Is there any kind of way to generate HTTP request within a servlet, dispatch it to the server and get back the answer delivered to the servlet? Or are the servlets meant only to respond to passed requests, not generate them?
(I asked a similar question here: [Code] ..... but no luck)
I would like to know the details about how a server handles a multipart request. I know that a webserver comprises of a HTTP adapter(which is responsible for receiving http requests and sending http responses) and a container(which is responsible for handling dynamic requests).
So, when a client sends a request, the HTTP adapter receives it. Then transfers the request to the container if the http adapter cannot handle it(jsps, servlets for example).
Suppose, a client sends a multipart request which has an avi file of size upto 100mb. For example, lets assume that the client takes 5 minutes to upload the file.
Lets also assume that my application is only interested in flv files. Is there any way to stop/terminate the multipart request before the file is transferred to the server? So that the client's time will not be wasted?
I think that the HTTP adapter will transfer the request to the container only after receiving the entire request, i.e. the servlet will be called only after the file is transferred to the server from client. Is it right?
If its right then there is no easy way to terminate the multipart request unless the entire file is transferred to the server. Is this right?
Generally Socket Programming uses HTTP Protocol to send and receive messages in Java. Can we try to exchange HTTP/HTTPS requests instead of TCP?
a Socket constructs a HTTP request to send to another socket from information it has and sends to another one and Server responds with HTTPResponse.
The JSP page is opening but the problem is if l click on the ADD or EDIT button l receive the 405 error Iam using MySQL and glassfish server
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
[Code].....
Using Java 7 update 5 (I know it's old...), we are trying to send concurrent requests to a RMI Server. When we start to tamp up the load (not too much - up to 50 concurrent requests) we start to see many IO Problems like Broken Pipe and Connection Reset By Peer. Could we be hitting some unknown limitation on concurrent access? Is there such limitation?
View Replies View RelatedI have written the following code to handle multiple Client Request. Lets Assume that it takes server 300 nano seconds(ns) to process one connection request. It recieves two connection requests at time t1 and t1+200ns. Since server is busy handling request 1 at time t1+200ns. what will happen to request 2.if yes what is the max size of that buffer?Maximum number of request that a server process per unit time depends on the java code.Is there also a limit to how many request a server can recieve per unit time?
public class EchoServer
{
public static void main(String args[])
{
ServerSocket serverSocket = null;
BufferedReader readSocket = null;
PrintStream writeSocket = null;
serverSocket = new ServerSocket(9998);
[code]...
I did a Servlet and a JSP with a combobox. I called the JSP on one browser and selected value n1 from the combobox. From another computer, I called the (same URL) and selected value n2. I expected the Servlet to handled both requests separately, however when I select value n2 on the 2nd browser, the jsp on the 1st browser that initially had value 1, now changes into value 2 as well.
Why cant the servlet handle requests separately? users actions on different browsers should not interfere with each other..!
I've written an HTTPServlet that send an HTTP request to one HttpListener and receive POST requests from an Http Sender.This is the code:
package sspa.huvr.git;
import java.io.DataOutputStream;
import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.Date;
[code]...
but when is called from the doPost method it seems that the html content is not sent from the processRequest method.
my project is all about downloading files(text files, music files, etc) from a LINUX server using UI build in java, my mentor told me to use HTTP Client (Java apache), but how to start this.
Here's a sample scenario:
ScreenHunter_1.jpg
Consider the directory structure above.
First, how to connect with this LINUX server using JAVA.
ScreenHunter_2.jpg
and how to dowload the above file.
I am trying to write to an http server, but nothing happens. I can read from the file, I just cannot write to it and no errors are thrown. I do not know how to proceed.
Specifically, I have a text file on my server, and I can read from it (the text file already has content), but I cannot write to it. And, no exceptions are thrown.
url = new URL("http://kajl-ig.com/txt.txt");
urlConn = url.openConnection();
urlConn.setDoInput(true);
urlConn.setDoOutput(true);
urlConn.setUseCaches(false);
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(urlConn.getOutputStream()));
String s = "TEST Successfull!";
[code].....
The second code, I got from some random website, and I was desperate so I tried it. I am not sure what the
urlConn.setRequestProperty (String, String);
method does, so I removed it and it reads fine it just cannot write.
Now, I would like to properly stop the server. For that, I can do server.stop(); . However, this does not work since the object server is not public, it is contained within the public pc_proxy class.How do I do that?
Java Code: import java.net.*;
import java.io.*;
import com.sun.net.httpserver.*;
import java.util.concurrent.Executors;
import java.lang.reflect.Array;
[code]....
I am trying to check the integrity in a Bank Transaction that the message sent to the server has not been modified by any malware in the client system. For this I am trying to read the message sent to the server at the client boundary so as that it enters the network as customer with customer intended values. So, firstly I need to check where to I need intercept the message within client boundary. Secondly, Can I intercept the message and read its contents using Java?
I want to check what my Online Banking Server( Leta Say Bank of America) receives if I ask to transfer amount $100 to Account A . I assume that there is a malware in client system that changes recipient to B,$10000. My aplicaion which I intend to design, shoudl inform the user that the integrity of the message is compromised and should give the option to the user to abort it. plan to track what message is being sent from client to server. This I want to achieve by reading the message from client at the last point before it leaves the client and enter the network.
