work. I'm assuming that there is some sort of system variable that explains why simply typing "notepad" works? As if you type notepad into the run box, notepad will open. Soo does that snippet work by going through some sort of system variables?How would I go about opening other programs, such as the one I referenced above.
I am trying to execute a program from the command prompt. I type java -jar zuul.jar (zuul is the name of my project) and I get a message that java is not recognized as an internal or external command. What do I do wrong?
View Replies View RelatedMy Java program is failing to run in command prompt and no result is produced.I am currently using windows 8 and I have changed my Environmental variable to C:Windowssystem32;C:Program filesJavajdkin.
View Replies View RelatedWe are using Kronos and when our staff trys to run reports -- they get three java prompts.The first one is asking if they would like to update java.The second one is do you want to run this application.The third one is allow access to the following application from this website
We are in a non persistent VDI environment so these prompts come up over and over and over.how to edit the Windows 7 image to disable all three of these prompts.Is there a way to install java from the command prompt with the parameters to disable these prompts from ocurring? if so i will uninstall and re-install with those prompts.
I am just learning Java and I am have a problem running programs at the command line. I have the following code:
package java_help;
import java.io.IOException;
class help {
[Code].....
I can run this program in net beans were I originally wrote the program and it runs fine there. I also compile the program at the command line using javac but when I go to run this program I get a error message that it cant find main.
i have windows 7. cmd.exe told me it couldn't recognize javac.i have a JDK installed though...
View Replies View RelatedI've Installed oracle JDK version 1.8 on a debian machine that already has openjdk 1.6.i've set the path variable in etc/login.defs and java_home variable In etc/environment. When I echo $JAVA_HOME it points to the oracle version correctly and when I run javac It uses the oracle 1.8 version. The problem is when I run the java command , It runs the openjdk 1.6 version and I'm not sure why.If I type java -version It shows the openjdk version.
View Replies View RelatedI have set the CLASSPATH
(C:Program FilesApache-Tomcat-7apache-tomcat-7.0.53libservlet-api.jar,
PATH(C:Program FilesJavajdk1.7.0_51in)
and JAVA_HOME
(C:Program FilesJavajdk1.7.0_51) environmental variable on my windows XP.
I installed tomcat server and its running fine. I made my first servlet(DemoServlet.java) in
C:Program FilesApache-Tomcat-7apache-tomcat-7.0.53webappsDEMOWEB-INFclasses folder.
I made the XML file (web.xml) in C:Program FilesApache-Tomcat-7apache-tomcat-7.0.53webappsDEMOWEB-INF folder. In command prompt I went to the classes folder
(C:Program FilesApache-Tomcat-7apache-tomcat-7.0.53webappsDEMOWEB-INFclasses).
And tried to compile my servlet(javac DemoServlet.java) but it is showing file not found error. I am new to servlets.
I currently finding a way how can i package a required/dependency JAR with my runnable JAR only using a command prompt like :
how the ECLIPSE IDE export RUNNABLE JAR
I am running on a linux environment, is there a way to do this.
I can only make Runnable Jar without the required JAR by using this command
jar cvfm Test.jar manifest.txt package/*.class
Im following a simple set of code and can not get the correct output, in chapter 1 (Intro to Java).Im stuck on getting a set of code to run completely through command prompt. I installed.JDK and textpad4, type the code, save it, direct towards it in cmd prompt but javac wont work. Here's the code I put in textpad;
public class Test {
public static void main(string[] args)
Ststem.out.println("3.5 * 4 / 2 - 2.5 is ")
System.out.println(3.5 * 4 / 2 - 2.5);
[code]....
I am using Oreilly Head First Servlet book and having trouble in compiling servlets from cmd.
Tomcat path is : C:Program FilesApache Software FoundationTomcat 6.0
Below is compiling result
C:ProjectseerV1>javac -classpath "%TOMCAT_HOME%libservlet-api.jar:"classes:
. -d classes src/com/example/web/BeerSelect.java
srccomexamplewebBeerSelect.java:3: error: package com.example.model does not
exist
import com.example.model.*;
^
srccomexamplewebBeerSelect.java:4: error: package javax.servlet does not exi
st
import javax.servlet.*;
[Code] ....
14 errors
C:ProjectseerV1>
I have installed java and I am not able to compile codes using command prompt.... what are the correct settings so that I can proceed further ....
Capture.JPGCapture2.JPG
I was wondering if their is an easily explainable way to convert a jar for a text-based game that runs off the command prompt into a executable. I would guess there probably is not and the game would have to run off of completely different commands, but I thought it couldn't hurt to ask.
