Separating Integers Into Individual Digits And Print Separately By Three Spaces Each

Mar 11, 2014

Write an application that inputs one number consisting of five digits from the user, separates the number into in individual digits and prints the digits separated from the user, separates the number into its individual digits and prints the digits separated from one another by three spaces each.

For example, if the user types in the number 42339,

the program should input 4 2 3 3 9.

Here is my code so far but I am stuck.

mport java.util.Scanner;
public class Seperating {
public static void main ( String[] args) {
Scanner input = new Scanner(System.in);
int number = 0 ;
System.out.printf("%d" , number );
System.out.print("Enter integer");
number = input.nextInt();
}
}

but I am not getting the result I wanted what am I doing wrong

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User To Input Integer And Then Outputs Both Individual Digits Of Number And Sum Of Digits

Feb 2, 2015

Goal is to: Write a program that prompts the user to input an integer and then outputs both the individual digits of the number and the sum of the digits.

First I don't know where I made mistakes here, and the only error it finds right now is that str2 was not initialized and I cannot figure out where/when to initialize it.

import javax.swing.JOptionPane;
public class DigitsAndSum {
public static void main (String[] args) {
String str1;
String str2;
int int1 = 0;
int int2 = 0;

[Code] ....

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Separating Digits With Modulus?

Feb 4, 2015

The following code splits an integer into separate digits. It then adds 7 to each of those digits, and then finds the remainder when the result is divided by ten. To do this it uses the Modulus operator.

public class manipulateIntegers {
public manipulateIntegers() {
System.out.println("Enter a four digit Integer");
String y = System.console().readLine();
int[] list = new int[5];

[code].....

I understand completely about what modulus does vis-à-vis fetching the remainder, but I don't understand why using the modulus operator gets you each digit individually?

for example, this snippet splits the digits of an integer - but how??

int number; // = some int
while (number > 0) {
print( number % 10);
number = number / 10;
}

and why does number have to be reassigned as number / 10?

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How To Delimit Spaces In User Input Separating Two Data Types

Jan 17, 2015

I am creating a calculator in which a user will directly input the numbers and the operator...

Here is my code:

int answer = 0;
int num1, num2;
char operator;
System.out.print("Enter calculation: ");
num1 = kb.nextInt();
operator = kb.next().charAt(0);
num2 = kb.nextInt();

The code above will accept the user input when there are spaces like this: 1 + 1

So the program will give an answer which is 2...BUT

if i input 1+1 it will give an error...Exception in thread "main" java.util.InputMismatchException

How can i do that it will separate integer to character? because i set the operator as character....

So that it will accept one digit to several digit numbers... like 500+84 or 1520+872??

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Breaking Integer Into Individual Digits?

Oct 12, 2003

I'm trying to figure out how to read in an integer and break it down into a sequence of individual digits in reverse order. Example: an integer input of 12345 gives an output of54321.

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String Formatting - Enter Three Positive Integers Separated By Spaces

Sep 18, 2014

double a = scan.nextInt();
double b = scan.nextInt();
double c = scan.nextInt();

//**********************************Equations**********************************
System.out.println ();

double sum = a + b + c;
System.out.printf("Sum = %d", sum);

Heres the error I'm getting

Enter three positive integers separated by spaces, then press enter:
15 20 9

Sum = Exception in thread "main" java.util.IllegalFormatConversionException: d != java.lang.Double
at java.util.Formatter$FormatSpecifier.failConversion(Unknown Source)
at java.util.Formatter$FormatSpecifier.printInteger(Unknown Source)
at java.util.Formatter$FormatSpecifier.print(Unknown Source)
at java.util.Formatter.format(Unknown Source)
at java.io.PrintStream.format(Unknown Source)
at java.io.PrintStream.printf(Unknown Source)
at project2.main(project2.java:52)

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Multiplying Long Integers 10+ Digits?

Nov 7, 2014

Taking two input strings that are integers such as "1234" and "567" then multiplying as you would do by hand. Trying to get them saved in the n3 new string but something is going wrong. You also need to account for the zeroes that have to be added just like on paper.

String mulN(String n1, String n2) {
int p = 0, tmp = 0; int zeros = 0;
String n3= "";
String r = "";
for(int i = n2.length()-1; i >= 0; i--) {

[Code] .....