I have been trying to implement custom request method in HTTP header while posting my data to the server URL. My application specific URL accepts -X parameter and -d for the data and it is mandatory for that url. Basically I am trying to dump JSON data into my influx DB using CURL command which is working fine from the shell. But the issue is, if I am implementing the same in java with proper approach, it is not supported or working. My CURL command is :
curl -X POST -d '<my_json_data>' '<my_url>'
How can I implement the same in java using HttpUrlConnection or other available approach?
I am working on a chess game. I need to construct a game room where all the player are present and room chat is up. Also some tables where games are being played. Now my question is how to create this game room?
To me this room must need to be like static or global (if I am not mistaken) that is up when server starts and players can join this room and should be down when server is done. How can I implement such room that would stay up for infinite time.
i am using netbeans6.7.1 version i implemented one program i.e web application ..when am excuting this one i got one error http status 500...
this is the code:
SumServlet.java
package com.sum;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
[code]....
i have one html page through which i want to go to servlet page but after submit it give the http 404 error.
i am using tomcat apache server.
correct this error
WishSrv.java
package com.wish;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Calendar;
import javax.servlet.ServletException;
[code]...
in my web.xml I declared a resource under the block
<user-data-constraint>
<transport-guarantee>CONFIDENTIAL</transport-guarantee>
</user-data-constraint>
This resource is about a login page.But when I logout or when I visit some pages like Contacts or Home Page, I wouldn't use HTTPS protocol.At the moment, HTTPS remain in the url even if I declared this protocol only for that resource..This is my (little) web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
[code]....
I am trying to use hidden variable in project.When I launch my project i am able to get the welcome page.But when submit login values i am getting HTTP 404 error- Resource not found error.
`My home Page/Login Page
<body>
<form action="<%=request.getContextPath() %>/LoginServlet" method="get">
USERNAME<input type="text" name="uname"><br>
PASSWORD<input type="password" name="pass"><br>
<input type="submit" name="submit" value="submit">
My LoginServlet
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
System.out.println("sandeep");
PrintWriter out=response.getWriter();
String userName=request.getParameter("uname");
[code].....
So I have a screen I click on. The "webPage" comes back as the requested resource unavailable.
What I don't get is that when I run the server locally on my machine it works just fine. But when this is deployed out to server I get the error. The screen comes up but the data doesn't show up. Where should I look to troubleshoot this?
@RequestMapping(value = "/webPage_data", method = RequestMethod.GET)
public @ResponseBody
DataTableDto pastControllerDataFeed(Model model) {
Below is my Servletclass code
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class MyFirstServlet extends HttpServlet {
[Code] .....
I have configured tomcat7 in my ecclipse ide...
I need to built a file upload service which should be memory effective. I should avoid loading the entire file into memory,Since I may have multiple http request which will pile up the Heap memory. Any effective way to upload a large file(For ex:1GB file) using http Streaming. I need to do the file upload on a single http call. Let's consider a scenario where 1 GB file to be uploaded using 512MB Heap memory. Not Sure If practically I can achieve this or not.
View Replies View RelatedWhen does HTTP Session object is created in web application. Suppose I have a website. Home page of website is HTTP page which contains details of company and link to Login page.
Consider below mentioned user journey as scenario:
a. user arrives at home page of website
b. user click on Login page
c. user fill in login details on login page and click on Submit
d. user is successfully authenticated and authorized from back end
e. User specific page is shown
f. user click on logout link
g. user is successfully logged out from website
h. user is redirected to home page
i. user closes browser
In the above mentioned user journey,
a. at which step does HTTP session starts (means at which steps does HTTP Session object is created ? )
b. at which step does HTTP session ends ?
In case required, assume tech stack to be Java 7, Servlet 2.5, JSP, Tomcat 7, Apache web server (for static web contents).....
i have one html page ,inside html radio button and 3 textboxes and one submit button ->action->SampleServlet.java-> from here again come back to html page with checked radio buttton value and text box value. I dont want to click back button in this case, html page to servlet->here i have to call back to my html page with checked radio button and text box value .
I tried response.redirect(original.html)-->i cant able to display checked radio button and textbox value also tried requestdispatcher forward/include,html page comes newly from starting but i dont want it,i want to view in html page with checked radio button and text box value.
I'm trying to learn java by making a login page using java, servlet, javascript, html and mysql. I can login with username and password, I can get all the information from database in the edit page. However, when I edit and click on "Submit" in EditPage.jsp, it gives HTTP Status 404. Same screen appears when I click on "Sign Up" from first page (NewFile.jsp) and click on "Submit" button after filling up user information.
I am posting all my code here but probably important ones are:
EditPage.jsp, Edit.java, EditDetails.java, UpdateUser.java and for Sign Up SignUpPage.jsp and Registration.java.
Firstly here are my error message and ss from my project explorer:
Here is my code:
LoginServlet.java
package com.amzi.servlets;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
[Code] ....
I am running a test servlet on Tomcat and have implemented different behaviours for the doPost and doGet methods. When I access from the browser, only the doGet method gets called ultimately.
The Firefox developer tools show me a GET request from the browser to my Tomcat instance. Do browsers ever call the POST http method? How could I make this happen?