i am using netbeans6.7.1 version i implemented one program i.e web application ..when am excuting this one i got one error http status 500...
this is the code:
SumServlet.java
package com.sum;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
[code]....
correct this error
WishSrv.java
package com.wish;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Calendar;
import javax.servlet.ServletException;
[code]...
Below is my Servletclass code
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class MyFirstServlet extends HttpServlet {
[Code] .....
I have configured tomcat7 in my ecclipse ide...
I'm trying to learn java by making a login page using java, servlet, javascript, html and mysql. I can login with username and password, I can get all the information from database in the edit page. However, when I edit and click on "Submit" in EditPage.jsp, it gives HTTP Status 404. Same screen appears when I click on "Sign Up" from first page (NewFile.jsp) and click on "Submit" button after filling up user information.
I am posting all my code here but probably important ones are:
EditPage.jsp, Edit.java, EditDetails.java, UpdateUser.java and for Sign Up SignUpPage.jsp and Registration.java.
Firstly here are my error message and ss from my project explorer:
Here is my code:
LoginServlet.java
package com.amzi.servlets;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
[Code] ....
I'm a new Java user and I'm trying to code a simple login page. In first page (NewFile.jsp) users should enter their username and password and should click on "login", or click on "sign up".
1.) If user enters his username and password correctly, a login page (LoginPage.jsp) appears and says "welcome null" but it should show the name of that user instead of null.
2.) In that login page there is an edit button to edit profile information. When I clicked on it, every information is "null" and when I edit them and click on "Submit" button;
HTTP Status 404 -
type Status report
message
description The requested resource () is not available.
GlassFish Server Open Source Edition 3.1.2
that message appears.
3.) If I click on "Sign Up" button at the beginning, a registration jsp (SignUpPage.jsp) appears. After filling up text boxes and clicking on "Submit", same Status 404 screen appears.
I created a mysql database called "loginpage" using xampp. In that database there is a table called "users" and it has un, pass, name, surname, email and degree attributes.
Here is a screenshot of my project explorer:
Here is my code:
1. NewFile.jsp
<%@ page import="java.sql.*" %>
<%@ page import="java.io.*" %>
<%@ page import="java.util.*"%>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
[Code] .....
The JSP page is opening but the problem is if l click on the ADD or EDIT button l receive the 405 error Iam using MySQL and glassfish server
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
[Code].....
I am working wit netbean 7.2 ide,oracle 10g. the servlet program does not connected to the oracle db. i always recieve a
HTTP Status 404 -
type Status report
message
descriptionThe requested resource () is not available.
Oracle GlassFish Server 3.1.2.2
I have created a jsp file which does the simple task of reading data from a mysql database and displaying the results on a web page. Please see below:
<%@ page import="java.io.*,java.util.*,java.sql.*"%>
<%@ page import="javax.servlet.http.*,javax.servlet.*" %>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/sql" prefix="sql"%>
[Code] ....
However, each time I run the jsp file in the browser with my localhost as server, I get an HTTP Status 500 error.
I am trying to use hidden variable in project.When I launch my project i am able to get the welcome page.But when submit login values i am getting HTTP 404 error- Resource not found error.
`My home Page/Login Page
<body>
<form action="<%=request.getContextPath() %>/LoginServlet" method="get">
USERNAME<input type="text" name="uname"><br>
PASSWORD<input type="password" name="pass"><br>
<input type="submit" name="submit" value="submit">
My LoginServlet
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
System.out.println("sandeep");
PrintWriter out=response.getWriter();
String userName=request.getParameter("uname");
[code].....
below is my code and this exception was thrown in another page so I created a new page and only imported just a single package still its throwing an exception? Any reasons why?
<%@page contentType="text/html" pageEncoding="UTF-8" %>
<%@page import="java.sql.*;" %>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<h1>Hello World!</h1>
</body>
</html>
I have written some error checking code
File name ErrorPage.jsp
<%@ page language="java" isErrorPage="true" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Error</title>
</head>
[code]...
I have put error.jsp and badpage.jsp file in public access folder that is web content in eclipsewhen I am running the code I am status code of 500 and not the errorpage.jsp message .
i have one html page through which i want to go to servlet page but after submit it give the http 404 error.
i am using tomcat apache server.
in my web.xml I declared a resource under the block
<user-data-constraint>
<transport-guarantee>CONFIDENTIAL</transport-guarantee>
</user-data-constraint>
This resource is about a login page.But when I logout or when I visit some pages like Contacts or Home Page, I wouldn't use HTTPS protocol.At the moment, HTTPS remain in the url even if I declared this protocol only for that resource..This is my (little) web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
[code]....
So I have a screen I click on. The "webPage" comes back as the requested resource unavailable.
What I don't get is that when I run the server locally on my machine it works just fine. But when this is deployed out to server I get the error. The screen comes up but the data doesn't show up. Where should I look to troubleshoot this?
@RequestMapping(value = "/webPage_data", method = RequestMethod.GET)
public @ResponseBody
DataTableDto pastControllerDataFeed(Model model) {
I need to built a file upload service which should be memory effective. I should avoid loading the entire file into memory,Since I may have multiple http request which will pile up the Heap memory. Any effective way to upload a large file(For ex:1GB file) using http Streaming. I need to do the file upload on a single http call. Let's consider a scenario where 1 GB file to be uploaded using 512MB Heap memory. Not Sure If practically I can achieve this or not.