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Print Range Of Integers From X To Y With Increment Of 5

May 6, 2015

Working on problem in my book in which I have to print a range of integers from x to y with an increment of 5. I thought I had the right idea when writing out this code, but apparently, it only gives a few of the numbers in the range, not all, what I am doing wrong?

import java.util.Scanner;
public class Ranges
{
public static void main (String[] args) {
Scanner input = new Scanner (System.in);
System.out.print("Enter a value for x and y: ");
int x = input.nextInt();

[Code]...

import java.util.Scanner;
public class Ranges
{
public static void main (String[] args) {
Scanner input = new Scanner (System.in);
System.out.print("Enter a value for x and y: ");
int x = input.nextInt();

[Code]...

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Creating Method To Print Array Of Integers

May 7, 2014

I am trying to create a method that takes an array of integers and prints it out using System.out.print. I'm having trouble creating the right way to print it out since I cannot find a way to convert the int array to a string to print it out.
 
public static String printArray(int[] num){
for (int i=0; i<num.length;i++){
String msg = num[i];
}
return System.out.print(msg + " ");
}

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Unable To Print Repeating Integers In Array

Aug 5, 2012

I have a problem where i have to write some code to read through an int array and print out the different integers and how many times they occur. For example:

if the array contained the numbers 1,4,2,3,5,4,4,7,5,4,3,6,8,6,4,

i would need the print to appear something like this

integer: 1, times: 1
integer: 4, times: 5
integer: 2, times: 1

etc

as the array is read sequentialy from element 0 to the end. the program should find the integer value in the first element (increment a counter by 1) and then search all other elements to see if the integer reoccurs (counter++ for each time it reappears). obviously the counter would be the 'times' value in the second column.

My problem is i can get this accomplished yet i cant get the program to recognise when it has already registered an integer in a previous element and skip to the next element looking for a new integer. SO for each element in the array it prints the integer and then searches the entire array for the integer again and increments the counter accordingly. so in essence there is a line printed for each integer the number of times it actually occurs.

I simply wish to have my code to find an integer and the number of times it occurs. and then disregard the elements it has registered the previous integer in.

Also, keep in mind that i am NOT permitted to use any new data structures/arrays for storing/remembering values. I can only use int and double variables throughout.

what i have so far is this: with the array being customerID[] :

Java Code:

int num;
int counter;
for(int count = 0; count < customerID.length; count++)
{
counter = 0;
num = customerID[count];
for(int count2 = 0; count2 < customerID.length; count2++)

[Code]...

The output for the int array 1,1,3,0,3,2,0,4,1,3, looks something like this:

Integer: 1, Times: 3
Integer: 1, Times: 3
Integer: 3, Times: 3
Integer: 0, Times: 2
Integer: 3, Times: 3
Integer: 2, Times: 1

[Code]...

and as you can see lines are repeated for each time the same integer occurs in a new element. i just need my code to skip an element if the integer has been previously encounterd and recorded. i.e i need it to look more like this :

Integer: 1, Times: 3
Integer: 3, Times: 3
Integer: 0, Times: 2
Integer: 2, Times: 1
Integer: 4, Times: 1

with the first encountered integer being checked throughout the array and then moving to the next integer/element which is not the same as any previous.

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Print Maximum And Minimum Values Of Integers From User Input

Apr 27, 2015

So I'm learning java from a website and I was tasked with creating a simple program which allows the user to enter a series of integers, then finally when they decide to input a non-integer the program will print the maximum and minimum values of the integers they entered. So for example if they entered 5, 4, 3 and 2 then enter a non-integer the program would output 5 (maximum value), then 2 on a new line (minimum value).

Here is my code:

import java.util.Scanner;
public class MaxMinPrinter {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;

[Code] ....

And this is what the output looks like:

Actual output
-------------------------------------------
Enter an integer: 5
- 10
-
- Enter an integer: -4
- 8
- -6
-
- Enter an integer: 11
- -1
-
- Enter an integer: q
- -1
- -6

When it's supposed to look like this:

Expected output
-------------------------------------------
Enter an integer: 5
Enter an integer: 10
Enter an integer: -4
Enter an integer: 8
Enter an integer: -6
Enter an integer: 11
Enter an integer: -1
Enter an integer: q
11
-6

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Feb 13, 2014

I have double checked this code over and over and I just can't find the problem.

What I'm trying to do is take a file and input it into an 2D array.

Ultimately, I should convert the array of integers to an array of characters, then print it out. The file contains a set of ASCII values.

After printing it out, I should then create methods to manipulate the image produced.

Using 2D arrays is a requirement for this exercise.

I think that somehow I'm overcomplicating this and the solution is a lot more simple than I think, but I can't think of what to change.

The error I am getting is:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 40
at main.main(main.java:17)

Java Code:

import java.util.*;
import java.io.*;
public class main {
public static void main(String[] args)
throws FileNotFoundException {
String[][] data = new String[22][40];

[Code] .....

