If I try CLASSPATH: C:Program FilesMicrosoft JDBC Driver 4.0 for SQL Serversqljdbc_4.0enusqljdbc4.jar I receive a "Could not find or load main class" error.
I have an app that saves pdfs and images from a web page. The web sections send info to the server elements running in Java. I have hardcoded the path to where the images and pdfs need to be saved but on the server, these paths will be different. I'd prefer to just save them to something like:
whateverMyDeploymentDirectoryIs/files/pdfs
or something. How do I find out what my root directory is so that I can make the path relative instead of hard coded?
I have a requirement where a large file (100 -200MB) is uploaded from the client to a content management system. I am using a servlet with Apache Commons File Upload API. Apache FileUpload has 2 ways of handling files,
1) Non-Streaming 2) Streaming
Currently I use the Non-Streaming approach where the servlet stores the file in a temp location and upload the same into the content management system - This is taking lot of time so I am trying to implement Streaming API.
Content Management API supports streaming in 2 methods,
a) SetContent - Takes the file's ByteArrayOutputStream as input -> This gives OutOfMemoryException because the file being large b) AppendContent - Takes the file's ByteArrayOutputStream as input -> This method can be called multiple times to upload the large file but I dont know how to do this. The Apache File Upload gives InputStream of the file and I need to split that into chuncks and append into the content management system.
How to convert InputStream to 4KB ByteArrayOutputStream so that I can use the AppendContent method in content management API?
This is a snippet code that im developing. (no source of it) . I am facing a trouble to extract file in the same directory as the source file (example: extract here option)
public class HelperAction { public static void unzip(String zipFilePath)throws IOException { File dir = new File(zipFilePath.substring(0,zipFilePath.length())); // create output directory if it doesn't exist if(!dir.exists()) dir.mkdirs(); FileInputStream fis;
i downloaded a sample database code of an online payroll system. How can i assemble it to know how it works. the files include php and mysql files. it is to build an online payroll system
I am creating a web application that runs on server X(unix) and it has another unix system mounted on it. I want to generate the file tree structure of this mounted unix file system and show it on to a web application so that users can select a file and move it onto this current unix machine.
I know this sounds stupid and you may want to say why cant we directly copy the file, I am doing a proof of concept and using this as a basis.
I am new to java and I am creating a system that will ask the user to create a file that will store to a text file, Once the user created the file I have a class that will let the user input the subject name that has been created, However, I keep on getting this java.util.nosuchelementexception.Here's my code:
public void display_by_name() { String id, name,total; String key[]=new String[30]; String value[]=new String[30]; int i=0;
Consider the url-pattern: <url-pattern> /Beer/* </url-pattern>
The web app structure is: -
webapps | -->AdviceApp | -->WEB-INF --> {{Beer}} This can be real or virtual.
My book says that /Beer/* can be a real or a virtual directory. What is the difference between the two and how do I create a virtual directory in tomcat ?
In the following piece of code Iam trying to display the the loan amounts of the various loan objects located in a binary file. Iam trying to do his using getLoanAmount() in the loan class. the program is compiling but nothing is showing up on he console.
Program import java.io.*; public class Exercise19_06 { public static void main(String[] args) throws ClassNotFoundException, IOException { ObjectOutputStream output = new ObjectOutputStream( new FileOutputStream("loan.dat"));
So i have this program that is supposed to execute a command when a button is clicked. I get an error: java.io.IOException: Cannot run program "/Users /brianallison/Documents/Java/RELAP5": error=2, No such file or directory
The actual PATH should be /Users/brianallison/Documents/Java/RELAP5 GUI/issrs/Dist.At least that is where the Java app is and the executable that I am trying to execute when the butotn is clicked. Executable name is relap5.x or relap5.exe depending on the OS.
