Consider the url-pattern:
<url-pattern> /Beer/* </url-pattern>
The web app structure is: -
webapps
|
-->AdviceApp
|
-->WEB-INF
--> {{Beer}} This can be real or virtual.
My book says that /Beer/* can be a real or a virtual directory. What is the difference between the two and how do I create a virtual directory in tomcat ?
this is the following task i am trying to do. Write an interface Directory to manipulate entries in a telephone directory for the University. The interface must support the following operations:
1) The ability to insert new entries into the directory. Entries should be stored in alphabetical order of surname.
2) Delete entries from the directory either by name or number
3) Provide a lookup method that will find the extension no of a member of staff given
his/her name. You should try to make this method run as efficiently as possible.
4) Change a person's telephone number
5) Print the telephone directory in a neatly tabulated fashion.
Write a class ArrayDirectory that implements this interface using an array to store the telephone directory information. The class must store the surname and initial for each member of staff and their telephone extension (a four digit number which may start with a zero). You may find it useful to define a class Entry to store information about individual entries. The entries should be read into the array from a text file consisting of multiple lines in the following format:
Surname<tab>Initials<tab>Telephone extension
The part that i am stuck on is trying to do the entry method, delete entries method, loop up method, change persons telephone number and be able to print it.
I have an app that saves pdfs and images from a web page. The web sections send info to the server elements running in Java. I have hardcoded the path to where the images and pdfs need to be saved but on the server, these paths will be different. I'd prefer to just save them to something like:
whateverMyDeploymentDirectoryIs/files/pdfs
or something. How do I find out what my root directory is so that I can make the path relative instead of hard coded?
I need to make some operations with a file. I struggle to understand why Apache is throwing this error:
(The system cannot find the file specified)
My file is located in the root directory of the project.
And here is how I indicate the path to it:
String filePath = "default.jpg";
InputStream inputStream = new FileInputStream(new File(filePath));
If I put the file in the Eclipse folder, it works... But I need it to work if I put it in my project's root folder.
So i have this program that is supposed to execute a command when a button is clicked. I get an error: java.io.IOException: Cannot run program "/Users /brianallison/Documents/Java/RELAP5": error=2, No such file or directory
The actual PATH should be /Users/brianallison/Documents/Java/RELAP5 GUI/issrs/Dist.At least that is where the Java app is and the executable that I am trying to execute when the butotn is clicked. Executable name is relap5.x or relap5.exe depending on the OS.
private void btnRunRelapActionPerformed(java.awt.event.ActionEvent evt) {
String in = " -i " + tfIntdta.getText();
String rst = " - r " + tfRstplt.getText();
String out = " -o " + tfOutdta.getText();
String strip = tfStpdta.getText();
String guistring = "-n gui";
String wd = System.getProperty("user.dir");
String osver = System.getProperty("os.name");
String app = "";
[code].....
I see you can import in 2 ways:
import java.util.*;
or
import java.util.Scanner/Random/etc;
if I used the first one it imports all the librarys within that (directory?). If so would that add to a bigger file size?
I have a directories in UNIX:
/home/t_bmf/Java/HelloWorld/src/helloworld :will contain a .java file
/home/t_bmf/Java/HelloWorld/bin :will contain all .class file
Let say a have a code:
package helloworld;
public class HelloWorld {
public static void main(String[] arg) {
System.out.println("Hello World");
}
}
a command to compile this even outside the directory /home/t_bmf/Java/HelloWorld/src/helloworld
javac -d /home/t_bmf/Java/HelloWorld/bin /home/t_bmf/Java/HelloWorld/src/helloworld/HelloWorld.java
This will generate a directory /home/t_bmf/Java/HelloWorld/bin/helloworld and file inside this is HelloWorld.class
To run this program I must be in directory /home/t_bmf/Java/HelloWorld/bin and using this command:
java helloworld.HelloWorld
Question:
I already how to run the HelloWorld.class, but I must be in helloworld /home/t_bmf/Java/HelloWorld/bin to run it. Is there's a way to run the class even when I am not in directory /home/t_bmf/Java/HelloWorld/bin? Let's say I'm in /home/t_bmf, can I still run the HelloWorld.class?
I am trying to unzip a zip file to a directory but I've tried several different codes and none of them work.The zip structure is like this:
test.zip
New Text Doc.txtNew Folder
New Text Doc.txt
and this is the code I am using
try {
// Open the zip file
ZipFile zipFile = new ZipFile(outputFileName);
Enumeration<?> enu = zipFile.entries();
while (enu.hasMoreElements()) {
ZipEntry zipEntry = (ZipEntry) enu.nextElement();
[code]....
In my program I have to get directory name&address, in this directory is none, one, or more *.txt(maybe not *.txt files) and I have to read info from all of them.
On C++ is very easy to do that with "findnext, find last, findfirst", so how can I do this in Java?