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May 13, 2013

I have a text file that has the results of rock paper scissors game.

R P
S R
P P

I need to have the first letter in each line assigned to player1 and the second letter in each line assigned to player 2. where to start. I have the file input correct. It is reading the file and I can separate ints from strings. I just don't know how to separate the strings.

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May 12, 2013

Web Layer - JSP/Servlets
Business Layer - EJB 3

I want to develop separate projects for web layer (.war) and for Business layer (.jar). I want to deploy these layers on different Glassfish servers.

Here is my Approach -

1. Create a separate module for remote interfaces (.jar), use @remote annotations
2. Create a Web module using JSP/Servlets (.war) and use this remote interface jar in it.
3. Create a EJB module (.jar) and implement these remote interface in it.
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I want to know if this is the correct approach?

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Dec 3, 2014

What my program needs to do:

1) accepts a filename from the user that indicates the input file
2)obtains a filename to use as the output file
3)the program then reads the file and reports how many of each letter are there in the file.
4)if the file could not be opened, you must ask the user for valid file name until one is given
5)once a valid file name is given, print all of contents and store the analysis of the file in the output file name specified

You will be reading the input from a file and printing the output to another file. For example, if the file input.txt contains:

This file contains lett3rs.
YoU counT Only lEtTers, not numb3rs.
How many h's are in "Ohhhhhhhhhhh no!"?

The program should ignore white spaces, new lines and other special characters or numbers. It should count only the letters (a-z and/or A-Z) in the input file.

An example execution might look like this:

Input a file name: notAFile.txt
Invalid filename given. Input another.
Input a file name: alsoNotAFile.txt
Invalid filename given. Input another.
Input a file name: input.txt

[Code] ....

1)The last try/catch block was given by my professor, however the only thing it does is print out "hello java" into an out file. How would I make it print out similar to that of the given example?

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So after downloading some basic jars other needed individual class files are downloaded as and when requested by user. For signing applet, applet class files are moved to jar and this jar is signed with following attributes in manifest.
 
Jar file manifest:
Permissions: all-permissions
Codebase: *
Application-Name: XYZ
Application-Library-Allowable-Codebase: *
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I have written a program (DOM Parser) that parses data from a XMl File. I would like to create an individual file with the corresponding name for each set of data parsed from the xml document. If the parsed output is Single, Double, Triple, I would like to create an individual xml file (Single.xml, Double.xml, Triple.xml)with those corresponding names. How do I create the xml files and give each file the name of my parsed data output?

import java.io.IOException; 
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import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;

[code]....

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Page 1 - Gyazo - d4f7da28285f16a2a0069ac1631290fa.png
Page 2 - Gyazo - 470cf689a3126b7ab6c64bb14ae80a0d.png

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I have huge PDF files which are in booklet format. Example:
 
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The first page has 48th page number on the left side and 1st page number on the right side
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3rd pdf file - 2nd page
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the first page has 95th page number on the left side and 1st page number on the right side
 
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After renaming correctly in the proper sequence for the above file
 
1st pdf file should point to 1st page
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PDF2 file - has 96 pages -> files should be renamed and arranged as 1, 2, 3, 4.....96 correctly
PDF3 file - has 56 pages -> files should be renamed and arranged as 1, 2, 3, 4.....56 correctly
 
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I have created this program that outputs

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123456

I tried looking up some ways to create spaces in between each number, but I failed miserably. Here is what I have right now.

public class Iterations {
public static void main(String[] args){
for(int i=1;i<=6;i++)
{
for(int j=1;j<=i;j++)
System.out.print(j);

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May 2, 2014

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Oct 14, 2014

I am having a problem of how to write a program dat will input one number consisting of five digit,separate the number and print the digits separated from one another by three spaces each.. I tried to use divisional and remainder operation but it didn't work.

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How can i make sure that when user enter value there is no space between words example :

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Apr 22, 2014

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=================== =================== ====================== ===
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Jan 21, 2014

I am trying to split a string into a String[] tokens array to declare variables for an object; however, I'm having an issue getting the string to tokenize correctly. Here's an example of the input:

a : 100 : John Smith : 20 Main St.
a : 101 : Mary Jones : 32 Brook Rd.

Here is the basic code I have now, to properly sort each line of text, etc. (without the split() method):

Java Code:

while (scanner.hasNextLine()) {
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[Code] ....

I was able to eliminate the comments and identifiers from the text by trimming the first two characters of the string. For the split, I tried String[] tempArray = currentLine.split("s+"); however, that also took the spaces out of the addresses and names...so the results looked like this:

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