I am trying to unzip a zip file to a directory but I've tried several different codes and none of them work.The zip structure is like this:
test.zip New Text Doc.txtNew Folder New Text Doc.txt
and this is the code I am using
try { // Open the zip file ZipFile zipFile = new ZipFile(outputFileName); Enumeration<?> enu = zipFile.entries(); while (enu.hasMoreElements()) { ZipEntry zipEntry = (ZipEntry) enu.nextElement();
I am working on a java logic game and I want it to be able to work on other people's Mac's, so I tried to figure out how to make it create a folder in which it can create files. The file creating is going fine however the folder never seems to create.Here is the code I attempted to use:
Here my code . Iam trying to open text file in window_pane it will open when i click on save it will ask destination to save file if i save example like Read.txt it will save...when i go and check in that folder Read.txt file won't found...what is the error ....
Java Code:
import javax.swing.*; import javax.swing.filechooser.FileFilter; import javax.swing.filechooser.FileNameExtensionFilter; import java.io.*; import java.net.MalformedURLException; import java.awt.*; import java.awt.event.*; public class Read extends JFrame
Here my code am trying to open text file in window_pane it will open when i click on save it will ask destination to save file if i save example like Read.txt it will save...when i go and check in that folder Read.txt file won't found..
JFileChooser fileChooser = new JFileChooser(); fileChooser.setCurrentDirectory(new File(currentDirectory));
File f = new File(currentDirectory); ArrayList<String> names = new ArrayList<>(Arrays.asList(f.list())); for (String s : names) if (s.startsWith(yearofIssueTXT.getText())) { fileChooser.setSelectedFile(new File(s));
int result = fileChooser.showOpenDialog(addNewCoinBody);
The file is not visible because it is at almost the end of the files in the directory. I want the filechooser to automatically scroll so that the file is seen in the list.
In my web application i want to upload file to drop-box. I am getting file name from browser.Is it possible to upload file to drop-box with only file name.
I don't really understand the question is the thing. Its about calling a file in the java program. I read the book and i can see how to call a file from a directory and how to save it and edit it but I don't understand what the instructor is asking for. Mostly what files need called and println.
Assuming the object that manages output will be called writer, write a statement that opens a text file called home.html for output by println statements.
To be file-writable and file-readable, an object must be an instance of a class that implements___________.
Write a statemnt that opens a file for input of objects and assigns a reference to the connection to ObjectIn. Assume the file is in the current directory, with the name automobiles. data.
And this works fine: URL....The war file is deployed under the context root /bankconnect/ I want to make a servlet mapping, before the context root "i still want the context root bankconnect". URL....
I need to write the exact directory path like C:LisaestUpdate to a properties file.
I am trying it by
FileInputStream in = new FileInputStream(test.properties); Properties props = new Properties(); props.load(in); in.close(); FileOutputStream out = new FileOutputStream(newprop.properties); props.setProperty("myDirectory","C:Lisa estUpdate" ); props.store(out, null); out.close();
but the properties file is updated as C:Lisa estUpdate
Extra comes before :.
How can I remove that.
Even I tried it with an command but got same output.
i have a folder which contains two types of files (for eg: .csv and .tiff) with same names like, abc.csv and abc.tiff.How to compare the list of files with same names while ignoring their extensions.And my second task is to copy the content from csv file and i have to use that name as file name of .tiff file(Ex: if i have a1 as content in csv file, i have to change .tiff file name from abc.tiff to a1.tiff)
I'm trying to do a program that send a single file from a client to a default directory of a Server. The program use the datagramSocket and datagramPacket for the transfer via UDP. The client sent the packet of the file correctly and the server start the receiving but every time the Server class crashes after it's receiving 4/5 packet (exactly 8192 byte)
Then i put the code of the 2 class and the 2 output.
OUTPUT CLIENT:
PROGRAM TRANSFER PACKAGES name of file is : Doc1.pdf his dimension: 11408 byte
PROGRAM TRANSFER PACKAGES START NEW CONNECTION Directory: C:prova Server waiting in port: 9876 Waiting Client... Name of file is : Doc1.pdf Dimension : 11408
[Code] ....
In this point the program go in loop and didn't anything. I don't understand how can i resolve it...