I am working on a java logic game and I want it to be able to work on other people's Mac's, so I tried to figure out how to make it create a folder in which it can create files. The file creating is going fine however the folder never seems to create.Here is the code I attempted to use:
File logicFile = new File("/Library/Application Support/LogicGameSupport");
if(!logicFile.exists()){
if(logicFile.mkdir()){
System.out.println("Directory success");
}else{
System.out.println("Directory failed");
}
}
Here my code . Iam trying to open text file in window_pane it will open when i click on save it will ask destination to save file if i save example like Read.txt it will save...when i go and check in that folder Read.txt file won't found...what is the error ....
Java Code:
import javax.swing.*;
import javax.swing.filechooser.FileFilter;
import javax.swing.filechooser.FileNameExtensionFilter;
import java.io.*;
import java.net.MalformedURLException;
import java.awt.*;
import java.awt.event.*;
public class Read extends JFrame
[Code] .....
Here my code am trying to open text file in window_pane it will open when i click on save it will ask destination to save file if i save example like Read.txt it will save...when i go and check in that folder Read.txt file won't found..
import javax.swing.*;
import javax.swing.filechooser.FileFilter;
import javax.swing.filechooser.FileNameExtensionFilter;
import java.io.*;
import java.net.MalformedURLException;
import java.awt.*;
import java.awt.event.*;
[code]....
Requirements - Use only standard Java API and no apache file utils for this.
Most of the answers I found on the internet either dont meet this requirement or load all file names into an array which can consume too much memory when no. of files = 20,000+. how I can do this. Is there also a way to keep track of new files that were added during the execution of the loop in this code ?
Im trying to create a linked stack that will hold the starting directory to the current directory, so that when i finish a directory it would go back to the parent. as i go through the files in a directory and find a child directory, i have to stack current directory and process the child directory, when thats done, pop the parent from the stack and continue processing it. Here is my code:
//import io File and ioexception
import java.io.File;
import java.io.IOException;
/*create class that will take a path to a directory, print the name of the argument directory, print the name of each file and directory in argument directory. Prints the directory name and each file and directory inside*/
public class dirStackPrint
[Code] .....
when I run the program, nothing prints, why is that? I'm having trouble understanding the processing of the top, push and pop functions, i have them in my code but they don't seem to be working as they should?
ensureFileIsVisible not working.
JFileChooser fileChooser = new JFileChooser();
fileChooser.setCurrentDirectory(new File(currentDirectory));
File f = new File(currentDirectory);
ArrayList<String> names = new ArrayList<>(Arrays.asList(f.list()));
for (String s : names)
if (s.startsWith(yearofIssueTXT.getText())) {
fileChooser.setSelectedFile(new File(s));
fileChooser.ensureFileIsVisible(fileChooser.getSelectedFile());
break;
}
int result = fileChooser.showOpenDialog(addNewCoinBody);
The file is not visible because it is at almost the end of the files in the directory. I want the filechooser to automatically scroll so that the file is seen in the list.
I've written a program to read files in a directory but I'd like for it to only read the text files of that directory.
import java.io.*;
public class Data {
public static void main(String[] args) throws IOException {
String target_dir = "C:files";
File dir = new File(target_dir);
File[] files = dir.listFiles();
[Code] .....
I am trying to crate an interface for the following file (code). The interface that I am trying to create will display a open dialog box where the user chooses which image (.dcm) it would like to open and then it should open it in a frame. The code below shows opening the image. The image opens when the image is in the same folder as the source code but I need it to open from a given path and I am really confused on how to do that. I have tried a lot of methods but still doesn't seem work. How to make it work.
This is the code (assuming the parameter that you are passing in image.dcm, I have tried a full path name on mac computer which is like /Users/Documents/image.dcm, where this path name never works):
/**
* This class displays the first frame of a file from any format
* supported by ImageIO.
* In the case of DICOM files, stored values are displayed as
* is, without using Value of Interest or Presentation LUTs.
*/
class Read1 {
public static void main(String[] s) {
[Code] .....
Can we set the class path for one level down the current directory? My structure is like
binlibresourceshexicon.cmdinside the folder dist.
In this case I could run the .cmd file which has java -cp .;lib;resources client.Test .
c: rycpdist>java hexicon.cmdBut if i put the .cmd file inside bin as like this and run as
c: rycpdistin>java hexicon.cmdI am getting this error Error: Could not find or load main class
Is there any possibility to set the class path in this case
I need to design a gui that will find out all the dead symbolic link from the directories. And I used the logic and syntax I find out in java orcle docs. And If I will give the direct path name of the symbolic file then it is running fine with the output and enable to find the smbolic link is active or not. Now the real problem is that , I want that logic of detection should run out through the complete files and subdirectories of the directory. So Then I used the tree walk concept to transver through the complete file system of the directory and embed the logic of the detection inside it for detection of the dead symbolic link. But now it showing erroe which is not approacable for me.
import java.io.File;
import java.io.IOException;
import java.io.PrintStream;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
public class To_Transver {
[Code]...