View Replies View RelatedWhen does HTTP Session object is created in web application. Suppose I have a website. Home page of website is HTTP page which contains details of company and link to Login page.
Consider below mentioned user journey as scenario:
a. user arrives at home page of website
b. user click on Login page
c. user fill in login details on login page and click on Submit
d. user is successfully authenticated and authorized from back end
e. User specific page is shown
f. user click on logout link
g. user is successfully logged out from website
h. user is redirected to home page
i. user closes browser
In the above mentioned user journey,
a. at which step does HTTP session starts (means at which steps does HTTP Session object is created ? )
b. at which step does HTTP session ends ?
In case required, assume tech stack to be Java 7, Servlet 2.5, JSP, Tomcat 7, Apache web server (for static web contents).....
I would like to know the details about how a server handles a multipart request. I know that a webserver comprises of a HTTP adapter(which is responsible for receiving http requests and sending http responses) and a container(which is responsible for handling dynamic requests).
So, when a client sends a request, the HTTP adapter receives it. Then transfers the request to the container if the http adapter cannot handle it(jsps, servlets for example).
Suppose, a client sends a multipart request which has an avi file of size upto 100mb. For example, lets assume that the client takes 5 minutes to upload the file.
Lets also assume that my application is only interested in flv files. Is there any way to stop/terminate the multipart request before the file is transferred to the server? So that the client's time will not be wasted?
I think that the HTTP adapter will transfer the request to the container only after receiving the entire request, i.e. the servlet will be called only after the file is transferred to the server from client. Is it right?
If its right then there is no easy way to terminate the multipart request unless the entire file is transferred to the server. Is this right?
I am running a test servlet on Tomcat and have implemented different behaviours for the doPost and doGet methods. When I access from the browser, only the doGet method gets called ultimately.
The Firefox developer tools show me a GET request from the browser to my Tomcat instance. Do browsers ever call the POST http method? How could I make this happen?
I am generating java script tag and javascript code in servlet and displaying it in each jsp page. i include this in every jsp in my application. I am preparing the following javascript content and diplayin each jsp
<script type="text/javascript"> BOOM.addVar (clientId = SOME universal unique ID ) </script>
the clientid will be uniqueid it gets generated every time.
Here my question is, is there any possibility the clientId will be store in browser cache or third party cache server. if yes how to prevent clientId from cache.
I don't want to prevent the whole jsp file from cache. i just want to prevent only that particular field. so that i can use advantages cache and also prevent particular header field to be cached.
Also can we prevent particular http header attribute from cache.
Is there any kind of way to generate HTTP request within a servlet, dispatch it to the server and get back the answer delivered to the servlet? Or are the servlets meant only to respond to passed requests, not generate them?
(I asked a similar question here: [Code] ..... but no luck)
I am trying to write a webservice class which actually handles multipart requests. T client will try to upload zip or tar.gz files which may be upto 1GB in size.
I dont want to validate the extension i client side.
I want to validate the file extension in server side and discard the request before the file is uploaded.
How can I do this?
I have the following questions:
1. Does a GET HTTP request contain a request body? If yes what is contained in it? Are the request headers also part of the request body?
2. Is it possible to send a byte array as part of the GET request in its body?
3. Is there a size limitation on the data that can be sent via a GET request?
I have a servlet that adds entries to a table and when there is a duplicate it redirects to an error page and I'd like to make it display the duplicate entry id.The problem is when I try to get the parameter and show the error (the duplicate entry id) on my jsp error page it shows null instead of the appropriate number.this is my servlet:
package package_ergasia;
import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
[code]....
I've the below data in my HTML.
<body>
<div class="container">
<form name="main" action="Insert_Record" method="post">
<table class="bordered">
<tr>
[Code]....
I'm getting the below error.
java.text.ParseException: Unparseable date: "09-10-14"
if i use d-MM-yyy, the output is
Thu Aug 09 00:00:00 IST 14
but i want the date in output to be.
09-10-14
below is how my data base is like.
how can i get this.
My dynamic web project has a java class that captures a session variable with the following code.
HttpSession LoginSession = request.getSession();
String VAR = LoginSession.getAttribute("myVar").toString(); //This is the row 127
If i test the app in local (Mac + Java 1.8 + Tomcat 8) all works. In my remote cloud server (Ubuntu 14.10 + Java 1.8 + Tomcat 8) all works, except this class, that has this code. I copy the complete error here. Note that the row 127 of the error message is the second row of the previous code; and, if i comment this row with // and assign a fix variable all works. So, the problem is that 127^ row.
14-Dec-2014 08:15:23.923 SEVERE [http-nio-8080-exec-14] org.apache.catalina.core.StandardWrapperValve.invoke Servlet.service() for servlet [srvNavigation.SrvPT] in context with path [/myapp] threw exception
java.lang.NullPointerException
at srvNavigation.SrvPT.doGet(SrvPT.java:127)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:618)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
[Code] ....
How can i solve the problem?
I am stuck with my application. I have jsp, servlet application with jasper report server. When I run the application through eclipse, everything works perfectly. But When I try to run it in Tomcat (without eclipse) it gives me the "Unable to resolve the class file " error. I tried all the solutions I got through the google, but still I am unable to come over it.
View Replies View Related