View Replies View RelatedI just created a Hello World program in Notepad, but command prompt still can't find it even when ran as administrator. I've even tried to use command line to run Hello World programs I've created with Eclipse but it still doesn't work. Here's proof I have JDK setup as PATH:
I've even tried having the JRE as path but that still doesn't solve my problem. I'm really trying to learn Java programming but this problem is holding me back.
I am making a ui in which i have a JTextfield and a JButton(run). I am reading values to JTextField from text file and on pressing Jbutton a Batch file runs. Now when i press the Jbutton the batch file runs showing number running, in place of number running, i want to display the JTextfield value. So i want in place of number running it should display JTextfield value running. How can i achieve it.
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.io.*;
import java.util.*;
import java.awt.event.*;
[Code] .....
a.text: 1248
p.bat:
echo number running
pause
I'm suddenly having trouble running classes from the command line. Previously, things were working. I cant imagine I'm doing anything differently. The sample code is below:
Code:
class HelloWorldTester{
public static void main(String[] args){
System.out.println("Hello World");
}
}
Terminal output:
C:UsersmattmanDropboxProgrammingJava>javac helloWorldTest.java
C:UsersmattmanDropboxProgrammingJava>java HelloWorldTester.class
Exception in thread "main" java.lang.NoClassDefFoundError: HelloWorldTester/clas
s
Caused by: java.lang.ClassNotFoundException: HelloWorldTester.class
at java.net.URLClassLoader$1.run(URLClassLoader.java:202)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:190)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
at java.lang.ClassLoader.loadClass(ClassLoader.java:247)
Could not find the main class: HelloWorldTester.class. Program will exit.
I am operating java from the command line (using Terminal on Mac OSX 10.9.5).The current directory within Terminal is called "orange" and the following sourcecode file is in the orange directory :
Test1.java
package orange;
public class Test1 {
public static void main(String[] args) {
System.out.println("Test1 works");
}
}
This complies to Test1.class (visible in the orange directory) but when I try to run it in Terminal (simply using "java Test1" from within the orange directory). I get the following error message (which I don't get if I simply comment out the line //package orange;)
Exception in thread "main" java.lang.NoClassDefFoundError: Test1 (wrong name: orange/Test1)
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClass(ClassLoader.java:800)
at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:142)
at java.net.URLClassLoader.defineClass(URLClassLoader.java:449)
[code]...
how to structure simple programs (i.e. one-method algorithms for a simple purpose). There are a few different ways that I have been doing it, but I want to be consistent. Should I put both the one-method algorithm (e.g. a factorial function) and the main method that executes the algorithm into the same class and then export it to an executable .jar file for use? Or should I create one class for the algorithm and another for the main method that executes the algorithm? In addition, is there any reason that I should out these classes in a package before I export it?
As another similar question, if I have constructed two distinct classes with two separate purposes, and they are both used in the construction of a single program, then would it be best to just put the main method in a third, separate class or should I put it in one of the two classes?
How do I set the class path, the path, compile and run java programs using jdk and jcreator?
View Replies View RelatedWrite a program that prompts the user for an input number and checks to see if that input number is greater than zero. If the input number is greater than 0, the program does a multiplication of all the numbers up to the input number starting with the input number. For example if the user inputs the number 9, then the program displays the following sum:
9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 362880
That's the question I'm getting and so far all I've got is
import java.util.Scanner;
public class Lab4Q3
{
public static void main (String[] args)
{
int keyboard;
[Code] .....
I am using java process to start a system command in windows
Runtime r = Runtime.getRuntime();
Process pr = r.exec(cmdString);
I want to get the prompt out put from cmdString = "cmd /c type fileSmallSize"->>>> It is ok the have the content of the file when file is small.
However, for a large file java process will hang and no Exception occurred, what is the problem?
The easiest testing you can try on the logging.properties file in java.
public static String executeCmdAndReturnPromptResult(String cmdString)
throws Exception {
LOGGER.entering(CLASSNAME,
"Entering executeCmdAndReturnPromptResult()", cmdString);
String cmd = cmdString;
[Code] ....
It seemed to me that the bufferSize is limited so that I can only have it less than a default one, how to increase it?
My question now is how to increase the size of buffer in order to read a larger InputStream ?
BufferedInputStream() default size is
private static int defaultCharBufferSize = 8192;
private static int defaultExpectedLineLength = 80;
How to make it larger and working? I tried to increase the defaultCharBufferSize to 500000000 but it did not work!
I was wondering if you use an IDE when writing programs?Can you use J frame when using command line or is it just used with an IDE and do you go into framing in the book?I have taken programming classes and I am still stuck.
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