I'm using Ubuntu. After unpacking the tar file for JSE 1.7 version 45, in the the bin directory for adding an entry to PATH variable, I typed
javac
and I get the message
The program 'javac' can be found in the following packages:
* default-jdk
* ecj
* gcj-4.6-jdk
* gcj-4.7-jdk
* openjdk-7-jdk
* openjdk-6-jdk
Try: sudo apt-get install <selected package>
Do I have to install these ?
I don't really understand the question is the thing. Its about calling a file in the java program. I read the book and i can see how to call a file from a directory and how to save it and edit it but I don't understand what the instructor is asking for. Mostly what files need called and println.
Assuming the object that manages output will be called writer, write a statement that opens a text file called home.html for output by println statements.
To be file-writable and file-readable, an object must be an instance of a class that implements___________.
Write a statemnt that opens a file for input of objects and assigns a reference to the connection to ObjectIn. Assume the file is in the current directory, with the name automobiles. data.
My problem is that I want to load an Image from the source directory in Canavas' paint() method.
My code is currently (in a try/catch)
g.drawImage(ImageIO.read(new File(imageLocation)), imageX, imageY, null);
Where imageLocation leads to an image on my HDD ("C:UsersVladdeDocumentsFolders-Filesfolder.png")
I am trying to understand how package(directory structure) and JAR files work interchangeably. From my understanding JAR is a package file format typically used to aggregate many Java classes. Since many classes are usually contained inside a package, I should be able to create a JAR file from a package, and use them interchangeably. A single JAR file is easier to handle then multiple classes and folders.
To test my understanding of the concept, I am working with the following project structure,
/development_directory
____/BookPackage
________Book.java
____BookDemo.java
Book.java contains the following code,
package BookPackage;
public class Book{
private String bookname;
public Book(String str){
bookname = str;
}
public String getBookName(){
return bookname;
}
}
and BookDemo.java contains the following code,
import BookPackage.Book;
class BookDemo{
public static void main(String ... args){
Book b = new Book("Lord of the Rings");
System.out.println(b.getBookName());
}
}
From the development_directory, I used the following commands to compile and run the project,
development_directory/ javac BookDemo.java
development_directory/ java BookDemo
...and it compiles and works as expected.Now, I will try to convert the BookPackage folder(package) into single jar file for portability, and I am using the following command to do that,development_directory/ jar -cf bookpkg.jar BookPackage ...this command generates the bookpkg.jar file.
I am going to remove the BookPackage folder to see if bookpkg.jar file really works as a replacement for the BookPackage directory structure.
After removal of BookPackage folder, the development_directory structure looks like this,
/development_directory
____bookpkg.jar
____BookDemo.java
Now, I tried to use the following commands to see if the program works as before,
// to compile
development_directory/ javac -cp ./bookpkg.jar BookDemo.java
...it compiles without any error - this means the replacement of bookpkg.jar for BookPackage(package) folder structure is working - Am I correct?
// to run
development_directory/ java -cp ./bookpkg.jar BookDemo
...And I hit an error,
Error: Could not find or load main class BookDemo
But the BookDemo class is at default namespace - why it JRE won't be able to find the main method?
And, the way I am trying to replace package folder structure with a single JAR file - am I getting the concept correctly?
I'm trying to add a CLASSPATH to a manifest file linking (not sure If that's the right word) to an sqljdbc4.jar file.
If I copy the file Into my root folder and use CLASSPATH: sqljdbc4.jar It works fine.
Class-Path: sqljdbc4.jar
Main-Class: com.ncntech.go
If I try CLASSPATH: C:Program FilesMicrosoft JDBC Driver 4.0 for SQL Serversqljdbc_4.0enusqljdbc4.jar I receive a "Could not find or load main class" error.
Class-Path: C:Program FilesMicrosoft JDBC Driver 4.0 for SQL Serversqljdbc_4.0enusqljdbc4.jar
Main-Class: com.ncntech.go
Is the syntax correct for specifying a directory path ?
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties);
Properties props = new Properties();
props.load(in);
in.close();
FileOutputStream out = new FileOutputStream(newprop.properties);
props.setProperty("myDirectory","C:Lisa estUpdate" );
props.store(out, null);
out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
i have a folder which contains two types of files (for eg: .csv and .tiff) with same names like, abc.csv and abc.tiff.How to compare the list of files with same names while ignoring their extensions.And my second task is to copy the content from csv file and i have to use that name as file name of .tiff file(Ex: if i have a1 as content in csv file, i have to change .tiff file name from abc.tiff to a1.tiff)
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